PIVOT datetime and ORDER column values of multiple rows - sql

Question

I have a table with values which are not in order
Id
DateTime
Status
1
2022-03-01 18:00:00.000
Stop1
2
2022-03-01 08:00:00.000
Start
3
2022-03-01 20:00:00.000
Stop2
4
2022-03-02 09:00:00.000
Start
5
2022-03-01 10:00:00.000
Stop2
6
2022-03-02 11:00:00.000
Finish
7
2022-03-01 14:00:00.000
Start
8
2022-03-02 10:00:00.000
Stop1
where Status can be 'Start', 'Stop1', 'Stop2', or 'Finish'.
I need the timeline like this, where the values are pivoted in the order (from the earliest to the latest; id is not relevant at this point)
Id
Start
Stop1
Stop2
Finish
2
2022-03-01 08:00:00
NULL
2022-03-01 10:00:00
NULL
7
2022-03-01 14:00:00
2022-03-01 18:00:00
2022-03-01 20:00:00
NULL
4
2022-03-02 09:00:00
2022-03-02 10:00:00
NULL
2022-03-02 11:00:00
After I PIVOTed it in SQL Server
SELECT *
FROM (
SELECT Id, DateTime, Status FROM table
) t
PIVOT (
MAX(DateTime)
FOR Status IN (Start, Stop1, Stop2, Finish)
) p
I got
Id
Start
Stop1
Stop2
Finish
2
2022-03-01 08:00:00
NULL
NULL
NULL
5
NULL
NULL
2022-03-01 10:00:00
NULL
7
2022-03-01 14:00:00
NULL
NULL
NULL
1
NULL
2022-03-01 18:00:00
NULL
NULL
3
NULL
NULL
2022-03-01 20:00:00
NULL
6
NULL
NULL
NULL
2022-03-02 11:00:00
8
NULL
2022-03-02 10:00:00
NULL
NULL
4
2022-03-02 09:00:00
NULL
NULL
NULL
How can I get that timeline?

Answer 1

Perhaps this will help. The window functions can be invaluable
Also, remember to "FEED" your pivot with only the required columns.
Example
Select *
From (
Select id = min(case when Status='Start' then ID end) over (partition by Grp)
,DateTime
,Status
From (
Select *
,Grp = sum( case when [Status]='Start' then 1 else 0 end) over (order by datetime)
from YourTable
) A
) src
Pivot ( max(DateTime) FOR Status IN (Start, Stop1, Stop2, Finish) ) p
Results