How to loop through all same name parent and child nodes - xslt-1.0

Question

I have an XML file where I have same name nodes: Parent and child, for example:
<Root>
<Field name="ID">
<description>Test 1</description>
</Field>
<Field name="Period">
<description>Test 2</description>
<Field name="Name">
<description>Test 3</description>
</Field>
<Field name="Name2">
<description>Test 4</description>
<Field name="address">
<description>Test 5</description>
</Field>
<Field name="partyID">
<description>Test 6</description>
<Field name="E-ID">
<Field name="address">
<description>Test 7</description>
</Field>
</Field>
</Field>
</Field>
</Field>
</Root>
The problem is, I am not sure how deep we can have child elements with the same name:
I used template-match on top parent node:
<xsl:template match="Field">
<xsl:value-of select="description"/>
<xsl:for-each select="Field">
<xsl:value-of select="description"/>
</xsl:for-each>
</xsl:template>
This code is not providing me all the child node values. I am looking for a code which can loop through all same name nodes and provide value of description element.
I cannot add multiple for-each because as I said, this is unknown how many times we will have Field node inside another Field node.
Please help me to solve this problem.

Answer 1

You could use recursion to process all Field elements from the root of the tree to the leaves - for example (you did not post the expected result, so I made something up):
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/Root">
<output>
<xsl:apply-templates select="Field"/>
</output>
</xsl:template>
<xsl:template match="Field">
<desc>
<xsl:value-of select="description"/>
</desc>
<xsl:apply-templates select="Field"/>
</xsl:template>
</xsl:stylesheet>
Alternatively, you could just select all Field elements regardless of their position in the tree hierarchy:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/Root">
<output>
<xsl:for-each select="//Field">
<desc>
<xsl:value-of select="description"/>
</desc>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>