I have data that looks like this. Thousands of rows returned, but this is just a sample.
Most days have the same numbers in them, but some do not. Note that ID 1 and 5 have identical numbers every day.
ID
Sunday
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
1
26
26
26
26
26
26
26
2
44
44
30
30
44
44
44
3
55
55
55
55
80
90
55
4
12
12
43
43
43
43
43
5
36
36
36
36
36
36
36
I'd like to only return rows where the days of the week have different numbers.
In this case, the only IDs returned should be 2, 3 & 4.
What would I want this query to look like?
Thanks!
One idea that should work in most RDBMS (with some syntax tweaks) is the following.
This is SQL Server compatible: pivot the days into rows and count the distinct values and filter accordingly:
select id
from t
cross apply (
select Count(distinct d) from (
values(sunday),(monday),(tuesday),(wednesday),(thursday),(friday),(saturday)
)d(d)
)d(v)
where d.v>1
Related
I have the following table:
Column1 Column2 Column3
04/07/2019 1
04/08/2019 2
04/09/2019 8
04/10/2019 9
04/11/2019 15
04/12/2019 16
04/13/2019 5
04/14/2019 6
04/15/2019 8
04/16/2019 9
04/17/2019 10
04/18/2019 11
04/19/2019 5
04/20/2019 5
04/21/2019 8
04/22/2019 8
04/23/2019 9
04/24/2019 10
04/25/2019 11
04/26/2019 12
04/27/2019 10
I need to find out a way to iterate through the values in column one and identify weeks which should start from Saturday - Sunday. So, in this example one iteration should be from the 14 - 20th. Or another iteration would be from the 7th through the 13th which is Saturday - Sunday. Then After identifying each week, I need to do some calculation on the other columns.The calculation would be updating Column3 if the total amount for Column2 within 1 week (Based on Column1 Saturday to Sunday) exceeds 40 or not. Then the same for the next iteration of week (Saturday - Sunday).
Desired Results:
Column1 Column2 Column3
04/07/2019 1 56
04/08/2019 2 56
04/09/2019 8 56
04/10/2019 9 56
04/11/2019 15 56
04/12/2019 16 56
04/13/2019 5 56
04/14/2019 6 54
04/15/2019 8 54
04/16/2019 9 54
04/17/2019 10 54
04/18/2019 11 54
04/19/2019 5 54
04/20/2019 5 54
04/21/2019 8 68
04/22/2019 8 68
04/23/2019 9 68
04/24/2019 10 68
04/25/2019 11 68
04/26/2019 12 68
04/27/2019 10 68
Please note: The data can range from 3 weeks to a few month. So, the code needs to capture the weeks for any specific range.
You can use datepart() to get the week of a date. You can then use the week to partition by in a windowed sum(). From there you can UPDATE the table joining a derived table that gets the sum like mentioned before. To make sure the week begins on Sunday issue a SET DATEFIRST 7 before the UPDATE.
SET DATEFIRST 7;
UPDATE t1
SET t1.column3 = t3.column3
FROM elbat t1
INNER JOIN (SELECT t2.column1,
sum(t2.column2) OVER (PARTITION BY datepart(week, t2.column1)) column3
FROM elbat t2) t3
ON t3.column1 = t1.column1;
db<>fiddle
I have a column in table which is varchar2(3) style column. This column has some nulls and when I try to run following query it runs for some records but when I scroll to some record I get ORA-01722: invalid number error.
Query used:
Select TRUNC(NVL(COLUMN, '2'))
from TABLE;
Also I ran distinct on column to see what values it has.
Select distinct COLUMN
from TABLE;
I got following results:
1
2 62
3 90
4 70
5 82
6 71
7 05
8 21
9 81
10 66
11 12
12 95
13 02
14 91
15 92
16 94
17 01
18 65
19 30
20 20
21
22 50
23 63
24 51
25 64
26 09
Why am I getting this error and how can I do this without getting error?
https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions200.htm
Because you want to trunc a string, but TRUNC function is for number or date .
This function takes as an argument any numeric datatype or any nonnumeric datatype that can be implicitly converted to a numeric datatype
Maybe one of your string value cannot be converted to number
edit : your 21t value is not a number and is not null, you should trim your column
SELECT trunc(nvl(trim(column),'2'))
FROM table;
I have the following table in postgresql;
Value period
1 [2017-01-01,2017-02-01)
2 [2017-02-01,2017-03-01)
3 [2017-03-01,2017-04-01)
4 [2017-04-01,2017-05-01)
5 [2017-05-01,2017-06-01)
6 [2017-06-01,2017-07-01)
7 [2017-07-01,2017-08-01)
8 [2017-08-01,2017-09-01)
9 [2017-09-01,2017-10-01)
10 [2017-10-01,2017-11-01)
11 [2017-11-01,2017-12-01)
12 [2017-12-01,2018-01-01)
13 [2018-01-01,2018-02-01)
14 [2018-02-01,2018-03-01)
15 [2018-03-01,2018-04-01)
16 [2018-04-01,2018-05-01)
17 [2018-05-01,2018-06-01)
18 [2018-06-01,2018-07-01)
19 [2018-07-01,2018-08-01)
20 [2018-08-01,2018-09-01)
21 [2018-09-01,2018-10-01)
22 [2018-10-01,2018-11-01)
23 [2018-11-01,2018-12-01)
24 [2018-12-01,2019-01-01)
25 [2019-01-01,2019-02-01)
26 [2019-02-01,2019-03-01)
27 [2019-03-01,2019-04-01)
28 [2019-04-01,2019-05-01)
29 [2019-05-01,2019-06-01)
30 [2019-06-01,2019-07-01)
31 [2019-07-01,2019-08-01)
32 [2019-08-01,2019-09-01)
33 [2019-09-01,2019-10-01)
34 [2019-10-01,2019-11-01)
35 [2019-11-01,2019-12-01)
36 [2019-12-01,2020-01-01)
37 [2020-01-01,2020-02-01)
38 [2020-02-01,2020-03-01)
39 [2020-03-01,2020-04-01)
40 [2020-04-01,2020-05-01)
41 [2020-05-01,2020-06-01)
42 [2020-06-01,2020-07-01)
How can I get yearly average from monthly data in postgresql?
Note: Column Value is type integer and column period is type daterange.
The expected result should be
6.5 2017
18.5 2018
30.5 2019
39.5 2020
If your periods are always taking one month, including the lower bound and excluding the upper, you could try this
select
avg(value * 1.0) as average,
extract(year from lower(period)) as year
from table
group by year
Lets say I have a table which holds all exports for some time back in Microsoft SQL database:
Name:
ExportTable
Columns:
id - numeric(18)
exportdate - datetime
In order to get the number of exports per week I can run the following query:
SELECT DATEPART(ISO_WEEK,[exportdate]) as 'exportdate', count(exportdate) as 'totalExports'
FROM [ExportTable]
Group By DATEPART(ISO_WEEK,[exportdate])
order by exportdate;
Returns:
exportdate totalExports
---------- ------------
27 13
28 12
29 15
30 8
31 17
32 10
33 7
34 15
35 4
36 18
37 10
38 14
39 14
40 21
41 19
Would it be possible to aggregate the week results by quarter so the output becomes something like the bellow?
UPDATE
Sorry for not being crystal clear, I would like the current result to add upp with previous result up to a new quarter.
Note week 41 contains 21+19 = 40
Week 39 contains 157 (13+12+15+8+17+10+7+15+4+18+10+14+14)
exportdate totalExports Quarter
---------- ------------ -------
27 13 3
28 25 3
29 40 3
30 48 3
31 65 3
32 75 3
33 82 3
34 97 3
35 101 3
36 119 3
37 129 3
38 143 3
39 157 3 -- Sum of 3 Quarter values.
40 21 4 -- New Quarter show current week value
41 40 4 -- (21+19)
You can use this.
SELECT
DATEPART(ISO_WEEK,[exportdate]) as 'exportdate'
, SUM( count(exportdate) ) OVER ( PARTITION BY DATEPART(QUARTER,MIN([exportdate])) ORDER BY DATEPART(ISO_WEEK,[exportdate]) ROWS UNBOUNDED PRECEDING ) as 'totalExports'
, DATEPART(QUARTER,MIN([exportdate])) [Quarter]
FROM [ExportTable]
Group By DATEPART(ISO_WEEK,[exportdate])
order by exportdate;
You could use a case statement to separate the dates into quarters.
e.g.
CASE
WHEN EXPORT_DATE BETWEEN '1' AND '4' THEN 1
WHEN Export_Date BETWEEN '5' and '9' THEN 2
ELSE 0 AS [Quarter]
END
Its just an example but you get the idea.
You could then use the alias from the case
SELECT DATEPART(ISO_WEEK,[exportdate]) as 'exportdate', count(exportdate) as 'totalExports', DATEPART(quarter,[exportdate]) as quarter FROM [ExportTable] Group By DATEPART(ISO_WEEK,[exportdate]), DATEPART(quarter,[exportdate]) order by exportdate;
I have a query returned value in this form (query return more than 50 columns).
1-99transval 100-200transval 200-300transval ... 1-99nontransval 100...
50 90 80 67 58
For a row value. I want these details to be converted into columns and take the following shape:
Range Transval NonTransval
1-99 50 67
100-200 90 58
In pure SQL, it will need a lot of coding because you will have to manually put the range as there is no relation between the values and the range at all. Had there been a relationship, you could use CASE expression and build the range dynamically.
SQL> WITH DATA AS
2 (SELECT 50 "1-99transval",
3 90 "100-200transval",
4 80 "200-300transval",
5 67 "1-99nontransval",
6 58 "100-200nontransval",
7 88 "200-300nontransval"
8 FROM dual
9 )
10 SELECT '1-99' range,
11 "1-99transval" transval,
12 "1-99nontransval" nontransval
13 FROM DATA
14 UNION
15 SELECT '100-200' range,
16 "100-200transval",
17 "100-200nontransval" nontransval
18 FROM DATA
19 UNION
20 SELECT '200-300' range,
21 "200-300transval",
22 "200-300nontransval" nontransval
23 FROM DATA;
RANGE TRANSVAL NONTRANSVAL
------- ---------- -----------
1-99 50 67
100-200 90 58
200-300 80 88
From Oracle database 11g Release 1 and above, you could use UNPIVOT
SQL> WITH DATA AS
2 (SELECT 50 "1-99transval",
3 90 "100-200transval",
4 80 "200-300transval",
5 67 "1-99nontransval",
6 58 "100-200nontransval",
7 88 "200-300nontransval"
8 FROM dual
9 )
10 SELECT *
11 FROM DATA
12 UNPIVOT( (transval,nontransval)
13 FOR RANGE IN ( ("1-99transval","1-99nontransval") AS '1-99'
14 ,("100-200transval","100-200nontransval") AS '100-200'
15 ,("200-300transval","200-300nontransval") AS '200-300'));
RANGE TRANSVAL NONTRANSVAL
------- ---------- -----------
1-99 50 67
100-200 90 58
200-300 80 88
Above, in your case you need to replace the WITH clause with your existing query as a sub-query. You need to include other columns in the UNION.
In PL/SQL, you could (ab)use EXECUTE IMMEDIATE and get the "range" by extracting the column names in dynamic sql.
Although, it would be much better to modify/rewrite your existing query which you have not shown yet.
If you are using Oracle 11g version then you can use the UNPIVOT feature.
CREATE TABLE DATA AS
SELECT 50 "1-99transval",
90 "100-200transval",
80 "200-300transval",
67 "1-99nontransval",
58 "100-200nontransval",
88 "200-300nontransval"
FROM dual
SELECT *
FROM DATA
UNPIVOT( (Transval,NonTransval) FOR Range IN ( ("1-99transval","1-99nontransval") as '1-99'
,("100-200transval","100-200nontransval") as '100-200'
,("200-300transval","200-300nontransval") as '200-300'))
http://sqlfiddle.com/#!4/c9747/3/0