Count of consecutive days ORACLE SQL - sql

I need help with a query where a need to count de consecutive days like this
select
a.numcad, a.datapu , f.datapu , nvl(to_char(f.datapu, 'DD'),0)dia,
row_number() over (partition by a.numcad, f.datapu order by f.datapu)particao
from
ronda.r066apu a
left join (select t.numcad, t.numemp, t.datacc, t.datapu
from ronda.r070acc t
where t.datacc >= '21/01/2022'
and t.datacc <= trunc(sysdate)
group by t.numcad, t.numemp, t.datacc, t.datapu)f
on a.numemp = f.numemp
and a.numcad = f.numcad
and a.datapu = f.datapu
where a.numcad = 2675
and A.DATAPU >= '21/01/2022'
and A.DATAPU <= trunc(sysdate)
group by a.numcad, a.datapu, f.datapu, f.datacc
order by a.datapu
result is
between 24/01/2022 and 04/02/2022
is 12 days i need know this count , but i will ways get the '21/mes/year'

You can try:
SELECT TO_DATE('2022-01-24', 'YYYY-MM-DD') -
TO_DATE('2022-02-04', 'YYYY-MM-DD')
FROM dual
This returns 21, for example...

Related

How to subtract two timestamps in SQL and then count?

I want to basically find out how many users paid within 15 mins, 30 mins and 60 mins of my payment_time and trigger_time
I have the following query
with redshift_direct() as conn:
trigger_time_1 = pd.read_sql(f"""
with new_data as
(
select
cycle_end_date
, prime_tagging_by_issuer_and_product
, u.user_id
, settled_status
, delay,
ots_created_at + interval '5:30 hours' as payment_time
,case when to_char(cycle_end_date,'DD') = '15' then 'Odd' else 'Even' end as cycle_order
from
settlement_summary_from_snapshot s
left join (select distinct user_phone_number, user_id from user_events where event_name = 'UserCreatedEvent') u
on u.user_id = s.user_id
and cycle_type = 'end_cycle'
and cycle_end_date > '2021-11-30' and cycle_end_date < '2022-01-15'
)
select
bucket_id
, cycle_end_date, d.cycle_order
, date(cycle_end_date) as t_cycle_end_date
,d.prime_tagging_by_issuer_and_product
,source
,status as cause
,split_part(campaign_name ,'|', 1) as campaign
,split_part(campaign_name ,'|', 2) as sms_cycle_end_date
,split_part(campaign_name ,'|', 3) as day
,split_part(campaign_name ,'|', 4) as type
,to_char(to_date(split_part(campaign_name ,'|', 2) , 'DD/MM/YYYY'), 'YYYY-MM-DD') as campaign_date,
d.payment_time, payload_event_timestamp + interval '5:30 hours' as trigger_time
,count( s.user_id) as count
from sms_callback_events s
inner join new_data d
on s.user_id = d.user_id
where bucket_id > 'date_2021_11_30' and bucket_id < 'date_2022_01_15'
and campaign_name like '%RC%'
and event_name = 'SmsStatusUpdatedEvent'
group by 1,2,3,4,5,6,7,8,9,10,11,12,13,14
""",conn)
How do i achieve making 3 columns with number of users who paid within 15mins, 30 mins and 60 mins after trigger_time in this query? I was doing it with Pandas but I want to find a way to do it here itself. Can someone help?
I wrote my own DATEDIFF function, which returns an integer value of differencing between two dates, difference by day, by month, by year, by hour, by minute and etc. You can use this function on your queries.
DATEDIFF Function SQL Code on GitHub
Sample Query about using our DATEDIFF function:
select
datediff('minute', mm.start_date, mm.end_date) as diff_minute
from
(
select
'2022-02-24 09:00:00.100'::timestamp as start_date,
'2022-02-24 09:15:21.359'::timestamp as end_date
) mm;
Result:
---------------
diff_minute
---------------
15
---------------

how to use double group by and sum statements together in oracle

I am trying to use query below but it is giving an error
SELECT s.LOCAL_CODE,substr(p.ACCOUNT_CREDIT,-3),(p.SUMMA/100) as profit
FROM OPERATIONS s INNER JOIN LEADS p ON s.PAY_ID = p.PAY_ID
WHERE s.date_paid >= TO_DATE('03.12.2019', 'DD.MM.YYYY')
AND s.date_paid < TO_DATE('03.12.2019', 'DD.MM.YYYY') + INTERVAL '1' DAY
AND state = 'T'
AND s.filial_code = '006789'
AND SUBSTR(p.ACCOUNT_CREDIT, 1, 5) = '765294'
GROUP BY s.LOCAL_CODE,substr(p.ACCOUNT_CREDIT,-3);
If LEADS.SUMMA has expected value then you don't need Group By clause, else if you use Group By then all not grouped fields can be used only as arguments of aggregate functions:
SELECT s.LOCAL_CODE
, Substr(p.ACCOUNT_CREDIT, -3)
, Sum(p.SUMMA)/100 as profit
FROM OPERATIONS s
INNER JOIN LEADS p ON s.PAY_ID = p.PAY_ID
WHERE s.date_paid >= TO_DATE('03.12.2019', 'DD.MM.YYYY')
AND s.date_paid < TO_DATE('03.12.2019', 'DD.MM.YYYY') + INTERVAL '1' DAY
AND state = 'T'
AND s.filial_code = '006789'
AND SUBSTR(p.ACCOUNT_CREDIT, 1, 5) = '765294'
GROUP BY s.LOCAL_CODE
, substr(p.ACCOUNT_CREDIT, -3);

How do I display records in the same row although I am using group by on 2 columns that appear in different rows right now?

This is the output I am getting now but I want all the records for one gateway in one row I am trying to find the damage count and total count of packages processed by an airport in a week. Currently I am grouping by airport and week so I am getting the records in different rows for an airport and week. I want to have the records for a particular airport in a single row with weeks being in the same row.
I tried putting a conditional group by but that did not work.
select tmp.gateway,tmp.weekbucket, sum(tmp.damaged_count) as DamageCount, sum(tmp.total_count) as TotalCount, round(sum(tmp.DPMO),0) as DPMO from
(
select a.gateway,
date_trunc('week', (a.processing_date + interval '1 day')) - interval '1 day' as weekbucket,
count(distinct(b.fulfillment_shipment_id||b.package_id)) as damaged_count,
count(distinct(a.fulfillment_shipment_id||a.package_id)) as total_count,
count(distinct(b.fulfillment_shipment_id||b.package_id))*1.00/count(distinct(a.Fulfillment_Shipment_id || a.package_id))*1000000 as DPMO
from booker.d_air_shipments_na a
left join trex.d_ps_packages b
on (a.fulfillment_shipment_id||a.package_id =b.Fulfillment_Shipment_id||b.package_id)
where a.processing_date >= current_date-7
and (exception_summary in ('Reprint-Damaged Label') or exception_summary IS NULL)
and substring(route, position(a.gateway IN route) +6, 1) <> 'K'
group by a.gateway, weekbucket) as tmp
group by tmp.gateway, tmp.weekbucket
order by tmp.gateway, tmp.weekbucket desc;
As you get two week's days starting and ending hence its likely that youll get 2 rows for each. Can try to remove week bucket from group by after performing your actual select/within the inner select and put a max on week bucket with summing both counts of both start and end of week dates.
select
tmp.gateway,max(tmp.weekbucket),
sum(tmp.damaged_count) as
DamageCount,
sum(tmp.total_count) as TotalCount,
round(sum(tmp.DPMO),0) as DPMO
from
(
select a.gateway,
date_trunc('week', (a.processing_date +
interval '1 day')) - interval '1 day' as
weekbucket, count(distinct(b.fulfillment_shipment_id||b
.package_id)) as damaged_count,
count(distinct(a.fulfillment_shipment_id||a .package_id)) as total_count,
count(distinct(b.fulfillment_shipment_id||b.package_id))*1.00/count(distinct(a.Fulfillment_Shipment_id || a.package_id))*1000000 as DPMO
from booker.d_air_shipments_na a
left join trex.d_ps_packages b
on (a.fulfillment_shipment_id||a.package_id =b.Fulfillment_Shipment_id||b.package_id)
where a.processing_date >= current_date-7
and (exception_summary in ('Reprint-Damaged Label') or exception_summary IS NULL)
and substring(route, position(a.gateway IN route) +6, 1) <> 'K'
group by a.gateway, weekbucket) as tmp
group by tmp.gateway
order by tmp.gateway,
max(tmp.weekbucket) desc;
So you want to pivot the two weeks into a single row with two sets of aggregates?:
select
tmp.gateway,
tmp.weekbucket,
min(case when rn = 1 then tmp.damaged_count end) as DamageCountWeek1,
min(case when rn = 2 then tmp.damaged_count end) as DamageCountWeek2,
min(case when rn = 1 then tmp.total_count end) as TotalCountWeek1,
min(case when rn = 2 then tmp.total_count end) as TotalCountWeek2,
min(case when rn = 1 then round(tmp.DPMO, 0) end) as DPMOWeek1,
min(case when rn = 2 then round(tmp.DPMO, 0) end) as DPMOWeek2,
from (
select row_number() over (partition by gateway order by weekbucket) as rn,
...
) as tmp
group by tmp.gateway
order by tmp.gateway;

Retrieve records by continuation of days in oracle

I want to retrieve records where cash deposits are more than 4 totaling to 1000000 during a day and continues for more than 5 days.
I have came up with below query.
SELECT COUNT(a.txamt) AS "txcount"
, SUM(a.txamt) AS "txsum"
, b.custcd
, a.txdate
FROM tb_transactions a
INNER JOIN tb_accounts b
ON a.acctno = b.acctno
WHERE a.cashflowtype = 'CR'
GROUP BY b.custcd, a.txdate
HAVING COUNT(a.txamt)>4 and SUM(a.txamt)>='1000000'
ORDER BY a.txdate;
But I'm stuck on how to fetch the records if the pattern continues for 5 days.
How to achieve the desired result?
Something like:
SELECT *
FROM (
SELECT t.*,
COUNT( txdate ) OVER ( PARTITION BY custcd
ORDER BY txdate
RANGE BETWEEN INTERVAL '0' DAY PRECEDING
AND INTERVAL '4' DAY FOLLOWING ) AS
num_days
FROM (
select count(a.txamt) as "txcount",
sum(a.txamt) as "txsum",
b.custcd,
a.txdate
from tb_transactions a inner join tb_accounts b on a.acctno=b.acctno
where a.cashflowtype='CR'
group by b.custcd, a.txdate
having count(a.txamt)>4 and sum(a.txamt)>=1000000
) t
)
WHERE num_days = 5
order by a.txdate;

SQL Query Help (Advanced - for me!)

I have a question about a SQL query I am trying to write.
I need to query data from a database.
The database has, amongst others, these 3 fields:
Account_ID #, Date_Created, Time_Created
I need to write a query that tells me how many accounts were opened per hour.
I have written said query, but there are times that there were 0 accounts created, so these "hours" are not populated in the results.
For example:
Volume Date__Hour
435 12-Aug-12 03
213 12-Aug-12 04
125 12-Aug-12 06
As seen in the example above, hour 5 did not have any accounts opened.
Is there a way that the result can populate the hour but and display 0 accounts opened for this hour?
Example of how I want my results to look like:
Volume Date_Hour
435 12-Aug-12 03
213 12-Aug-12 04
0 12-Aug-12 05
125 12-Aug-12 06
Thanks!
Update: This is what I have so far
SELECT count(*) as num_apps, to_date(created_ts,'DD-Mon-RR') as app_date, to_char(created_ts,'HH24') as app_hour
FROM accounts
WHERE To_Date(created_ts,'DD-Mon-RR') >= To_Date('16-Aug-12','DD-Mon-RR')
GROUP BY To_Date(created_ts,'DD-Mon-RR'), To_Char(created_ts,'HH24')
ORDER BY app_date, app_hour
To get the results you want, you will need to create a table (or use a query to generate a "temp" table) and then use a left join to your calculation query to get rows for every hour - even those with 0 volume.
For example, assume I have a table with app_date and app_hour fields. Also assume that this table has a row for every day/hour you wish to report on.
The query would be:
SELECT NVL(c.num_apps,0) as num_apps, t.app_date, t.app_hour
FROM time_table t
LEFT OUTER JOIN
(
SELECT count(*) as num_apps, to_date(created_ts,'DD-Mon-RR') as app_date, to_char(created_ts,'HH24') as app_hour
FROM accounts
WHERE To_Date(created_ts,'DD-Mon-RR') >= To_Date('16-Aug-12','DD-Mon-RR')
GROUP BY To_Date(created_ts,'DD-Mon-RR'), To_Char(created_ts,'HH24')
ORDER BY app_date, app_hour
) c ON (t.app_date = c.app_date AND t.app_hour = c.app_hour)
I believe the best solution is not to create some fancy temporary table but just use this construct:
select level
FROM Dual
CONNECT BY level <= 10
ORDER BY level;
This will give you (in ten rows):
1
2
3
4
5
6
7
8
9
10
For hours interval just little modification:
select 0 as num_apps, (To_Date('16-09-12','DD-MM-RR') + level / 24) as created_ts
FROM dual
CONNECT BY level <= (sysdate - To_Date('16-09-12','DD-MM-RR')) * 24 ;
And just for the fun of it adding solution for you(I didn't try syntax, so I'm sorry for any mistake, but the idea is clear):
SELECT SUM(num_apps) as num_apps, to_date(created_ts,'DD-Mon-RR') as app_date, to_char(created_ts,'HH24') as app_hour
FROM(
SELECT count(*) as num_apps, created_ts
FROM accounts
WHERE To_Date(created_ts,'DD-Mon-RR') >= To_Date('16-09-12','DD-MM-RR')
UNION ALL
select 0 as num_apps, (To_Date('16-09-12','DD-MM-RR') + level / 24) as created_ts
FROM dual
CONNECT BY level <= (sysdate - To_Date('16-09-12','DD-MM-RR')) * 24 ;
)
GROUP BY To_Date(created_ts,'DD-Mon-RR'), To_Char(created_ts,'HH24')
ORDER BY app_date, app_hour
;
You can also use a CASE statement in the SELECT to force the value you want.
It can be useful to have a "sequence table" kicking around, for all sorts of reasons, something that looks like this:
create table dbo.sequence
(
id int not null primary key clustered ,
)
Load it up with million or so rows, covering positive and negative values.
Then, given a table that looks like this
create table dbo.SomeTable
(
account_id int not null primary key clustered ,
date_created date not null ,
time_created time not null ,
)
Your query is then as simple as (in SQL Server):
select year_created = years.id ,
month_created = months.id ,
day_created = days.id ,
hour_created = hours.id ,
volume = t.volume
from ( select * ,
is_leap_year = case
when id % 400 = 0 then 1
when id % 100 = 0 then 0
when id % 4 = 0 then 1
else 0
end
from dbo.sequence
where id between 1980 and year(current_timestamp)
) years
cross join ( select *
from dbo.sequence
where id between 1 and 12
) months
left join ( select *
from dbo.sequence
where id between 1 and 31
) days on days.id <= case months.id
when 2 then 28 + years.is_leap_year
when 4 then 30
when 6 then 30
when 9 then 30
when 11 then 30
else 31
end
cross join ( select *
from dbo.sequence
where id between 0 and 23
) hours
left join ( select date_created ,
hour_created = datepart(hour,time_created ) ,
volume = count(*)
from dbo.SomeTable
group by date_created ,
datepart(hour,time_created)
) t on datepart( year , t.date_created ) = years.id
and datepart( month , t.date_created ) = months.id
and datepart( day , t.date_created ) = days.id
and t.hour_created = hours.id
order by 1,2,3,4
It's not clear to me if created_ts is a datetime or a varchar. If it's a datetime, you shouldn't use to_date; if it's a varchar, you shouldn't use to_char.
Assuming it's a datetime, and borrowing #jakub.petr's FROM Dual CONNECT BY level trick, I suggest:
SELECT count(*) as num_apps, to_char(created_ts,'DD-Mon-RR') as app_date, to_char(created_ts,'HH24') as app_hour
FROM (select level-1 as hour FROM Dual CONNECT BY level <= 24) h
LEFT JOIN accounts a on h.hour = to_number(to_char(a.created_ts,'HH24'))
WHERE created_ts >= To_Date('16-Aug-12','DD-Mon-RR')
GROUP BY trunc(created_ts), h.hour
ORDER BY app_date, app_hour