I have dataset which looks like this:
UserID AccountID CloseDate
1 1000 14/3/2022
1 2000 16/3/2022
2 1000 NULL
2 2000 4/3/2022
2 3000 NULL
And I would like to check if within one user_id all of the close dates are not null. In other words if all accounts within user_id are closed. I was trying using MAX or MIN but it is not working as I expected, because it is simply avoiding NULL values. Is there any other function which can check it? Let's say that my output would be another column which will assign 1 when all CloseDates are not null and else 0.
Sample output:
UserID AccountID CloseDate Check
1 1000 14/3/2022 1
1 2000 16/3/2022 1
2 1000 NULL 0
2 2000 4/3/2022 0
2 3000 NULL 0
Use conditional aggregation to explicitly COUNT the rows where the column has the value NULL:
SELECT GroupedColumn,
COUNT(CASE WHEN NullableColumn IS NULL THEN 1 END) AS NullCount
FROM dbo.YourTable
GROUP BY GroupedColumn;
If you want to just have a 1 or 0 just wrap the count in a CASE expression:
CASE COUNT(CASE WHEN NullableColumn IS NULL THEN 1 END) WHEN 0 THEN 1 ELSE 0 END
You can try to use FIRST_VALUE condition window function
SELECT *,
FIRST_VALUE(IIF(CloseDate IS NULL,0,1)) OVER(PARTITION BY UserID ORDER BY CloseDate )
FROM T
sqlfiddle
with dataset as (select 1 as UserId, 1000 as AccountID, '14/3/2022' as CloseDate
union all select 1, 2000, '16/3/2022'
union all select 2, 1000, NULL
union all select 2, 2000, '4/3/2022'
union all select 2, 3000, NULL)
select userid from dataset
group by userid
having sum(case when closedate is null then 1 else 0 end) = 0;
select d.*, iif(chk>0, 0, 1) chk
from d
outer apply (
select UserId, COUNT(*) CHK
from d dd
WHERE d.UserId = dd.UserId
and dd.CloseDate IS NULL
group by UserId
) C
You can also use "exists". e.g. :
select y.UserID, y.AccountID, y.CloseDate,
-- [Check]: returns 0 if there is a row in the table for the
-- UserID where CloseDate is null, else 1
(case when exists(select * from YourTable y2 where y2.UserID = y.UserID
AND y2.CloseDate is null) then 0 else 1 end) as [Check]
from YourTable y
Related
let's say there's a table have data like below
id
status
date
1
4
2022-05
2
3
2022-06
I want find count of id of each month by their status. Something like this below
date
count(status1) = 4
count(status2) =3
2022-05
1
null
2022-06
null
1
I tried doing
-- select distinct (not working)
select date, status1, status2 from
(select date, count(id) as "status1" from myTable
where status = 4 group by date) as myTable1
join
(select date, count(id) as "status2" from myTable
where status = 3 group by date) as myTable2
on myTable1.date = myTable2.date;
-- group by (not working)
but it does duplicate the data needed.
and I am using SQL Server.
select d.date,
sum
(
case
when d.status=4 then 1
else 0
end
)count_status_4,
sum
(
case
when d.status=5 then 1
else 0
end
)count_status_5
from your_table as d
group by d.date
I have the following table invoving sort of 3 sets and I'm going to calculate the count of sets in whcich there is no (TaskId = 4), How can I achieve that?
SetId TaskId
1 0
1 1
1 4
2 0
2 2
2 3
3 0
3 2
3 4
Use conditional aggregation:
SELECT SetId
FROM yourTable
GROUP BY SetId
HAVING SUM(CASE WHEN TaskId = 4 THEN 1 ELSE 0 END) = 0;
The basic idea here is to scan each SetId group of records and count the number of times which a TaskId value of 4 occurs. The HAVING clause retains only groups for which the 4 value never occurs.
Use a CASE expression to check whether the TaskId value is 4. And use SUM function with grouping SetId.
Query
select [SetId],
SUM(case [TaskId] when 4 then 0 else 1 end) as [sum]
from [your_table_name]
group by [SetId];
I think you are looking for something like
SELECT *
FROM mytable t1
WHERE t1.SetId NOT IN (SELECT t2.SetId FROM mytable t2 WHERE t2.TaskId = 4)
(select the full sets that have no TaskId=4)
or
SELECT distinct SetId
FROM mytable t1
WHERE t1.SetId NOT IN (SELECT t2.SetId FROM mytable t2 WHERE t2.TaskId = 4)
(select just the SetIds that have no TaskId=4)
Say for example I have a table that contains a description of a customer's activities while in a cafe. (Metaphor of the actual table I am working on)
Customer Borrowed Book Ordered Drink Has Company
1 1
1 1
1 Yes
2 1
3 1
3 Yes
4 1 1
4 1
I wish to combine the rows in this way
Customer Borrowed Book Ordered Drink Has Company
1 1 1 Yes
2 1
3 1 Yes
4 1 2
I did self join with coalesce, but it did not give my desired results.
You can do this by group by,
select Customer,sum([borrowed book]), sum([ordered drink]), max([has company])
from customeractivity group by Customer
As per your comment, initial table is a temp table,
Try to make the result as a cte result, then do aggregation on that, like the below query.
; WITH cte_1
AS
( //your query to return the result set)
SELECT customer,sum([borrowed book]) BorrowedBook,
sum([ordered drink]) OrderedDrink,
max([has company]) HasCompany
FROM cte_1
GROUP BY Customer
Use Group By:
DECLARE #tblTest as Table(
Customer INT,
BorrowedBook INT,
OrderedDrink INT,
HasCompany BIt
)
INSERT INTO #tblTest VALUES
(1,1,NULL,NULL)
,(1,NULL,1,NULL)
,(1,NULL,NULL,1)
,(2,NULL,1,NULL)
,(3,NULL,1,NULL)
,(3,NULL,NULL,1)
,(4,1,1,NULL)
,(4,NULL,1,NULL)
SELECT
Customer,
SUM(ISNULL(BorrowedBook,0)) AS BorrowedBook,
SUM(ISNULL(OrderedDrink,0)) AS OrderedDrink,
CASE MIN(CAST(HasCompany AS INT)) WHEN 1 THEN 'YES' ELSE '' END AS HasCompany
FROM #tblTest
GROUP BY Customer
Not sure, why you are getting error with group by.
Your coalesce should be correct. Refer below way.
Select customer
, case when [borrowed] = 0 then NULL else [borrowed] end as [borrowed]
, case when [ordered] = 0 then NULL else [ordered] end as [ordered]
, case when [company] = 1 then 'Yes' end as company
from
(
Select customer,
coalesce(
case when (case when borrowed = '' then null else borrowed end) = 1 then 'borrowed' end,
case when (case when ordered = '' then null else ordered end) = 1 then 'ordered' end,
case when (case when company = '' then null else company end) = 'Yes' then 'company' end
) val
from Table
) main
PIVOT
(
COUNT (val)
FOR val IN ( [borrowed], [ordered], [company] )
) piv
OUTPUT:
customer | borrowed | ordered | company
---------------------------------------
1 1 1 Yes
2 NULL 1 NULL
3 NULL 1 Yes
I get crazy because of one query. I have a table like following and I want to get a data - Summa of Values by Status For every Date in interval.
Table
Id Name Value Date Status
1 pro1 2 01.04.14 0
2 pro1 8 02.04.14 1
3 pro2 6 02.04.14 1
4 pro3 0 03.04.14 0
5 pro4 7 03.04.14 0
6 pro4 2 03.04.14 0
7 pro4 4 03.04.14 1
8 pro4 6 04.04.14 1
9 pro4 1 04.04.14 1
For example,
Input: Name = pro4, minDate = 01.02.14, maxDate = 04.09.14
Output:
Date Values sum for 0 Status Values sum for 1 Status
01.04.14 0 0
02.04.14 0 0
03.04.14 9 (=7+2) 4 (only 4 exist)
04.04.14 0 7 (6+1)
In 01.02.14 and 02.04.14 dates, pro4 has not values by status, but I want to show that rows, because I need all dates in that interval. Can anyone help me to create this query?
Edit:
I can not change structure, I have already that table with data. Every day exist in table many times (minimum 1 time)
Thanks in advance.
Assuming you have a row for each date in the table, use conditional aggregation:
select date,
sum(Case when name = 'pro4' and status = 0 then Value else 0 end) as values_0,
sum(case when name = 'pro4' and status = 1 then Value else 0 end) as values_1
from Table t
where date >= '2014-04-01' and date <= '2014-04-09'
group by date
order by date;
If you don't have this list of dates, you can take this approach instead:
with dates as (
select cast('2014-04-01' as date) as thedate
union all
select dateadd(day, 1, thedate)
from dates
where thedate < '2014-04-09'
)
select dates.thedate,
sum(Case when status = 0 then Value else 0 end) as values_0,
sum(case when status = 1 then Value else 0 end) as values_1
from dates left outer join
table t
on t.date = dates.thedate and t.name = 'pro4'
group by dates.thedate;
just an assumption query :
select Distinct date ,case when status = 0 and MAX(date) then SUM(value) ELSE 0 END Status0 ,
case when status = 1 and MAX(date) then SUM(value) ELSE 0 END Status1 from table
To expand my comment the complete query is
WITH [counter](N) AS
(SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1)
, days(N) AS (
SELECT row_number() over (ORDER BY (SELECT NULL)) FROM [counter])
, months (N) AS (
SELECT N - 1 FROM days WHERE N < 13)
, calendar ([date]) AS (
SELECT DISTINCT cast(dateadd(DAY, days.n
, dateadd(MONTH, months.n, '20131231')) AS date)
FROM months
CROSS JOIN days
)
SELECT a.Name
, c.Date
, [Sum of 0] = SUM(CASE Status WHEN 0 THEN Value ELSE 0 END)
, [Sum of 1] = SUM(CASE Status WHEN 1 THEN Value ELSE 0 END)
FROM Calendar c
LEFT JOIN myTable a ON c.Date = a.Date AND a.name = 'pro4'
WHERE c.date BETWEEN '20140201' AND '20140904'
GROUP BY c.Date, a.Name
ORDER BY c.Date
Note that the condition on the name need to be in the JOIN, otherwise you'll get only the date of your table.
If you need multiple years just add another CTE for the count and a dateadd(YEAR,...) in the CTE calendar
This is not really the exact query, but I think you can get that by having a query that looks like:
select date, status, sum(value) from table
where (date between mindate and maxdate) and name = product_name
group by date, status;
this page gives more info.
EDIT
So the above query only gives a part of the answer required by the OP. A LEFT OUTER JOIN of the original table and the result of the above query on thedate and status fields will give the missing info.
e.g.
select x.date, x.status, x.sum_of_values from table as y
left outer join
(select date, status, sum(value) as sum_of_values
from table
where (date between mindate and maxdate) and name = product_name
group by date, status) as x
on y.date= x.date and y.status = x.status
order by x.date;
I'm trying get to find out if a row has the max value in a group. Here's really simple example:
Data
VoteCount LocationId UserId
3 1 1
4 1 2
3 2 2
4 2 1
Pseudo-query
select
LocationId,
sum(case
when UserId = 1 /* and has max vote count*/
then 1 else 0
end) as IsUser1Winner,
sum(case
when UserId = 2 /* and has max vote count*/
then 1 else 0
end) as IsUser2Winner
from LocationVote
group by LocationID
It should return:
LocationId IsUser1Winner IsUser2Winner
1 0 1
2 1 1
I also couldn't find a way to generate dynamic column names here. What would be the simplest way to write this query?
You could also do this using a Case statement
WITH CTE as
(SELECT
MAX(VoteCount) max_votes
, LocationId
FROM LocationResult
group by LocationId
)
SELECT
A.LocationId
, Case When UserId=1
THEN 1
ELSE 0
END IsUser1Winner
, Case when UserId=2
THEn 1
ELSE 0
END IsUser2Winner
from LocationResult A
inner join
CTE B
on A.VoteCount = B.max_votes
and A.LocationId = B.LocationId
Try this:
select *
from table t
cross apply (
select max(votes) max_value
from table ref
where ref.group = t.group
)votes
where votes.max_value = t.votes
but if your table is huge and has no propriate indexes performance may be poor
Another way is to get max values by groups into table variable or temp table and then join it to original table.