Suppose sound1 is 10 mins long and I would like to overlay sound2 (3mins) between 7:00 till 9:00 mins (only first 2 mins of sound2)?
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I'm trying to create a stop report for my plant while learning SQL.
The goal is to get a report containing the amount of minutes stopped planned and unplanned and the amount of stops planned and unplanned. All of this should be reported by day.
Currently I have these values:
Datum: Date
Unplanned: The amount of minutes our plant stopped that day when it was not planned
#unpplanned: the amount of stops we had that day that were unplanned
Daysunplanned: The amount of days the unplanned stop lasted
planned: The amount of minutes our plant stopped that day when it was planned
#planned: The amount of stops we had that day that were planned
dayspl: The amount of days the planned stop lasted
nextday: The amount of minutes that the stop took that should be counted to the next day. A stop can last from 20:00 7/02/2023 till 05:00 8/02/2023).
Can't embed yet :/
My issue is the following:
On 2023-02-06 the plant stopped 1130 minutes unplanned. The stop lasted till 07-02-2023. You can see this because dayunpla = 1.
So the results should be:
2023-02-07 1378
2023-02-06 1130
If dayunpla = 4 we should get:
2023-02-11 1378
2023-02-10 1440
2023-02-09 1440
2023-02-08 1440
2023-02-06 1130
1440 is 24 hours.
I can't think of a way to get from my current table to what I want.
I tried all google searches I could think of but did not find anything helpfull.
Is there a way to fix this using just SQL?
Thanks for your time!
Tried google and a lot of tinkering
Goal: highlight regular trading market hours in a plotly chart.
-Using a df with standard datetime and 1 minute intervals.
-Regular trading hours = 9:30am EST to 4pm EST
—-Incase interested:
——-pre market = 4am to 9:30am
——-post market = 4pm to 8pm
Stack overflow has great links for highlighting weekend data like this:
Nevermind that link was just removed by the author as I tried to post it, but it’s too difficult for me to translate that to specific times of day anyway.
This is relatively easy to do using fig.add_vrect()
I built a similar highlighting system for night and day:
time = df.index.get_level_values("time")
# Getting info for plotting the day/night indicator
# time[0].date() picks out 00:00 (midnight) and then we add 6 hours to get 6 am.
start_morning = pd.to_datetime(time[0].date()) + pd.Timedelta(
hours=6
)
end_morning = pd.to_datetime(time[-1].date()) + pd.Timedelta(
hours=30
)
num_mornings = (end_morning - start_morning).days
# Now we build up the morning times, every day at 6 am
mornings = [
start_morning + timedelta(days=x) for x in range(num_mornings)
]
for morning in mornings:
fig.add_vrect(
# Highlighted region starts at 6 am and ends at 6 pm, every day.
x0=morning,
x1=morning + timedelta(hours=12),
fillcolor="white",
opacity=0.1,
line_width=0,
)
For you, it would just be a simple matter of adjusting the times. So for instance, for 9:30 am you can use
morning = pd.to_datetime(time[0].date()) + pd.Timedelta(hours=9.5)
to get the first day of your data, at 9:30 am. Now in fig.add_vrect() use
x0= morning
x1= morning + timedelta(hours=6.5)
to highlight between 9:30 am and 4 pm.
I am a admin of a bio-metric device, there are 3 shifts are going in my office.
In time Out time Date
Shift1 6AM 2PM 5th April
Shift2 2PM 10PM 5th April
Shift3 10PM 5th April 6AM 6th April
but the 3rd shift time intime 10PM is taking as
In time Out Time
day1 out time 10PM
day2 in time 6AM
How can I make it for same date 10PM as intime and 6AM as out time in excel?
And also I want to generate it automatically.
I want the Out Time must shown as the same date.
Date Intime Outtime
5.4.17 6AM 2PM
5.4.17 2PM 10PM
5.4.17 10PM 6AM
And I want to automate the report while generating from web.
=Now() will generate a number (double type) like 42832.8008217593 where the date is shown on the left of the period and the time on the right. 10 PM (22:00:00) will be expressed as 0.9166666667. Add 8 hours to this number (1/24*8) and the result is 1.25 which means, in plain language, "next day 6 AM".
To solve your problem you can use a condition, like, If the end time is on the next day, deduct one day from the result date. This would mean 1.25 - 1 = 0.25 = 6:00AM on the day which is one day earlier than it actually is. Whether your end time is a proper date/time, like 42833.25 or a relative time like 1.25 depends upon how you enter your data.
You can extract the time from the date/time value by calculating (Date/Time - Int(Date/Time), like 1.25 - Int(1.25) = 1.25 -1 = 0.25
I need to subtract two dates (including hours and minutes), but I only need to consider working hours. That is, I need to omit lunch time (from 13 to 14 hrs), weekends and hours after 18 hrs and before 9 hrs of the following day, in a working day (from Mo to Fr). Any thoughts?
I don't mind if it's an Excel formula or a vba code.
I have this formula, but it doesn't omit lunch time:
9*(NETWORKDAYS(initial_time;ending_time)-1)-24*((MOD(initial_time;1)-MOD(ending_time;1)))
Here's a possible solution. It assumes an 8 hour work days for all but the start and end date. Also that start date/time is 9:00 or after and end date/time is 18:00 or earlier and that both are on a weekday.
=(NETWORKDAYS(A2,B2)-2)*8+IF(MOD(A2,1)>0.58333,(TIME(18,0,0)-MOD(A2,1))*24,(TIME(18,0,0)-MOD(A2,1))*24-1)+IF(MOD(B2,1)>0.58333,(MOD(B2,1)-TIME(9,0,0))*24-1,(MOD(B2,1)-TIME(9,0,0))*24)
.58333 equates to 14:00. The formula:
multiplies networkdays * 8
+ hours from start date/time until 18:00 subtracting 1 hour if start time is before 14:00
+ hours from 9:00 until end date/time subtracting 1 hour if end time is after 14:00
Of course this doesn't take any holidays into account.
I want to create a basic case logging system and when somebody opens a new issue, the issue is assigned a Sr_number with a given number of hours. For example Sr_number 1 is 4 hours, 2 is 6 hours, 3 is 8 hours and 4 is 24 hours.
Now adding hours onto a time stamp is easy but the catch is I need to take into account working hours which are 09:00 to 17:00 Monday to Friday.So if a case is given a 12 hour Sr_number and the deadline for this falls at 16:00 on a week day then the deadline is extended to the next working day. Basically the deadline is 12 working hours.And calculation should be 1 hour worked for the issue logged on same day and remaining 11 hours to next working day.
If in case it is sun, it should consider directly go to monday.
Example:
Case created on: 10/06/2015 12:04:39 PM- with Sr_number 1 (12 Hours) Deadline is now: 10/07/2015 12.05 PM
Make sense?
Another catch is I need to take into account hours On Hold and these two have to be only within working hours.
For some case,saturdays is working ,for some its holiday.
How should i proceed.
I tried performing datepart,dateadd and datediff functions.But i could find only weekday.
I am new at sql.Please guide for the same