I have a table table1 where I want to do a case statement that selects an employee ID based on the most recent hire date. An employee can have 2 separate user ID's in the system, I wanted to grab the user ID that was most recent. I tried approaching this by joining the fica_nbr of the employee from another table (table2), that way if it shows up more than once, I know the employee has 2 different hire dates and I can go
SELECT
CASE
WHEN COUNT(table2.fica_nbr) > 1
THEN SELECT(table1.employeeID)
WHERE employeeID is MAX date /*->This is the line im having trouble on, how would I get the employee ID that is the most up to date using the where clause*/
Thank you
you need to do something like this
change colunms with your required colunms
SELECT report_id, computer_id, date_entered
FROM reports AS a
WHERE date_entered = (
SELECT MAX(date_entered)
FROM reports AS b
WHERE a.report_id = b.report_id
AND a.computer_id = b.computer_id
)
Related
I'm working in a telecom and part of work is to check the last status for a specific mobile number along with that last de-active status,it's easy to get the active number by using the condition ACTIVE int the statement ,but it's not easy to pick the last de-active status because each number might have more than one de-active status or only one status ACTIVE, I use the EXP_DATE as an indicator for the last de-active status,I want to show both new data and old data in one row,but I'm struggling with that ,below my table and my expected result :-
my expected result
query that I use on daily basis
select * from test where exp_date>sysdate; to get the active numbers , to get the de-active number select * from test where exp_date<sysdate;
You just need to do outer join with one subquery containing ACTIVE records and one with latest DE-ACTIVE record as following:
SELECT A.MSISDN,
A.NAME,
A.SUB_STATUS,
A.CREATED_DATE,
A.EXP_DATE,
D.MSISDN AS MSISDN_,
D.NAME AS OLD_NAME,
D.SUB_STATUS OLD_STATUS,
D.CREATED_DATE AS OLD_CREATED_DATE,
D.EXP_DATE AS OLD_EXP_DATE
FROM
(SELECT * FROM TEST
WHERE EXP_DATE > SYSDATE
AND SUB_STATUS = 'ACTIVE') A -- ACTIVE RECORD
-- USE CONDITION TO FETCH ACTIVE RECORD AS PER YOUR REQUIREMENT
FULL OUTER JOIN
(SELECT * FROM
(SELECT T.*,
ROW_NUMBER() OVER (PARTITION BY T.MSISDN ORDER BY EXP_DATE DESC NULLS LAST) AS RN
FROM TEST T
WHERE T.EXP_DATE < SYSDATE
AND T.SUB_STATUS='DE-ACTIVE')
-- USE CONDITION TO FETCH DEACTIVE RECORD AS PER YOUR REQUIREMENT
WHERE RN = 1
) D
ON (A.MSISDN = D.MSISDN)
Cheers!!
Here is an overview of how to do this -- one query to get a distinct list of all the phone numbers, left join to a list of the most recent active on that phone number,left join to a list of the most recent de-active on the phone number
How about conditional aggregation?
select msidn,
max(case when status = 'DE-ACTIVE' then create_date end) as deactive_date,
max(case when status = 'ACTIVE' then exp_date end) as active_date
from test
group by msisdn
I am newbie to SQL Server, and I want to select all those who changed their department at least once.
The table structure is:
BusinessEntityID
DepartmentID
ShiftID
StartDate
RateChangeDate
Rate
NationalIDNumber
I have the following code to generate an intermediate table
select distinct
DepartmentID, NationalIDNumber
from
Table
where
NationalIDNumber in (select NationalIDNumber
from Ben_VEmployee
group by NationalIDNumber
having count(NationalIDNumber) > 1)
Output:
DepartmentID NationalIDNumber
-----------------------------
1 112457891
2 112457891
4 24756624
4 895209680
5 24756624
5 895209680
7 259388196
My questions is: how to remove non-duplicate records in the intermediate table as above?
So record "7 - 259388196" should be removed because he did not change department.
Thanks.
Try using group by and comparing the maximum and minimum department. If it changed, then these will be different:
select NationalIDNumber
from Ben_VEmployee
group by NationalIDNumber
having min(DepartmentID) <> max(DepartmentID);
If you need the actual departments, you can join this back in to the original data.
If you want a list of every ID number that has been in more than one department, you can use
SELECT COUNT(DepartmentID) AS noDepartments
, NationalIDNumber
FROM Table
GROUP BY NationalIDNumber
HAVING COUNT(DepartmentID) > 1
If you want to delete the records for the deparment the employee used to be in, but isn't any more, than you'd have to know which department that was to know which record to delete! If you do know this, then say, and we can work it out.
I have an access database with a table called SicknessLog. The fields are ID, StaffName, [Start/Return], DateStamp.
When a member of staff is off work for sickness then a record is added to the table and the value in the [Start/Return] field is 1. When they return to work a new record is added with the same details except the [Start/Return] field is 0.
I am trying to write a query that will return all distinct staff names where the most recent record for that person has a value of 1 (ie, all staff who are still off sick)
Does anyone know if this is possible? Thanks in advance
Here's one way, all staff that has been sick where it does not exist an event after that where that staff is "nonsick":
select distinct x.staffname
from sicknesslog x
where Start/Return = 1
and not exists (
select 1
from sicknesslog y
where x.StaffName = y.StaffName
and y.DateStamp > x.DateStamp
and y.Start/Return = 0
)
You can use group by to achieve this.
select staffname ,max(datestamp) from sicknesslog where start/return = 1 group by staffname
it will return all latest recored for all staff. If ID column is autogenerated PK then you can use it in max function.
select staffname,MAX(datestamp)
from sicknesslog
where [start/return]=1
group by staffname
order by max(datestamp) desc,staffname
This will retrieve latest records who is sick and off to work
This should be close:
select s.StaffName, s.DateStamp, s.[Start/Return]
from SicknessLog s
left join (
select StaffName, max(DateStamp) as MaxDate
from SicknessLog
group by StaffName
) sm on s.StaffName = sm.StaffName and s.DateStamp = sm.MaxDate and s.[Start/Return] = 1
I have a table with 3 columns example below. The table is populated with few records. I am given a task to search through each debtorid below, and return the last occurrence of a specific status lets say PTP. I query through the table order by the followupdate as below:
SELECT TOP 50 [status],[FollowupDate],debtorid
FROM dbo.FollowUp
WHERE ( dbo.FollowUp.FollowUpDate >= '01-01-2014 00:00:00.000'
and dbo.FollowUp.FollowUpDate <= '01-10-2014 23:59:00.00')
ORDER BY FollowUpDate
From the table above, the last the [status] 'PTP' record for debtorid '589009' is at the first row and I want the first row returned, for [debtorid] 589006 is on the second row and finally for debtorid '589002' is third on the table from below/DESC order. The query should return those three rows presumably . Please how do I archive this.
I thought I should be able to return the status 'PTP' from the table by simply like
SELECT TOP 1 * FROM [tblname] WHERE date BETWEEN date1 and dat2 AND status='PTP'
HOWEVER this is not table wise. Its rather debtorid wise which is a column in the table and
The following should do the trick:
SELECT Status, DebtorId, MAX(FollowUpDate)
FROM dbo.FollowUp
WHERE Status = 'PTP'
GROUP BY
Status, DebtorId;
Note that e.g. debtor 589002 has more than one status of 'PTP' on the same day, hence the need for the GROUPING to ensure that duplicates are ignored.
try this..
SELECT DISTINCT Status,DebtorId,FollowupDate
FROM dbo.FollowUp
WHERE Status='PTP'
AND FollowupDate BETWEEN date1 AND date2
I have 2 Tables in Ms Access
tbl_Master_Employess
tbl_Emp_Salary
I want to show all the employees in the employee table linked with employee salary table
to link both table the id is coluqEmpID in both table
In the second table, I have a date column. I need a query which should fetch records from both tables using a particular date
I tried the following query:
select coluqEID as EmployeeID , colEName as EmployeeName,"" as Type, "" as Amt
from tbl_Master_Employee
union Select b.coluqEID as EmployeeID, b.colEName as EmployeeName, colType as Type, colAmount as Amt
from tbl_Emp_Salary a, tbl_Master_Employee b
where a.coluqEID = b.coluqEID and a.colDate = #12/09/2013#
However, it shows duplicates.
Query4
EmployeeID EmployeeName Type Amt
1 LAKSHMANAN
1 LAKSHMANAN Advance 100
2 PONRAJ
2 PONRAJ Advance 200
3 VIJAYAN
4 THIRUPATHI
5 VIJAYAKUMAR
6 GOVINDAN
7 TAMILMANI
8 SELVAM
9 ANAMALAI
10 KUMARAN
How would I rewrite my query to avoid duplicates, or what would be a different way to not show duplicates?
The problem with your query is that you are using union when what you want is a join. The union is first going to list all employees with the first part:
select coluqEID as EmployeeID , colEName as EmployeeName,"" as Type, "" as Amt
from tbl_Master_Employee
and then adds to that list all employee records where they have a salary with a certain date.
Select b.coluqEID as EmployeeID, b.colEName as EmployeeName, colType as Type,
colAmount as Amt
from tbl_Emp_Salary a, tbl_Master_Employee b
where a.coluqEID = b.coluqEID and a.colDate = #12/09/2013#
Is your goal to get a list of all employees and only display salary information for those who have a certain date? Some sample data would be useful. Assuming the data here: SQL Fiddle this query should create what you want.
Select a.coluqEID as EmployeeID, colEName as EmployeeName,
b.colType as Type, b.colAmount as Amt
FROM tbl_Master_Employees as a
LEFT JOIN (select coluqEID, colType, colAmount FROM tbl_EMP_Salary
where colDate = '20130912') as b ON a.coluqEID = b.coluqEID;
The first step is to create a select that will get you just the salaries that you want by date. You can then perform a join on this as if you were performing a separate query. You use a LEFT JOIN because you want all of the records from one side, the employees, and only the records that match your criteria from the second side, your salaries.
I believe you will need a join, however as to your question on Unique names.
select **DISTINCT** coluqEID as EmployeeID
Adding the distinct operator would give only uniquely returned results.