I have a table that looks like below. In my query I'm sum:ing the order item value for each order item type, but I'm not sure how to summarize the providerfee per order id when the providerfee appears on multiple rows. Sum(providerfee) would give me 60 instead of 30.
Raw table (sample):
order id
order item type
order item value
providerfee
1
Product
300
30
1
Shipping
40
30
1
Invoicefee
30
30
Aggregated table if I would query above example table with the query I'm using now:
noOfOrders
productAmount
ShippingAmount
InvoiceAmount
providerfee
1
300
40
30
60
What value I wish to get in the providerfee column in my aggregated table instead:
noOfOrders
productAmount
ShippingAmount
InvoiceAmount
providerfee
1
300
40
30
30
Does anyone now best practice of fetching the right sum per order id from the providerfee-column? I think it won't make any sense to publish the actual query I'm writing but basically what I'm doing to fetch the amounts for order item types is:
with amounts as (
select
case when orderItemType= 'Product' then orderItemValue else 0 end as productAmount
,case when orderItemType = 'Shipping' then orderItemvalue else 0 end as shippingAmount
case when orderItemType = 'Fee' then orderItemvalue else 0 end as InvoicefeeAmount
,providerfee
from exampleTable
)
select
sum(amounts.productAmount) as productAmount
,sum(amounts.shippingAmount) as shippingAmount
,sum(amounts.invoicefeeAmount) as invoicefeeAmount
,sum(amounts.providerfee) as providerfeeAmount <---- This one gives me too high values since I'm summing every rows and providerfee appears on every row
from amounts
Here's a picture of how my actual table look like. Providerfee is supposed to be 638 just like invoiceAmount
One thing I also tried was a logic with row number function. But this gave me a result where three providerfees where missing. Instead of 638 I got 551. Can't see why since I counted in the raw table and got it to 638 myself. Not sure if I'm missing something logical with row number function that can have an impact on the SUM. Should I try another function to be able to pull out only one providerfee-row per order id?
with amounts as (
select
row_number() over (partition by orderId order by orderItemTimestamp DESC) as rn
,case when orderItemType= 'Product' then orderItemValue else 0 end as productAmount
,case when orderItemType = 'Shipping' then orderItemvalue else 0 end as shippingAmount
,case when orderItemType = 'Fee' then orderItemvalue else 0 end as InvoicefeeAmount
,providerfee
from exampleTable
)
select
sum(amounts.productAmount) as productAmount
,sum(amounts.shippingAmount) as shippingAmount
,sum(amounts.invoicefeeAmount) as invoicefeeAmount
,sum(amounts.providerfee) as providerfeeAmount <---- This one gives me too high values since I'm summing every rows and providerfee appears on every row
,sum(case when (amounts.providerfee is not null and amounts.rn = 1) then amounts.providerfee else 0 end) as providerfee2
from amounts
Grand total can be done using conditional aggregation. (Note that I here expect every Orderto have exactly one Invoicefee.)
select COUNT(distinct OrderId) as noOfOrders,
SUM(case when orderItemType = 'Product' then orderItemValue else 0 end) as productAmount,
SUM(case when orderItemType = 'Shipping' then orderItemvalue else 0 end) as shippingAmount,
SUM(case when orderItemType = 'Fee' then orderItemvalue else 0 end) as InvoicefeeAmount,
SUM(case when orderItemType = 'Fee' then providerfee else 0 end) as providerfee
from amounts
You can also add a GROUP BY, to get aggregation per order:
select OrderId,
SUM(case when orderItemType = 'Product' then orderItemValue else 0 end) as productAmount,
SUM(case when orderItemType = 'Shipping' then orderItemvalue else 0 end) as shippingAmount,
SUM(case when orderItemType = 'Fee' then orderItemvalue else 0 end) as InvoicefeeAmount,
SUM(case when orderItemType = 'Fee' then providerfee else 0 end) as providerfee
from amounts
group by OrderId
Related
I have a code as below where I want to count number of first purchases for a given period of time. I have a column in my sales table where if the buyer is not a first time buyer, then is_first_purchase = 0
For example:
buyer_id = 456391 is already an existing buyer who made purchases on 2 different dates.
Hence is_first_purchase column will show as 0 as per below.
If i do a count() on is_first_purchase for this buyer_id = 456391 then it should return 0 instead of 2.
My query is as follows:
with first_purchases as
(select *,
case when is_first_purchase = 1 then 'Yes' else 'No' end as first_purchase
from sales)
select
count(case when first_purchase = 'Yes' then 1 else 0 end) as no_of_first_purchases
from first_purchases
where buyer_id = 456391
and date_id between '2021-02-01' and '2021-03-01'
order by 1 desc;
It returned the below which is not an intended output
Appreciate if someone can help explain how to exclude is_first_purchase = 0 from the count, thanks.
Because COUNT function count when the value isn't NULL (include 0), if you don't want to count, need to let CASE WHEN return NULL
There are two ways you can count as your expectation, one is SUM other is COUNT but remove the part of else 0
SUM(case when first_purchase = 'Yes' then 1 else 0 end) as no_of_first_purchases
COUNT(case when first_purchase = 'Yes' then 1 end) as no_of_first_purchases
From your question, I would combine CTE and main query as below
select
COUNT(case when is_first_purchase = 1 then 1 end) as no_of_first_purchases
from sales
where buyer_id = 456391
and date_id between '2021-02-01' and '2021-03-01'
order by 1 desc;
I think that you are using COUNT() when you want SUM().
with first_purchases as
(select *,
case when is_first_purchase = 1 then 'Yes' else 'No' end as first_purchase
from sales)
select
SUM(case when first_purchase = 'Yes' then 1 else 0 end) as no_of_first_purchases
from first_purchases
where buyer_id = 456391
and date_id between '2021-02-01' and '2021-03-01'
order by 1 desc;
You could simplify your query as:
SELECT COUNT(*) AS
FROM sales no_of_first_purchases
WHERE is_first_purchase = 1
AND buyer_id = 456391
AND date_id BETWEEN '2021-02-01' AND '2021-03-01'
ORDER BY 1 DESC;
It is better to avoid the use of functions like IF and CASE when it can be done with WHERE.
The simplest approach for Trino (f.k.a. Presto SQL) is to use an aggregate with a filter:
count(name) FILTER (WHERE first_purchase = 'Yes') AS no_of_first_purchases
I have here a sample table data which i want to use pivot and make my DedCode data into column.
the AMount example is already computed to its total but how can i count the number of employee if it is same with branch,deptcode and emptype.
my sample table data.
expected output:
You can use conditional aggregation:
select branch, deptcode, emptype, sum(empcount) as empcount,
sum(case when dedcode = 'PHIC' then amount else 0 end) as phic,
sum(case when dedcode = 'SLOAN' then amount else 0 end) as sloan,
sum(case when dedcode = 'VLOAN' then amount else 0 end) as vloan
from t
group by branch, deptcode, emptype;
I have a table of invoices and Record_Types that I need to reconcile to open invoice report. I have the process down and know what I need to do. Just dont know how to properly structure the query and would prefer to not create 3 tables.
Record Types.
Invoice = 1 Credit = 5 Payment = 7
Invoice_Number, Record_Type, Dollar figure
Outstanding_Balance = Invoice(1) -(Payment(7)-(Credit))
Invoice_number Record_type Gen_Numeric_3
Basically I need to take the record_Type 1 and subtract the total of record type 7's from the below.
Invoice_Num Rec_Type Dollar_Amt
00820437 1 536.7700000000
00820437 7 469.6200000000
00820437 7 67.1500000000
Any advice would be great. messer
You can do this with aggregation and case statements:
SELECT invoice_num,
SUM(CASE WHEN rec_type = 1 THEN dollar_amt ELSE 0 END) - (SUM(CASE WHEN rec_type=7 THEN dollar_amt ELSE 0 END) - SUM(CASE WHEN rec_type=5 THEN dollar_amt ELSE 0 END)) as outstanding_balance
FROM yourtable
GROUP BY invoice_num
i have table named source table with data like this :
And i want to do query that subtract row with status plus and minus to be like this group by product name :
How to do that in SQL query? thanks!
Group by the product and then use a conditional SUM()
select product,
sum(case when status = 'plus' then total else 0 end) -
sum(case when status = 'minus' then total else 0 end) as total,
sum(case when status = 'plus' then amount else 0 end) -
sum(case when status = 'minus' then amount else 0 end) as amount
from your_table
group by product
There is another method using join, which works for the particular data you have provided (which has one "plus" and one "minus" row per product):
select tplus.product, (tplus.total - tminus.total) as total,
(tplus.amount - tminus.amount) as amount
from t tplus join
t tminus
on tplus.product = tminus.product and
tplus.status = 'plus' and
tplus.status = 'minus';
Both this and the aggregation query work well for the data you have provided. In other words, there are multiple ways to solve this problem (each has its strengths).
you can query as below:
select product , sum (case when [status] = 'minus' then -Total else Total end) as Total
, sum (case when [status] = 'minus' then -Amount else Amount end) as SumAmount
from yourproduct
group by product
I want to do a query like:
select
count(asterisk) where acción='a'/count(asterisk) where acción='b' * 100
from
same_table
grouped by day
but I don't want use subquery, is it possible with joins?
I`m not sure the syntax is correct, but you can use something like this:
SELECT day,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A,
SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) AS SUM_B,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A / SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) * 100 AS result
FROM your_table
GROUP BY day
The concept is to actually sum the the values that you need, instead of count.