In db<>fiddle for Oracle 18c:
If I select a varray, then db<>fiddle returns an empty resultset, which is misleading.
with data as (select sys.odcivarchar2list('a', 'b', 'c') as my_array from dual)
select my_array from data
Result:
MY_ARRAY
-------- [resultset is empty]
db<>fiddle
#JackDouglas said this in a related post:
PHP’s oci_fetch_all doesn’t like abstract data types like
SDO_GEOMETRY, I’m getting errors like this in the logs:
PHP Warning: oci_fetch_all(): ORA-00932: inconsistent datatypes: expected CHAR got ADT PHP
Warning: oci_fetch_all(): ORA-00932: inconsistent datatypes: expected CHAR got ADT
Source: Return a value/row when selecting SDO_GEOMETRY
As a workaround, I want to return the varray's values as a concatenated text list (the same way it works in SQL Developer).
Like this:
with data as (select sys.odcivarchar2list('a', 'b', 'c') as my_array from dual)
select varray_list(my_array) from data
-- ^^^ A fake function.
Result:
MY_ARRAY
--------
SYS.ODCIVARCHAR2LIST('a', 'b', 'c')
--or
'a', 'b', 'c'
--or
a,b,c
Question:
In a query, is there a way to get a varray's values as a concatenated text list?
LATERAL join a table collection expression and then use LISTAGG:
with data (my_array) as (
select sys.odcivarchar2list('a', 'b', 'c') from dual union all
select sys.odcivarchar2list('d', 'e') from dual
)
select s.my_array_str
from data d
CROSS JOIN LATERAL (
SELECT LISTAGG(column_value, ',') WITHIN GROUP (ORDER BY ROWNUM)
AS my_array_str
FROM TABLE(d.my_array)
) s
Which outputs:
MY_ARRAY_STR
a,b,c
d,e
or, if you want the surrounding quotes:
with data (my_array) as (
select sys.odcivarchar2list('a', 'b', 'c') from dual union all
select sys.odcivarchar2list('d', 'e') from dual union all
select sys.odcivarchar2list('f', NULL, 'g') from dual
)
select s.my_array_str
from data d
CROSS JOIN LATERAL (
SELECT LISTAGG(
'''' || column_value || '''',
','
) WITHIN GROUP (ORDER BY ROWNUM)
AS my_array_str
FROM TABLE(d.my_array)
) s
Which outputs:
MY_ARRAY_STR
'a','b','c'
'd','e'
'f','','g'
db<>fiddle here
Related
I have a table with two columns
type
TXT
A
this is some text for %1 and %2
B
this is another step for %1
in a translation table I have the signification of the variables %X that looks like
Type
variable
descr
A
%1
#person1#
A
%2
#person2#
B
%1
#manager#
I want to replace in my first table all the variables by the description, so the result has to looks like this:
type
TXT
A
this is some text for #person1# and #person2#
B
this is another step for #manager#
I tried with a replace, but I didn't figured out how to make it work
To replace all variables you could use a recursive algorithm:
with data(typ, txt) as (
select 'A', 'this is some text for %1 and %2' from dual union all
select 'B', 'this is another step for %1' from dual
),
translations(typ, var, description) as (
select 'A', '%1', '#person1#' from dual union all
select 'A', '%2', '#person2#' from dual union all
select 'B', '%1', '#manager#' from dual -- union all
),
rtranslations(typ, var, description,rn) as (
select t.*, row_number() over(partition by typ order by var) as rn
from translations t
),
replacecte(typ, txt, replaced_txt, rn) as (
select d.typ, d.txt, replace(d.txt, t.var, t.description), t.rn
from data d
join rtranslations t on t.typ = d.typ
where t.rn = 1
union all
select r.typ, r.txt, replace(r.replaced_txt, t.var, t.description), t.rn
from replacecte r
join rtranslations t on t.typ = r.typ and t.rn = r.rn + 1
)
select r.typ, r.txt, replaced_txt from replacecte r
where rn = length(txt) - length(replace(txt,'%',''))
;
You can also do it this way without recursion. data and descr are of course just mock ups for your tables, you would not need any WITH clauses. This method uses the steps (1) break up the sentences into words, (2) outer join using those words to your description table, replacing any matches with the description values, (3) reassemble the words back into sentences using LISTAGG.
WITH data AS(SELECT 'A' type, 'this is some text for %1 and %2' txt FROM dual
UNION ALL
SELECT 'B' type, 'this is another step for %1' txt FROM dual
),
descr AS (SELECT 'A' type, '%1' variable,'#person1#' description FROM dual
UNION ALL
SELECT 'A' type, '%2' variable,'#person2#' description FROM dual
UNION ALL
SELECT 'B' type, '%1' variable,'#manager#' description FROM dual)
SELECT type,
LISTAGG(new_word,' ') WITHIN GROUP (ORDER BY seq) txt
FROM (SELECT x.type,
NVL(descr.description,x.word) new_word,
seq
FROM (SELECT type,SUBSTR(' '||txt,INSTR(' '||txt,' ',1,seq)+1,INSTR(' '||txt||' ',' ',1,seq+1) - (INSTR(' '||txt,' ',1,seq)+1)) word,seq
FROM data,
(SELECT ROWNUM seq FROM dual CONNECT BY LEVEL <= 50) x) x,
descr
WHERE x.type = descr.type(+)
AND x.word = descr.variable(+))
GROUP BY type
You could use PIVOT to get the var values from rows into columns (geting all vars in the same row with text) and then do multiple replaces depending on number of var values:
SELECT t.A_TYPE,
CASE WHEN d.V3 Is Not Null THEN REPLACE(REPLACE(REPLACE(t.TXT, '%1', d.V1), '%2', d.V2), '%3', d.V3)
WHEN d.V2 Is Not Null THEN REPLACE(REPLACE(t.TXT, '%1', d.V1), '%2', d.V2)
WHEN d.V1 Is Not Null THEN REPLACE(t.TXT, '%1', d.V1)
ELSE t.TXT
END "TXT"
FROM tbl t
INNER JOIN ( SELECT *
FROM ( Select A_TYPE, VAR, DESCRIPTION FROM descr )
PIVOT ( MAX(DESCRIPTION) For VAR IN('%1' "V1", '%2' "V2", '%' "V3") )
) d ON(d.A_TYPE = t.A_TYPE)
With sample data as:
WITH
tbl (A_TYPE, TXT) AS
(
Select 'A', 'this is some text for %1 and %2' From Dual Union All
Select 'B', 'this is another step for %1' From dual
),
descr (A_TYPE, VAR, DESCRIPTION) AS
(
Select 'A', '%1', '#person1#' From Dual UNION ALL
Select 'A', '%2', '#person2#' From Dual UNION ALL
Select 'B', '%1', '#manager#' From Dual
)
... the result should be
A_TYPE TXT
------ -----------------------------------------------
A this is some text for #person1# and #person2#
B this is another step for #manager#
I have the below table:
COL
---
XXY
YXX
XXX
NULL
I want to filter out the rows which don't consist of all 'X's.
Expected output:
COL
---
XXX
We can use REGEXP_LIKE here:
SELECT COL
FROM yourTable
WHERE REGEXP_LIKE(COL, '^X+$'); -- ^X+$ means all X from start to end
Another similar version:
SELECT COL
FROM yourTable
WHERE NOT REGEXP_LIKE(COL, '[^X]'); -- this means no non X present
Another option(without using a regular expression) might be using
WITH t(col) AS
(
SELECT 'XXY' FROM dual UNION ALL
SELECT 'YXX' FROM dual UNION ALL
SELECT 'XXX' FROM dual UNION ALL
SELECT NULL FROM dual UNION ALL
SELECT 'XX ' FROM dual
)
SELECT *
FROM t
WHERE REPLACE(NVL(col,'Y'),'X') IS NULL;
COL
----
XXX
without forgetting the case col = NULL through use of a NVL()
You can use the following syntax (assuming you are using MySQL database 5.6 or greater version):
SELECT * FROM table_name WHERE col_name REGEXP '^X+$';
If you don't want/have regexp then:
WITH
tbl AS
( Select 'XXY' "COL" From dual Union All
Select 'YXX' "COL" From dual Union All
Select 'XXX' "COL" From dual Union All
Select null "COL" From dual
)
Select COL
From tbl
Where Length(Nvl(COL, 'Z')) - Length( Replace( Upper(Nvl(COL, 'Z')), 'X', '')) Is Null
COL
---
XXX
This covers both small 'x' and capital 'X' if needed and returns original COL value
I generate SQL statements dynamically from the input file and I want to have the output in JSON format grouped by a key which I provide in an alias in the select statement.
The input file comes from another system and it looks like this:
'abc' AS [x.test1],
'cde' AS [y.test2],
'fgh' AS [y.test3]
In SQL Server I have a working query like this:
SELECT
(SELECT
'abc' AS [x.test1],
'cde' AS [y.test2],
'fgh' AS [y.test3]
FROM "dbo"."TEST"
FOR JSON PATH,
WITHOUT_ARRAY_WRAPPER
) AS RESULT
It returns this output which is grouped by key and this is working perfectly:
{"x":{"test1":"abc"},"y":{"test2":"cde","test3":"fgh"}}
I want to achieve the same output with oracle.
Currently, I got to here:
SELECT
(
SELECT json_object(
KEY '[x.test1]' IS 'abc',
KEY '[y.test2]' IS 'cde',
KEY '[y.test3]' IS 'fgh'
)
FROM test
)
AS RESULT from DUAL;
Problem is that this doesn't group my output by the key:
{"[x.test1]":"abc","[y.test2]":"cde","[y.test3]":"fgh"}
You could nest json_object() calls:
SELECT json_object(
KEY 'x' IS json_object(
KEY 'test1' IS 'abc'
),
KEY 'y' IS json_object(
KEY 'test2' IS 'cde',
KEY 'test3' IS 'fgh'
)
)
AS RESULT from DUAL;
RESULT
{"x":{"test1":"abc"},"y":{"test2":"cde","test3":"fgh"}}
fiddle
Or as you refer to grouping, if your data is really coming from tables, you could use json_objectagg() and the table data, with something like:
select json_object(
'x' value json_object(x.j_key value x.j_value),
'y' value json_objectagg(y.j_key, y.j_value)
) as result
from x
left join y on y.id = x.id
group by x.id, x.j_key, x.j_value
RESULT
{"x":{"test1":"abc"},"y":{"test2":"cde","test3":"fgh"}}
fiddle
WITH data (expr) AS (
SELECT q'~'abc' AS [x.test1],'cde' AS [y.test2],'fgh' AS [y.test3]~' FROM DUAL
),
rdata(expr) AS (
SELECT regexp_substr(expr,'[^,]+',1,LEVEL) AS expr
FROM data
CONNECT BY regexp_substr(expr,'[^,]+',1,LEVEL) IS NOT NULL
),
exprs AS (
SELECT expr, regexp_substr(expr, q'~'(.*)'~', 1, 1, 'i', 1) as val,
regexp_substr(expr, q'~\[(.*)\]~', 1, 1, 'i', 1) as path
FROM rdata
),
spaths AS (
SELECT e.*, LEVEL as lvl, regexp_substr(path,'[^\.]+',1,LEVEL) as pitem
FROM exprs e
CONNECT BY regexp_substr(path,'[^\.]+',1,LEVEL) IS NOT NULL AND prior val = val AND PRIOR sys_guid() IS NOT NULL
)
SELECT json_object(
s.pitem VALUE json_objectagg(
p.pitem VALUE p.val
)
) AS js
FROM spaths s
JOIN spaths p ON s.val = p.val AND p.lvl = 2
WHERE s.lvl = 1
GROUP BY s.pitem
;
JS
{"x":{"test1":"abc"}}
{"y":{"test2":"cde","test3":"fgh"}}
I have 2 lists which I need to compare. I need to find if at least one element from List A is found in List B. I know IN doesn't work with 2 lists. What are my other options?
Basically something like this :
SELECT
CASE WHEN ('A','B','C') IN ('A','Z','H') THEN 1 ELSE 0 END "FOUND"
FROM DUAL
Would appreciate any help!
You are probably looking for something like this. The WITH clause is there just to simulate your "lists" (whatever you mean by that); they are not really part of the solution. The query you need is just the last three lines (plus the semicolon at the end).
with
first_list (str) as (
select 'A' from dual union all
select 'B' from dual union all
select 'C' from dual
),
second_list(str) as (
select 'A' from dual union all
select 'Z' from dual union all
select 'H' from dual
)
select case when exists (select * from first_list f join second_list s
on f.str = s.str) then 1 else 0 end as found
from dual
;
FOUND
----------
1
In Oracle you can do:
select
count(*) as total_matches
from table(sys.ODCIVarchar2List('A', 'B', 'C')) x,
table(sys.ODCIVarchar2List('A', 'Z', 'H')) y
where x.column_value = y.column_value;
You need to repeat the conditions:
SELECT (CASE WHEN 'A' IN ('A', 'Z', 'H') OR
'B' IN ('A', 'Z', 'H') OR
'C' IN ('A', 'Z', 'H')
THEN 1 ELSE 0
END) as "FOUND"
FROM DUAL
If you are working with collection of String you can try Multiset Operators.
create type coll_of_varchar2 is table of varchar2(4000);
and:
-- check if exits
select * from dual where cardinality (coll_of_varchar2('A','B','C') multiset intersect coll_of_varchar2('A','Z','H')) > 0;
-- list of maching elments
select * from table(coll_of_varchar2('A','B','C') multiset intersect coll_of_varchar2('A','Z','H'));
Additionally:
-- union of elemtns
select * from table(coll_of_varchar2('A','B','C') multiset union distinct coll_of_varchar2('A','Z','H'));
select * from table(coll_of_varchar2('A','B','C') multiset union all coll_of_varchar2('A','Z','H'));
-- eelemnt from col1 not in col2
select * from table(coll_of_varchar2('A','A','B','C') multiset except all coll_of_varchar2('A','Z','H'));
select * from table(coll_of_varchar2('A','A','B','C') multiset except distinct coll_of_varchar2('A','Z','H'));
-- check if col1 is subset col2
select * from dual where coll_of_varchar2('B','A') submultiset coll_of_varchar2('A','Z','H','B');
I am trying to do something very similar but the first list is another field on the same query created with listagg and containing integer numbers like:
LISTAGG(my_first_list,', ') WITHIN GROUP(
ORDER BY
my_id
) my_first_list
and return this with all the other fields that I am already returning
SELECT
CASE WHEN my_first_list IN ('1,2,3') THEN 1 ELSE 0 END "FOUND"
FROM DUAL
I have data like this in a table
NAME PRICE
A 2
B 3
C 5
D 9
E 5
I want to display all the values in one row; for instance:
A,2|B,3|C,5|D,9|E,5|
How would I go about making a query that will give me a string like this in Oracle? I don't need it to be programmed into something; I just want a way to get that line to appear in the results so I can copy it over and paste it in a word document.
My Oracle version is 10.2.0.5.
-- Oracle 10g --
SELECT deptno, WM_CONCAT(ename) AS employees
FROM scott.emp
GROUP BY deptno;
Output:
10 CLARK,MILLER,KING
20 SMITH,FORD,ADAMS,SCOTT,JONES
30 ALLEN,JAMES,TURNER,BLAKE,MARTIN,WARD
I know this is a little late but try this:
SELECT LISTAGG(CONCAT(CONCAT(NAME,','),PRICE),'|') WITHIN GROUP (ORDER BY NAME) AS CONCATDATA
FROM your_table
Usually when I need something like that quickly and I want to stay on SQL without using PL/SQL, I use something similar to the hack below:
select sys_connect_by_path(col, ', ') as concat
from
(
select 'E' as col, 1 as seq from dual
union
select 'F', 2 from dual
union
select 'G', 3 from dual
)
where seq = 3
start with seq = 1
connect by prior seq+1 = seq
It's a hierarchical query which uses the "sys_connect_by_path" special function, which is designed to get the "path" from a parent to a child.
What we are doing is simulating that the record with seq=1 is the parent of the record with seq=2 and so fourth, and then getting the full path of the last child (in this case, record with seq = 3), which will effectively be a concatenation of all the "col" columns
Adapted to your case:
select sys_connect_by_path(to_clob(col), '|') as concat
from
(
select name || ',' || price as col, rownum as seq, max(rownum) over (partition by 1) as max_seq
from
(
/* Simulating your table */
select 'A' as name, 2 as price from dual
union
select 'B' as name, 3 as price from dual
union
select 'C' as name, 5 as price from dual
union
select 'D' as name, 9 as price from dual
union
select 'E' as name, 5 as price from dual
)
)
where seq = max_seq
start with seq = 1
connect by prior seq+1 = seq
Result is: |A,2|B,3|C,5|D,9|E,5
As you're in Oracle 10g you can't use the excellent listagg(). However, there are numerous other string aggregation techniques.
There's no particular need for all the complicated stuff. Assuming the following table
create table a ( NAME varchar2(1), PRICE number);
insert all
into a values ('A', 2)
into a values ('B', 3)
into a values ('C', 5)
into a values ('D', 9)
into a values ('E', 5)
select * from dual
The unsupported function wm_concat should be sufficient:
select replace(replace(wm_concat (name || '#' || price), ',', '|'), '#', ',')
from a;
REPLACE(REPLACE(WM_CONCAT(NAME||'#'||PRICE),',','|'),'#',',')
--------------------------------------------------------------------------------
A,2|B,3|C,5|D,9|E,5
But, you could also alter Tom Kyte's stragg, also in the above link, to do it without the replace functions.
Here is another approach, using model clause:
-- sample of data from your question
with t1(NAME1, PRICE) as(
select 'A', 2 from dual union all
select 'B', 3 from dual union all
select 'C', 5 from dual union all
select 'D', 9 from dual union all
select 'E', 5 from dual
) -- the query
select Res
from (select name1
, price
, rn
, res
from t1
model
dimension by (row_number() over(order by name1) rn)
measures (name1, price, cast(null as varchar2(101)) as res)
(res[rn] order by rn desc = name1[cv()] || ',' || price[cv()] || '|' || res[cv() + 1])
)
where rn = 1
Result:
RES
----------------------
A,2|B,3|C,5|D,9|E,5|
SQLFiddle Example
Something like the following, which is grossly inefficient and untested.
create function foo returning varchar2 as
(
declare bar varchar2(8000) --arbitrary number
CURSOR cur IS
SELECT name,price
from my_table
LOOP
FETCH cur INTO r;
EXIT WHEN cur%NOTFOUND;
bar:= r.name|| ',' ||r.price || '|'
END LOOP;
dbms_output.put_line(bar);
return bar
)
Managed to get till here using xmlagg: using oracle 11G from sql fiddle.
Data Table:
COL1 COL2 COL3
1 0 0
1 1 1
2 0 0
3 0 0
3 1 0
SELECT
RTRIM(REPLACE(REPLACE(
XMLAgg(XMLElement("x", col1,',', col2, col3)
ORDER BY col1), '<x>'), '</x>', '|')) AS COLS
FROM ab
;
Results:
COLS
1,00| 3,00| 2,00| 1,11| 3,10|
* SQLFIDDLE DEMO
Reference to read on XMLAGG