SQL : Get yesterdays day with a certain timestamp - sql

i am trying to get yesterdays date in SQL SERVER with a certain timestamp.
I know how to get yesterdays date in SQL without the timestamp using the following query :
Which gives me every startdate starting from '00:00:00':
SELECT se.startdate
FROM sessions se
WHERE se.startdate >= DATEADD(day, -1, CAST(GETDATE() AS date))
Instead I want to get the yesterdays date with a certain timestamp.
For this example every startdate starting from '06:00:00'(AM). Like shown below:
SELECT se.startdate
FROM sessions se
WHERE se.startdate >= '05-09-2022 06:00:00'
If I do it the way it was shown in the second example I would have to change the day manually, which would obviously repetitive.
Is there a way to combine the first example with second one so that we get always yesterdays date at
'06:00:00' ?
(OR ANY GIVEN TIME )

Might as well add another solution, DATETIMEFROMPARTS:
DECLARE #Yesterday date = DATEADD(DAY, -1, GETDATE());
SELECT DATETIMEFROMPARTS(YEAR(#Yesterday),MONTH(#Yesterday),DAY(#Yesterday),6,0,0,0);

For example 06:20:40 of the previous day:
select DATEADD(second, (6 * 60 + 20 ) * 60 + 40, cast(DATEADD(day, -1, cast(GETDATE() AS date)) as datetime)) t

you can do it this way:
SELECT DATEADD(day, DATEDIFF(day, 1, GETDATE()), '06:00:00')

Related

IF condition with getdate() in sybase

I have a requirement where if
getdate()
returns time between midnight 12 to 2 AM, I should consider Date of previous day. How to frame this in a select query ?
The simplest method is to subtract two hours from the date and do the comparison. For instance:
where col_date < convert(date, dateadd(hour, -2, getdate()))

get the first n characters of getdate()

I have a case compare date, hour of datetime column and current date,hour
select * from tbl where LEFT(EVENT_TIME_column,13) !=LEFT(GETDATE(),13)
EVENT_TIME_column format is '2019-08-15 12:32:40.0000000'
when i perform LEFT(GETDATE(),13) result is 'Aug 15 2019'
can you suggest how to get GETDate() in '2019-08-15 12' (date and hour)
If you want the format yyyy-MM-dd hh then can do this:
SELECT CONVERT(varchar(13),GETDATE(),120);
db<>fiddle
You can find a full list of all the style codes for CONVERT in the documentation: Date and Time Styles
However, it looks like you want to check if the date is within the current hour. That would be:
WHERE EVENT_TIME_column >= DATEADD(HOUR, DATEDIFF(HOUR, 0,GETDATE()),0)
AND EVENT_TIME_column < DATEADD(HOUR, DATEDIFF(HOUR, 0,GETDATE())+1, 0)
This explicitly avoids any functions on the column EVENT_TIME_column; which would make the query non-SARGable.
Don't use string functions on date/time values! There are perfectly good built-in functions:
where convert(date, event_time_column) = convert(date, getdate()) and
datepart(hour, event_time_column) = datepart(hour, getdate())
If you don't care about index usage, then use datediff():
where datediff(hour, event_time_column, getdate()) = 0
You can check this with 2 separate comparison as below. This is for checking Date and Hour part is same as date and hour part if GETDATE() or not.
WHERE CAST(EVENT_TIME_column AS DATE) = CAST(GETDATE() AS DATE)
AND DATEPART(HH,EVENT_TIME_column) = DATEPART(HH,GETDATE())
To check NOT EQUAL TO, Just replace = sign with != sign.
In addition, If I guess correct you are only trying to avoid records from running hour of to date. If this is the case, you can also filter your data with below logic-
WHERE EVENT_TIME_column < DATEADD(hh, DATEDIFF(hh, 0, getdate()), 0)

Anything that expected within the last 10 days back should be received if not ignore them in SQL

I need to ignore data anything that expected within the last 10 days back should be received if not ignore it. I am not sure how to write this in SQL. I have EXPDATE column. I am not sure my statement correct or not.
I believe the logic should be like this
Expected Date + 10 Days < Today`s date?
GETDATE() < DATEADD(DAY, +10, GETDATE()) - I found this online but where can I plug in my ExpectedDate column?
Thanks in advance!!
You can do it either way-
First add 10 days to EXPDATE and compare it with todays date like below.
select * from MyTable Where DATEADD(DAY, 10, EXPDATE) < GETDATE()
The other way, you can substract 10 days from today and compare it with EXPDATE.
select * from MyTable Where DATEADD(DAY, -10, GETDATE()) > EXPDATE
I would prefer 2nd one and would use variable to calculate 10 days back date as it's constant and then use it in where clause like below.
Declare #myDate datetime
SET #myDate = DATEADD(DAY, -10, GETDATE())
select * from MyTable Where #myDate > EXPDATE

Comparing results with today's date?

Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()

SQL statement to select all rows from previous day

I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)