I have a query where I am trying to add a prefix to week numbers.
Right now, the query puts out the week numbers as (1,2,3,4...) Is there a way where I can add "Wk" to the beginning of the week number for the entire row? (ex: Wk 1)
'''FORMAT_TIMESTAMP('%m-%d-%Y', CAST( ttl.insert_timestamp AS DATE)) AS Cycle_Time,
EXTRACT(ISOWEEK FROM ttl.insert_timestamp) AS Week,
FROM tableName ttl'''
You might be looking for
CONCAT("Wk ", CAST(EXTRACT(ISOWEEK FROM ttl.insert_timestamp) AS STRING)) AS Week
Related
I am using standard SQL and am trying to add the weekly sum for product usage by week.
Using code below, I was able to add to each row the respective week and year it falls into. How would I go about summing the totals for an item by week and outputting it in columns, say up to the last 8 weeks.
extract(week from Metrics_Date) as week, EXTRACT(YEAR FROM Metrics_Date) AS year
Image is my raw data with the week and year next to an item:
This image is of above raw data being analyzed further(grouping them together). Here is where I would want to add columns, current_week & firstday of week date, and a sum of that weeks totals.
Any help would be appreciated.
You don't need the extract() by the way, you can do truncation DATE_TRUNC(your_date, WEEK) and it will truncate it to the week, usually easier.
Also, because the result of the truncation is a date, you will have the first day of the week already.
The rest I believe you have it figured out already, but just in case:
SELECT DATE_TRUNC(your_date_field, WEEK) AS week, SUM(message_count) AS total_messages FROM your_table GROUP BY 1
I have a series of email engagement dates, to create dashboard on QLIK. It has SQL Editor
I want to group a series of dates as Week 1, Week 2, and so on. My table has date column.
I am thinking along the lines for insert a column named "Week Number", based on the oldest date in the table, add 7 days range as week 1 and next 7 days range as Week 2 and so on.
In Qlik you can use the weekstart(Date) function or the week(Date) for just a week number. Either inthe script or as a calculated dimension in the chart.
Extra credit for year(Date)&'-'&week(Date) for 2019-23 etc
You can use datepart(wk, date_column) for grouping by week. You may want to add datepart(yy, date_column) to group by year and week.
You need to know the first day in your table was which day of the week, and then use the following script in SQL Server
declare #FirstDayOfTableWeekDay int = 2
SELECT CEILING( (CAST(ROW_NUMBER() OVER(ORDER BY [Date] ASC) AS float)+ CAST(#FirstDayOfTableWeekDay AS float)-1) / 7) AS WeekNumber
FROM YourTable
SELECT strftime('%W', 'Week'), sum(income) FROM tableOne GROUP BY Week;
Format for date is a simple date: YYYY-MM-DD
PROBLEM: When run no value for the Week column is provided. Any suggestions?
There is data in the table and when the query is run the income is summarized by the date in the week column. Thing is, this column contains a date that may be any day of the week and often multiple different days of the same week. I need to summarize the income by week.
In SQL, 'Week' is a string containing four characters.
To reference the value in a column named "Week", remove the quotes: Week.
I need to run a weekly report based on the arrival date. How can I set the arrival date in the where clause so that I can get the result only for each week. The hard part is I DO NOT want to modify the dates each week. I need the permanent where clause for the date. I have to provide a list of customers who arrived every week and I just want to run the same script without changing the week dates.
Please assist.
Thanks.
SELECT * FROM TABLE WHERE
(ARRIVAL_DATE>DATEFROMPARTS(YEAR(GETDATE()-7), MONTH(GETDATE()-7), DAY(GETDATE()-7)))//7 days before starting at midnight
AND
(ARRIVAL_DATE<DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), DAY(GETDATE()))) //NOW in the YYYY, MM,DD format
This will get everything that happened in the current calendar week (Mon-Sun)
SELECT * FROM Table1
WHERE ArrivalDate BETWEEN
CAST(DATEADD(dd,(((DATEPART(dw,getdate())+##DATEFIRST) % 7)+5) % 7 ,getdate()) as date) AND
CAST(DATEADD(dd,6+((((DATEPART(dw,getdate())+##DATEFIRST) % 7)+5) % 7 ),getdate()) as date)
Edit - Removed extra E in BETWEEN
I need to show distinct users per week. I have a date-visit column, and a user id, it is a big table with 1 billion rows.
I can change the date column from the CSVs to year,month, day columns. but how do I deduce the week from that in the query.
I can calculate the week from the CSV, but this is a big process step.
I also need to show how many distinct users visit day after day, looking for workaround as there is no date type.
any ideas?
To get the week of year number:
SELECT STRFTIME_UTC_USEC(TIMESTAMP('2015-5-19'), '%W')
20
If you have your date as a timestamp (i.e microseconds since the epoch) you can use the UTC_USEC_TO_DAY/UTC_USEC_TO_WEEK functions. Alternately, if you have an iso-formatted date string (e.g. "2012/03/13 19:00:06 -0700") you can call PARSE_UTC_USEC to turn the string into a timestamp and then use that to get the week or day.
To see an example, try:
SELECT LEFT((format_utc_usec(day)),10) as day, cnt
FROM (
SELECT day, count(*) as cnt
FROM (
SELECT UTC_USEC_TO_DAY(PARSE_UTC_USEC(created_at)) as day
FROM [publicdata:samples.github_timeline])
GROUP BY day
ORDER BY cnt DESC)
To show week, just change UTC_USEC_TO_DAY(...) to UTC_USEC_TO_WEEK(..., 0) (the 0 at the end is to indicate the week starts on Sunday). See the documentation for the above functions at https://developers.google.com/bigquery/docs/query-reference for more information.