How to extract attribute value from XML in SQL Server 2019 (v15)? - sql

Question

I would need to extract elements from this XML into a tabular form, but I can't seem to get my head around how this would work on SQL Server via something like XQuery.
I have all the data in a temporary table called "#1" and the XML itself lies in a field called "Message" in that temporary table. How can I extract the values "Test1" and "2,2 %" into separate fields called "W08003" and "W1A081", respectively? The attribute names and the schema will remain the same over time? I would also need to do this on a row by row basis for each XML in the current temporary table.
<Individual xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Content>
<status xmlns:d3p1="http://www.uc.se/schemas/ucOrderReply/" xmlns="http://www.uc.se/schemas/ucOrderReply/" d3p1:result="ok" />
<uc xmlns="http://www.uc.se/schemas/ucOrderReply/">
<xmlReply>
<reports xmlns:d5p1="http://www.uc.se/schemas/ucOrderReply/" d5p1:lang="eng">
<d5p1:report d5p1:id="7605089247" d5p1:name="Test1 Test2" d5p1:styp="K39" d5p1:index="0">
<d5p1:group d5p1:id="W080" d5p1:index="0" d5p1:key="" d5p1:name="ID particulars">
<d5p1:term d5p1:id="W08001">9760508923</d5p1:term>
<d5p1:term d5p1:id="W08002">7605089277</d5p1:term>
<d5p1:term d5p1:id="W08003">Test1</d5p1:term>
<d5p1:term d5p1:id="W08004">Test2</d5p1:term>
</d5p1:group>
<d5p1:group d5p1:id="W1A0" d5p1:index="0" d5p1:key="" d5p1:name="UC RPB">
<d5p1:term d5p1:id="W1A003">000000000000000022</d5p1:term>
<d5p1:term d5p1:id="W1A081">2,2 %</d5p1:term>
<d5p1:term d5p1:id="W1A082">2,18839</d5p1:term>
</d5p1:group>
</d5p1:report>
</reports>
</xmlReply>
</uc>
</Content>
</Individual>
Current SQL code:
WITH XMLNAMESPACES('http://www.uc.se/schemas/ucOrderReply/' AS ns,'http://www.uc.se/schemas/ucOrderReply/' AS d5p1)
SELECT ok.*
,X.g.value('(#d5p1:id)','varchar(20)') AS id
,X.g.value('(text())[1]','varchar(20)') AS term
into #2
FROM #1 as ok
CROSS APPLY(ok.[Message].nodes('Individual/Content/ns:uc/ns:xmlReply/ns:reports/ns:report/ns:group/ns:term') X(g)

Answer 1

With no expected results, perhaps this is enough to get you started.
As you define a default namespace only once you get to status, you can't use a DEFAULT namespace in XMLNAMESPACES, so I name it ns and reference that instead. This gives you the value of all the terms and their id attribute:
DECLARE #XML xml = '<Individual xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Content>
<status xmlns:d3p1="http://www.uc.se/schemas/ucOrderReply/" xmlns="http://www.uc.se/schemas/ucOrderReply/" d3p1:result="ok" />
<uc xmlns="http://www.uc.se/schemas/ucOrderReply/">
<xmlReply>
<reports xmlns:d5p1="http://www.uc.se/schemas/ucOrderReply/" d5p1:lang="eng">
<report d5p1:id="7605089247" d5p1:name="Test1 Test2" d5p1:styp="K39" d5p1:index="0">
<group d5p1:id="W080" d5p1:index="0" d5p1:key="" d5p1:name="ID particulars">
<term d5p1:id="W08001">9760508923</term>
<term d5p1:id="W08002">7605089277</term>
<term d5p1:id="W08003">Test1</term>
<term d5p1:id="W08004">Test2</term>
</group>
<group d5p1:id="W1A0" d5p1:index="0" d5p1:key="" d5p1:name="UC RPB">
<term d5p1:id="W1A003">000000000000000022</term>
<term d5p1:id="W1A081">2,2 %</term>
<term d5p1:id="W1A082">2,18839</term>
</group>
</report>
</reports>
</xmlReply>
</uc>
</Content>
</Individual>';
WITH XMLNAMESPACES('http://www.uc.se/schemas/ucOrderReply/' AS ns,'http://www.uc.se/schemas/ucOrderReply/' AS d5p1)
SELECT X.g.value('(#d5p1:id)','varchar(20)') AS id,
X.g.value('(text())[1]','varchar(20)') AS term
FROM #XML.nodes('Individual/Content/ns:uc/ns:xmlReply/ns:reports/ns:report/ns:group/ns:term') X(g);
I note that the XML has been changed since the initial version I used to write this answer. This answer has not been (read "won't be") adjusted for that.