Related
Let's say I am returning the following table from a select
CaseId
DocId
DocumentTypeId
DocumentType
ExpirationDate
1
1
1
I797
01/02/23
1
2
2
I94
01/02/23
1
3
3
Some Other Value
01/02/23
I want to select ONLY the row with DocumentType = 'I797', then if there is no 'I797', I want to select ONLY the row where DocumentType = 'I94'; failing to find either of those two I want to take all rows with any other value of DocumentType.
Using SQL Server ideally.
I think I'm looking for an XOR clause but can't work out how to do that in SQL Server or to get all other values.
Similar to #siggemannen answer
select top 1 with ties
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end gr
,docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Shortest:
select top 1 with ties
docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Something like this perhaps:
select *
from (
select t.*, DENSE_RANK() OVER(ORDER BY CASE WHEN DocumentType = 'I797' THEN 0 WHEN DocumentType = 'I94' THEN 1 ELSE 2 END) AS prioorder
from
(
VALUES
(1, 1, 1, N'I797', N'01/02/23')
, (1, 2, 2, N'I94', N'01/02/23')
, (1, 3, 3, N'Some Other Value', N'01/02/23')
, (1, 4, 3, N'Super Sekret', N'01/02/23')
) t (CaseId,DocId,DocumentTypeId,DocumentType,ExpirationDate)
) x
WHERE x.prioorder = 1
The idea is to rank rows by 1, 2, 3 depending on document type. Since we rank "the rest" the same, you will get all rows if I797 and I94 is missing.
select * from YourTable where DocumentType = 'I797'
union
select * from YourTable t where DocumentType = 'I94' and (not exists (select * from YourTable where DocumentType = 'I797'))
union
select * from YourTable t where (not exists (select * from YourTable where DocumentType = 'I797' or DocumentType = 'I94' ))
Given a table representing a many-many join between IDs like the following:
WITH t AS (
SELECT 1 AS id_1, 'a' AS id_2,
UNION ALL SELECT 2, 'a'
UNION ALL SELECT 2, 'b'
UNION ALL SELECT 3, 'b'
UNION ALL SELECT 4, 'c'
UNION ALL SELECT 5, 'c'
UNION ALL SELECT 6, 'd'
UNION ALL SELECT 6, 'e'
UNION ALL SELECT 7, 'f'
)
SELECT * FROM t
id_1
id_2
1
a
2
a
2
b
3
b
4
c
5
c
6
d
6
e
7
f
I would like to be able recursively join then aggregate rows in order to find each disconnected sub-graph represented by these links - that is each collection of IDs that are linked together:
The desired output for the example above would look something like this:
id_1_coll
id_2_coll
1, 2, 3
a, b
4, 5
c
6
d, e
7
f
where each row contains all the other IDs one could reach following the links in the table.
Note that 1 links to b even although there is no explicit link row because we can follow the path 1 --> a --> 2 --> b using the links in the first 3 rows.
One potential approach is to remodel the relationships between id_1 and id_2 such that we get all the links from id_1 to itself then use a recursive common table expression to traverse all the possible paths between id_1 values then aggregate (somewhat arbitrarily) to the lowest such value that can be reached from each id_1.
Explanation
Our steps are
Remodel the relationship into a series of self-joins for id_1
Map each id_1 to the lowest id_1 that it is linked to via a recursive CTE
Aggregate the recursive CTE using the lowest id_1s as the GROUP BY column and grabbing all the linked id_1 and id_2 values via the ARRAY_AGG() function
We can use something like this to remodel the relationships into a self join (1.):
SELECT
a.id_1, a.id_2, b.id_1 AS linked_id
FROM t as a
INNER JOIN t as b
ON a.id_2 = b.id_2
WHERE a.id_1 != b.id_1
Next - to set up the recursive table expression (2.) we can tweak the query above to also give us the lowest (LEAST) of the values for id_1 at each link then use this as the base iteration:
WITH RECURSIVE base_iter AS (
SELECT
a.id_1, b.id_1 AS linked_id, LEAST(a.id_1, b.id_1) AS lowest_linked_id
FROM t as a
INNER JOIN t as b
ON a.id_2 = b.id_2
WHERE a.id_1 != b.id_1
)
We can also grab the lowest id_1 value at this time:
id_1
linked_id
lowest_linked_id
1
2
1
2
1
1
2
3
2
3
2
2
4
5
4
5
4
4
For our recursive loop, we want to maintain an ARRAY of linked ids and join each new iteration such that the id_1 value of the n+1th iteration is equal to the linked_id value of the nth iteration AND the nth linked_id value is not in the array of previously linked ids.
We can code this as follows:
recursive_loop AS (
SELECT id_1, linked_id, lowest_linked_id, [linked_id ] AS linked_ids
FROM base_iter
UNION ALL
SELECT
prev_iter.id_1, prev_iter.linked_id,
iter.lowest_linked_id,
ARRAY_CONCAT(iter.linked_ids, [prev_iter.linked_id])
FROM base_iter AS prev_iter
JOIN recursive_loop AS iter
ON iter.id_1 = prev_iter.linked_id
AND iter.lowest_linked_id < prev_iter.lowest_linked_id
AND prev_iter.linked_id NOT IN UNNEST(iter.linked_ids )
)
Giving us the following results:
|id_1|linked_id|lowest_linked_id|linked_ids|
|----|---------|------------|---|
|3|2|1|[1,2]|
|2|3|1|[1,2,3]|
|4|5|4|[5]|
|1|2|1|[2]|
|5|4|4|[4]|
|2|3|2|[3]|
|2|1|1|[1]|
|3|2|2|[2]|
which we can now link back to the original table for the id_2 values then aggregate (3.) as shown in the complete query below
Solution
WITH RECURSIVE t AS (
SELECT 1 AS id_1, 'a' AS id_2,
UNION ALL SELECT 2, 'a'
UNION ALL SELECT 2, 'b'
UNION ALL SELECT 3, 'b'
UNION ALL SELECT 4, 'c'
UNION ALL SELECT 5, 'c'
UNION ALL SELECT 6, 'd'
UNION ALL SELECT 6, 'e'
UNION ALL SELECT 7, 'f'
),
base_iter AS (
SELECT
a.id_1, b.id_1 AS linked_id, LEAST(a.id_1, b.id_1) AS lowest_linked_id
FROM t as a
INNER JOIN t as b
ON a.id_2 = b.id_2
WHERE a.id_1 != b.id_1
),
recursive_loop AS (
SELECT id_1, linked_id, lowest_linked_id, [linked_id ] AS linked_ids
FROM base_iter
UNION ALL
SELECT
prev_iter.id_1, prev_iter.linked_id,
iter.lowest_linked_id,
ARRAY_CONCAT(iter.linked_ids, [prev_iter.linked_id])
FROM base_iter AS prev_iter
JOIN recursive_loop AS iter
ON iter.id_1 = prev_iter.linked_id
AND iter.lowest_linked_id < prev_iter.lowest_linked_id
AND prev_iter.linked_id NOT IN UNNEST(iter.linked_ids )
),
link_back AS (
SELECT
t.id_1, IFNULL(lowest_linked_id, t.id_1) AS lowest_linked_id, t.id_2
FROM t
LEFT JOIN recursive_loop
ON t.id_1 = recursive_loop.id_1
),
by_id_1 AS (
SELECT
id_1,
MIN(lowest_linked_id) AS grp
FROM link_back
GROUP BY 1
),
by_id_2 AS (
SELECT
id_2,
MIN(lowest_linked_id) AS grp
FROM link_back
GROUP BY 1
),
result AS (
SELECT
by_id_1.grp,
ARRAY_AGG(DISTINCT id_1 ORDER BY id_1) AS id1_coll,
ARRAY_AGG(DISTINCT id_2 ORDER BY id_2) AS id2_coll,
FROM
by_id_1
INNER JOIN by_id_2
ON by_id_1.grp = by_id_2.grp
GROUP BY grp
)
SELECT grp, TO_JSON(id1_coll) AS id1_coll, TO_JSON(id2_coll) AS id2_coll
FROM result ORDER BY grp
Giving us the required output:
grp
id1_coll
id2_coll
1
[1,2,3]
[a,b]
4
[4,5]
[c]
6
[6]
[d,e]
7
[7]
[f]
Limitations/Issues
Unfortunately this approach is inneficient (we have to traverse every single pathway before aggregating it back together) and fails with the real-world case where we have several million join rows. When trying to execute on this data BigQuery runs up a huge "Slot time consumed" then eventually errors out with:
Resources exceeded during query execution: Your project or organization exceeded the maximum disk and memory limit available for shuffle operations. Consider provisioning more slots, reducing query concurrency, or using more efficient logic in this job.
I hope there might be a better way of doing the recursive join such that pathways can be merged/aggregated as we go (if we have an id_1 value AND a linked_id in already in the list of linked_ids we dont need to check it further).
Using ROW_NUMBER() the query is as the follow:
WITH RECURSIVE
t AS (
SELECT 1 AS id_1, 'a' AS id_2,
UNION ALL SELECT 2, 'a'
UNION ALL SELECT 2, 'b'
UNION ALL SELECT 3, 'b'
UNION ALL SELECT 4, 'c'
UNION ALL SELECT 5, 'c'
UNION ALL SELECT 6, 'd'
UNION ALL SELECT 6, 'e'
UNION ALL SELECT 7, 'f'
),
t1 AS (
SELECT ROW_NUMBER() OVER(ORDER BY t.id_1) n, t.id_1, t.id_2 FROM t
),
t2 AS (
SELECT n, [n] n_arr, [id_1] arr_1, [id_2] arr_2, id_1, id_2 FROM t1
WHERE n IN (SELECT MIN(n) FROM t1 GROUP BY id_1)
UNION ALL
SELECT t2.n, ARRAY_CONCAT(t2.n_arr, [t1.n]),
CASE WHEN t1.id_1 NOT IN UNNEST(t2.arr_1)
THEN ARRAY_CONCAT(t2.arr_1, [t1.id_1])
ELSE t2.arr_1 END,
CASE WHEN t1.id_2 NOT IN UNNEST(t2.arr_2)
THEN ARRAY_CONCAT(t2.arr_2, [t1.id_2])
ELSE t2.arr_2 END,
t1.id_1, t1.id_2
FROM t2 JOIN t1 ON
t2.n < t1.n AND
t1.n NOT IN UNNEST(t2.n_arr) AND
(t2.id_1 = t1.id_1 OR t2.id_2 = t1.id_2) AND
(t1.id_1 NOT IN UNNEST(t2.arr_1) OR t1.id_2 NOT IN UNNEST(t2.arr_2))
),
t3 AS (
SELECT
n,
ARRAY_AGG(DISTINCT id_1 ORDER BY id_1) arr_1,
ARRAY_AGG(DISTINCT id_2 ORDER BY id_2) arr_2
FROM t2
WHERE n IN (SELECT MIN(n) FROM t2 GROUP BY id_1)
GROUP BY n
)
SELECT n, TO_JSON(arr_1), TO_JSON(arr_2) FROM t3 ORDER BY n
t1 : Append with row numbers.
t2 : Extract rows matching either id_1 or id_2 by recursive query.
t3 : Make arrays from id_1 and id_2 with ARRAY_AGG().
However, it may not help your Limitations/Issues.
The way this question is phrased makes it appear you want "show me distinct groups from a presorted list, unchained to a previous group". For that, something like this should suffice (assuming auto-incrementing order/one or both id's move to the next value):
SELECT GrpNr,
STRING_AGG(DISTINCT CAST(id_1 as STRING), ',') as id_1_coll,
STRING_AGG(DISTINCT CAST(id_2 as STRING), ',') as id_2_coll
FROM
(
SELECT id_1, id_2,
SUM(CASE WHEN a.id_1 <> a.previous_id_1 and a.id_2 <> a.previous_id_2 THEN 1 ELSE 0 END)
OVER (ORDER BY RowNr) as GrpNr
FROM
(
SELECT *,
ROW_NUMBER() OVER () as RowNr,
LAG(t.id_1, 1) OVER (ORDER BY 1) AS previous_id_1,
LAG(t.id_2, 1) OVER (ORDER BY 1) AS previous_id_2
FROM t
) a
ORDER BY RowNr
) a
GROUP BY GrpNr
ORDER BY GrpNr
I don't think this is the question you mean to ask. This seems to be a graph-walking problem as referenced in the other answers, and in the response from #GordonLinoff to the question here, which I tested (and presume works for BigQuery).
This can also be done using sequential updates as done by #RomanPekar
here (which I also tested). The main consideration seems to be performance. I'd assume dbms have gotten better at recursion since this was posted.
Rolling it up in either case should be fairly easy using String_Agg() as given above or as you have.
I'd be curious to see a more accurate representation of the data. If there is some consistency to how the data is stored/limitations to levels of nesting/other group structures there may be a shortcut approach other than recursion or iterative updates.
I'm creating a report with SQL server 2012 and Report Builder which must show the total number of Risks at a high, medium and low level for each Parent Element.
Each Element contains a number of Risks which are rated at a certain level. I need the total for the Parent Elements. The total will include the number of all the Child Elements and also the number the Element itself may have.
I am using CTEs in my query- the code I have attached isn't working (there are no errors - it's just displaying the incorrect results) and I'm not sure that my logic is correct??
Hopefully someone can help. Thanks in advance.
My table structure is:
ElementTable
ElementTableId(PK) ElementName ElementParentId
RiskTable
RiskId(PK) RiskName RiskRating ElementId(FK)
My query:
WITH cte_Hierarchy(ElementId, ElementName, Generation, ParentElementId)
AS (SELECT ElementId,
NAME,
0,
ParentElementId
FROM Extract.Element AS FirtGeneration
WHERE ParentElementId IS NULL
UNION ALL
SELECT NextGeneration.ElementId,
NextGeneration.NAME,
Parent.Generation + 1,
Parent.ElementId
FROM Extract.Element AS NextGeneration
INNER JOIN cte_Hierarchy AS Parent
ON NextGeneration.ParentElementId = Parent.ElementId),
CTE_HighRisk
AS (SELECT r.ElementId,
Count(r.RiskId) AS HighRisk
FROM Extract.Risk r
WHERE r.RiskRating = 'High'
GROUP BY r.ElementId),
CTE_LowRisk
AS (SELECT r.ElementId,
Count(r.RiskId) AS LowRisk
FROM Extract.Risk r
WHERE r.RiskRating = 'Low'
GROUP BY r.ElementId),
CTE_MedRisk
AS (SELECT r.ElementId,
Count(r.RiskId) AS MedRisk
FROM Extract.Risk r
WHERE r.RiskRating = 'Medium'
GROUP BY r.ElementId)
SELECT rd.ElementId,
rd.ElementName,
rd.ParentElementId,
Generation,
HighRisk,
MedRisk,
LowRisk
FROM cte_Hierarchy rd
LEFT OUTER JOIN CTE_HighRisk h
ON rd.ElementId = h.ElementId
LEFT OUTER JOIN CTE_MedRisk m
ON rd.ElementId = m.ElementId
LEFT OUTER JOIN CTE_LowRisk l
ON rd.ElementId = l.ElementId
WHERE Generation = 1
Edit:
Sample Data
ElementTableId(PK) -- ElementName -- ElementParentId
1 ------------------- Main --------------0
2 --------------------Element1-----------1
3 --------------------Element2 ----------1
4 --------------------SubElement1 -------2
RiskId(PK) RiskName RiskRating ElementId(FK)
a -------- Financial -- High ----- 2
b -------- HR --------- High ----- 3
c -------- Marketing -- Low ------- 2
d -------- Safety -----Medium ----- 4
Sample Output:
Element Name High Medium Low
Main ---------- 2 ---- 1 -------1
Here is your sample tables
SELECT * INTO #TABLE1
FROM
(
SELECT 1 ElementTableId, 'Main' ElementName ,0 ElementParentId
UNION ALL
SELECT 2,'Element1',1
UNION ALL
SELECT 3, 'Element2',1
UNION ALL
SELECT 4, 'SubElement1',2
)TAB
SELECT * INTO #TABLE2
FROM
(
SELECT 'a' RiskId, 'Fincancial' RiskName,'High' RiskRating ,2 ElementId
UNION ALL
SELECT 'b','HR','High',3
UNION ALL
SELECT 'c', 'Marketing','Low',2
UNION ALL
SELECT 'd', 'Safety','Medium',4
)TAB
We are finding the children of a parent, its count of High,Medium and Low and use cross join to show parent with all the combinations of its children's High,Medium and Low
UPDATE
The below variable can be used to access the records dynamically.
DECLARE #ElementTableId INT;
--SET #ElementTableId = 1
And use the above variable inside the query
;WITH CTE1 AS
(
SELECT *,0 [LEVEL] FROM #TABLE1 WHERE ElementTableId = #ElementTableId
UNION ALL
SELECT E.*,e2.[LEVEL]+1 FROM #TABLE1 e
INNER JOIN CTE1 e2 on e.ElementParentId = e2.ElementTableId
AND E.ElementTableId<>#ElementTableId
)
,CTE2 AS
(
SELECT E1.*,E2.*,COUNT(RiskRating) OVER(PARTITION BY RiskRating) CNT
from CTE1 E1
LEFT JOIN #TABLE2 E2 ON E1.ElementTableId=E2.ElementId
)
,CTE3 AS
(
SELECT DISTINCT T1.ElementName,C2.RiskRating,C2.CNT
FROM #TABLE1 T1
CROSS JOIN CTE2 C2
WHERE T1.ElementTableId = #ElementTableId
)
SELECT *
FROM CTE3
PIVOT(MIN(CNT)
FOR RiskRating IN ([High], [Medium],[Low])) AS PVTTable
SQL FIDDLE
RESULT
UPDATE 2
I am updating as per your new requirement
Here is sample table in which I have added extra data to test
SELECT * INTO #ElementTable
FROM
(
SELECT 1 ElementTableId, 'Main' ElementName ,0 ElementParentId
UNION ALL
SELECT 2,'Element1',1
UNION ALL
SELECT 3, 'Element2',1
UNION ALL
SELECT 4, 'SubElement1',2
UNION ALL
SELECT 5, 'Main 2',0
UNION ALL
SELECT 6, 'Element21',5
UNION ALL
SELECT 7, 'SubElement21',6
UNION ALL
SELECT 8, 'SubElement22',7
UNION ALL
SELECT 9, 'SubElement23',7
)TAB
SELECT * INTO #RiskTable
FROM
(
SELECT 'a' RiskId, 'Fincancial' RiskName,'High' RiskRating ,2 ElementId
UNION ALL
SELECT 'b','HR','High',3
UNION ALL
SELECT 'c', 'Marketing','Low',2
UNION ALL
SELECT 'd', 'Safety','Medium',4
UNION ALL
SELECT 'e' , 'Fincancial' ,'High' ,5
UNION ALL
SELECT 'f','HR','High',6
UNION ALL
SELECT 'g','HR','High',6
UNION ALL
SELECT 'h', 'Marketing','Low',7
UNION ALL
SELECT 'i', 'Safety','Medium',8
UNION ALL
SELECT 'j', 'Safety','High',8
)TAB
I have written the logic in query
;WITH CTE1 AS
(
-- Here you will find the level of every elements in the table
SELECT *,0 [LEVEL]
FROM #ElementTable WHERE ElementParentId = 0
UNION ALL
SELECT ET.*,CTE1.[LEVEL]+1
FROM #ElementTable ET
INNER JOIN CTE1 on ET.ElementParentId = CTE1.ElementTableId
)
,CTE2 AS
(
-- Filters the level and find the major parant of each child
-- ie, 100->150->200, here the main parent of 200 is 100
SELECT *,CTE1.ElementTableId MajorParentID,CTE1.ElementName MajorParentName
FROM CTE1 WHERE [LEVEL]=1
UNION ALL
SELECT CTE1.*,CTE2.MajorParentID,CTE2.MajorParentName
FROM CTE1
INNER JOIN CTE2 on CTE1.ElementParentId = CTE2.ElementTableId
)
,CTE3 AS
(
-- Since each child have columns for main parent id and name,
-- you will get the count of each element corresponding to the level you have selected directly
SELECT DISTINCT CTE2.MajorParentName,RT.RiskRating ,
COUNT(RiskRating) OVER(PARTITION BY MajorParentID,RiskRating) CNT
FROM CTE2
JOIN #RiskTable RT ON CTE2.ElementTableId=RT.ElementId
)
SELECT MajorParentName, ISNULL([High],0)[High], ISNULL([Medium],0)[Medium],ISNULL([Low],0)[Low]
FROM CTE3
PIVOT(MIN(CNT)
FOR RiskRating IN ([High], [Medium],[Low])) AS PVTTable
SQL FIDDLE
Suppose I have a list of values, such as 1, 2, 3, 4, 5 and a table where some of those values exist in some column. Here is an example:
id name
1 Alice
3 Cindy
5 Elmore
6 Felix
I want to create a SELECT statement that will include all of the values from my list as well as the information from those rows that match the values, i.e., perform a LEFT OUTER JOIN between my list and the table, so the result would be like follows:
id name
1 Alice
2 (null)
3 Cindy
4 (null)
5 Elmore
How do I do that without creating a temp table or using multiple UNION operators?
If in Microsoft SQL Server 2008 or later, then you can use Table Value Constructor
Select v.valueId, m.name
From (values (1), (2), (3), (4), (5)) v(valueId)
left Join otherTable m
on m.id = v.valueId
Postgres also has this construction VALUES Lists:
SELECT * FROM (VALUES (1, 'one'), (2, 'two'), (3, 'three')) AS t (num,letter)
Also note the possible Common Table Expression syntax which can be handy to make joins:
WITH my_values(num, str) AS (
VALUES (1, 'one'), (2, 'two'), (3, 'three')
)
SELECT num, txt FROM my_values
With Oracle it's possible, though heavier From ASK TOM:
with id_list as (
select 10 id from dual union all
select 20 id from dual union all
select 25 id from dual union all
select 70 id from dual union all
select 90 id from dual
)
select * from id_list;
the following solution for oracle is adopted from this source. the basic idea is to exploit oracle's hierarchical queries. you have to specify a maximum length of the list (100 in the sample query below).
select d.lstid
, t.name
from (
select substr(
csv
, instr(csv,',',1,lev) + 1
, instr(csv,',',1,lev+1 )-instr(csv,',',1,lev)-1
) lstid
from (select ','||'1,2,3,4,5'||',' csv from dual)
, (select level lev from dual connect by level <= 100)
where lev <= length(csv)-length(replace(csv,','))-1
) d
left join test t on ( d.lstid = t.id )
;
check out this sql fiddle to see it work.
Bit late on this, but for Oracle you could do something like this to get a table of values:
SELECT rownum + 5 /*start*/ - 1 as myval
FROM dual
CONNECT BY LEVEL <= 100 /*end*/ - 5 /*start*/ + 1
... And then join that to your table:
SELECT *
FROM
(SELECT rownum + 1 /*start*/ - 1 myval
FROM dual
CONNECT BY LEVEL <= 5 /*end*/ - 1 /*start*/ + 1) mypseudotable
left outer join myothertable
on mypseudotable.myval = myothertable.correspondingval
Assuming myTable is the name of your table, following code should work.
;with x as
(
select top (select max(id) from [myTable]) number from [master]..spt_values
),
y as
(select row_number() over (order by x.number) as id
from x)
select y.id, t.name
from y left join myTable as t
on y.id = t.id;
Caution: This is SQL Server implementation.
fiddle
For getting sequential numbers as required for part of output (This method eliminates values to type for n numbers):
declare #site as int
set #site = 1
while #site<=200
begin
insert into ##table
values (#site)
set #site=#site+1
end
Final output[post above step]:
select * from ##table
select v.id,m.name from ##table as v
left outer join [source_table] m
on m.id=v.id
Suppose your table that has values 1,2,3,4,5 is named list_of_values, and suppose the table that contain some values but has the name column as some_values, you can do:
SELECT B.id,A.name
FROM [list_of_values] AS B
LEFT JOIN [some_values] AS A
ON B.ID = A.ID
I have a product table with 15 fields like ItemID (primary),Name ,UPC,Price,Cost, etc.
Now I need to print labels the user can say
from Item "ABC" I need 15 labels
from item 'XYZ" I need 10 labels
I need a SQL statement which I will send the ItemID and the label Qty for Each record and it should give me back for each label a record for example 15 records for item "ABC" and 10 records for Item "XYZ" and so on
SELECT <fields>
FROM Mytable
Where Item = 'ABC'
GO 10
Will select those fields from that table 10 times in a row in 10 result sets.
Really though it sounds like you need to do what you are trying to do not in SQL, but in your calling application.
I agree this should be done on the client but if you insist, following duplicates each record 100 times and selects the amount you need from it.
;WITH ATable AS (
SELECT Item = 'ABC'
UNION ALL SELECT Item = 'XYZ'
)
, Temp (Item, Amount) AS (
SELECT 'ABC', 15
UNION ALL SELECT 'XYZ', 10
)
, q AS (
SELECT ID = 1
, Item
FROM ATable
UNION ALL
SELECT ID = q.ID +1
, q.Item
FROM q
WHERE ID < 100
)
SELECT q.*
FROM q
INNER JOIN Temp t ON t.Item = q.Item
AND t.Amount >= q.ID
You create the dynamic table aliased as r below. Works for amounts up to 2047.
select t.*
from
(select label='ABC', required=15 union all
select label='XYZ', required=10) r
inner join tbl t
on t.ItemID = r.label
inner join master..spt_values v
on v.type=Number and v.number between 1 and r.required
order by t.ItemID