I need to run a weekly report based on the arrival date. How can I set the arrival date in the where clause so that I can get the result only for each week. The hard part is I DO NOT want to modify the dates each week. I need the permanent where clause for the date. I have to provide a list of customers who arrived every week and I just want to run the same script without changing the week dates.
Please assist.
Thanks.
SELECT * FROM TABLE WHERE
(ARRIVAL_DATE>DATEFROMPARTS(YEAR(GETDATE()-7), MONTH(GETDATE()-7), DAY(GETDATE()-7)))//7 days before starting at midnight
AND
(ARRIVAL_DATE<DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), DAY(GETDATE()))) //NOW in the YYYY, MM,DD format
This will get everything that happened in the current calendar week (Mon-Sun)
SELECT * FROM Table1
WHERE ArrivalDate BETWEEN
CAST(DATEADD(dd,(((DATEPART(dw,getdate())+##DATEFIRST) % 7)+5) % 7 ,getdate()) as date) AND
CAST(DATEADD(dd,6+((((DATEPART(dw,getdate())+##DATEFIRST) % 7)+5) % 7 ),getdate()) as date)
Edit - Removed extra E in BETWEEN
Related
I have a below query that I run to extract material movements from the last 7 days.
Purpose is to get the data for the last calender week for certain reports.
select
*
From
redshift
where
posting_date between CURRENT_DATE - 7 and CURRENT_DATE - 1
That means I need to run the query on every Monday to get the data for the former week.
Sometimes I am too busy on Monday or its vacation/bank holiday. In that case I would need to change the query or pull the data via SAP.
Question:
Is there a function for redshift that pulls out the data for the last calender week regardless when I run the query?
I already found following solution
SELECT id FROM table1
WHERE YEARWEEK(date) = YEARWEEK(NOW() - INTERVAL 1 WEEK)
But this doesnt seem to be working for redshift sql
Thanks a lot for your help.
Redshift offers a DATE_TRUNC('week', datestamp) function. Given any datestamp value, either a date or datetime, it gives back the date of the preceding Sunday.
So this might work for you. It filters rows from the Sunday before last, up until but not including, the last Sunday, and so gets a full week.
SELECT id
FROM table1
WHERE date >= DATE_TRUNC('week', NOW()) - INTERVAL 1 WEEK
AND date < DATE_TRUNC('week', NOW())
Pro tip: Every minute you spend learning your DBMS's date/time functions will save you an hour in programming.
I'm looking to create a recurring date calculator that will correspond to EVENTS on a specific calendar date. Each event has its own rule.
For example, for EVENT A rule is "Occurs Tuesday monthly with the start date Tuesday 9-17-2019. I'm using a time dimension table with every date populated until 2025. Using these dates I was using in the WHERE clause
WHERE dayname = 'tuesday' and ( DATEDIFF(DAY, '2019-09-17', Calendar_Date) % 28 ) = 0 to get monthly tuesdays.
But I'm running into issues when there are two 5 Tuesdays in a month. 3-3-2020 and 3-31-2020. Need date populated to be 4-7-2020 instead of 3-31-2020.
Can anyone help with a solution?
With your query, you're pretty close. All you need to do is to then sub-select
SELECT MIN(CalendarDate) AS CalendarDate
FROM (your query goes here) AS d
GROUP BY YEAR(CalendarDate), MONTH(CalendarDate);
I know this one is pretty easy but I've always had a nightmare when it comes to comparing dates in SQL please can someone help me out with this, thanks.
I need to get the month and year of now then compare it to a date stored in a DB.
Time Format in the DB:
2015-08-17 11:10:14.000
I need to compare the month and year with now and if its > 12 months old I will increment a count. I just need the number of rows where this argument is true.
I assume you have a datetime field.
You can use the DATEDIFF function, which takes the kind of "crossed boundaries", the start date and the end date.
Your boundary is the month because you are only interested in year and month, not days, so you can use the month macro.
Your start time is the value stored in the table's row.
Your end time is now. You can get system time selecting SYSDATETIME function.
So, assuming your table is called mtable and the datetime object is stored in its date field, you simply have to query:
SELECT COUNT(*) FROM mtable where DATEDIFF(month, mtable.date, (SELECT SYSDATETIME())) > 12
I am new to hive and sql.
Is there any way if we run a query today with count fields then it should fetch last 7 days data ( example- if i run a query with count fields on monday then I should get the total count from last week monday to sunday) And date in my table is in the format 20150910. (yyyyMMdd).
Kindly please help me on this.
You can use date_sub() in this case. Something like this should work...
select * from table
where date_field >= date_sub(current_date, 7)
assuming that the current day's data is not loaded yet. If you want to exclude the current day's data too, you will have to include that too in the filter condition
and date_field <= date_sub(current_date, 1)
current_date would work if your hive version > 0.12
else, you can explicitly pull the date from unix using to_date(from_unixtime(unix_timestamp()))
In SQL Server, trying to write a age-off report for inventory purposes. Each week, the inventory system marks thousands of rows for deletion. This takes place on Sundays # 06:00:00 as part of weekly SQL DB purge schedule.
Using (yyyy-mm-dd hh:mm:ss:ms) format for closed_time, how can I calculate the numbers of days between that date, until next Sunday of the current week? And to be more elaborate, is there a way to narrow it down to the exact DD:HH:MM? The problem is the each client's Sunday DB schedule for purge varies. So that might be difficult to compute. Might be easier to just calculate whole days until Sunday 00:00:00. I tried using the DATEDIFF function with no success.
SELECT
Yada
DATEDIFF(DAY, closed_time,DW) AS Days_Until_Purged
FROM DB1
WHERE closed_time DESC
Thx in advance
If you choose any Sunday in the past (Such as 06:00 Sunday 2nd January 2000), you can calculate time that has GONE BY since then.
Then, if you take that and do modulo 7-days you get the time that has gone by since the most recent Sunday.
Then, if you do 7 - time_gone_by_since_last_sunday you get the time until the next sunday.
I'm going to do this in minutes to cope with a client that has a setting of 06:30.
DECLARE
#batch_processing_time SMALLDATETIME
SET
#batch_processing_time = '2000-01-02 06:00'
SELECT
(60*24*7) - DATEDIFF(minute, #batch_processing_time, closed_time) % (60*24*7)
FROM
yourTable
That's the number of minutes from each record's closed_time until the next #batch_processing_time.
Divide by (24*60) to get it in days.
try this:
select 8-DATEpart(w, closed_time) AS Days_Until_Purged from DB1 ...
This should solve your problem
SET DATEFIRST 1
Select DATEDIFF(dd,GETDATE(),DATEADD(DAY , 7-DATEPART(WEEKDAY,GETDATE()),GETDATE()))