Let's say I am returning the following table from a select
CaseId
DocId
DocumentTypeId
DocumentType
ExpirationDate
1
1
1
I797
01/02/23
1
2
2
I94
01/02/23
1
3
3
Some Other Value
01/02/23
I want to select ONLY the row with DocumentType = 'I797', then if there is no 'I797', I want to select ONLY the row where DocumentType = 'I94'; failing to find either of those two I want to take all rows with any other value of DocumentType.
Using SQL Server ideally.
I think I'm looking for an XOR clause but can't work out how to do that in SQL Server or to get all other values.
Similar to #siggemannen answer
select top 1 with ties
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end gr
,docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Shortest:
select top 1 with ties
docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Something like this perhaps:
select *
from (
select t.*, DENSE_RANK() OVER(ORDER BY CASE WHEN DocumentType = 'I797' THEN 0 WHEN DocumentType = 'I94' THEN 1 ELSE 2 END) AS prioorder
from
(
VALUES
(1, 1, 1, N'I797', N'01/02/23')
, (1, 2, 2, N'I94', N'01/02/23')
, (1, 3, 3, N'Some Other Value', N'01/02/23')
, (1, 4, 3, N'Super Sekret', N'01/02/23')
) t (CaseId,DocId,DocumentTypeId,DocumentType,ExpirationDate)
) x
WHERE x.prioorder = 1
The idea is to rank rows by 1, 2, 3 depending on document type. Since we rank "the rest" the same, you will get all rows if I797 and I94 is missing.
select * from YourTable where DocumentType = 'I797'
union
select * from YourTable t where DocumentType = 'I94' and (not exists (select * from YourTable where DocumentType = 'I797'))
union
select * from YourTable t where (not exists (select * from YourTable where DocumentType = 'I797' or DocumentType = 'I94' ))
Related
I have this query
select *
from dbo.EventLogs
where EntityID = 60181615
and EventTypeID in (1, 2, 3, 4, 5)
and NewValue = 'Received'
If 2 and 4 does not exist with NewValue 'Received' it shows this
current results
What I want
Ideally you should maintain somewhere a table containing all possible EventTypeID values. Sans that, we can use a CTE in place along with a left join:
WITH EventTypes AS (
SELECT 1 AS ID UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
)
SELECT et.ID AS EventTypeId, el.*
FROM EventTypes et
LEFT JOIN dbo.EventLogs el
ON el.EntityID = 60181615 AND
el.NewValue = 'Received'
WHERE
et.ID IN (1,2,3,4,5);
I have a table called recipes with following data.
page_no title
-----------------
1 pancake
2 pizza
3 pasta
5 cookie
page_no 0 is always blank, and missing page_no are blank, I want output as below, for the blank page NULL values in the result.
left_title right_title
------------------------
NULL pancake
Pizza pasta
NULL cookie
I have tried this SQL statement, but it's not returning the desired output:
SELECT
CASE WHEN id % 2 = 0
THEN title
END AS left_title,
CASE WHEN id %2 != 0
THEN title
END AS right_title
FROM
recipes
You are quite close. You just need aggregation:
select max(case when id % 2 = 0 then title end) as left_title,
max(case when id % 2 = 1 then title end) as right_title
from recipes
group by id / 2
order by min(id);
SQL Server does integer division, so id / 2 is always an integer.
Using CTE.. this should be give you a good CTE overview
DECLARE #table TABLE (
pageno int,
title varchar(30)
)
INSERT INTO #table
VALUES (1, 'pancake')
, (2, 'pizza')
, (3, 'pasta')
, (5, 'cookie')
;
WITH cte_pages
AS ( -- generate page numbers
SELECT
0 n,
MAX(pageno) maxpgno
FROM #table
UNION ALL
SELECT
n + 1 n,
maxpgno
FROM cte_pages
WHERE n <= maxpgno),
cte_left
AS ( --- even
SELECT
n,
ROW_NUMBER() OVER (ORDER BY n) rn
FROM cte_pages
WHERE n % 2 = 0),
cte_right
AS ( --- odd
SELECT
n,
ROW_NUMBER() OVER (ORDER BY n) rn
FROM cte_pages
WHERE n % 2 <> 0)
SELECT
tl.title left_title,
tr.title right_title --- final output
FROM cte_left l
INNER JOIN cte_right r
ON l.rn = r.rn
LEFT OUTER JOIN #table tl
ON tl.pageno = l.n
LEFT OUTER JOIN #table tr
ON tr.pageno = r.n
This question already has answers here:
Pivoting in DB2
(3 answers)
Closed 5 years ago.
I have table A, below, where for each unique id, there are three codes with some value.
ID Code Value
---------------------
11 1 x
11 2 y
11 3 z
12 1 p
12 2 q
12 3 r
13 1 l
13 2 m
13 3 n
I have a second table B with format as below:
Id Code1_Val Code2_Val Code3_Val
Here there is just one row for each unique id. I want to populate this second table B from first table A for each id from the first table.
For the first table A above, the second table B should come out as:
Id Code1_Val Code2_Val Code3_Val
---------------------------------------------
11 x y z
12 p q r
13 l m n
How can I achieve this in a single SQL query?
select Id,
max(case when Code = '1' then Value end) as Code1_Val,
max(case when Code = '2' then Value end) as Code2_Val,
max(case when Code = '3' then Value end) as Code3_Val
from TABLEA
group by Id
SELECT Id,
max(DECODE(Code, 1, Value)) AS Code1_Val,
max(DECODE(Code, 2, Value)) AS Code2_Val,
max(DECODE(Code, 3, Value)) AS Code3_Val
FROM A
group by Id
If your version doesn't have DECODE(), you can also use this:
INSERT INTO B (id, code1_val, code2_val, code3_val)
WITH Ids (id) as (SELECT DISTINCT id
FROM A) -- Only to construct list of ids
SELECT Ids.id, a1.value, a2.value, a3.value
FROM Ids -- or substitute the actual id table
JOIN A a1
ON a1.id = ids.id
AND a1.code = 1
JOIN A a2
ON a2.id = ids.id
AND a2.code = 2
JOIN A a3
ON a3.id = ids.id
AND a3.code = 3
(Works on my V6R1 DB2 instance, and have an SQL Fiddle Example).
Here is a SQLFiddle example
insert into B (ID,Code1_Val,Code2_Val,Code3_Val)
select Id, max(V1),max(V2),max(V3) from
(
select ID,Value V1,'' V2,'' V3 from A where Code=1
union all
select ID,'' V1, Value V2,'' V3 from A where Code=2
union all
select ID,'' V1, '' V2,Value V3 from A where Code=3
) AG
group by ID
Here is the SQL Query:
insert into pivot_insert_table(id,code1_val,code2_val, code3_val)
select * from (select id,code,value from pivot_table)
pivot(max(value) for code in (1,2,3)) order by id ;
WITH Ids (id) as
(
SELECT DISTINCT id FROM A
)
SELECT Ids.id,
(select sub.value from A sub where Ids.id=sub.id and sub.code=1 fetch first rows only) Code1_Val,
(select sub.value from A sub where Ids.id=sub.id and sub.code=2 fetch first rows only) Code2_Val,
(select sub.value from A sub where Ids.id=sub.id and sub.code=3 fetch first rows only) Code3_Val
FROM Ids
You want to pivot your data. Since DB2 has no pivot function, yo can use Decode (basically a case statement.)
The syntax should be:
SELECT Id,
DECODE(Code, 1, Value) AS Code1_Val,
DECODE(Code, 2, Value) AS Code2_Val,
DECODE(Code, 3, Value) AS Code3_Val
FROM A
I have a table like this:
TransId. LayerNo. AccountId.
100. 1. 2.
100. 2. 3.
120. 1. 5.
120. 2. 6.
120. 3. 12.
70. 1. 2.
I want to find transId(s) where:
(LayerNo = 1 and (accountId = 2 or 5))
and
(LayerNo = 2 and (accountId = 3 or 6))
And result set would be row no 1,2,3,4.
How could I write query to get the result?
My database is SQL server 2008 r2
Thanks in advance
Nima
SELECT TransId
FROM your_table
WHERE ( layerno = 1
AND accountid IN ( 2, 5 ) )
INTERSECT
SELECT TransId
FROM your_table
WHERE ( layerno = 2
AND accountid IN ( 3, 6 ) )
One approach is to ensure that each transID must have two records that satisfy the conditions you outlined.
SELECT * FROM
TABLE
WHERE TransID IN(
SELECT TransId
FROM table
WHERE ( layerno = 1
AND accountid IN ( 2, 5 ) )
OR ( layerno = 2
AND accountid IN( 3, 6 ) )
GROUP BY
TransId
HAVING Count(*) = 2
)
However this could be a problem if you can have multple records where layerno = 1. So you can use self joins instead to ensure the criteria.
SELECT DISTINCT a.transid
FROM table a
INNER JOIN table b
ON a.transid = b.transid
INNER JOIN table c
ON a.transid = c.transid
WHERE b.layerno = 1
AND accountid IN ( 2, 5 )
AND c.layerno = 2
AND accountid IN ( 3, 6 )
That said Martin's INTERSECT approach is probably the best
Do you mean:
SELECT
TransId,
LayerNo,
AccountId
FROM Table
WHERE (LayerNo = 1 AND AccountId IN (2, 5)) OR
(LayerNo = 2 AND AccountId IN (3, 7))
create table #temp
( rowId Int Identity(1,1), transId int)
INSERT INTO #temp(transId)
select TransId
from TableName
where (layerNo = 1 and accountID IN (2, 5))
OR (layerNo = 2 and accountId IN (3, 6))
select * from #temp
SELECT
base.TransId,
base.LayerNo,
base.AccountId
FROM TableX AS base
JOIN TableX AS a
ON a.TransId = base.TransId
AND a.LayerNo = 1 AND a.AccountId IN (2, 5)
JOIN TableX AS b
ON b.TransId = base.TransId
AND b.LayerNo = 2 AND b.AccountId IN (3, 7)
WHERE (base.LayerNo = 1 AND base.AccountId IN (2, 5))
OR (base.LayerNo = 2 AND base.AccountId IN (3, 7))
This intersection is empty. If you take the values where LayerNo = 1 and LayerNo = 2 and intersect them their intersection is empty because these events are mutually exclusive. I believe this error comes from how the question was originally stated. I might be wrong but the predicate should have been
(LayerNo = 1 and (accountId = 2 or 5)) OR (LayerNo = 2 and (accountId = 3 or 6))
Replace the AND with an OR. If the predicate was stated correctly then the intersect is correct but will always be empty.
SELECT *
FROM table
WHERE (LayerNo = 1 AND (AccountID = 2 OR AccountID = 5))
OR (LayerNo = 2 AND (AccountID = 3 OR AccountID = 6))
I've got a Table that stores messages
like this:
codMsg, message, anotherCod
1, 'hi', 1
2, 'hello', 1
3, 'wasup', 1
4, 'yo', 2
5, 'yeah', 2
6, 'gogogo', 3
I was wondering if is possible to select top 1 of each anotherCod
What I expect:
1, 'hi', 1
4, 'yo', 2
6, 'gogogo', 3
I want the whole line, not just the number of the anotherCod, so group by should not work
select mytable.*
from mytable
join (select min(codMsg) as codMsg, anotherCod from mytable group by 2) x
on mytable.codMsg = x.codMsg
SQL Server 2005+, Oracle :
SELECT codMsg,
message,
anotherCod
FROM
(
SELECT codMsg,
message,
anotherCod,
RANK() OVER (PARTITION BY anotherCod ORDER BY codMsg ASC) AS Rank
FROM mytable
) tmp
WHERE Rank = 1
SELECT
*
FROM
myTable
WHERE
codMSG = (SELECT MIN(codMsg) FROM myTable AS lookup WHERE anotherCod = myTable.anotherCod)