I have a column in a table with words separated by comma. I need to count each occurence of each word
My column looks like : ('a, b, c'), ('a, b, d'), ('b, c, d'), ('a'), ('a, c');
(fiddle at the bottom)
Here is what I get :
MyCol Count
-----------------
a 1
a, b, c 3
a, b, d 3
a, c 2
b, c, d 3
But here is what I expect
MyCol Count
-------------
a 4
b 3
c 3
d 2
Here is what I've done so far :
select MyCol, COUNT(*)
from Test
cross apply string_split(MyCol, ',')
group by MyCol
Fiddle : http://sqlfiddle.com/#!18/4e52e/3
Please note the words are separated by a comma AND a space
You are using the wrong column. Simply use the [value] column (returned from the STRING_SPLIT() call) and remove the space characters (using TRIM() for SQL Server 2017+ or LTRIM() and RTRIM() for earlier versions):
SELECT TRIM(s.[value]) AS [value], COUNT(*) AS [count]
FROM Test t
CROSS APPLY STRING_SPLIT(t.MyCol, ',') s
GROUP BY TRIM(s.[value])
ORDER BY TRIM(s.[value])
select value,count(*)cntt
from Test
cross apply string_split(MyCol,',')
group by value
order by value;
remove white space by using REPLACE and then use Subquery
select MyCol,count(MyCol) as Count from(
select
REPLACE (value, ' ', '' ) as MyCol
--TRIM(value) as MyCol -- both TRIM and REPLACE are equivalent
----comment one of them
from test
cross apply string_split(MyCol, ',')) b
group by MyCol
fiddle
Simply :
select MyCol, 1 + LEN(MyCol) - LEN(REPLACE(MyCol, ',', '')) AS NUM
from Test
Related
For Eg; abc.def.efg , separate into independent strings as abc def efg
Head
abc.def.efg
to
left
center
right
abc
def
efg
On SQL Server with a 3-part delimited string you can use parsename
with t as (
select 'left.centre.right' Head
)
select ParseName(Head,3) L, ParseName(Head,2) C, ParseName(Head,1) R
from t;
on MySQL, you can do:
with t as (
select 'left.centre.right' Head
)
select
substring_index(Head,'.',1) as L,
substring_index(substring_index(Head,'.',2),'.',-1) as M,
substring_index(Head,'.',-1) as R
from t;
results:
L
M
R
left
centre
right
see: DBFIDDLE, and DOCS
Look into the split_part() equivalent for the RDBMS you're using.
E.g.
SELECT
split_part(Head, '.', 1) AS "left",
split_part(Head, '.', 2) AS center,
split_part(Head, '.', 3) AS "right"
FROM your_table
EDIT: corrected the indexes, see: https://www.postgresqltutorial.com/postgresql-split_part/
I need to extract a comma separated list from the following:
Return should gives something like
1 : Route#1, Route#2
2 : Route#3, Route#4
3 : Route#5
4 : Route#6
I'm struggling with the STUFF function. So far I have:SELECT STUFF( (SELECT DISTINCT ';' + T4.[Outbound Trucks] FROM #TEMP4 T4 FOR XML PATH('') ),1,1,'') AS MasterRoutes
Result gives me
any help would be really appreciated.
thanks a lof for your time
If your sql server is 2017 or more :
SELECT dorno, STRING_AGG ([Outbound Trucks], ',') as CSV
FROM #TEMP4
GROUP BY dorno
Explanation Here
In you case you can eliminate doublon to like this:
with tmp as (
select distinct dorno, [Outbound Trucks] Truck from #TEMP4
)
SELECT dorno, STRING_AGG (Truck, ',') as CSV
FROM tmp
GROUP BY dorno
I have two comma-separated string which needs to be converted into a temptable with two columns synchronized based on the index.
If the input string as below
a = 'abc,def,ghi'
b = 'aaa,bbb,ccc'
then output should be
column1 | column2
------------------
abc | aaa
def | bbb
ghi | ccc
Let us say I have function fnConvertCommaSeparatedStringToColumn which takes in comma-separated string and delimiter as a parameter and returns a column with values. I use this on both strings and get two columns to verify if the count is the same on both sides. But it would be nice two have them in a single temp table. How can i do that?
Let us say I have function which ... returns a column with values.
At that point, the basic idea is to select the column and use the row_number() function with both of your strings. Then you can JOIN the two together using the row_number() result as the matching field for the join.
One method is a recursive CTE:
with cte as (
select convert(varchar(max), null) as a_part, convert(varchar(max), null) as b_part,
convert(varchar(max), 'abc,def,ghi') + ',' as a,
convert(varchar(max), 'aaa,bbb,ccc') + ',' as b,
0 as lev
union all
select convert(varchar(max), left(a, charindex(',', a) - 1)),
convert(varchar(max), left(b, charindex(',', b) - 1)),
stuff(a, 1, charindex(',', a), ''),
stuff(b, 1, charindex(',', b), ''),
lev + 1
from cte
where a <> '' and lev < 10
)
select a_part, b_part
from cte
where lev > 0;
Here is a db<>fiddle.
Here's something a bit sneaky you can try.
I don't have your bespoke function so have used the built-in string_split function (SQL2016+) - for quickly testing, but assuming the parameters are the same. Ideally, your bespoke function should return its own row number in which case you'd use that instead of a rownumber function.
declare #a varchar(20)='abc,def,ghi', #b varchar(20)='aaa,bbb,ccc';
with v as (
select a.value A,b.value B,
row_number() over(partition by a.value order by (select 1/0))Arn,
row_number() over(partition by b.value order by (select 1/0))Brn
from fnConvertCommaSeparatedStringToColumn (#a,',')a
cross apply fnConvertCommaSeparatedStringToColumn (#b,',')b
)
select A,B from v
where Arn=Brn
I would suggest getting a (set based) function that can split a string, based on a delimiter, that returns the ordinal position as well. For example DelimitedSplit8k_LEAD. Then you can trivially split the value, and JOIN on the ordinal position:
DECLARE #a varchar(100) = 'abc,def,ghi';
DECLARE #b varchar(100) = 'aaa,bbb,ccc';
SELECT A.Item AS A,
B.Item AS B
FROM dbo.delimitedsplit8k_lead(#a,',') A
FULL OUTER JOIN dbo.delimitedsplit8k_lead(#a,',') B ON A.ItemNumber = B.ItemNumber;
db<>fiddle
I use a FULL OUTER JOIN and then if either column has a NULL value you know that the 2 delimited lists don't have the same number of delimited values.
I want to get the below result:
source table :
Cnt A B
4 ABC YU/FGH
5 ABC YU/DFE
5 ABC KL
2 LKP BN/ER
4 JK RE
Result:
Cnt A B
9 ABC YU
5 ABC KL
2 LKP BN
4 JK RE
Here I want the count by grouping 'B' and want to display the 'B' record only till the special character (/)
Basically, you will have to filter out the all the characters after the "/" symbol and then apply a SUM and a GROUP BY. You can see this below. The inner query filters out the unwanted string and the outer query does the SUM and the GROUP BY :
SELECT SUM(t.Cnt), t.A, t.B
FROM (
SELECT Cnt,
A,
CASE
WHEN CHARINDEX('/', B) > 0 THEN SUBSTRING(B, 0, CHARINDEX('/', B))
ELSE B
END AS B
FROM #Tab
) t
GROUP BY t.A, t.B
ORDER BY t.A
You can see this working here -> http://rextester.com/IQJ79191
Hope this helps!!!
You can get your string till '/' by using SUBSTRING.
select
count(SUBSTRING(reverse(B),0,charindex('/',reverse(B)))),
A,
SUBSTRING(reverse(B),0,charindex('/',reverse(B)))
from source_table group by B;
Solution for Oracle - substr(B,0,instr(B,'/',1)-1) B
Put this both in select and groupby
I can suggest you to use a query like this:
select
sum(Cnt) Cnt,
A,
left(B, charindex('/',B+'/',0)-1) B -- Using `+'\'` will do the trick
from
t
group by
A,
left(B, charindex('/',B+'/',0)-1);
By using String and CharIndex Functions.
;WITH SourceTable(Cnt,A,B) AS
(
SELECT 4,'ABC','YU/FGH'UNION ALL
SELECT 5,'ABC','YU/DFE'UNION ALL
SELECT 5,'ABC','KL' UNION ALL
SELECT 2,'LKP','BN/ER' UNION ALL
SELECT 4,'JK','RE'
)
SELECT SUM(Cnt) AS Cnt,A,CASE WHEN CHARINDEX('/',B) = 0 THEN B
ELSE SUBSTRING(B,0,CHARINDEX('/',B)) END AS [B] FROM SourceTable
GROUP BY A,CASE WHEN CHARINDEX('/',B) = 0 THEN B
ELSE SUBSTRING(B,0,CHARINDEX('/',B)) END
ORDER BY Cnt DESC
Try this query --
SELECT SUM(Cnt) AS [COUNT]
,A
,CASE
WHEN CHARINDEX('/', B) > 0
THEN SUBSTRING(B, 1, (CHARINDEX('/', B) - 1))
ELSE B
END
FROM tblSample
GROUP BY A, B
ORDER BY A, B
I'm looking for a t-sql function to get a string like:
a:b,c:d,e:f
and convert it to a table like
ID Value
a b
c d
e f
Anything I found in Internet incorporated single column parsing (e.g. XMLSplit function variations) but none of them letting me describe my string with two delimiters, one for column separation & the other for row separation.
Can you please guiding me regarding the issue? I have a very limited t-sql knowledge and cannot fork those read-made functions to get two column solution?
You can find a split() function on the web. Then, you can do string logic:
select left(val, charindex(':', val)) as col1,
substring(val, charindex(':', val) + 1, len(val)) as col2
from dbo.split(#str, ';') s(val);
You can use a custom SQL Split function in order to separate data-value columns
Here is a sql split function that you can use on a development system
It returns an ID value that can be helpful to keep id and value together
You need to split twice, first using "," then a second split using ";" character
declare #str nvarchar(100) = 'a:b,c:d,e:f'
select
id = max(id),
value = max(value)
from (
select
rowid,
id = case when id = 1 then val else null end,
value = case when id = 2 then val else null end
from (
select
s.id rowid, t.id, t.val
from (
select * from dbo.Split(#str, ',')
) s
cross apply dbo.Split(s.val, ':') t
) k
) m group by rowid