I am trying to fetch a number which starts with 628 in a comma separated string.
Below is what I am using:
SELECT
REGEXP_REPLACE(REGEXP_SUBSTR('62810,5152,,', ',?628[[:alnum:]]+,?'),',','') first,
REGEXP_REPLACE(REGEXP_SUBSTR('5152,62810,,', ',?628[[:alnum:]]+,?'),',','') second,
REGEXP_REPLACE(REGEXP_SUBSTR('5152,562810,,', ',?628[[:alnum:]]+,?'),',','') third,
REGEXP_REPLACE(REGEXP_SUBSTR(',5152,,62810', ',?(628[[:alnum:]]+),?'),',','') fourth
FROM DUAL;
Its working but in one case it fails which is the third column where number is 562810. Actually I am expecting NULL in the third column.
Actual output from above query is:
"FIRST","SECOND","THIRD","FOURTH"
"62810","62810","62810","62810"
Not sure why you are using [[:alnum::]]. You could use matching group to extract the number starting with 628 or followed by a comma. REPLACE may be avoided this way
If you have alphabets as well, modify the 2nd match group () accordingly.
SELECT
REGEXP_SUBSTR('62810,5152,,' , '(^|,)(628\d*)',1,1,NULL,2) first,
REGEXP_SUBSTR('5152,62810,,' , '(^|,)(628\d*)',1,1,NULL,2) second,
REGEXP_SUBSTR('5152,562810,,', '(^|,)(628\d*)',1,1,NULL,2) third,
REGEXP_SUBSTR(',5152,,62810' , '(^|,)(628\d*)',1,1,NULL,2) fourth
FROM DUAL;
Demo
The problem with your regex logic is that you are searching for an optional comma before the numbers 628. This means that any number having 628 anywhere would match. Instead, you can phrase this by looking for 628 which is either preceded by either a comma, or the start of the string.
SELECT
REGEXP_REPLACE(REGEXP_SUBSTR('62810,5152,,', '(,|^)628[[:alnum:]]+,?'),',','') first,
REGEXP_REPLACE(REGEXP_SUBSTR('5152,62810,,', '(,|^)628[[:alnum:]]+,?'),',','') second,
REGEXP_REPLACE(REGEXP_SUBSTR('5152,562810,,', '(,|^)628[[:alnum:]]+,?'),',','') third,
REGEXP_REPLACE(REGEXP_SUBSTR(',5152,,62810', '(,|^)(628[[:alnum:]]+),?'),',','') fourth
FROM DUAL
Demo
The ideal pattern we'd like to use here is \b628.*, or something along these lines. But Oracle's regex functions do not appear to support word boundaries, hence we can use (^|,)628.* as an alternative.
I have a table in an SQLite db which has multiple columns with leading '='. I understand that I can use...
SELECT TRIM(`column1`, '=') FROM table;
to clean one column however I get a syntax error if I try for example, this...
SELECT TRIM(`column1`, `column2`, `column3`, '=') FROM table;
Due to incorrect number of arguments.
Is there a more efficient way of writing this code than applying the trim to each column separately like this?
SELECT TRIM(`column1`,'=')as `col1`, TRIM(`column2`,'=')as `col2`, TRIM(`column3`,'=')as `col3` FROM table;
How SQLite guide tells:
trim(X,Y)
The trim(X,Y) function returns a string formed by removing any and all
characters that appear in Y from both ends of X. If the Y argument is
omitted, trim(X) removes spaces from both ends of X.
You have only two parameters, so it's impossible apply it one shot on 3 columns table.
The first parameter is a column, or variable on you can apply trim. The second parameter is a character to change.
Do you know how to remove below kind of Characters at once on a query ?
Note : .I'm retrieving this data from the Access app and put only the valid data into the SQL.
select DISTINCT ltrim(rtrim(a.Company)) from [Legacy].[dbo].[Attorney] as a
This column is company name column.I need to keep string characters only.But I need to remove numbers only rows,numbers and characters rows,NULL,Empty and all other +,-.
Based on your extremely vague "rules" I am going to make a guess.
Maybe something like this will be somewhere close.
select DISTINCT ltrim(rtrim(a.Company))
from [Legacy].[dbo].[Attorney] as a
where LEN(ltrim(rtrim(a.Company))) > 1
and IsNumeric(a.Company) = 0
This will exclude entries that are not at least 2 characters and can't be converted to a number.
This should select the rows you want to delete:
where company not like '%[a-zA-Z]%' and -- has at least one vowel
company like '%[^ a-zA-Z0-9.&]%' -- has a not-allowed character
The list of allowed characters in the second expression may not be complete.
If this works, then you can easily adapt it for a delete statement.
I have a column error_desc with values like:
Failure occurred in (Class::Method) xxxxCalcModule::endCustomer. Fan id 111232 is not Effective or not present in BL9_XXXXX for date 20160XXX.
What SQL query can I use to display only the number 111232 from that column? The number is placed at 66th position in VARCHAR column and ends 71st.
SELECT substr(ERROR_DESC,66,6) as ABC FROM bl1_cycle_errors where error_desc like '%FAN%'
This solution uses regular expressions.
The challenge I faced was on pulling out alphanumerics. We have to retain only numbers and filter out string,alphanumerics or punctuations in this case, to detect the standalone number.
Pure strings and words not containing numbers can be easily filtered out using
[^[:digit:]]
Possible combinations of alphanumerics are :
1.Begins with a character, contains numbers, may end with characters or punctuations :
[a-zA-Z]+[0-9]+[[:punct:]]*[a-zA-Z]*[[:punct:]]*
2.Begins with numbers and then contains alphabets,may contain punctuations :
[0-9]+[[:punct:]]*[a-zA-Z]+[[:punct:]]*
Begins with numbers then contains punctuations,may contain alphabets :
-- [0-9]+[a-zA-Z][[:punct:]]+[a-zA-Z] --Not able to highlight as code, refer solution's last regex combination
Combining these regular expressions using | operator we get:
select trim(REGEXP_REPLACE(error_desc,'[^[:digit:]]|[a-zA-Z]+[0-9]+[[:punct:]]*[a-zA-Z]*[[:punct:]]*|[0-9]+[[:punct:]]*[a-zA-Z]+[[:punct:]]*|[0-9]+[a-zA-Z]*[[:punct:]]+[a-zA-Z]*',' '))
from error_table;
Will work in most cases.
I have a nvarchar field in my table, which contains all sorts of strings.
In case there are strings which contain a number following a non-number sign, I want to insert a space before that number.
That is - if a certain entry in that field is abc123, it should be turned into abc 123, or ab12.34 should become ab 12. 34.I want this to be done throughout the entire table.
What's the best way to achieve it?
You can try something like that:
select left(col,PATINDEX('%[0-9]%',col)-1 )+space(1)+
case
when PATINDEX('%[.]%',col)<>0
then substring(col,PATINDEX('%[0-9]%',col),len(col)+1-PATINDEX('%[.]%',col))
+space(1)+
substring(col,PATINDEX('%[.]%',col)+1,len(col)+1-PATINDEX('%[.]%',col))
else substring(col,PATINDEX('%[0-9]%',col),len(col)+1-PATINDEX('%[0-9]%',col))
end
from tab
It's not simply, but I hope it will help you.
SQL Fiddle
I used functions (link to MSDN):
LEFT, PATINDEX, SPACE, SUBSTRING, LEN
and regular expression.