I'm trying to update the table with a lagging value for specific field when that field is different from '1900-01-01 00:00:00'
select Ticket_ID, Business_Area, Priority, HF_Client_Name, closed_date, Closed_Date_ID, Next_Create_date from schema.table_name order by closed_date desc;
And this is the result I'm trying to get:
I truly appreciate any help I can get. My DB is MYSQL db.
I'm working on a solution with a LAG function, an will paste my code as soon as I have something worth showing.
Thank you all!
Rosa
I've managed to solve this by creating a temp table which contains all the tickets with 0. I joined my original table without the 0 tickets to this second temp table.
The most important piece was to create a temp table with maximal next created date based on that month:
select a.business_area, a.priority, a.hf_client_name, DATE_FORMAT(a.closed_date ,'%Y-%m') month_of_ticket, max(next_created_date) next_created_date
from tmp_next_lead_date a
group by a.business_area, a.priority, a.hf_client_name, DATE_FORMAT(a.closed_date ,'%Y-%m');
After that I just joined the two tables based on month of ticket and the rest of the key.
select a.ticket_id, a.business_area, a.priority, a.hf_client_name, a.closed_date,
/*DATE_FORMAT(a.closed_date ,'%Y-%m') month_of_ticket,*/ a.closed_date_id, b.next_created_date
from tmp_missing_combination a
join tmp_next_created_Date b
on a.business_area=b.business_area
and a.hf_client_name=b.hf_client_name
and **DATE_FORMAT(a.closed_date ,'%Y-%m')=b.month_of_ticket** ;
Related
I have two SQL tables as follows:
As you may note, the first table has a monthly frequency (date column), while the second table has a quarterly frequency. Here is what I would like to do:
For each issueid from table 1, I would like to look at the date, determine what is the previous end of quarter, and go fetch data from table 2 corresponding to that issue for that end of quarter, and insert it in the first table in the last two columns.
For example: take issueid 123456 and date 1/31/2014. The previous end of quarter is 12/31/2013. I would like to go to table 1, copy q_exp and q_act that correspond to that issueid and 12/31/2013, and paste it into the first table.
Of course, I would like to fill the entire first table and minimize manual inserts.
Any help would be appreciated! Thanks!
Try the following query
UPDATE issues
SET q_exp=(SELECT TOP 1 q.q_exp
FROM quarterlyTable q
WHERE q.issueid=i.issueid
AND q.[date]<=i.[date]
ORDER BY q.[date] DESC)
,q_act= (SELECT TOP 1 q.q_act
FROM quarterlyTable q
WHERE q.issueid=i.issueid
AND q.[date]<=i.[date]
ORDER BY q.[date] DESC)
FROM issues i
can someone help me about counting rows in sql. I have a table, archive, in which I have bank account and status of that account. One account can have and usually have more records, in my count I have to use last record, not records before. Example:
account status
5552222 A
5552222 B
5552222 A
**5552222 B**
4445896 A
4445896 B
**4445896 A**
I have to use this who are bold. Based on this there is one B(blocked) and one A(active) account. I have column datetime, which can tell me what is last record. I just need query to count that
Assuming you want to count based on the most current row for an account:
SELECT tab.status,
COUNT(*)
FROM tab JOIN
(
SELECT account, MAX(datetime) AS maxdate
FROM tab
GROUP BY account
) AS dt
ON tab.account = dt.account
AND tab.datetime = dt.maxtime
GROUP BY tab.Status
SELECT COUNT(*)
FROM yourTable
WHERE Status='B'
or
WHERE AccountName LIKE '%B'
Edit: After OP modified the question to include the table data.
So, the problem is that the same account number can occur multiple times, and you want to count on the basis of last status of the account.
If the account is currently blocked, you would like to count it, irrespective of the number of times it gets blocked earlier.
Assumption: You have a date type column in your table which shows the date when the record's (with new status value) was inserted (or it may be an identity field which keeps track of the order of records created in the table)
The query will be:
SELECT COUNT (*)
FROM
(
SELECT DISTINCT
acNumber,
( SELECT Max(identityField_or_dateField)
FROM tableName t
WHERE t.acNumber = t2.acNumber AND Status='B')
FROM tableName t2
WHERE
( SELECT Max(identityField_or_dateField)
FROM tableName t
WHERE t.acNumber = t2.acNumber AND Status='B') IS NOT NULL
) tblAlias
Glad to help! Please remember to accept the answer if you found it helpful.
I would like to see a most concise way to do what is outlined in this SO question: Sum values from multiple rows into one row
that is, combine multiple rows while summing a column.
But how to then delete the duplicates. In other words I have data like this:
Person Value
--------------
1 10
1 20
2 15
And I want to sum the values for any duplicates (on the Person col) into a single row and get rid of the other duplicates on the Person value. So my output would be:
Person Value
-------------
1 30
2 15
And I would like to do this without using a temp table. I think that I'll need to use OVER PARTITION BY but just not sure. Just trying to challenge myself in not doing it the temp table way. Working with SQL Server 2008 R2
Simply put, give me a concise stmt getting from my input to my output in the same table. So if my table name is People if I do a select * from People on it before the operation that I am asking in this question I get the first set above and then when I do a select * from People after the operation, I get the second set of data above.
Not sure why not using Temp table but here's one way to avoid it (tho imho this is an overkill):
UPDATE MyTable SET VALUE = (SELECT SUM(Value) FROM MyTable MT WHERE MT.Person = MyTable.Person);
WITH DUP_TABLE AS
(SELECT ROW_NUMBER()
OVER (PARTITION BY Person ORDER BY Person) As ROW_NO
FROM MyTable)
DELETE FROM DUP_TABLE WHERE ROW_NO > 1;
First query updates every duplicate person to the summary value. Second query removes duplicate persons.
Demo: http://sqlfiddle.com/#!3/db7aa/11
All you're asking for is a simple SUM() aggregate function and a GROUP BY
SELECT Person, SUM(Value)
FROM myTable
GROUP BY Person
The SUM() by itself would sum up the values in a column, but when you add a secondary column and GROUP BY it, SQL will show distinct values from the secondary column and perform the aggregate function by those distinct categories.
i have loanTable that contain two field loan_id and status
loan_id status
==============
1 0
2 9
1 6
5 3
4 5
1 4 <-- How do I select this??
4 6
In this Situation i need to show the last Status of loan_id 1 i.e is status 4. Can please help me in this query.
Since the 'last' row for ID 1 is neither the minimum nor the maximum, you are living in a state of mild confusion. Rows in a table have no order. So, you should be providing another column, possibly the date/time when each row is inserted, to provide the sequencing of the data. Another option could be a separate, automatically incremented column which records the sequence in which the rows are inserted. Then the query can be written.
If the extra column is called status_id, then you could write:
SELECT L1.*
FROM LoanTable AS L1
WHERE L1.Status_ID = (SELECT MAX(Status_ID)
FROM LoanTable AS L2
WHERE L2.Loan_ID = 1);
(The table aliases L1 and L2 could be omitted without confusing the DBMS or experienced SQL programmers.)
As it stands, there is no reliable way of knowing which is the last row, so your query is unanswerable.
Does your table happen to have a primary id or a timestamp? If not then what you want is not really possible.
If yes then:
SELECT TOP 1 status
FROM loanTable
WHERE loan_id = 1
ORDER BY primaryId DESC
-- or
-- ORDER BY yourTimestamp DESC
I assume that with "last status" you mean the record that was inserted most recently? AFAIK there is no way to make such a query unless you add timestamp into your table where you store the date and time when the record was added. RDBMS don't keep any internal order of the records.
But if last = last inserted, that's not possible for current schema, until a PK addition:
select top 1 status, loan_id
from loanTable
where loan_id = 1
order by id desc -- PK
Use a data reader. When it exits the while loop it will be on the last row. As the other posters stated unless you put a sort on the query, the row order could change. Even if there is a clustered index on the table it might not return the rows in that order (without a sort on the clustered index).
SqlDataReader rdr = SQLcmd.ExecuteReader();
while (rdr.Read())
{
}
string lastVal = rdr[0].ToString()
rdr.Close();
You could also use a ROW_NUMBER() but that requires a sort and you cannot use ROW_NUMBER() directly in the Where. But you can fool it by creating a derived table. The rdr solution above is faster.
In oracle database this is very simple.
select * from (select * from loanTable order by rownum desc) where rownum=1
Hi if this has not been solved yet.
To get the last record for any field from a table the easiest way would be to add an ID to each record say pID. Also say that in your table you would like to hhet the last record for each 'Name', run the simple query
SELECT Name, MAX(pID) as LastID
INTO [TableName]
FROM [YourTableName]
GROUP BY [Name]/[Any other field you would like your last records to appear by]
You should now have a table containing the Names in one column and the last available ID for that Name.
Now you can use a join to get the other details from your primary table, say this is some price or date then run the following:
SELECT a.*,b.Price/b.date/b.[Whatever other field you want]
FROM [TableName] a LEFT JOIN [YourTableName]
ON a.Name = b.Name and a.LastID = b.pID
This should then give you the last records for each Name, for the first record run the same queries as above just replace the Max by Min above.
This should be easy to follow and should run quicker as well
If you don't have any identifying columns you could use to get the insert order. You can always do it like this. But it's hacky, and not very pretty.
select
t.row1,
t.row2,
ROW_NUMBER() OVER (ORDER BY t.[count]) AS rownum from (
select
tab.row1,
tab.row2,
1 as [count]
from table tab) t
So basically you get the 'natural order' if you can call it that, and add some column with all the same data. This can be used to sort by the 'natural order', giving you an opportunity to place a row number column on the next query.
Personally, if the system you are using hasn't got a time stamp/identity column, and the current users are using the 'natural order', I would quickly add a column and use this query to create some sort of time stamp/incremental key. Rather than risking having some automation mechanism change the 'natural order', breaking the data needed.
I think this code may help you:
WITH cte_Loans
AS
(
SELECT LoanID
,[Status]
,ROW_NUMBER() OVER(ORDER BY (SELECT 1)) AS RN
FROM LoanTable
)
SELECT LoanID
,[Status]
FROM LoanTable L1
WHERE RN = ( SELECT max(RN)
FROM LoanTable L2
WHERE L2.LoanID = L1.LoanID)
In SQL Server 2008,
I have a table for tracking the status history of actions (STATUS_HISTORY) that has three columns ([ACTION_ID],[STATUS],[STATUS_DATE]).
Each ACTION_ID can have a variable number of statuses and status dates.
I need to convert these rows into columns that preferably look something like this:
[ACTION_ID], [STATUS_1], [STATUS_2], [STATUS_3], [DATE_1], [DATE_2], [DATE_3]
Where the total number of status columns and date columns is unknown, and - of course - DATE_1 correlates to STATUS_1, etc. And I'd like for the status to be in chronological order (STATUS_1 has the earliest date, etc.)
My reason for doing this is so I can put the 10 most recent Statuses on a report in an Access ADP, along with other information for each action. Using a subreport with each status in a new row would cause the report to be far too large.
Is there a way to do this using PIVOT? I don't want to use the date or the status as a column heading.
Is it possible at all?
I have no idea where to even begin. It's making my head hurt.
Let us suppose for brevity that you only want 3 most recent statuses for each action_id (like in your example).
Then this query using CTE should do the job:
WITH rownrs AS
(
SELECT
action_id
,status
,status_date
,ROW_NUMBER() OVER (PARTITION BY action_id ORDER BY status_date DESC) AS rownr
FROM
status_history
)
SELECT
s1.action_id AS action_id
,s1.status AS status_1
,s2.status AS status_2
,s3.status AS status_3
,s1.status_date AS date_1
,s2.status_date AS date_2
,s3.status_date AS date_3
FROM
(SELECT * FROM rownrs WHERE rownr=1) AS s1
LEFT JOIN
(SELECT * FROM rownrs WHERE rownr=2) AS s2
ON s1.action_id = s2.action_id
LEFT JOIN
(SELECT * FROM rownrs WHERE rownr=3) AS s3
ON s1.action_id = s3.action_id
NULL values will appear in the rows where the action_id has less then 3 status-es.
I haven't had to do it with two columns, but a PIVOT sounds like what you should try. I've done this in the past with dates in a result set where I needed the date in each row be turned into the columns at the top.
http://msdn.microsoft.com/en-us/library/ms177410.aspx
I sympathize with the headache from trying to design and visualize it, but the best thing to do is try getting it working with one of the columns and then go from there. It helps once you start playing with it.