Oracle SQL count of unique IDs in moving time window - sql

Question

I need to query data on a large transaction dataset in a Oracle SQL Developer database but unfortunately I didn't came up with the correct solution yet - hopefully someone can help me.
The dataset consists of the following:
Customer_ID, Counterparty_ID, Transaction ID, Transaction_Amount, Date
Task :
Flag the transactions of a customer, when a customers made transactions (>= 1000 € each) with >= 5 different counterparties in a 7day time window.
The time window should be a moving time window: E.g. if the transaction date is 17.6. the time window would be +- 6 days (11. - 23.06.).
Within a time window only distinct counterparties should be counted. E.g. if a customer has made 5 transactions with counterparty X in time window A, it is counted as 1. If the customer made additional transactions with counterparty X but in time window B, it is again counted as 1 for that time window.
So far I was only able to solve the task with calendar weeks as time window but that is not as intended.

Answer 1

You haven't provided any sample data or expected output so its difficult to know exactly what you want to output; however, you can immediately filter out all the rows with transaction_amount < 1000 and then, from Oracle 12, you use MATCH_RECOGNIZE to perform row-by-row matching:
SELECT *
FROM (
SELECT m.*,
COUNT(DISTINCT counterparty_id) OVER (
PARTITION BY customer_id, match
) AS num_counterparties
FROM (
SELECT *
FROM table_name
WHERE transaction_amount >= 1000
)
MATCH_RECOGNIZE (
PARTITION BY customer_id
ORDER BY "DATE"
MEASURES
MATCH_NUMBER() AS match
ALL ROWS PER MATCH
AFTER MATCH SKIP TO NEXT ROW
PATTERN ( within_week+ )
DEFINE
within_week AS "DATE" < FIRST("DATE") + INTERVAL '7' DAY
) m
)
WHERE num_counterparties >= 5;
Which, for the sample data:
CREATE TABLE table_name (
Customer_ID, Counterparty_ID, Transaction_ID, Transaction_Amount, "DATE"
) AS
SELECT 1, 1, 1, 1000, DATE '1970-01-01' FROM DUAL UNION ALL
SELECT 1, 2, 2, 1000, DATE '1970-01-02' FROM DUAL UNION ALL
SELECT 1, 3, 3, 1000, DATE '1970-01-03' FROM DUAL UNION ALL
SELECT 1, 4, 4, 1000, DATE '1970-01-04' FROM DUAL UNION ALL
SELECT 1, 5, 5, 1000, DATE '1970-01-05' FROM DUAL;
Outputs:
CUSTOMER_ID
DATE
MATCH
COUNTERPARTY_ID
TRANSACTION_ID
TRANSACTION_AMOUNT
NUM_COUNTERPARTIES
1
01-JAN-70
1
1
1
1000
5
1
02-JAN-70
1
2
2
1000
5
1
03-JAN-70
1
3
3
1000
5
1
04-JAN-70
1
4
4
1000
5
1
05-JAN-70
1
5
5
1000
5
db<>fiddle here