Creating a matrix with values in Kotlin in convenience - kotlin

Question

I want to create the following one with a fancy notation:
arrayOf(intArrayOf(4, 5), intArrayOf(5, 8), intArrayOf(1, 9), intArrayOf(8, 10), intArrayOf(1, 6))
at least, cannot I achieve something that looks as follows:
arrayOf<IntArray>((4, 5), (5, 8), (1, 9), (8, 10), (1, 6))
because it is pretty awkward to rewrite intArrayOf for each row to put in.
Note that I do not ask for the following syntax I'm aware of which is used to initialize an empty matrix with values that are either same or following a common pattern.
val array = Array(row) { IntArray(column) }

Answer 1

val result = listOf(4, 5, 5, 8, 1, 9, 8, 10, 1, 6)
.chunked(2)
.map { it.toIntArray() }
.toTypedArray()
Edit 1:
The calculation could go into an extension function:
fun List<Int>.toArrayOfIntArrays() = this.chunked(2).map { it.toIntArray() }.toTypedArray()
val result = listOf(4, 5, 5, 8, 1, 9, 8, 10, 1, 6).toArrayOfIntArrays()
Edit 2:
Another option – assuming that the inner IntArrays all will consist of exactly two elements – would be to use a user-defined infix function:
infix fun Int.with(i1: Int) = intArrayOf(this, i1)
val result = arrayOf(4 with 5, 5 with 8, 1 with 9, 8 with 10, 1 with 6)
Any word not in conflict with the Kotlin keywords could be used, 'with' is just an example.

Answer 2

If you simply don't like the wordiness of using intArrayOf you could define a shorter name to do the same, for example
fun i(vararg e: Int) = intArrayOf(*e)
And then do
arrayOf(i(4, 5), i(5, 8), i(1, 9), i(8, 10), i(1, 6))

Answer 3

Here is my solution, abusing operator overloading ;)
object Matrix {
operator fun get(vararg rows: IntArray) = rows
operator fun get(vararg values: Int): IntArray = intArrayOf(*values)
}
fun main() {
val result = Matrix.let {
it[
it[1, 2, 3],
it[4, 5, 6],
it[7, 8, 9],
]
}
println(result.toList().map { it.toList() }) // [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
}
Please don't use it