I have a Varchar column which have data such as 1.025407162E7, 1.268479084E7 basically it contains something called as E7. How can i convert it to decimal ?
I have tried to convert it to decimal, I could have removed the E7 and moved the decimal point 7 steps forward or Add 7 zeros if there are no so many numbers. But I was looking for a right approach to do it.
CONVERT(DECIMAL(27, 7), ETL_AM.BNK_SHR_LGR_BAL_AMT)
So the actual values look different
1.025407162E7 = 10254071.6200000 and 1.268479084E7 = 12684790.8400000
That's a valid float constant for SQL Server. So convert the string to a float, and then to a decimal.
CONVERT(DECIMAL(27, 7), cast(ETL_AM.BNK_SHR_LGR_BAL_AMT as float))
eg
select convert(decimal(27,7), cast( '1.025407162E7' as float) )
returns
10254071.6200000
Okay, So Error_2646 has taken me in right direction. I converted the value to REAL then converted to decimal.
CASE WHEN SF_FAM.FinServ__Balance__c like '%E%' THEN CONVERT(DECIMAL(27, 7), CONVERT(float(27), SF_FAM.FinServ__Balance__c))
ELSE CONVERT(DECIMAL(27, 7), SF_FAM.FinServ__Balance__c) END
If it is an exponential function, a simple select, after converting it to a float can give you the decimal.
SELECT CAST('1.025407162E7' AS FLOAT)
Otherwise, if E is a random character and if you want to do the calculatoin, you can do it using a case statement.
DECLARE #value VARCHAR(100)
SET #value = '1.025407162E7'
SELECT CASE WHEN #value like '%E7%'
THEN (1.025407162 * 10000000)
END
I am having the below query.
declare
#a NUMERIC(20,4)
set #a=24900*0.3333333333
select #a
I am expecting 8299.999999 but it gives 8300.00. Can some body help me on this?
Your result is rounded as you have only 4 decimals at your disposal. Use
set #a = round(24900*0.3333333333, 4, 1)
This will not round but truncate the result.
I do not know if that is what you want, because a value like 0.12346 will be truncated to 0.1234 and not rounded to 0.1235.
you may want this or something like this:
declare #a NUMERIC(20,6)
set #a=cast(24900 as numeric(20,6))*cast(0.3333333333 as numeric(20,10))
select #a
I have the following query that gives a rounded result. How can I modify this to
Stop rounding
Display to 2 decimal places. E.g 3.456 -> 3.45
SELECT SUM(Invoice_Details.Amount) AS TotalNet_C FROM Invoice_Details WHERE Invoice_Details.Invoice_Number = ||InvNo||
To format it to 2 digits you can e.g. convert it to currency.
SELECT CAST(SUM(Invoice_Details.Amount) AS money) AS TotalNet_C
FROM Invoice_Details
WHERE Invoice_Details.Invoice_Number = ||InvNo||
For be more specific you can use CONVERT.
Check this for details: http://msdn.microsoft.com/de-de/library/ms187928.aspx
About rounding: You want to crop the digits, not round them:
SELECT CAST(CAST(3.456 * 100 AS int) as float)/100
This will do it. Your case then
SELECT CAST(CAST(CAST(SUM(Invoice_Details.Amount) * 100 AS int) as float)/100 AS money) AS TotalNet_C
FROM Invoice_Details
WHERE Invoice_Details.Invoice_Number = ||InvNo||
you can simply do this for rounding your value
Str(ColumnName, 10, 2)
10-- this is for total length of your value.
2-- this is for how many decimal you want
declare #Num decimal(6,3)
set #Num = 3.456
select LEFT(round(#Num, 2, 1),4)
OR
select CAST(round(#Num, 2, 1)AS MONEY)
I think u should to convert value before sum_function and u can use parameters of the numeric/decimal, just like this:
select SUM(TRY_CONVERT(decimal(18,2), value) from TestTable ...
I am getting result as decimal in stored procedure. If I am getting result as 123.45,
I want to split it into 123 and 45. Can anybody help?
use SQL function FLOOR() for getting integer part
and subtract that from the original for the decimal part
You can also make use of ROUND instead of FLOOR.
See section C. Using ROUND to truncate for trucate, and then subtract that from the original.
Be aware that using FLOOR on negative numbers might not give you the required result.
Have a look at this example
DECLARE #Dec DECIMAL(12,8)
SET #Dec = -123.45
SELECT FLOOR(#DEc)
select round(#Dec, 0, 1)
try this;
DECLARE #result DECIMAL(8,2) = 123.45
SELECT CAST(round(#result,0) AS FLOAT)
SELECT REPLACE(#result % 1 ,'0.','')
OR
DECLARE #result decimal(8,2) = 123.45
select PARSENAME(#result, 2) AS LeftSideValue, PARSENAME(#result, 1) AS RightSideValue
I'm trying to determine the best way to truncate or drop extra decimal places in SQL without rounding. For example:
declare #value decimal(18,2)
set #value = 123.456
This will automatically round #value to be 123.46, which is good in most cases. However, for this project, I don't need that. Is there a simple way to truncate the decimals I don't need? I know I can use the left() function and convert back to a decimal. Are there any other ways?
ROUND ( 123.456 , 2 , 1 )
When the third parameter != 0 it truncates rather than rounds.
Syntax
ROUND ( numeric_expression , length [ ,function ] )
Arguments
numeric_expression
Is an expression of the exact numeric or approximate numeric data
type category, except for the bit data type.
length
Is the precision to which numeric_expression is to be rounded. length must be an expression of type tinyint, smallint, or int. When length is a positive number, numeric_expression is rounded to the number of decimal positions specified by length. When length is a negative number, numeric_expression is rounded on the left side of the decimal point, as specified by length.
function
Is the type of operation to perform. function must be tinyint, smallint, or int. When function is omitted or has a value of 0 (default), numeric_expression is rounded. When a value other than 0 is specified, numeric_expression is truncated.
select round(123.456, 2, 1)
SELECT Cast(Round(123.456,2,1) as decimal(18,2))
Here's the way I was able to truncate and not round:
select 100.0019-(100.0019%.001)
returns 100.0010
And your example:
select 123.456-(123.456%.001)
returns 123.450
Now if you want to get rid of the ending zero, simply cast it:
select cast((123.456-(123.456%.001)) as decimal (18,2))
returns 123.45
Actually whatever the third parameter is, 0 or 1 or 2, it will not round your value.
CAST(ROUND(10.0055,2,0) AS NUMERIC(10,2))
Do you want the decimal or not?
If not, use
select ceiling(#value),floor(#value)
If you do it with 0 then do a round:
select round(#value,2)
Another truncate with no rounding solution and example.
Convert 71.950005666 to a single decimal place number (71.9)
1) 71.950005666 * 10.0 = 719.50005666
2) Floor(719.50005666) = 719.0
3) 719.0 / 10.0 = 71.9
select Floor(71.950005666 * 10.0) / 10.0
Round has an optional parameter
Select round(123.456, 2, 1) will = 123.45
Select round(123.456, 2, 0) will = 123.46
ROUND(number, decimals, operation)
number => Required. The number to be rounded
decimals => Required. The number of decimal places to round number to
operation => Optional. If 0, it rounds the result to the number of decimal. If another value than 0, it truncates the result to the number of decimals. Default value is 0
SELECT ROUND(235.415, 2, 1)
will give you 235.410
SELECT ROUND(235.415, 0, 1)
will give you 235.000
But now trimming0 you can use cast
SELECT CAST(ROUND(235.415, 0, 1) AS INT)
will give you 235
This will remove the decimal part of any number
SELECT ROUND(#val,0,1)
SELECT CAST(Value as Decimal(10,2)) FROM TABLE_NAME;
Would give you 2 values after the decimal point. (MS SQL SERVER)
Another way is ODBC TRUNCATE function:
DECLARE #value DECIMAL(18,3) =123.456;
SELECT #value AS val, {fn TRUNCATE(#value, 2)} AS result
LiveDemo
Output:
╔═════════╦═════════╗
║ val ║ result ║
╠═════════╬═════════╣
║ 123,456 ║ 123,450 ║
╚═════════╩═════════╝
Remark:
I recommend using built-in ROUND function with 3rd parameter set to 1.
I know this is pretty late but I don't see it as an answer and have been using this trick for years.
Simply subtract .005 from your value and use Round(#num,2).
Your example:
declare #num decimal(9,5) = 123.456
select round(#num-.005,2)
returns 123.45
It will automatically adjust the rounding to the correct value you are looking for.
By the way, are you recreating the program from the movie Office Space?
Try like this:
SELECT cast(round(123.456,2,1) as decimal(18,2))
If you desire to take some number like 89.0904987 and turn it into 89.09 by simply omitting the undesired decimal places, simply use the following:
select cast(yourColumnName as decimal(18,2))
The following screenshot is from W3Schools SQL Data Types section, which describes what decimal(18,2) is doing:
Therefore,
select cast(89.0904987 as decimal(18,2))
gives you: 89.09
Please try to use this code for converting 3 decimal values after a point into 2 decimal places:
declare #val decimal (8, 2)
select #val = 123.456
select #val = #val
select #val
The output is 123.46
I think you want only the decimal value,
in this case you can use the following:
declare #val decimal (8, 3)
SET #val = 123.456
SELECT #val - ROUND(#val,0,1)
I know this question is really old but nobody used sub-strings to round. This as advantage the ability to round really long numbers (limit of your string in SQL server which is usually 8000 characters):
SUBSTRING('123.456', 1, CHARINDEX('.', '123.456') + 2)
I think we can go much easier with simpler example solution found in Hackerrank:
Problem statement: Query the greatest value of the Northern Latitudes
(LAT_N) from STATION that is less than 137.2345. Truncate your answer
to 4 decimal places.
SELECT TRUNCATE(MAX(LAT_N),4)
FROM STATION
WHERE LAT_N < 137.23453;
Solution Above gives you idea how to simply make value limited to 4 decimal points. If you want to lower or upper the numbers after decimal, just change 4 to whatever you want.
Mod(x,1) is the easiest way I think.
select convert(int,#value)