I have a table with a field of type bigint. This field store a timestamp.
I want to date format the field like this :
to_char( bigint_field,'DD/MM/YYYY HH24:MI:SS')
I get the following error :
ERROR: multiple decimal points
État SQL :42601
TO_CHAR(TO_TIMESTAMP(bigint_field / 1000), 'DD/MM/YYYY HH24:MI:SS')
This is what worked for me
to_timestamp( bigint_field/1000)::date
This depends on what the bigint value represents - offset of epoch time, or not.
select to_timestamp(20120822193532::text, 'YYYYMMDDHH24MISS')
returns
"2012-08-22 19:35:32+00"
I did it like this:
to_timestamp(to_char(20120822193532, '9999-99-99 99:99:99'),'YYYY-MM-DD HH24:MI:SS')
the result looks like this:
2012-08-22 19:35:32
you also can use this in you select statemant, just exchange the number with your database colunm.
Step by Step Explanation:
to_char(20120822193532, '9999-99-99 99:99:99')
This will create a string like this:
"2012-08-22 19:35:32"
now we can easiely convert this into a timestamp:
to_timestamp('2012-08-22 19:35:32','YYYY-MM-DD HH24:MI:SS')
Result will look the same as before, but it's now a timestamp.
Also, if you use this for a command like
CREATE TABLE table2 AS SELECT to_timestamp(to_char(tb1.date, '9999-99-99 99:99:99'),'YYYY-MM-DD HH24:MI:SS') AS realDate FROM table1 AS tb1;
you might end up with timstamptz (timestamp with time zone) instead of timestamp (timestamp without time zone). You can change it like this:
ALTER TABLE table2 ALTER realDate SET DATA TYPE timestamp USING realDate;
Related
I have a date field in string format and I want to turn it into a timestamp, but this happens:
String: "24/12/2021 11:12:25"
Using: to_timestamp (date,'DD/MM/YYYY HH24:MI:SS') as date
Result: "2021-12-24 11:12:25.000 -0300"
So I think there is something going on not in your description. I can run the below code and get a reasonable answer.
create table foo as select '15/04/2022 08:04:37'::varchar(20) as dt;
select to_timestamp(dt,'DD/MM/YYYY HH24:MI:SS') from foo;
It produces -
2022-04-15 08:04:37+00
Can you show the error you are seeing with simple code like this? If not can you provide some more information about your exact query, table definition, etc.?
According to documentation TO_TIMESTAMP function converts string to TIMESTAMPTZ. This type is an alias of TIMESTAMP WITH TIME ZONE. All you have to do is to drop time zone part using a cast to TIMESTAMP type:
select cast(to_timestamp ('24/12/2021 11:12:25','DD/MM/YYYY HH24:MI:SS') as timestamp)
or in shorter form:
select to_timestamp ('24/12/2021 11:12:25','DD/MM/YYYY HH24:MI:SS')::timestamp
Both will return 2021-12-24 11:12:25
I inserted date and time in database, now when trying to retrieve date and time both from database only getting time part.
I tried insert date using TO_DATE('08/13/2019 09:10:03', 'MM/DD/YYYY HH24:MI:SS') into 'Time' col. Now trying to get date from table using TO_DATE(Time, 'DD/MON/RR HH24:MI:SS'), but only getting date part. My database nls date format is "DD/MON/RR". 'Time' col is date type and I'm using oracle 10g xe.
I can get date and time using TO_CHAR(Time, 'DD/MON/RR HH24:MI:SS') but as I need to use this in comparison operation like below:
select TO_CHAR(Time,'DD/MON/RR HH24:MI:SS') from Table where (TO_CHAR(Time, 'DD/MON/RR HH24:MI:SS') <= TO_DATE('08/07/2019 10:13:52', 'MM/DD/YYYY HH24:MI:SS'))
it gives this error 'ORA-01830: date format picture ends before converting entire input string'. Also tried to use TO_DATE(TO_CHAR(Time, 'DD/MON/RR HH24:MI:SS')), still it gives only time part. Should I use TIMESTAMP datatype for 'Time' col?
I want to get date and time from table where i can use them in comparison operation.
Date need not be converted into date again.
You can simply write your query like this:
SELECT
TIME -- use to_char for formatting the output date
FROM Table
WHERE
TIME <= TO_DATE('08/07/2019 10:13:52', 'MM/DD/YYYY HH24:MI:SS')
Cheers!!
I'm trying to convert string column to date in Oracle SQL.
Here is my an example of value from the data:
'03/12/14 11:00:00'
Here is my query:
select to_date(A,'DD/MM/YY HH24:MI:SS')
from MyTable
Here is an example of the output:
03-DEC-14
Why my query return only the date but not the hour?
Assuming you are using SQL*Plus (or SQL Developer) the default NLS_DATE_FORMAT is applied when a DATE value is displayed. To verify your current format you can run:
select value
from nls_session_parameters
where parameter = 'NLS_DATE_FORMAT';
To adjust this, run:
alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS';
Then you should see the time as well.
You are trying to DISPLAY the datetime value. Use TO_CHAR along with proper FORMAT MODEL.
For example,
select to_char(sysdate, 'mm/dd/yyyy hh24:mi:ss') from dual;
A DATE consists of both date and time portions. You just need to make sure you use appropriate format model to display it. Else, you end up with a format which depends on your locale-specific NLS settings.
You can use timestamp
select to_timestamp(A, 'DD/MM/YY HH24:MI:SS') from MyTable
If you want a query that returns the time portion of the date without having to alter the nls_date_format you can convert the date you got from the to_date function to a text representation (the default text representation is dd-Mon-yy as you found out) like this:
select to_char(
to_date(A,'DD/MM/YY HH24:MI:SS'),
''DD/MM/YY HH24:MI:SS')
from MyTable;
Ideally, column A of MyTable should have been defined as a date column instead of a varchar2 column. There are several reasons to do that; data integrity, and better SQL optimization.
I have a table like this in hbase:
tableExaple (timestamp, timestamp_string, someOtherStuff)
timestamp has the datatype timestamp
timestamp_string hast the datatype string and has the pattern 'yyyy-MM-dd HH:mm:ss.SSS'
Now I would like to read the value from timestamp_string convert it with the hive-UDF unix_timestamp(string date, string pattern) to a timestamp and save this in the same table to the value timestamp.
How can I do this?
Stuff like
INSERT INTO tableExaple (timestamp) SELECT unix_timestamp(timestamp_string, 'yyyy-MM-dd HH:mm:ss.SSS') FROM tableExaple;
does not work.
I don't think unix_timestamp likes the millisecond format. Since timestamp_string is of type string, you can just split on the '.' and grab the date and time. So if you had 2014-11-11 08:09:10.123, split(timestamp_string, '\\.') will give you [2014-11-11 08:09:10, 123]. You can now reference your array by [0] and [1].
Example:
SELECT otherStuff
, timestamp
, unix_timestamp(split(timestamp_string, '\\.')[0], 'yyyy-MM-dd HH:mm:ss') new_time
FROM some_table
If you want to include the milliseconds in your new_time column, just grab the [1]th index from the split array (and divide by 1000).
I have a table as
create table Dummy (date_created date)
in oracle.I want to store date in 'dd-mon-yyyy' (12-dec-2010) format.
How should i do this.
Please help.
In Oracle a column created with the DATE datatype just stores the date. It doesn't have a particular format, it just stores the day, month, year, hour, minute, and second. You need to convert from whatever format you have using the TO_DATE function. If you have a text string with the date in 'dd-mon-yyyy' format and you want to put this date into your table you'd use something like
INSERT INTO DUMMY (DATE_CREATED)
VALUES (TO_DATE('01-FEB-2011', 'DD-MON-YYYY');
Going the other way (from DATE column value to character string) you'd use the TO_CHAR function. If you were retrieving a value from your table and wanted to convert it to 'DD-MON-YYYY' format you'd use something like
SELECT TO_CHAR(DATE_CREATED, 'DD-MON-YYYY')
FROM DUMMY;
Share and enjoy.
Use to_date() function. In your case, the syntax would be
insert into Dummy values (to_date('08-09-2010', 'dd-mm-yyyy'));
Here is a link to the detailed help.
The DATE datatype will store date and time information (century, year, month, day, hours, minutes, and seconds) in an internal format in the database. When you get it out of the database, you can choose to display it in whatever format you like.
This information is either created using implicit conversion from a string or explicitly using either the TO_DATE function or the ANSI date literal. If you look in the v$nls_parameters view, this will tell you what the NLS_DATE_FORMAT is which is generally used for the implicit conversion. This may often be defined as DD-MON-RR, which might be why the date will come out as 23-DEC-10 when the query select sysdate from dual is run. (Not entirely sure I'm right about the nls stuff. Correct me if I'm wrong.)
However, all the date information is available if you know how to get it. The query select to_char(sysdate, 'dd-mon-yyyy hh24:mi:ss') from dual will return all the date fields.
Likewise, the insert statement shown below will create a row with a date value in it.
insert into dummy (date_created)
values (to_date('12-dec-2010 12:34:56', 'dd-mon-yyyy hh24:mi:ss'))`
This data can then be retrieved.
select date_created from dummy
This will implicitly convert the date to a character string using the NLS_DATE_FORMAT, providing the output below.
DATE_CREA
---------
23-DEC-10
The full date information is available by explicitly converting the date to a character string.
select to_char(date_created, 'DD-MON-YYYY') as date_created from dummy;
select to_char(date_created, 'DD-MON-YYYY HH24:MI:SS') as date_created
from dummy;
This will provide output in the format you require:
DATE_CREATE
-----------
23-DEC-2010
If you always use the TO_DATE and TO_CHAR functions to convert to/from a date datatype, then you will have fewer problems. Implicit conversion is useful but can cause some confusion or problems.
You can keep and eye here
http://www.techonthenet.com/oracle/functions/to_date.php
use to_date function to save a data with the format you need. I suggest to use SYSDATE updating table and when you need to read data from table use something like that:
dbms_output.put_line(TO_CHAR(SYSDATE, 'DD-MON-YYYY HH24:MI:SS'));
to solve your problem use:
to_date('08/JAN/2010', 'DD/MON/YYYY')
Just use TRUNC(YourDate) if date have time part, it will be truncate time part. Oracle have not just 'DATE' type, 'DATE' always have time part.
However if you do not specify time - it will 00:00:00.
SELECT TRUNC(SYSDATE) from dual
Result:
23-12-2010
Oracle does not support DATE without time part.
You can make it always be an integer date by adding a CHECK constraint:
CREATE TABLE dummy (date_created date CHECK (date_created = TRUNC(date_created)))
, insert it in any format you want:
INSERT
INTO dummy (date_created)
VALUES (TO_DATE('23-DEC-2010', 'dd-mon-yyyy'))
and select it in any format you want:
SELECT TO_CHAR(date_created, 'dd-mon-yyyy')
FROM dummy