Concatenate results from a SQL query in Oracle - sql

Question

I have data like this in a table
NAME PRICE
A 2
B 3
C 5
D 9
E 5
I want to display all the values in one row; for instance:
A,2|B,3|C,5|D,9|E,5|
How would I go about making a query that will give me a string like this in Oracle? I don't need it to be programmed into something; I just want a way to get that line to appear in the results so I can copy it over and paste it in a word document.
My Oracle version is 10.2.0.5.

Answer 1

-- Oracle 10g --
SELECT deptno, WM_CONCAT(ename) AS employees
FROM scott.emp
GROUP BY deptno;
Output:
10 CLARK,MILLER,KING
20 SMITH,FORD,ADAMS,SCOTT,JONES
30 ALLEN,JAMES,TURNER,BLAKE,MARTIN,WARD

Answer 2

I know this is a little late but try this:
SELECT LISTAGG(CONCAT(CONCAT(NAME,','),PRICE),'|') WITHIN GROUP (ORDER BY NAME) AS CONCATDATA
FROM your_table

Answer 3

Usually when I need something like that quickly and I want to stay on SQL without using PL/SQL, I use something similar to the hack below:
select sys_connect_by_path(col, ', ') as concat
from
(
select 'E' as col, 1 as seq from dual
union
select 'F', 2 from dual
union
select 'G', 3 from dual
)
where seq = 3
start with seq = 1
connect by prior seq+1 = seq
It's a hierarchical query which uses the "sys_connect_by_path" special function, which is designed to get the "path" from a parent to a child.
What we are doing is simulating that the record with seq=1 is the parent of the record with seq=2 and so fourth, and then getting the full path of the last child (in this case, record with seq = 3), which will effectively be a concatenation of all the "col" columns
Adapted to your case:
select sys_connect_by_path(to_clob(col), '|') as concat
from
(
select name || ',' || price as col, rownum as seq, max(rownum) over (partition by 1) as max_seq
from
(
/* Simulating your table */
select 'A' as name, 2 as price from dual
union
select 'B' as name, 3 as price from dual
union
select 'C' as name, 5 as price from dual
union
select 'D' as name, 9 as price from dual
union
select 'E' as name, 5 as price from dual
)
)
where seq = max_seq
start with seq = 1
connect by prior seq+1 = seq
Result is: |A,2|B,3|C,5|D,9|E,5

Answer 4

As you're in Oracle 10g you can't use the excellent listagg(). However, there are numerous other string aggregation techniques.
There's no particular need for all the complicated stuff. Assuming the following table
create table a ( NAME varchar2(1), PRICE number);
insert all
into a values ('A', 2)
into a values ('B', 3)
into a values ('C', 5)
into a values ('D', 9)
into a values ('E', 5)
select * from dual
The unsupported function wm_concat should be sufficient:
select replace(replace(wm_concat (name || '#' || price), ',', '|'), '#', ',')
from a;
REPLACE(REPLACE(WM_CONCAT(NAME||'#'||PRICE),',','|'),'#',',')
--------------------------------------------------------------------------------
A,2|B,3|C,5|D,9|E,5
But, you could also alter Tom Kyte's stragg, also in the above link, to do it without the replace functions.

Answer 5

Here is another approach, using model clause:
-- sample of data from your question
with t1(NAME1, PRICE) as(
select 'A', 2 from dual union all
select 'B', 3 from dual union all
select 'C', 5 from dual union all
select 'D', 9 from dual union all
select 'E', 5 from dual
) -- the query
select Res
from (select name1
, price
, rn
, res
from t1
model
dimension by (row_number() over(order by name1) rn)
measures (name1, price, cast(null as varchar2(101)) as res)
(res[rn] order by rn desc = name1[cv()] || ',' || price[cv()] || '|' || res[cv() + 1])
)
where rn = 1
Result:
RES
----------------------
A,2|B,3|C,5|D,9|E,5|
SQLFiddle Example

Answer 6

Something like the following, which is grossly inefficient and untested.
create function foo returning varchar2 as
(
declare bar varchar2(8000) --arbitrary number
CURSOR cur IS
SELECT name,price
from my_table
LOOP
FETCH cur INTO r;
EXIT WHEN cur%NOTFOUND;
bar:= r.name|| ',' ||r.price || '|'
END LOOP;
dbms_output.put_line(bar);
return bar
)

Answer 7

Managed to get till here using xmlagg: using oracle 11G from sql fiddle.
Data Table:
COL1 COL2 COL3
1 0 0
1 1 1
2 0 0
3 0 0
3 1 0
SELECT
RTRIM(REPLACE(REPLACE(
XMLAgg(XMLElement("x", col1,',', col2, col3)
ORDER BY col1), '<x>'), '</x>', '|')) AS COLS
FROM ab
;
Results:
COLS
1,00| 3,00| 2,00| 1,11| 3,10|
* SQLFIDDLE DEMO
Reference to read on XMLAGG