I want to do a query like:
select
count(asterisk) where acción='a'/count(asterisk) where acción='b' * 100
from
same_table
grouped by day
but I don't want use subquery, is it possible with joins?
I`m not sure the syntax is correct, but you can use something like this:
SELECT day,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A,
SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) AS SUM_B,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A / SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) * 100 AS result
FROM your_table
GROUP BY day
The concept is to actually sum the the values that you need, instead of count.
Related
I have a bit of sql code that look similar to this:
select sum(case when latitude = '0' then 1 else 0 end) as count_zero,
sum(case when latitude is NULL then 1 else 0 end) as count_null,
sum((case when latitude = '0' then 1 else 0 end) +
(case when latitude is NULL then 1 else 0 end)
) as total_zero,
count(latitude) as count_not_nulls,
count(*) as total
from sites_database
Is there a "cleaner" way to write this same query. I have tried using the "sum" expression using the column alias, something like:
Sum(count_zero + count_null) as total_null
But this doesn't seem to work for some reason
You could use COUNT instead of SUM:
SELECT
COUNT(CASE WHEN latitude = '0' THEN 1 END) As count_zero,
COUNT(CASE WHEN latitude IS NULL THEN 1 END) AS count_null,
COUNT(CASE WHEN COALESCE(latitude, '0') = '0' THEN 1 END) AS total_zero,
COUNT(latitude) As count_not_nulls,
COUNT(*) as total
FROM sites_database;
Using COUNT here saves a bit of coding, because we don't have to provide an explicit ELSE condition (the default ELSE is NULL, which just isn't counted at all). Also note that for the total_zero conditional sum, I used COALESCE to merge the two counts into just one.
Hello guys i need to use mutiple where clause in one sql query as follows but it can't work please help me.
select (select count(total) as 'studentMarks1' from School where total <60 ),
(select count(total) as 'studentMarks2' from School where total >80 )
from School
where Id = '8'
You rather need to use CASE statement like
select SUM(case when total < 60 then 1 else 0 end) as 'studentMarks1',
sum(case when total > 80 then 1 else 0 end) as 'studentMarks2'
from School
where Id = '8'
You cau usually do this with an appropriate CASE statement:
SELECT COUNT(CASE WHEN total < 60 then 1 else NULL END)
, COUNT(CASE WHEN total > 80 then 1 else NULL END)
FROM School
WHERE ID = '8'
I've two query from same table but by two condition but how can I make two column for this two conditional count.
SELECT Count(*) FROM TBL_FT WHERE STATUS = 'X';
SELECT Count(*) FROM TBL_FT WHERE STATUS = 'Y' and
LOGDATE>trunc(sysdate);
You can use conditional aggregation:
SELECT
COUNT(CASE WHEN STATUS = 'X' THEN 1 END),
COUNT(CASE WHEN STATUS = 'Y' AND LOGDATE > trunc(sysdate) THEN 1 END)
FROM TBL_FT
You can also add a WHERE clause:
WHERE STATUS IN ('X', 'Y');
you can use something like this -
SELECT SUM(CASE
WHEN STATUS = 'X' THEN
1
ELSE
0
END) FIRST_VAL,
SUM(CASE
WHEN STATUS = 'Y'
AND LOGDATE > TRUNC(SYSDATE) THEN
1
ELSE
0
END) second_val
FROM TBL_FT;
I have the following data:
In SQL Server How can I have group by weekdate so I have only one row for each weekdate, example for the weekdate 2015-11-14:
Any clue?
Use conditional aggregation.
select cast(weekdate as date),
sum(case when permittype = 0 then total else 0 end) as permittype0,
sum(case when permittype = 1 then total else 0 end) as permittype1
from tablename
group by cast(weekdate as date)
I would do this using conditional aggregation:
select weekdate,
sum(case when permittype = 0 then total else 0 end) as permitttype0,
sum(case when permittype = 1 then total else 0 end) as permitttype1
from followingdata t
group by weekdate
order by weekdate;
You can also use pivot syntax, if you prefer.
I have a table like this
TABLEMAIN
Q1 Name Group Zone Month Type
1 'N1' 'G1' 'Z1' 12 'T1'
4 'N1' 'G3' 'Z2' 12 'T6'
6 'N1' 'G1' 'Z5' 12 'T2'
3 'N2' 'G4' 'Z5' 12 'T4'
.
.
.
And I have something like this to get certain results
Query1:
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Type,
**Zone,**
Month
from
TABLEMAIN
GROUP BY Type, **Zone,** Month;
Query2:
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Type,
**Group,**
Month
from
TABLEMAIN
GROUP BY Type, **Group,** Month;
As you can see I group this table many times in many ways, but this part is the same in every query
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Is there a better way to do this? I'm not sure if I can use a materialized view for this
Perhaps. You can do it all in one query, if you like by using grouping sets:
select SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END) as TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) as T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) as T2TYPE
Type, **Zone,**, **Group,** Month
from TABLEMAIN
GROUP BY GROUPING SETS((Type, **Zone,** Month), (Type, **Group,** Month));
This puts all the results in a single table.
I second with #GolezTrol comment. Would like to explain further.
SUBQUERY FACTORING is what you need. The WITH clause, or subquery factoring clause, is part of the SQL-99 standard and was added into the Oracle SQL syntax in Oracle 9.2. The WITH clause may be processed as an inline view or resolved as a temporary table. The advantage of the latter is that repeated references to the subquery may be more efficient as the data is easily retrieved from the temporary table, rather than being required by each reference.
WITH data AS(
<your subquery>
)
SELECT * FROM data
bla bla bla...