I'm trying get to find out if a row has the max value in a group. Here's really simple example:
Data
VoteCount LocationId UserId
3 1 1
4 1 2
3 2 2
4 2 1
Pseudo-query
select
LocationId,
sum(case
when UserId = 1 /* and has max vote count*/
then 1 else 0
end) as IsUser1Winner,
sum(case
when UserId = 2 /* and has max vote count*/
then 1 else 0
end) as IsUser2Winner
from LocationVote
group by LocationID
It should return:
LocationId IsUser1Winner IsUser2Winner
1 0 1
2 1 1
I also couldn't find a way to generate dynamic column names here. What would be the simplest way to write this query?
You could also do this using a Case statement
WITH CTE as
(SELECT
MAX(VoteCount) max_votes
, LocationId
FROM LocationResult
group by LocationId
)
SELECT
A.LocationId
, Case When UserId=1
THEN 1
ELSE 0
END IsUser1Winner
, Case when UserId=2
THEn 1
ELSE 0
END IsUser2Winner
from LocationResult A
inner join
CTE B
on A.VoteCount = B.max_votes
and A.LocationId = B.LocationId
Try this:
select *
from table t
cross apply (
select max(votes) max_value
from table ref
where ref.group = t.group
)votes
where votes.max_value = t.votes
but if your table is huge and has no propriate indexes performance may be poor
Another way is to get max values by groups into table variable or temp table and then join it to original table.
Related
Imagine this data.
Id
Type
1
A
1
B
1
B
2
A
3
B
I want to select table and ad two columns turning it to this. How can i do it? (In teradata)
Id
Type
Id with both A+B
Id with only A
1
A
1
0
1
B
1
0
1
B
1
0
2
A
0
1
3
B
0
0
I'm not familiar with teradata but in standard SQL next query should be working:
SELECT
T.*,
CASE WHEN Cnt = 2 THEN 1 ELSE 0 END AS BOTH_TYPES_PRESENT,
CASE WHEN Cnt = 1 AND Type = 'A' THEN 1 ELSE 0 END AS ONLY_A_PRESENT
FROM T
LEFT JOIN (
SELECT Id, COUNT(DISTINCT Type) Cnt FROM T WHERE Type IN ('A', 'B') GROUP BY Id
) CNT ON T.Id = CNT.Id;
SQL online editor
I have the following table invoving sort of 3 sets and I'm going to calculate the count of sets in whcich there is no (TaskId = 4), How can I achieve that?
SetId TaskId
1 0
1 1
1 4
2 0
2 2
2 3
3 0
3 2
3 4
Use conditional aggregation:
SELECT SetId
FROM yourTable
GROUP BY SetId
HAVING SUM(CASE WHEN TaskId = 4 THEN 1 ELSE 0 END) = 0;
The basic idea here is to scan each SetId group of records and count the number of times which a TaskId value of 4 occurs. The HAVING clause retains only groups for which the 4 value never occurs.
Use a CASE expression to check whether the TaskId value is 4. And use SUM function with grouping SetId.
Query
select [SetId],
SUM(case [TaskId] when 4 then 0 else 1 end) as [sum]
from [your_table_name]
group by [SetId];
I think you are looking for something like
SELECT *
FROM mytable t1
WHERE t1.SetId NOT IN (SELECT t2.SetId FROM mytable t2 WHERE t2.TaskId = 4)
(select the full sets that have no TaskId=4)
or
SELECT distinct SetId
FROM mytable t1
WHERE t1.SetId NOT IN (SELECT t2.SetId FROM mytable t2 WHERE t2.TaskId = 4)
(select just the SetIds that have no TaskId=4)
I have a scenario where I need to fetch all the records within an ID for the same source. Given below is my input set of records
ID SOURCE CURR_FLAG TYPE
1 IBM Y P
1 IBM Y OF
1 IBM Y P
2 IBM Y P
2 TCS Y P
3 IBM NULL P
3 IBM NULL P
3 IBM NULL P
4 IBM NULL OF
4 IBM NULL OF
4 IBM Y ON
From the above settings, I need to select all the records with source as IBM within that same ID group.Within the ID group if there is at least one record with a source other than IBM, then I don't want any record from that ID group. Also, we need to fetch only those records where at least one record in that ID group with curr_fl='Y'
In the above scenario even though the ID=3 have a source as IBM, but there is no record with CURR_FL='Y', my query should not fetch the value.In the case of ID=4, it can fetch all the records with ID=4, as one of the records have value='Y'.
Also within the group which has satisfied the above condition, I need one more condition for source_type. if there are records with source_type='P', then I need to fetch only that record.If there are no records with P, then I will search for source_type='OF' else source_type='ON'
I have written a query as given below.But it's running for long and not fetching any results. Is there any better way to modify this query
select
ID,
SOURCE,
CURR_FL,
TYPE
from TABLE a
where
not exists(select 1 from TABLE B where a.ID = B.ID and source <> 'IBM')
and exists(select 1 from TABLE C where a.ID = C.ID and CURR_FL = 'Y') and
(TYPE, ID) IN (
select case type when 1 then 'P' when 2 then 'OF' else 'ON' END TYPE,ID from
(select ID,
max(priority) keep (dense_rank first order by priority asc) as type
from ( select ID,TYPE,
case TYPE
when 'P' then 1
when 'OF' then 2
when 'ON' then 3
end as priority
from TABLE where ID
in(select ID from TABLE where CURR_FL='Y') AND SOURCE='IBM')
group by ID))
I think you can just do a single aggregation over your table by ID and check for the yes flag as well as assert that no non IBM source appears. I do this in a CTE below, and then join back to your original table to return full matching records.
WITH cte AS (
SELECT
ID,
CASE WHEN SUM(CASE WHEN TYPE = 'P' THEN 1 ELSE 0 END) > 0
THEN 1
WHEN SUM(CASE WHEN TYPE = 'OF' THEN 1 ELSE 0 END) > 0
THEN 2
WHEN SUM(CASE WHEN TYPE = 'ON' THEN 1 ELSE 0 END) > 0
THEN 3 ELSE 4 END AS p_type
FROM yourTable
GROUP BY ID
HAVING
SUM(CASE WHEN CURR_FLAG = 'Y' THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN SOURCE <> 'IBM' THEN 1 ELSE 0 END) = 0
)
SELECT t1.*
FROM yourTable t1
INNER JOIN cte t2
ON t1.ID = t2.ID
WHERE
t2.p_type = 1 AND t1.TYPE = 'P' OR
t2.p_type = 2 AND t1.TYPE = 'OF' OR
t2.p_type = 3 AND t1.TYPE = 'ON';
I have a table with Ids and a subId column. And I have a user defined data type with a list of SubIds. I want all those ids which have all the sub-ids present in my user-defined data type. for example:
The table is:
ID SubID
1 2
1 3
1 4
2 3
2 4
2 2
3 3
3 2
and the data type is
CREATE TYPE SubIds AS TABLE
( SubId INT );
GO
With Value
SubID
3
4
I want the output to be
ID
1
2
Because only the ID 1 and 2 contain both the subIds 3 & 4
Note: the combination of Id and Sub ID will always be unique if its of any use
Let's assume that #s is your table of ids:
select t.ID
from t
Where t.SubId in (select SubId from #s)
group by t.Id
having count(*) = (select count(*) from #s);
This assumes that the two tables do not have duplicates. If duplicates are present, you can use:
select t.ID
from t
Where t.SubId in (select SubId from #s)
group by t.Id
having count(distinct t.SubId) = (select count(distinct s.SubId) from #s s);
Try this way
select ID
from yourtable
Where SubID in (3,4)
Group by ID
having Count(distinct SubID)=2
Another more flexible approach
select ID
from yourtable
Group by ID
having sum(case when SubID = 3 then 1 else 0 end) >= 1
and sum(case when SubID = 4 then 1 else 0 end) >= 1
If you want to pull SubId's from SubIds table type then,
SELECT ID
FROM yourtable T
JOIN (SELECT SubID,
Count(1) OVER() AS cnt
FROM SubIds) S
ON T.SubID = S.SubID
GROUP BY ID,Cnt
HAVING Count(DISTINCT T.SubID) = s.cnt
I have 2 tables, one (Jobs) contains the list of the jobs and second contains the details of the records in each job.
Jobs
JobID Count
A 2
B 3
Records
JobID RecordID ToBeProcessed IsProcessed
A A1 1 1
A A2 1 1
B B1 1 1
B B2 1 0
B B3 1 0
How would I be able to create a query that would list all the jobs that have the count of ToBeProcessed which has a value of 1 is equal to the count of isProcessed that has a value of 1? Thanks in advance. Any help is greatly appreciated.
Start with the calculation of the number of items with ToBeProcessed set to 1 or IsProcessed set to one:
SELECT
JobID
, SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END) ToBeProcessedIsOne
, SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END) IsProcessedIsOne
FROM Records
GROUP BY JobID
This gives you all counts, not only ones where ToBeProcessedIsOne is equal to IsProcessedIsOne. To make sure that you get only the records where the two are the same, use either a HAVING clause, or a nested subquery:
-- HAVING clause
SELECT
JobID
, SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END) ToBeProcessedIsOne
, SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END) IsProcessedIsOne
FROM Records
GROUP BY JobID
HAVING SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END)=SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END)
-- Nested subquery with a condition
SELECT * FROM (
SELECT
JobID
, SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END) ToBeProcessedIsOne
, SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END) IsProcessedIsOne
FROM Records
GROUP BY JobID
) WHERE ToBeProcessedIsOne = IsProcessedIsOne
Note: if ToBeProcessed and IsProcessed are of type that does not allow values other than zero or one, you can replace the CASE statement with the name of the column, for example:
SELECT
JobID
, SUM(ToBeProcessed) ToBeProcessedIsOne
, SUM(IsProcessed) IsProcessedIsOne
FROM Records
GROUP BY JobID
HAVING SUM(ToBeProcessed)=SUM(IsProcessedD)
if im not misunderstanding your question it looks like you just need a WHERE clause in your statement to see when they are both equal to 1.
SELECT
r.JobID AS j_id,
r.RecordID as r_id,
r.ToBeProcessed AS tbp,
r.IsProcessed AS ip
FROM Records AS r
WHERE r.ToBeProcessed = 1 AND r.IsProcessed = 1
GROUP BY j_id;
let me know if this is not what you are asking for.
if its a count from a different table then just do a count of the tbp and ip rows grouped by jobID and then the where should still do the trick