I want to plot some coordinates using Plotly express because it allows me a more interactive approach, but I can not find the way to control the scale in the axis in the way I can manage with matplotlib.pyplot in one single line
plt.axis("scaled")
Could you please share some suggestions? Thanks.
Here is the code using Plotly express:
fig = px.scatter(coordinates_utm, x='EASTING', y='NORTHING', title=name,
hover_name=coordinates_utm.index,
hover_data={'NORTHING':':.6f','EASTING': ':.6f'})
fig.add_trace(px.scatter(coordinates_utm_lineal, x='x', y='ylineal',color_discrete_sequence=['red']).data[0])
Here is the code using plt:
fig.show()
plt.figure()
plt.scatter(coordinates_utm_lineal.x,coordinates_utm_lineal.ylineal,s=2)
plt.scatter(coordinates_utm.EASTING,coordinates_utm.NORTHING, s=2)
plt.axis("scaled")
plt.show()
This is my current output
Sadly, you didn't provide a fully reproducible example, so I'm going to create my own.
Also, I'm not really familiar with plt.axis("scaled"), as I usually use plt.axis("equal"). Reading the documentation associated to plt.axis, they appear to be somewhat similar. See if the following answer can satisfy your needs.
import plotly.express as px
import numpy as np
t = np.linspace(0, 2*np.pi)
x = np.cos(t)
y = np.sin(t)
fig = px.scatter(x=x, y=y)
fig.layout.yaxis.scaleanchor="x"
fig.show()
Related
the image of what I mean in my question
I'm using BMP280 to measure Temperature and Pressure using Raspberry.
I'm using matplotlib to make a graph, but the matplotlib simplify my Y axis bi adding +9.967e2.
is there any way to avoid matplotlib simplify my Y axis. Sorry I'm new to this so I don't know much.
I tried to search in google but I don't find anything. Maybe I'm using the wrong keyword as I don't know what should I search.
You can turn off the offset as shown in the examples here. For example, if you've made you plot with:
from matplotlib import pyplot as plt
plt.plot(x, y)
then you can turn off the offset with
ax = plt.gca() # get the axes object
# turn off the offset (on the y-axis only)
ax.ticklabel_format(axis="y", useOffset=False)
plt.show()
See the ticklabel_format docs for more info.
I want to plot a velocity versus depth model using the given data.
import matplotlib.pyplot as plt
import numpy as np
depth=np.array((0.0,5.0,30.0,40.0,50.0))
velocity=np.array((5.5,6.5,6.8,9.0,10.0))
plt.plot(velocity,depth)
plt.show()
But this script doesnot give the plot as i expected
I need something like example_plot
I hope experts may help me overcoming this problem. Thanks in advance.
You have to use matplotlib.pyplot.step
depth=np.array((0.0,5.0,30.0,40.0,50.0))*-1
velocity=np.array((5.5,6.5,6.8,9.0,10.0))
plt.step(velocity,depth)
plt.show()
EDIT:
depth=np.array((0.0,5.0,30.0,40.0,50.0))
velocity=np.array((5.5,6.5,6.8,9.0,10.0))
fig, ax = plt.subplots()
ax.step(velocity,depth)
ax.invert_yaxis()
fig.show()
I am trying to plot some data on an AzimuthalEquidistant projection using cartopy. However, it gives me a couple of problems. First the coastlines no longer show for this type of projection. Not sure if this is my code or a Cartopy problem. I also notice that if I use a ccrs.PlateCarree() transform in the pcolormesh command the coastlines do show but then, presumably, my data is on the wrong type of prejection?
Second I would prefer if the axis boarder was circular after plotting the data, is it possible to use set_extent or some similar function to do this?
The code below should reproduce the problems, the circle shows how I would like the boarder to look.
import matplotlib.pyplot as plt
import cartopy.crs as ccrs
import matplotlib.patches as mpatches
clat = 55.0
clon = -8.0
lons = np.arange(clon-15,clon+16,0.5)
lats = np.arange(clat-15,clat+16,0.5)
d = np.random.rand(lons.shape[0],lats.shape[0])
trans = ccrs.AzimuthalEquidistant(central_latitude=clat, central_longitude=clon)
ax = plt.axes(projection=trans)
ax.coastlines(resolution='10m')
CB=ax.pcolormesh(lons-0.25, lats-0.25, d.T,
cmap=plt.cm.viridis, alpha=0.5,
transform=trans)#ccrs.PlateCarree())
p1 = mpatches.Circle((clon,clat), radius=15, color='k', lw=5, fill=False,
transform=trans)
ax.add_patch(p1)
If the data you are plotting is in latitude/longitude coordinates then the correct value for the transform keyword is indeed ccrs.PlateCarree(). This is common gotcha for new users. The transform argument tells cartopy what coordinates your data are in, and is completely independent of the projection you want to plot onto.
To make the plot circular you'll need to set the boundary yourself. The Cartopy documentation have a couple of examples of this: http://scitools.org.uk/cartopy/docs/latest/examples/always_circular_stereo.html and http://scitools.org.uk/cartopy/docs/latest/examples/star_shaped_boundary.html.
So I'm trying to create a figure that presents a 3d plot from data points, along with the plots 3 projections in 3 other subplots. I can add the subplots for the projections with no problems, but when I try to place the 3 dimensional plot into the figure things backfire.
here's my code:
def plotAll(data):
fig = plt.figure()
plot_3d = fig.add_subplot(221)
ax = Axes3D(plot_3d)
for i,traj in enumerate(data.values()):
ax.plot3D([traj[0][-1]],[traj[1][-1]],[traj[2][-1]],".",color=[0.91,0.39,0.046])
#plot_12v13 = fig.add_subplot(222)
#plot_projections(data,0,1)
#plot_13v14 = fig.add_subplot(223)
#plot_projections(data,1,2)
#plot_12v14 = fig.add_subplot(224)
#plot_projections(data,0,2)
#plt.plot()
which throws back:
'AxesSubplot' object has no attribute 'transFigure'
I'm using matplotlib 0.99.3, any help would be greatly appreciated, thanks!
I was searching for a way to create my 3D-plots with the nice fig, axes = plt.subplots(...) shortcut, but since I just browsed Matplotlib's mplot3d tutorial, I want to share a quote from the top of this site.
New in version 1.0.0: This approach is the preferred method of creating a 3D axes.
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
Note
Prior to version 1.0.0, the method of creating a 3D axes was different. For those using older versions of matplotlib, change ax = fig.add_subplot(111, projection='3d') to ax = Axes3D(fig).
So if you have to use the <1.0.0 version of Matplotlib, this should be taken into account.
If you would like to use plt.subplots instead of plt.subplot (see the difference here), then you can do something like this one:
import matplotlib.pyplot as plt
from matplotlib import cm # for a scatter plot
from mpl_toolkits.mplot3d import Axes3D
fig, ax = plt.subplots(1,2,figsize=(10,10),subplot_kw=dict(projection='3d'))
sc1 = ax[0].scatter(x,y,z, c = true, cmap=cm.jet)
ax[0].set_title('True solution')
sc2 = ax[1].scatter(x,y,z c = y_pred, cmap=cm.jet)
ax[1].set_title('Predicted Solution')
Well, I don't know how to set individual axes as 3D using plt.subplots. It would be helpful if someone could comment down.
The preferred way of creating an 3D axis is giving the projection keyword:
def plotAll(data):
fig = plt.figure()
ax = fig.add_subplot(221, projection='3d')
for i,traj in enumerate(data.values()):
ax.plot3D([traj[0][-1]],[traj[1][-1]],[traj[2][-1]],".",color=[0.91,0.39,0.046])
plot_12v13 = fig.add_subplot(222)
plot_projections(data,0,1)
plot_13v14 = fig.add_subplot(223)
plot_projections(data,1,2)
plot_12v14 = fig.add_subplot(224)
plot_projections(data,0,2)
plt.plot()
Unfortunately, you didn't supply a working example with suitable data, so I couldn't test the code. Also, I would recommend updating to a newer version of matplotlib.
Hi I have a text file containing three columns of numbers; one column each for the x,y,z coordinates of a bunch of points. All numbers are between 0 ad 1.
I want to plot all these points in the unit cube [0,1]x[0,1]x[0,1].
Please let me know how I can do this in Octave or MatPlot lib, whichever prduces a better quality image.
If I understand your question correctly, this is how it looks in Matplotlib:
This is the code to produce this plot:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
np.random.seed(101)
x,y,z = np.random.rand(3,20)
fig = plt.figure()
# version 1.0.x syntax:
#ax = fig.add_subplot(111, projection='3d')
# version 0.99.x syntax: (accepted by 1.0.x as well)
ax = Axes3D(fig)
ax.scatter(x,y,z)
fig.savefig('scatter3d.png')
As the code suggests, there are slight differences in how matplotlib version 0.99.1.1 and version 1.0.1 behave, as noted in this SO question/answer. I am using 0.99.1.1, and I had trouble using all the options available to 2D scatter plots, which should be the same for 3D plots as well. The full list of scatter features are listed here.
The above code resulted from looking at the matplotlib tutorial on 3D plotting.