Replace Digits Using SubString and lpad/rpad - sql

Question

is there any way to replace digits using substring in Hive.
scenario:
1. I need to check 0's from right to left and as soon as i find 0 before any digit then i need to replace all the trailing 0's by 9.
2. In output at-least 3 digit should be there before 9.
3. In Input if 2 or less digits are available in input then I need to skip some 0's and make sure that at-least 3 digits are there before 9.
4. If more than 3 digits are available before trailing 0's then only need to replace 0.No need to replace digits.
see the below table
input output
123000 123999
120000 120999
123400 123499
101010 101019
I have tried using below query, and it is working as expected.(Hive Join with CTE)
with mytable as (
select '123000' as input
union all
select '120000' as input
union all
select '123400' as input
union all
select '101010' as input
)
select input,lpad(concat(splitted[0], translate(splitted[1],'0','9')),6,0) as output
from (
select input, split(regexp_replace(input,'(\\d{3,}?)(0+)$','$1|$2'),'\\|') splitted from mytable )s;
but In my actual query which is more than 500+ lines,it is very difficult to adjust this logic (with CTE) for the sigle column. so wondering if is there any way to achieve the same using only lpad/rpad and substring/length and can achieve by adding the functions without using CTE queries.
so let say if length of digits before trailing 0's is less than 6 then can skip the substring
from (input,1,6) and will replace the remaining 0's and if length of digits before trailing 0's is 6
or more then 6 then just keep digits as it is and replace remaining trailing 0's by 9.
Kindly Suggest.
My Actual Query Looks like.
with mytable as
(
select lpad(input,13,9) as output from mytable where code='00'
union
select output from mytable where code='01'
)
select t1.*,m1.output from table1 t1 , mytable m1 where
(t1.card='00' and substr(t1.low,1,13)<=m1.low and m1.output <= substr(t1.output,1,13) and m1.card='00' )
or
(t1.card='01' and substr(t1.low,1,16)<=m1.low and m1.output <= substr(t1.output,1,16) and m1.card='01' )
I want to Replace above logic for 2nd output where code=01 in union query.

Answer 1

Instead of UNION you can do the same using single query:
Instead of this
select lpad(output,13,9) as output from mytable where code='00'
union
select output from mytable where code='01'
use this
select distinct
case code when '00' then lpad(output,13,9)
when '01' then output
end output
from mytable
If you need to filter codes, add where code in ('00','01')

Answer 2

It Worked Now.I modified My query as below.
with mytable as
(
select lpad(input,13,9) as output from mytable where code='00'
union
select lpad(concat(split(regexp_replace('(\\d{6,}?)(0+)$','$1|$2'),'\\|') [0],
translate(split(regexp_replace(input,'(\\d{6,}?)(0+)$','$1|$2'),'\\|')[1],'0','9')),16,0 )
output from mytable where code='01'
)
select t1.*,m1.output from table1 t1 , mytable m1 where
(t1.card='00' and substr(t1.low,1,13)<=m1.low
and m1.output <= substr(t1.output,1,13) and m1.card='00' )
or
(t1.card='01' and substr(t1.low,1,16)<=m1.low
and output <= substr(output,1,16) and m1.card='01')