I have a date field in string format and I want to turn it into a timestamp, but this happens:
String: "24/12/2021 11:12:25"
Using: to_timestamp (date,'DD/MM/YYYY HH24:MI:SS') as date
Result: "2021-12-24 11:12:25.000 -0300"
So I think there is something going on not in your description. I can run the below code and get a reasonable answer.
create table foo as select '15/04/2022 08:04:37'::varchar(20) as dt;
select to_timestamp(dt,'DD/MM/YYYY HH24:MI:SS') from foo;
It produces -
2022-04-15 08:04:37+00
Can you show the error you are seeing with simple code like this? If not can you provide some more information about your exact query, table definition, etc.?
According to documentation TO_TIMESTAMP function converts string to TIMESTAMPTZ. This type is an alias of TIMESTAMP WITH TIME ZONE. All you have to do is to drop time zone part using a cast to TIMESTAMP type:
select cast(to_timestamp ('24/12/2021 11:12:25','DD/MM/YYYY HH24:MI:SS') as timestamp)
or in shorter form:
select to_timestamp ('24/12/2021 11:12:25','DD/MM/YYYY HH24:MI:SS')::timestamp
Both will return 2021-12-24 11:12:25
Related
I want to convert a given timestamp in such format: 2019-04-08 00:00:00.0 to a date in this format: 2019-04-08.
I have already tried using:
SELECT TO_DATE('2019-04-20 00:00:00.0','YYYY-MM-DD') from dual;
But I got prompted with:
ORA-01830: date format picture ends before converting entire input
string
I think you may have some conceptual misunderstanding about how the TO_DATE function works, and also about how dates are processed by the DBMS.
YYY-MM-DD does not match the format of the actual string you're importing (2019-04-20 00:00:00.0) That's what the error is telling you. You must tell the TO_DATE function what to expect in the date string you input into it. You do that by means of the format string. if you don't specify a format string which matches the format you're actually going to supply, then the function will fail to process the string.
Next, you say you want to convert it "to a date in this format"...but this does not entirely make sense. TO_DATE converts a string into a variable of type DATETIME - i.e. a date object. A date object does not not exist in any particular format, it exists as an object. Internally it will store the date information in a way which is independent of any human-readable date format. The format relates entirely to the presentation of the date when seen as a string. Once you have a date object, you can then output the date in a particular format if you want to a human to be able to read it in the style that their culture is familiar with.
So, firstly to import your date string correctly as a date object, you can use an accurate format string, an also use TO_TIMESTAMP instead of TO_DATE so that it captures the sub-seconds value:
SELECT TO_TIMESTAMP('2019-04-20 00:00:00.0','YYYY-MM-DD HH24:MI:SS.FF5') from dual;
If you run this in a console the SELECT will then automatically re-format that date object (the result of the TO_DATE function) into the default date format configured in your server / session.
However if you actually want to see it on screen in a particular format, you can explicitly say so - a sensible way is using the TO_CHAR function:
SELECT TO_CHAR(TO_TIMESTAMPT('2019-04-20 00:00:00.0','YYYY-MM-DD HH24:MI:SS.FF5'), 'YYYY-MM-DD') from dual;
The full list of format specifiers can be found here (and in other places online as well).
Live demo of the above here: https://dbfiddle.uk/?rdbms=oracle_18&fiddle=619d918ea73953e11b3150c6b560112c
Assuming the input is actual text, and not a real timestamp, you could try just truncating the text before you call TO_DATE:
WITH cte AS (
SELECT '2019-04-20 00:00:00.0' AS ts FROM dual
)
SELECT TO_DATE(SUBSTR(ts, 1, 10), 'YYYY-MM-DD')
FROM cte;
If your input is an actual Oracle timestamp, and you want to convert it to a date, then you may use CAST:
SELECT CAST(ts AS DATE) dt
FROM cte;
Would CAST do any good?
I'm setting date format so that it displays time component, although it is 00:00:
SQL> alter session set nls_date_format = 'dd.mm.yyyy hh24:mi:ss';
Session altered.
SQL> select cast(timestamp '2019-04-20 00:00:00.0' as date) result from dual;
RESULT
-------------------
20.04.2019 00:00:00
Another format (without time component):
SQL> alter session set nls_date_format = 'dd.mm.yyyy';
Session altered.
SQL> select cast(timestamp '2019-04-20 00:00:00.0' as date) result from dual;
RESULT
----------
20.04.2019
SQL>
Or, using TO_CHAR function (so that session's date format doesn't matter):
SQL> select to_char(timestamp '2019-04-20 00:00:00.0', 'dd.mm.yyyy') result from dual;
RESULT
----------
20.04.2019
SQL>
I have following 2015-06-17T00:00:00.000+05:00 string.
I want to convert this string to Date using oracle sql.
I tried lot of format mask but none works for me :
SELECT TO_DATE('2015-06-17T00:00:00.000+05:00','yyyy-mm-dd HH24:MI:SS TZR') FROM DUAL;
Any idea which format mask should i apply for above conversion.
Also please note that i only need date information i.e (mm-dd-yyyy). So its also ok if the conversion results in date information only (i.e skipping time information)
This should work:
SELECT TO_DATE(SUBSTR('2015-06-17T00:00:00.000+05:00',1,10),'yyyy-mm-dd') from dual
If you need to keep track of the time zone you should probably look at something like this:
SELECT CAST(TO_TIMESTAMP_TZ('2015-06-17T00:00:00.000+05:00','yyyy-mm-dd"T"HH24:MI:SS.FFTZH:TZM') AT TIME ZONE 'UTC' AS DATE) FROM DUAL;
I'm trying to convert string column to date in Oracle SQL.
Here is my an example of value from the data:
'03/12/14 11:00:00'
Here is my query:
select to_date(A,'DD/MM/YY HH24:MI:SS')
from MyTable
Here is an example of the output:
03-DEC-14
Why my query return only the date but not the hour?
Assuming you are using SQL*Plus (or SQL Developer) the default NLS_DATE_FORMAT is applied when a DATE value is displayed. To verify your current format you can run:
select value
from nls_session_parameters
where parameter = 'NLS_DATE_FORMAT';
To adjust this, run:
alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS';
Then you should see the time as well.
You are trying to DISPLAY the datetime value. Use TO_CHAR along with proper FORMAT MODEL.
For example,
select to_char(sysdate, 'mm/dd/yyyy hh24:mi:ss') from dual;
A DATE consists of both date and time portions. You just need to make sure you use appropriate format model to display it. Else, you end up with a format which depends on your locale-specific NLS settings.
You can use timestamp
select to_timestamp(A, 'DD/MM/YY HH24:MI:SS') from MyTable
If you want a query that returns the time portion of the date without having to alter the nls_date_format you can convert the date you got from the to_date function to a text representation (the default text representation is dd-Mon-yy as you found out) like this:
select to_char(
to_date(A,'DD/MM/YY HH24:MI:SS'),
''DD/MM/YY HH24:MI:SS')
from MyTable;
Ideally, column A of MyTable should have been defined as a date column instead of a varchar2 column. There are several reasons to do that; data integrity, and better SQL optimization.
I have a table with a field of type bigint. This field store a timestamp.
I want to date format the field like this :
to_char( bigint_field,'DD/MM/YYYY HH24:MI:SS')
I get the following error :
ERROR: multiple decimal points
État SQL :42601
TO_CHAR(TO_TIMESTAMP(bigint_field / 1000), 'DD/MM/YYYY HH24:MI:SS')
This is what worked for me
to_timestamp( bigint_field/1000)::date
This depends on what the bigint value represents - offset of epoch time, or not.
select to_timestamp(20120822193532::text, 'YYYYMMDDHH24MISS')
returns
"2012-08-22 19:35:32+00"
I did it like this:
to_timestamp(to_char(20120822193532, '9999-99-99 99:99:99'),'YYYY-MM-DD HH24:MI:SS')
the result looks like this:
2012-08-22 19:35:32
you also can use this in you select statemant, just exchange the number with your database colunm.
Step by Step Explanation:
to_char(20120822193532, '9999-99-99 99:99:99')
This will create a string like this:
"2012-08-22 19:35:32"
now we can easiely convert this into a timestamp:
to_timestamp('2012-08-22 19:35:32','YYYY-MM-DD HH24:MI:SS')
Result will look the same as before, but it's now a timestamp.
Also, if you use this for a command like
CREATE TABLE table2 AS SELECT to_timestamp(to_char(tb1.date, '9999-99-99 99:99:99'),'YYYY-MM-DD HH24:MI:SS') AS realDate FROM table1 AS tb1;
you might end up with timstamptz (timestamp with time zone) instead of timestamp (timestamp without time zone). You can change it like this:
ALTER TABLE table2 ALTER realDate SET DATA TYPE timestamp USING realDate;
I have a table as
create table Dummy (date_created date)
in oracle.I want to store date in 'dd-mon-yyyy' (12-dec-2010) format.
How should i do this.
Please help.
In Oracle a column created with the DATE datatype just stores the date. It doesn't have a particular format, it just stores the day, month, year, hour, minute, and second. You need to convert from whatever format you have using the TO_DATE function. If you have a text string with the date in 'dd-mon-yyyy' format and you want to put this date into your table you'd use something like
INSERT INTO DUMMY (DATE_CREATED)
VALUES (TO_DATE('01-FEB-2011', 'DD-MON-YYYY');
Going the other way (from DATE column value to character string) you'd use the TO_CHAR function. If you were retrieving a value from your table and wanted to convert it to 'DD-MON-YYYY' format you'd use something like
SELECT TO_CHAR(DATE_CREATED, 'DD-MON-YYYY')
FROM DUMMY;
Share and enjoy.
Use to_date() function. In your case, the syntax would be
insert into Dummy values (to_date('08-09-2010', 'dd-mm-yyyy'));
Here is a link to the detailed help.
The DATE datatype will store date and time information (century, year, month, day, hours, minutes, and seconds) in an internal format in the database. When you get it out of the database, you can choose to display it in whatever format you like.
This information is either created using implicit conversion from a string or explicitly using either the TO_DATE function or the ANSI date literal. If you look in the v$nls_parameters view, this will tell you what the NLS_DATE_FORMAT is which is generally used for the implicit conversion. This may often be defined as DD-MON-RR, which might be why the date will come out as 23-DEC-10 when the query select sysdate from dual is run. (Not entirely sure I'm right about the nls stuff. Correct me if I'm wrong.)
However, all the date information is available if you know how to get it. The query select to_char(sysdate, 'dd-mon-yyyy hh24:mi:ss') from dual will return all the date fields.
Likewise, the insert statement shown below will create a row with a date value in it.
insert into dummy (date_created)
values (to_date('12-dec-2010 12:34:56', 'dd-mon-yyyy hh24:mi:ss'))`
This data can then be retrieved.
select date_created from dummy
This will implicitly convert the date to a character string using the NLS_DATE_FORMAT, providing the output below.
DATE_CREA
---------
23-DEC-10
The full date information is available by explicitly converting the date to a character string.
select to_char(date_created, 'DD-MON-YYYY') as date_created from dummy;
select to_char(date_created, 'DD-MON-YYYY HH24:MI:SS') as date_created
from dummy;
This will provide output in the format you require:
DATE_CREATE
-----------
23-DEC-2010
If you always use the TO_DATE and TO_CHAR functions to convert to/from a date datatype, then you will have fewer problems. Implicit conversion is useful but can cause some confusion or problems.
You can keep and eye here
http://www.techonthenet.com/oracle/functions/to_date.php
use to_date function to save a data with the format you need. I suggest to use SYSDATE updating table and when you need to read data from table use something like that:
dbms_output.put_line(TO_CHAR(SYSDATE, 'DD-MON-YYYY HH24:MI:SS'));
to solve your problem use:
to_date('08/JAN/2010', 'DD/MON/YYYY')
Just use TRUNC(YourDate) if date have time part, it will be truncate time part. Oracle have not just 'DATE' type, 'DATE' always have time part.
However if you do not specify time - it will 00:00:00.
SELECT TRUNC(SYSDATE) from dual
Result:
23-12-2010
Oracle does not support DATE without time part.
You can make it always be an integer date by adding a CHECK constraint:
CREATE TABLE dummy (date_created date CHECK (date_created = TRUNC(date_created)))
, insert it in any format you want:
INSERT
INTO dummy (date_created)
VALUES (TO_DATE('23-DEC-2010', 'dd-mon-yyyy'))
and select it in any format you want:
SELECT TO_CHAR(date_created, 'dd-mon-yyyy')
FROM dummy