table 1 is maintable_KQPPJ : contains GroupID, Year, Name, VendorID. This table contains multiple records with the same GroupID
table 2 is cb_vendorinformation: contains GroupID and CompanyName
I would like to join both tables on GroupID. The output should only have GroupID, CompanyName, and Count. The Count is the distinct count of GroupID in maintable_KQPPJ.
I have the following code but it doesn't really give me the output I'm looking for.
SELECT maintable_KQPPJ.GROUPID, cb_vendorinformation.CompanyName, count(distinct maintable_KQPPJ.GROUPID)
FROM maintable_KQPPJ
JOIN cb_vendorinformation ON maintable_KQPPJ.GROUPID=cb_vendorinformation.GROUPID
maintable_KQPPJ:
GroupID Year VendorID Name
26 2019 9999 John
26 2020 2345 Jane
6 2018 3244 Jack
36 2021 3245 Jill
cb_vendorinformation:
GroupID CompanyName
26 Walmart
6 Target
36 Kroger
The output should look like
GroupID CompanyName Count
26 Walmart 2
6 Target 1
36 Kroger 1
You need group by and count(*)
SELECT maintable_KQPPJ.GROUPID
, cb_vendorinformation.CompanyName
, count(*)
FROM maintable_KQPPJ
JOIN cb_vendorinformation ON maintable_KQPPJ.GROUPID=cb_vendorinformation.GROUPID
GROUP BY maintable_KQPPJ.GROUPID
, cb_vendorinformation.CompanyName
Related
I'm attempting to select two tables that have the same columns and combining them into 1 which will rank column SalesAmount from Highest to Lowest. I've attempted to do this by using UNION ALL but currently, the returned select is ranking them both separately.
TableTwo has a different ReportId value then the values in TableOne.
Here is an example of the returned select from TableOne statement:
StateId
ReportTitle
ReportId
SalesAmount
SalesRank
1
Online Sales in California
21
22
1
12
Online Sales in New York
21
13
2
23
Online Sales in Nevada
21
9
4
Here is an example of the returned select from TableTwo which only has 1 value:
StateId
ReportTitle
ReportId
SalesAmount
SalesRank
14
Online Sales in Michigan
91
11
3
I am now attempting to combine these two tables and rank them accordingly. when using UNION ALL Here is what is being returned:
StateId
ReportTitle
ReportId
SalesAmount
SalesRank
1
Online Sales in California
21
22
1
12
Online Sales in New York
37
13
2
23
Online Sales in Nevada
14
9
4
14
Online Sales in Michigan
91
11
3
The row Michigan is ranked 3. It is selecting both tables into 1 statement but not ranking them as I am trying to do. How can I achieve this? My expected results is having both tables be Ordered By SalesRank appropriately
Here is an example of my expected result:
StateId
ReportTitle
ReportId
SalesAmount
SalesRank
1
Online Sales in California
21
22
1
12
Online Sales in New York
37
13
2
14
Online Sales in Michigan
91
11
3
23
Online Sales in Nevada
14
9
4
Here is a query of example:
CREATE TABLE TableOne
(
StateId INT,
ReportTitle VARCHAR(100),
ReportId INT,
SalesAmount Money,
SalesRank INT
)
INSERT INTO TableOne (StateId,ReportTitle,ReportId,SalesAmount, SalesRank)
VALUES (1,'Online Sales in California',21, 22, 1),(12,'Online Sales in New York ',21, 13, 1), (1,'Online Sales in Nevada',21, 9, 4)
CREATE TABLE TableTwo
(
StateId INT,
ReportTitle VARCHAR(100),
ReportId INT,
SalesAmount Money,
SalesRank INT
)
INSERT INTO TableOne (StateId,ReportTitle,ReportId,SalesAmount, SalesRank)
VALUES (14,'Online Sales in Michigan',91, 11, 3)
SELECT * FROM TableOne
UNION ALL
SELECT * FROM TableTwo
Your attempt doesn't have an order by clause? So of course it won't be ordered. Add order by SalesRank e.g.
SELECT *
FROM TableOne
UNION ALL
SELECT *
FROM TableTwo
ORDER BY SalesRank
Note: Rows in tables are not stored or accessed in any determinable order. If order is important you must use an order by clause as part of your select.
Generally I like to see the actual column names in a SELECT so I added those and an ORDER BY on the SalesRank - not sure if you want the default ascending or descending.
SELECT
StateId
ReportTitle,
ReportId,
SalesAmount,
SalesRank
FROM TableOne
UNION ALL
SELECT
StateId
ReportTitle,
ReportId,
SalesAmount,
SalesRank
FROM TableTwo
ORDER BY SalesRank;
So, i have an task in uni to get max stipend in each faculty from a table with stipends.
Faculty table is:
ID_FACULTY FACULTY_NAME DEAN TELEPHON
---------- ------------------------------ -------------------- --------
10 Informacijas tehnologiju Vitols 63023095
11 Lauksaimniecibas Gaile 63022584
12 Tehniska Dukulis 53020762
13 Partikas tehnologijas Sabovics 63021075
Money table is:
ID_PAYOUT STUDENT_ID PAYOUT_DA STIPEND COMPENSATION
---------- ---------- --------- ---------- ------------
100 1 24-SEP-20 45.25 15
101 7 20-SEP-20 149.99 0
102 3 18-SEP-20 100 0
103 17 02-SEP-20 90.85 20
104 9 03-SEP-20 85 20
105 19 09-SEP-20 70.75 0
106 25 15-SEP-20 55 15
107 17 17-SEP-20 105.54 0
108 15 22-SEP-20 94 0
109 27 28-SEP-20 100 20
And the student table is:
ID_STUDENT SURNAME NAME COURSE_YEAR FACULTY_ID BIRTHDATE
---------- ------------------------- -------------------- ----------- ---------- ---------
1 Lapa Juris 4 13 27-SEP-96
3 Vilkauss Fredis 2 10 17-MAY-99
5 Karlsone Rasa 1 11 13-MAR-00
7 Grozitis Guntars 3 12 16-APR-97
9 Sonciks Jurgis 2 10 17-MAR-99
11 Berzajs Olafs 3 10 14-FEB-97
13 Vike Ilvija 2 13 14-MAY-99
15 Baure Inga 3 11 12-APR-97
17 Viskers Zigmunds 2 13 15-AUG-99
19 Talmanis Harijs 3 13 15-JUL-97
21 Livmanis Indulis 1 10 19-JAN-00
23 Shaveja Uva 2 13 18-FEB-98
25 Lacis Guntis 4 10 17-SEP-96
27 Liepa Guna 4 11 18-AUG-96
29 Klava Juris 2 10 19-MAY-98
I have tried many variations of queries, i think that I even tried all the possible combinations of joins, but i cannot achieve the neccessary result.
One of my queries looked like this:
SQL> SELECT ROW_NUMBER() OVER (ORDER BY surname) "Nr.",
f.faculty_name,
s.surname,
s.name,
MAX(m.stipend)
FROM faculty f, student s INNER JOIN money m ON s.id_student = m.student_id
WHERE s.faculty_id = f.id_faculty
GROUP BY f.faculty_name, s.surname, s.name
ORDER BY s.surname;
Which returned me the following result:
Nr. FACULTY_NAME SURNAME NAME MAX(M.STIPEND)
---------- ------------------------------ ------------------------- -------------------- --------------
1 Lauksaimniecibas Baure Inga 94
2 Tehniska Grozitis Guntars 149.99
3 Informacijas tehnologiju Lacis Guntis 55
4 Partikas tehnologijas Lapa Juris 45.25
5 Lauksaimniecibas Liepa Guna 100
6 Informacijas tehnologiju Sonciks Jurgis 85
7 Partikas tehnologijas Talmanis Harijs 70.75
8 Informacijas tehnologiju Vilkauss Fredis 100
9 Partikas tehnologijas Viskers Zigmunds 105.54
9 rows selected.
So the goal of this task is to retrieve the maximum amount of stipend granted to a student in a certain faculty.
Can someone please tell what am I doing wrong here?
Just max amount per faculty:
SELECT
f.faculty_name,
MAX(m.stipend)
FROM
faculty f
INNER JOIN student s ON s.faculty_id = f.id_faculty
INNER JOIN money m ON s.id_student = m.student_id
GROUP BY f.faculty_name
Max amount and all other details too:
SELECT * FROM
(
SELECT
ROW_NUMBER() OVER (PARTITION BY f.faculty_name ORDER BY m.stipend desc) rn,
f.*,
s.*,
m.*
FROM
faculty f
INNER JOIN student s ON s.faculty_id = f.id_faculty
INNER JOIN money m ON s.id_student = m.student_id
) x
WHERE x.rn = 1
Points of note:
Do not use old style joins; if you ever write one table_name, other_table_name in a FROM block, you're using old style joins. Don't do it; they became bad news about 30 years ago
When you have a max-n-per-group, you specify how finely detailed the group is. If you GROUP BY s.first_name, s.last_name, f.faculty_name then your groups are "every unique combination of firstname/lastname/faculty, so the only way you'll get multiple items in your group is if there are two John Smiths in Mathematics. If the group is to be the whole of mathematics, then the faculty name (and anything else that is uniquely related 1:1 to it, like the faculty ID) is all that you can put in your group. Anything not in a group must be in an aggregation, like MAX
When you want other details too, you either group and max the data and then join this groupmaxed data back to the original data to use it as a filter, or you use an approach like here where you use a row_number or rank, with a partition (which is like an autojoined grouped summary). There is no group here; the row numbering acts like a group because it restarts from 1 every different faculty and proceeds incrementally as stipend decreses. This means that the highest stipend is always in row number 1.
Unlike using a groupmax that you join back to get the detail, the row_number route does not produce duplicate rows with tied-for-highest stipends
I am on Oracle 12c and need help with the simple query.
Here is the sample data of what I currently have:
Table Name: customer
Table DDL
create table customer(
customer_id varchar2(50),
name varchar2(50),
activation_dt date,
space_occupied number(50)
);
Sample Table Data:
customer_id name activation_dt space_occupied
abc abc-001 2016-09-12 20
xyz xyz-001 2016-09-12 10
Sample Data Output
The query I am looking for will provide the following:
customer_id name activation_dt space_occupied
abc abc-001 2016-09-12 20
xyz xyz-001 2016-09-12 10
Total_Space null null 30
Here is a slightly hack-y approach to this, using the grouping function ROLLUP(). Find out more.
SQL> select coalesce(customer_id, 'Total Space') as customer_id
2 , name
3 , activation_dt
4 , sum(space_occupied) as space_occupied
5 from customer
6 group by ROLLUP(customer_id, name, activation_dt)
7 having grouping(customer_id) = 1
8 or (grouping(name) + grouping(customer_id)+ grouping(activation_dt)) = 0;
CUSTOMER_ID NAME ACTIVATIO SPACE_OCCUPIED
------------ ------------ --------- --------------
abc abc-001 12-SEP-16 20
xyz xyz-001 12-SEP-16 10
Total Space 30
SQL>
ROLLUP() generates intermediate totals for each combination of column; the verbose HAVING clause filters them out and retains only the grand total.
What you want is a bit unusual, as if customer_id is integer, then you have to cast it to string etc, but it this is your requirement, then if be achieved this way.
SELECT customer_id,
name,
activation_dt,
space_occupied
FROM
(SELECT 1 AS seq,
customer_id,
name,
activation_dt,
space_occupied
FROM customer
UNION ALL
SELECT 2 AS seq,
'Total_Space' AS customer_id,
NULL AS name,
NULL AS activation_dt,
sum(space_occupied) AS space_occupied
FROM customer
)
ORDER BY seq
Explanation:
Inner query:
First part of union all; I added 1 as seq to give 1
hardcoded with your resultset from customer.
Second part of union
all: I am just calculating sum(space_occupied) and hardcoding other
columns, including 2 as seq
Outer query; Selecting the data
columns and order by seq, so Total_Space is returned at last.
Output
+-------------+---------+---------------+----------------+
| CUSTOMER_ID | NAME | ACTIVATION_DT | SPACE_OCCUPIED |
+-------------+---------+---------------+----------------+
| abc | abc-001 | 12-SEP-16 | 20 |
| xyz | xyz-001 | 12-SEP-16 | 10 |
| Total_Space | null | null | 30 |
+-------------+---------+---------------+----------------+
Seems like a great place to use group by grouping sets seems like this is what they were designed for. Doc link
SELECT coalesce(Customer_Id,'Total_Space') as Customer_ID
, Name
, ActiviatioN_DT
, sum(Space_occupied) space_Occupied
FROM customer
GROUP BY GROUPING SETS ((Customer_ID, Name, Activation_DT, Space_Occupied)
,())
The key thing here is we are summing space occupied. The two different grouping mechanisms tell the engine to keep each row in it's original form and 1 records with space_occupied summed; since we group by () empty set; only aggregated values will be returned; along with constants (coalesce hardcoded value for total!)
The power of this is that if you needed to group by other things as well you could have multiple grouping sets. imagine a material with a product division, group and line and I want a report with sales totals by division, group and line. You could simply group by () to get grand total, (product_division, Product_Group, line) to get a product line (product_Divsion, product_group) to get a product_group total and (product_division) to get a product Division total. pretty powerful stuff for a partial cube generation.
I've got the following table:
ID Name Sales
1 Kalle 1
2 Kalle -1
3 Simon 10
4 Simon 20
5 Anna 11
6 Anna 0
7 Tina 0
I want to write a SQL query that only returns the rows that
represents a salesperson with sum of sales > 0.
ID Name Sales
3 Simon 10
4 Simon 20
5 Anna 11
6 Anna 0
Is this possible?
You can easily get names of the people with the sum of sales that are greater than 0 by using the a HAVING clause:
select name
from yourtable
group by name
having sum(sales) > 0;
This query will return both Simon and Anna, then if you want to return all of the details for each of these names you can use the above in a WHERE clause to get the final result:
select id, name, sales
from yourtable
where name in (select name
from yourtable
group by name
having sum(sales) > 0);
See SQL Fiddle with Demo.
You can make it like this, I think the join will be more effective than the where name in() clause.
SELECT Sales.name, Sales.sales
FROM Sales
JOIN (SELECT name FROM Sales GROUP BY Sales.name HAVING SUM(sales) > 0) AS Sales2 ON Sales2.name = Sales.name
This will work on some databases, like oracle, mssql, db2
SELECT ID, Name, Sales
FROM
(
SELECT ID, Name, Sales, sum(sales) over (partition by name) sum1
FROM <table>
) a
WHERE sum1 > 0
I have a Table called "MIVTable" which has the following records,
MIVID Quantity Value
------ ---------- --------
14 10 3000
14 20 3500
14 15 2000
15 20 3000
15 50 7500
16 25 2000
Here, I need to store the above Table into two tables such as "HeaderTbl" and "DetailTbl" based on the MIVID as follows:
HeaderTbl:
HID MIVID TotalQuantity TotalValue
----- ------- ------------- -----------
1 14 45 8500
2 15 70 10500
3 16 25 2000
Here HID is the Primary Key with Identity Column.
DetailTbl:
HID MIVID Quantity Value
----- ------- ------------ -------
1 14 10 3000
1 14 20 3500
1 14 15 2000
2 15 20 3000
2 15 50 7500
3 16 25 2000
Suppose, if the MIVTable contains 4 different MIVID means, then 4 row should be created based on the MIVID on the HeaderTbl. How to do this?
To insert records in HeaderTbl from MIVTable use this: (HID should be auto increment)
INSERT INTO HeaderTbl
([MIVID], [TotalQuantity], [TotalValue])
SELECT MIVID, SUM(Quantity), SUM(Value) FROM MIVTable GROUP BY MIVID;
To insert records in DetailTbl from HeaderTbl and MIVTable use this:
INSERT INTO DetailTbl
([HID], [MIVID], [Quantity], [Value])
SELECT H.HID, M.*
FROM HeaderTbl H
INNER JOIN MIVTable M
ON H.MIVID = M.MIVID;
Look at this SQLFiddle
Here you need to use INSERT INTO SELECT statement to insert data from one table to another. You can also use JOIN in such statement as I did it for DetailTbl.
You would generate the HeaderTbl using RANK() SQL Server function, as follows:
SELECT RANK() OVER (ORDER BY MIVID) as HID, MIVID, TotalQuantity, TotalValue
FROM
(
SELECT
MIVID,
SUM(Quantity) as TotalQuantity,
SUM(Value) as TotalValue
FROM MIVTable GROUP BY MIVID
) AS A
and the Detail table using the ROW_NUMBER() SQL Server function, as follows:
SELECT
ROW_NUMBER() OVER (ORDER BY MIVID) AS HID,
MIVID,
Quantity,
Value
FROM MIVTable