Getting key column in loop + XSLT - stylesheet

I need a help on getting primary key values repeated times from the xml.Here is the xml file.
<?xml version="1.0" encoding="UTF-8"?>
<request id="test">
<dataSets>
<dataSet name="dim_table" friendlyName="dim" tableType="DIM">
<fields>
<field name="customer_id" dataType="varchar" primaryKey="true"/>
<field name="customer_name" dataType="VARCHAR" primaryKey="false"/>
<field name="customer_address" dataType="CHAR" primaryKey="false"/>
</fields>
</dataSet>
</dataSets>
</request>
the required output is
KeycolumnName,Columnname
customer_id,customer_id
customer_id,customer_name
customer_id,customer_address
Can anyone help me on this?

Updated code (previous answer couldn't handle this much new code):
This code works for me:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="//dataSet">
<xsl:for-each select="fields/field">
KeyColumnName="<xsl:value-of select="../field[#primaryKey='true']/#name" />" ColumnName="bar <xsl:value-of select="#name" />"
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

XML formatting is needed for a full answer, but:
<xsl:template match="/dataSets/dataSet/fields">
<xsl:for-each select="field">
<xsl:value-of select="#name" />
</xsl:for-each>
</xsl:template>
(example code not tested)
Use XPath to define the content of the "select" attributes.
Reference:
http://www.w3schools.com/xsl/el_for-each.asp

Related

XSLT 1.0 Select Name field based on evaluation of Date and Time fields

I have XML form data coming in from a vendor app that allows me to select values for fields on the form by using this format.
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/XSL/Transform" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output method="text" /><xsl:template match="/"><xsl:apply-templates/></xsl:template>
<xsl:template match="DataSet/diffgr:diffgram/Forms">
<xsl:for-each select="Form">
<xsl:value-of select="FieldName1"/>
<xsl:value-of select="FieldName2"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I can't see the XML, but I can surmise from this that all of the fields are siblings within the <form> and looks something like this:
<form>
<CosignerName1 value="John Doe"/>
<CosignerDate1 value="1/1/1970"/>
<CosignerTime1 value="8:46 PM"/>
<CosignerName2 value="Jane Smith"/>
<CosignerDate2 value="2/2/1972"/>
<CosignerTime2 value="11:46 AM"/>
...
<CosignerName12 value="Will Hunting"/>
<CosignerDate12 value="12/12/1982"/>
<CosignerTime12 value="1:00 AM"/>
</form>
<form>
<CosignerName1 value="Bill Thomas"/>
<CosignerDate1 value="5/5/2020"/>
<CosignerTime1 value="8:46 PM"/>
<CosignerName2 value="Bev Poole"/>
<CosignerDate2 value="6/6/2022"/>
<CosignerTime2 value="11:46 AM"/>
...
<CosignerName12 value="Bob Ross"/>
<CosignerDate12 value="12/12/1982"/>
<CosignerTime12 value="1:00 AM"/>
</form>
Known factors:
Each form has 12 cosigners, each with numbered field names i.e. CosignerName1, CosignerName2, etc.
Each named cosigner also has a CosignerDate and a CosignerTime field associated by number. i.e. CosignerName1 has CosignerDate1 and CosignerTime1 fields that, when combined, show when that user signed the form.
I am using the word 'idnum' in my code and in this question to refer to the number at the end of each label that shows they are part of a set i.e CosignerName1, CosignerDate1, and CosignerTime1 all share idnum=1
Goal: Identify and select only the most recent CosignerName, based on CosignerDate and CosignerTime.
To do this, I figure I need to:
Find the most recent CosignerDate/CosignerTime combination
Read the label of either of the identified fields to extract the idnum from the end
Use the idnum to to identify the correct CosignerName and output it
I have some pieces of the solution, but no way to bring them together:
Create a Timestamp
I can combine a set of CosignerDate[idnum] and CosignerTime[idnum] fields, then translate them into a timestamp. If I could create an array of these timestamps, then I could sort and find the most recent one, but as I understand it XSLT 1.0 doesn't have arrays. So I am not sure what to do with this.
<xsl:variable name="mm" select="substring-before(CosignerDate1,'/')" />
<xsl:variable name="mmyyyy" select="substring-after(CosignerDate1,'/')"/>
<xsl:variable name="dd" select="substring-before($mmyyyy,'/')" />
<xsl:variable name="yyyy" select="substring-after($mmyyyy,'/')" />
<xsl:variable name="ampm" select="substring-after(CosignerTime1,' ')" />
<xsl:variable name="time">
<xsl:choose>
<xsl:when test="$ampm = 'AM'">
<xsl:value-of select="number(translate(substring-before(CosignerTime1,' '),':',''))" />
</xsl:when>
<xsl:when test="$ampm = 'PM'">
<xsl:value-of select="number(translate(substring-before(CosignerTime1,' '),':',''))+number('1200')" />
</xsl:when>
</xsl:choose>
</xsl:variable>
<xsl:value-of select="concat('Timestamp:',$yyyy,$mm,$dd,$time)"/>
The code above outputs something like: Timestamp:202209191128
Get idnums
I can loop through all of the Cosigners and extract the identifying number shared by their labels.
<xsl:for-each select="*[starts-with(local-name(), 'CosignerName')]">
<xsl:variable name="idnum">
<xsl:value-of select="translate(local-name(),'CosignerName','')" />
</xsl:variable>
<xsl:value-of select="$idnum"/>
<xsl:value-of select="','"/>
</xsl:for-each>
This code above outputs something like: 1,4,7,12
But, this is where I get lost.
Failed Attempt
I tried something like the code below. The logic was to loop through each Cosigner name (12 iterations), get the idnum from the label, use that to get the CosignerDate and CosignerTime, create a timestamp, then sort the timestamps, if the timestamp we are looking at is the top one (most recent) then use the idnum to select the correct CosignerName and output it.
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/XSL/Transform" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output method="text" /><xsl:template match="/"><xsl:apply-templates/></xsl:template>
<xsl:template match="DataSet/diffgr:diffgram/Forms">
<xsl:for-each select="Form">
<xsl:for-each select="*[starts-with(local-name(), 'CosignerName')]">
<xsl:variable name="idnum">
<xsl:value-of select="translate(local-name(),'CosignerName','')" />
</xsl:variable>
<xsl:variable name="mm" select="substring-before(concat(CosignerDate,$idnum),'/')" />
<xsl:variable name="mmyyyy" select="substring-after(concat(CosignerDate,$idnum),'/')"/>
<xsl:variable name="dd" select="substring-before($mmyyyy,'/')" />
<xsl:variable name="yyyy" select="substring-after($mmyyyy,'/')" />
<xsl:variable name="ampm" select="substring-after(concat(CosignerTime,$idnum),' ')" />
<xsl:variable name="time">
<xsl:choose>
<xsl:when test="$ampm = 'AM'">
<xsl:value-of select="number(translate(substring-before(concat(CosignerTime,$idnum),' '),':',''))" />
</xsl:when>
<xsl:when test="$ampm = 'PM'">
<xsl:value-of select="number(translate(substring-before(concat(CosignerTime,$idnum),' '),':',''))+number('1200')" />
</xsl:when>
</xsl:choose>
</xsl:variable>
<xsl:variable name="timestamp" select="concat('Timestamp: ',$yyyy,$mm,$dd,$time)"/>
<xsl:sort select="$timestamp" data-type="number" order="descending"/>
<xsl:if test="position() = 1"><xsl:value-of select="."/></xsl:if>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This of course fails for several reasons:
the concat with the $idnum doesn't actually pull values from fields
the sort has to be the first thing in the for-each
the sort has to happen after all of the timestamps are created
the sorted list of timestamps still needs to reference which idnum they were generated from
Without being able to create an array of timestamps and idnums, I don't know how you can accomplish this.
Does anyone know how can I get at the CosignerName[idnum] that is correlated with the most recent CosignerDate[idnum]/CosignerTime[idnum]?
I believe you could just sort the CosignerNameX nodes by the individual components of their associated dates and times, as shown in the two other answers I linked to:
https://stackoverflow.com/a/59288030/3016153
https://stackoverflow.com/a/30631073/3016153
However, it might be more efficient - and certainly more readable - to do this in two steps:
Construct a dateTime value for each cosigner;
Find the cosigner with the most recent value.
Consider the following example:
XML
<DataSet xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<diffgr:diffgram>
<Forms>
<form>
<CosignerName1 value="John Doe"/>
<CosignerDate1 value="1/1/1970"/>
<CosignerTime1 value="8:46 PM"/>
<CosignerName2 value="Jane Smith"/>
<CosignerDate2 value="2/2/1972"/>
<CosignerTime2 value="11:46 AM"/>
<CosignerName12 value="Will Hunting"/>
<CosignerDate12 value="12/12/1982"/>
<CosignerTime12 value="1:00 AM"/>
</form>
<form>
<CosignerName1 value="Bill Thomas"/>
<CosignerDate1 value="5/5/2020"/>
<CosignerTime1 value="8:46 PM"/>
<CosignerName2 value="Bev Poole"/>
<CosignerDate2 value="6/6/2022"/>
<CosignerTime2 value="11:46 AM"/>
<CosignerName12 value="Bob Ross"/>
<CosignerDate12 value="12/12/1982"/>
<CosignerTime12 value="1:00 PM"/>
</form>
</Forms>
</diffgr:diffgram>
</DataSet>
XSLT 1.0 + EXSLT node-set()
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1"
xmlns:exsl="http://exslt.org/common"
exclude-result-prefixes="diffgr exsl">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/DataSet">
<output>
<xsl:for-each select="diffgr:diffgram/Forms/form">
<xsl:variable name="datetimes">
<xsl:for-each select="*[starts-with(local-name(), 'CosignerName')]">
<!-- identify values -->
<xsl:variable name="i" select="substring-after(local-name(), 'CosignerName')" />
<xsl:variable name="date" select="../*[local-name()=concat('CosignerDate', $i)]/#value" />
<xsl:variable name="time" select="../*[local-name()=concat('CosignerTime', $i)]/#value" />
<!-- extract date components -->
<xsl:variable name="year" select="substring-after(substring-after($date, '/'), '/')" />
<xsl:variable name="month" select="substring-before($date, '/')" />
<xsl:variable name="day" select="substring-before(substring-after($date, '/'), '/')" />
<!-- extract time components -->
<xsl:variable name="hour12" select="substring-before($time, ':')" />
<xsl:variable name="minute" select="substring-before(substring-after($time, ':'), ' ')" />
<xsl:variable name="pm" select="contains($time,'PM')" />
<xsl:variable name="hour" select="$hour12 mod 12 + 12*$pm"/>
<!-- construct dateTime -->
<datetime cosigner="{#value}" index="{$i}">
<xsl:value-of select="$year"/>
<xsl:value-of select="format-number($month, '-00')"/>
<xsl:value-of select="format-number($day, '-00')"/>
<xsl:value-of select="format-number($hour, 'T00')"/>
<xsl:value-of select="format-number($minute, ':00')"/>
<xsl:text>:00</xsl:text>
</datetime>
</xsl:for-each>
</xsl:variable>
<!-- output -->
<form>
<xsl:for-each select="exsl:node-set($datetimes)/datetime">
<xsl:sort select="." data-type="text" order="descending"/>
<xsl:if test="position()=1">
<last-cosigner index="{#index}" dateTime="{.}" >
<xsl:value-of select="#cosigner"/>
</last-cosigner>
</xsl:if>
</xsl:for-each>
</form>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<output>
<form>
<last-cosigner index="12" dateTime="1982-12-12T01:00:00">Will Hunting</last-cosigner>
</form>
<form>
<last-cosigner index="2" dateTime="2022-06-06T11:46:00">Bev Poole</last-cosigner>
</form>
</output>
P.S. With a Microsoft processor you may need to change the namespace declaration:
xmlns:exsl="http://exslt.org/common"
to:
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
and then change the exsl prefix in lines #5 and #39 to msxsl.

Advanced muenchian grouping: group by items in child collection

I'm familiar with simple muenchian grouping in XSL, but I've encountered a problem, which I honestly don't even know, how to approach it.
So I've got an XML:
<whiskies>
<whisky name="ABC" percent="" region="" type="">
<tastingNotesCollection/>
<bottles>
<bottle price="" size="" level="0" date=""/>
<bottle price="" size="" level="70" date=""/>
<bottle price="" size="" level="100" date=""/>
</bottles>
<comments/>
</whisky>
<whisky name="DEF" percent="" region="" type="">
<tastingNotesCollection/>
<bottles>
<bottle price="" size="" level="0" date=""/>
<bottle price="" size="" level="100" date=""/>
</bottles>
<comments/>
</whisky>
<whisky name="GHI" percent="" region="" type="">
<tastingNotesCollection/>
<bottles>
<bottle price="" size="" level="30" date=""/>
</bottles>
<comments/>
</whisky>
<whiskies>
And the goal is to group the whiskies by levels of a bottle:
So level="0" is considered empty.
Anything from level="1" to level="99" is considered open.
And level="100" is considered unopened.
So the transformed result (will be done in HTML) should look like this:
<h1>Empty</h1>
<ul>
<li>ABC</li>
<li>DEF</li>
</ul>
<h1>Open</h1>
<ul>
<li>ABC</li>
<li>GHI</li>
</ul>
<h1>Unopened</h1>
<ul>
<li>ABC</li>
<li>DEF</li>
</ul>
As you can see, the same whisky can show up in multiple groups, depending on how much bottles there are and how full those bottles are.
The second problem is, that the "Open" group doesn't have an exact value and can be aynthing from 1 to 99.
So yeah, don't really know if this can be solved at all or how to even start on this. Any tips appreciated.
I don't think you want to use Muenchian grouping for this. You would need to define a key that enumerates all values in the range from 1 to 99 - and I believe that would take away any advantage that using a key would otherwise bring.
Since your result has either exactly or at most 3 groups (your question is ambiguous in this respect), you could do simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:template match="/whiskies">
<output>
<group status="empty">
<xsl:for-each select="whisky[bottles/bottle/#level=0]">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
<group status="open">
<xsl:for-each select="whisky[bottles/bottle[#level>0 and #level < 100]]">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
<group status="unopened">
<xsl:for-each select="whisky[bottles/bottle/#level=100]">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
</output>
</xsl:template>
</xsl:stylesheet>
to get (after fixing the input to be a well-formed XML!):
Result
<?xml version="1.0" encoding="utf-8"?>
<output>
<group status="empty">
<name>ABC</name>
<name>DEF</name>
</group>
<group status="open">
<name>ABC</name>
<name>GHI</name>
</group>
<group status="unopened">
<name>ABC</name>
<name>DEF</name>
</group>
</output>
Make your own adjustment for HTML output.
Added:
Here is an alternative approach using keys (though still not Muenchian grouping) which might be more performant:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:key name="w" match="whisky" use="bottles/bottle/#level" />
<xsl:key name="w1" match="whisky" use="boolean(bottles/bottle[#level!=0 and #level!=100])" />
<xsl:template match="/whiskies">
<output>
<group status="empty">
<xsl:for-each select="key('w', 0)">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
<group status="open">
<xsl:for-each select="key('w1', true())">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
<group status="unopened">
<xsl:for-each select="key('w', 100)">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
</output>
</xsl:template>
</xsl:stylesheet>
Or even:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:key name="bottle" match="bottle" use="ceiling(#level div 99)" />
<xsl:template match="/whiskies">
<output>
<group status="empty">
<xsl:for-each select="key('bottle', 0)/../..">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
<group status="open">
<xsl:for-each select="key('bottle', 1)/../..">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
<group status="unopened">
<xsl:for-each select="key('bottle', 2)/../..">
<name>
<xsl:value-of select="#name"/>
</name>
</xsl:for-each>
</group>
</output>
</xsl:template>
</xsl:stylesheet>
If you did want to use xsl:key, you could create 3 of them with the filter criteria:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" />
<xsl:key name="Empty" match="whisky[bottles/bottle/#level=0]" use="#name"/>
<xsl:key name="Open" match="whisky[bottles/bottle/#level[. > 1 and . < 99]]" use="#name"/>
<xsl:key name="Unopened" match="whisky[bottles/bottle/#level=100]" use="#name"/>
<xsl:template match="/">
<xsl:variable name="whiskies" select="/whiskies/whisky/#name"/>
<xsl:for-each select="document('')/xsl:stylesheet/xsl:key/#name">
<xsl:variable name="status" select="."/>
<h1><xsl:value-of select="$status"/></h1>
<ul>
<xsl:for-each select="$whiskies[key($status, .)]">
<li><xsl:value-of select="."/></li>
</xsl:for-each>
</ul>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

XSLT: Convert Name/Value pair and transform an XML

I need to convert a name value pair into XML. I'm able to generate an XML, but the element name should be grouped and it should not be duplicated. Please see below. The FieldValue element contains 2 OrderItem values in the Detail node. If the FieldValue with OrderItem repeats, then the result should be grouped into one OrderItem node. Please help.
Source XML:
<SC>
<Header>
<Record>
<FieldName>Schema</FieldName>
<FieldValue>OrderHeader</FieldValue>
</Record>
<Record>
<FieldName>Order</FieldName>
<FieldValue>1234</FieldValue>
</Record>
</Header>
<Detail>
<Record>
<FieldName>Schema</FieldName>
<FieldValue>OrderItem</FieldValue>
</Record>
<Record>
<FieldName>Item</FieldName>
<FieldValue>1</FieldValue>
</Record>
<Record>
<FieldName>Qty</FieldName>
<FieldValue>10</FieldValue>
</Record>
</Detail>
<Detail>
<Record>
<FieldName>Schema</FieldName>
<FieldValue>OrderItem</FieldValue>
</Record>
<Record>
<FieldName>Item</FieldName>
<FieldValue>2</FieldValue>
</Record>
<Record>
<FieldName>Qty</FieldName>
<FieldValue>20</FieldValue>
</Record>
</Detail>
</SC>
Target XML:
<Order>
<OrderItem>
<Item>
<Item>1</Item>
<Qty>10</Qty>
</Item>
<Item>
<Item>2</Item>
<Qty>20</Qty>
</Item>
</OrderItem>
</Order>
XSLT:
<xsl:template match="#*|node()">
<Order>
<xsl:for-each select="Detail">
<Item>
<xsl:apply-templates select="Record[position()>1]"/>
</Item>
</xsl:for-each>
</Order>
</xsl:template>
<xsl:template match="Record">
<xsl:element name="{FieldName}">
<xsl:value-of select="FieldValue"/>
</xsl:element>
</xsl:template>
The grouping can be done as follows:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="SC">
<Order>
<xsl:for-each-group select="Detail" group-by="Record[1]/FieldValue">
<xsl:element name="{current-grouping-key()}">
<xsl:apply-templates select="current-group()"/>
</xsl:element>
</xsl:for-each-group>
</Order>
</xsl:template>
<xsl:template match="Detail">
<Item>
<xsl:apply-templates select="Record[position() gt 1]"/>
</Item>
</xsl:template>
<xsl:template match="Record">
<xsl:element name="{FieldName}">
<xsl:value-of select="FieldValue"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
It appears that you are trying to define two XSLT templates, when one should be sufficient. You want to match on the root and then that you want to iterate over each SC/Detail.
Then, you want to take the FieldValue of the sibling of the FieldName node that is 'Item' (for item value) and 'Qty' (for quantity value), but only those listed under 'Record'.
Note: You have specified a doubly-nested <Item> in your transformed output and this solution reflects that requirement.
This XSLT should do what you are requesting:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
<xsl:for-each select="SC/Detail">
<Order>
<OrderItem>
<Item>
<Item>
<xsl:value-of select="Record[FieldName[text()='Item']]/FieldValue" />
</Item>
<Qty>
<xsl:value-of select="Record[FieldName[text()='Qty']]/FieldValue" />
</Qty>
</Item>
</OrderItem>
</Order>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

XSLT: Need to convert name value pair content into XML

I'm new to XSLT. I have a requirement to convert an XML containing name value pair into target XML.
I need to generate a target XML where each FieldName is an element name and it value is FieldValue. Please find below the output which I need.
Thanks in advance for the help.
Source XML:
<SC>
<Header>
<Record>
<FieldName>Schema</FieldName>
<FieldValue>OrderHeader</FieldValue>
</Record>
<Record>
<FieldName>Order</FieldName>
<FieldValue>1234</FieldValue>
</Record>
</Header>
<Detail>
<Record>
<FieldName>Schema</FieldName>
<FieldValue>OrderItem</FieldValue>
</Record>
<Record>
<FieldName>Item</FieldName>
<FieldValue>1</FieldValue>
</Record>
<Record>
<FieldName>Qty</FieldName>
<FieldValue>10</FieldValue>
</Record>
</Detail>
<Detail>
<Record>
<FieldName>Schema</FieldName>
<FieldValue>OrderItem</FieldValue>
</Record>
<Record>
<FieldName>Item</FieldName>
<FieldValue>2</FieldValue>
</Record>
<Record>
<FieldName>Qty</FieldName>
<FieldValue>20</FieldValue>
</Record>
</Detail>
</SC>
Target XML to be generated:
<SC>
<OrderHeader>
<Order>1234</Order>
</OrderHeader>
<OrderItem>
<Item>1</Item>
<Qty>10</Qty>
</OrderItem>
<OrderItem>
<Item>2</Item>
<Qty>20</Qty>
</OrderItem>
</SC>
XSLT which I tried: I'm not getting the desired output
<xsl:template match="Header">
<xsl:apply-templates select="Record"/>
</xsl:template>
<xsl:template match="Record">
<xsl:if test="FieldName = 'Structure'">
<xsl:element name="{FieldValue}">
<xsl:value-of select="./text()"/>
</xsl:element>
</xsl:if>
<xsl:element name="{FieldName}">
<xsl:value-of select="FieldValue"/>
</xsl:element>
</xsl:template>
Here's another option that is similar to Martin's.
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Header|Detail">
<xsl:element name="{Record[1]/FieldValue}">
<xsl:apply-templates select="Record[position()>1]"/>
</xsl:element>
</xsl:template>
<xsl:template match="Record">
<xsl:element name="{FieldName}">
<xsl:value-of select="FieldValue"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
It seems you want to process the first Record child as a container element and the following siblings are to be transformed as in your description:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="SC">
<xsl:copy>
<xsl:apply-templates select="*/Record[1]"/>
</xsl:copy>
</xsl:template>
<xsl:template match="SC/*/Record[1]">
<xsl:element name="{FieldValue}">
<xsl:apply-templates select="following-sibling::Record"/>
</xsl:element>
</xsl:template>
<xsl:template match="SC/*/Record[position() gt 1]">
<xsl:element name="{FieldName}">
<xsl:value-of select="FieldValue"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

xslt nested transformation : unable to transnform

I am learning XSLT and trying to transform below xml. But couldn't achieve the task
<sample id="7">
<land1 id="8">
<owner>TOMMY</owner>
<type>INDIVIDUAL</type>
<hint>TOM_INDIVIDUAL</hint>
<date>12.02.2014</date>
<text>land details</text>
<number>1</number>
<cost>WIDERRUFLICH</cost>
</land1>
</sample>
and trying to convert above into
<table name="sample">
<tablename="land1">
<rel name="owner" value="TOMMY"/>
<rel name="type" value="INDIVIDUAL"/>
<rel name="<hint" value="TOM_INDIVIDUAL"/>
<rel name="date" value="12.02.2014"/>
<rel name="details" value="land details"/>
<rel name="number" value="1"/>
<rel name="cost" value="25%"/>
</table>
</table>
I tried below to generate the same, but it's not working.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:for-each select="*">
<xsl:if test="current().count(*)>0">
<xsl:element name="table">
<xsl:attribute name="name">
<xsl:value-of select="name(.)"/>
</xsl:attribute>
<xsl:apply-templates select="/"
</xsl:element>
</xsl:if>
<xsl:if test="current().count(*)=0">
<xsl:element name="rel">
<xsl:attribute name="name">
<xsl:value-of select="name(.)"/>
</xsl:attribute>
<xsl:attribute name="value">
<xsl:value-of select="current()"/>
</xsl:attribute>
</xsl:element>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Can someone please let me know where I am doing wrong?
Can someone please let me know where I am doing wrong?
Well, for one thing, current().count(*)>0 is not a valid expression.
And you have <xsl:apply-templates select="/" without closing the tag. Which may be a good thing - because if it worked, it would have created an infinite loop.
I also don't understand the overall logic of your approach. Couldn't you do simply:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*[*]">
<table name="{name()}">
<xsl:apply-templates/>
</table>
</xsl:template>
<xsl:template match="*">
<rel name="{name()}" value="{.}"/>
</xsl:template>
</xsl:stylesheet>
Added:
every element with an attribute should also be a table. For example,
in the above xml, <land1 id="8"> has children and your logic works
fine. But my inout can also contain <land1 id="8"/>. Now even though
it doesn't have any child elements, still element name has to be
considered as Table
Then use:
<xsl:template match="*[#*]">
instead of:
<xsl:template match="*[*]">