How to union all common columns from every table in SQLite - sql

For tables
t1:
C1 C2 C3
1 2 3
4 5 6
table t2:
C1 C2 C4
33 44 55
What query should be written to do a union of all common columns so that the result will be this:
C1 C2
1 2
4 5
33 44
Important to note that I'm not looking for a solution for only two tables but for a solution that does this for every table in the database. DB is SQLite

SQLite does not support dynamic sql, so the most that you can do by using its own capabilities is construct a SQL statement that would do what you want and you can execute it by using a programming language like Java or Python.
This query:
WITH tables AS (SELECT name FROM sqlite_master WHERE type = 'table')
SELECT pti.name col
FROM tables t CROSS JOIN pragma_table_info(t.name) pti
GROUP BY col
HAVING COUNT(*) = (SELECT COUNT(*) FROM tables);
returns all the columns that are common in all tables of the databse.
By using GROUP_CONCAT() you can get all these columns as a comma separated list which you can use in a SELECT statement:
WITH tables AS (SELECT name FROM sqlite_master WHERE type = 'table')
SELECT GROUP_CONCAT(col) columns
FROM (
SELECT pti.name col
FROM tables t CROSS JOIN pragma_table_info(t.name) pti
GROUP BY col
HAVING COUNT(*) = (SELECT COUNT(*) FROM tables)
);
Finally, concatenate the keywords 'SELECT' and 'FROM' and each table's name and with GROUP_CONCAT() once more and 'UNION ALL' (or 'UNION') as separator construct the sql statement:
WITH tables AS (SELECT name FROM sqlite_master WHERE type = 'table')
SELECT GROUP_CONCAT(sql, ' UNION ALL ') sql
FROM (
SELECT 'SELECT ' ||
(
SELECT GROUP_CONCAT(col) columns
FROM (
SELECT pti.name col
FROM tables t CROSS JOIN pragma_table_info(t.name) pti
GROUP BY col
HAVING COUNT(*) = (SELECT COUNT(*) FROM tables)
)
) || ' FROM ' || name AS sql
FROM tables
);
This will return a string like:
SELECT col1,col2 FROM table1 UNION ALL SELECT col1,col2 FROM table2 UNION ALL SELECT col1,col2 FROM table3
which you can execute.
See a simplified demo.

Related

Find all pairs of identical columns in different tables in a database

I would like to find identical column headers in different tables throughout a database (or across databases). I am trying to learn what are unique or foreign keys in each table fit with other keys in other tables in a multi-database SQL environment (using Teradata), and I think such a query would expedite this process.
I know how to query the database name, table name, and column name, but I don't know how to specify a condition to return only column headers in one table that exist in a different table
Here is some sample code that I think is the starter to this type of query:
select DatabaseName,TABLENAME as Tab1,Columnname as Col1, TABLENAME as Tab2, Columnname as Col2
from DBC.ColumnsV
order by DatabaseName,TABLENAME;
DatabaseName Tab1 Col1 Tab2 Col2
Dat1 Table0 Col0 Table9 Col0
Andrews query simplified:
SELECT DatabaseName, TableName, ColumnName,
Count(*) Over (PARTITION BY ColumnName) AS Cnt
FROM dbc.ColumnsV
QUALIFY Cnt > 1 -- only repeated columns
I think this is enough data to work with, but if you really want pairs of tables you need a self join:
WITH cte AS
(
SELECT DatabaseName, TableName, ColumnName,
Count(*) Over (PARTITION BY ColumnName) AS Cnt
FROM dbc.ColumnsV
WHERE databasename = 'open_data'
QUALIFY Cnt > 1 -- only repeated columns
)
SELECT *
FROM cte AS t1
JOIN cte AS t2
ON t1.ColumnName = t2.ColumnName -- same column
WHERE t1.DatabaseName || '.' || t1.TableName < t2.DatabaseName || '.' || t2.TableName
Of course, this will greatly increase the number of rows, it returns each table name once, thus n*(n-1)/2 rows for n tables with the same column name.
If you change the condition to <> instead of < you get all combinations and twice the number of rows, i,e, both table1,table2 and table2,table1.
First we'll get a list of column names that are duplicated. Then we join that back to ColumnsV and get whatever information you want on those columns.
with cols as (
select
columnname ,
count (*) as cnt
from
dbc.columnsv
group by columnname
having count (*) > 1)
select
columnsv.*
from
dbc.columnsv
inner join cols
on columnsv.columnname = cols.columnname

How to create table with multiple rows and columns using only SELECT clause (i.e. using SELECT without FROM clause)

I know that in SQL Server, one can use SELECT clause without FROM clause, and create a table with one row and one column
SELECT 1 AS n;
But I was just wondering, is it possible to use SELECT clause without FROM clause, to create
a table with one column and multiple rows
a table with multiple columns and one row
a table with multiple columns and multiple rows
I have tried many combinations such as
SELECT VALUES(1, 2) AS tableName(n, m);
to no success.
You can do it with CTE and using union(Use union all if you want to display duplicates)
Rextester Sample for all 3 scenarios
One Column and multiple rows
with tbl1(id) as
(select 1 union all
select 2)
select * from tbl1;
One row and multiple columns
with tbl2(id,name) as
(select 1,'A')
select * from tbl2;
Multiple columns and multiple rows
with tbl3(id,name) as
(select 1,'A' union all
select 2,'B')
select * from tbl3;
-- One column, multiple rows.
select 1 as ColumnName union all select 2; -- Without FROM;
select * from ( values ( 1 ), ( 2 ) ) as Placeholder( ColumnName ); -- With FROM.
-- Multiple columns, one row.
select 1 as TheQuestion, 42 as TheAnswer; -- Without FROM.
select * from ( values ( 1, 42 ) ) as Placeholder( TheQuestion, TheAnswer ); -- With FROM.
-- Multiple columns and multiple rows.
select 1 as TheQuestion, 42 as TheAnswer union all select 1492, 12; -- Without FROM.
select * from ( values ( 1, 2 ), ( 2, 4 ) ) as Placeholder( Column1, Column2 ); -- With FROM.
You can do all that by using UNION keyword
create table tablename as select 1 as n,3 as m union select 2 as n,3 as m
In Oracle it will be dual:
create table tablename as select 1 as n,3 as m from dual union select 2 as n,3 as m from dual
You can use UNION operator:
CREATE TABLE AS SELECT column_name(s) FROM table1
UNION
SELECT column_name(s) FROM table2;
The UNION operator selects only distinct values by default. To allow duplicate values you can use UNION ALL.
The column names in the result-set are usually equal to the column names in the first SELECT statement in the UNION.
try this:
--1) a table with one column and multiple rows
select * into tmptable0 from(
select 'row1col1' as v1
union all
select 'row2col1' as v1
) tmp
--2) a table with multiple columns and one row
select 'row1col1' as v1, 'row1col2' as v2 into tmptable1
--3) a table with multiple columns and multiple rows
select * into tmptable2 from(
select 'row1col1' as v1, 'row1col2' as v2
union all
select 'row2col1' as v2, 'row2col2' as v2
) tmp
One can create a view and later can query it whenever required
-- table with one column and multiple rows
create view vw1 as
(
select 'anyvalue' as col1
union all
select 'anyvalue' as col1
)
select * from vw1
-- table with multiple columns and multiple rows
create view vw2 as
(
select 'anyvalue1' as col1, 'anyvalue1' as col2
union all
select 'anyvalue2' as col1, 'anyvalue2' as col2
)
select * from vw2

Oracle: SQL Dynamic cursor statement

I have a dynamic temporary table like below.
Table name for assumption: TB_EMP_TEMP_TABLE
Column1 | column2 | column3
Emp_NM | EMP_ID |TB_EMP_DTLS
Emp_Adr | EMP_ID |TB_EMP_DTLS
Emp_Sal | EMP_ID |TB_EMP_OTHER
The above data is retrieved as a Cursor(Emp_cursor) and i need to construct a dynamic SQL Query as below based on cursor data.
Expected Output:
SELECT TB_EMP_DTLS.EMP_NM,TB_EMP_DTLS.EMP_Adr,TB_EMP_OTHER.EMP_SAL
FROM TB_EMP_DTLS,TB_EMP_OTHER
WHERE TB_EMP_DTLS.EMP_ID=TB_EMP_OTHER.EMP_ID
I havent worked extensively on PLSQL/Cursor concepts. How the cursor can be looped to get expected output.
If i understand it right, you want column1 values selected from column3 tables joined by column2 columns.
It's not elegant but should work:
select listagg(v, ' ') within group (order by n asc) my_cursor from (
with
tb as (select distinct column3 val from tb_emp_temp_table), --tables
sl as (select distinct column3||'.'||column1 val from tb_emp_temp_table), --selected columns
pr as (select distinct column3||'.'||column2 val from tb_emp_temp_table) --predicates
select 1 n, 'SELECT' v from dual
union
select 2 n, listagg(val, ', ') within group (order by val) v from sl
union
select 3 n, 'FROM' v from dual
union
select 4 n, listagg(val, ', ') within group (order by val) v from tb
union
select 5 n, 'WHERE' v from dual
union
select 6 n, listagg(pra.val||'='||prb.val, ' AND ') within group (order by pra.val) v from pr pra, pr prb where pra.val != prb.val
)

MINUS functionality in BigQuery database

I am new to BigQuery database.
Like in Oracle database MINUS operator what is the same functionality in BigQuery? I did not find MINUS operator in BigQuery.
Oracle --> Minus
BigQuery --> ??
Though there is no MINUS function in BigQuery, you can use a LEFT OUTER JOIN as an alternative.
SELECT name, uid FROM a
MINUS
SELECT name, uid FROM b
Can be written as:
SELECT a.name, a.uid
FROM a LEFT OUTER JOIN b ON a.name= b.name AND a.uid= b.uid
WHERE b.name IS NULL
BigQuery doesn't have "MINUS", but it does have the functionally identical "EXCEPT DISTINCT".
with whole as
( select 1 as id, 'One' as value
union all
select 2 as id, 'Two' as value
union all
select 3 as id, 'Three' as value
),
sub_set as
(
select 1 as id, 'One' as value
union all
select 2 as id, 'Two' as value
)
select * from whole
except distinct
select * from sub_set
Result was
3 Three
Refer: https://cloud.google.com/bigquery/docs/reference/standard-sql/query-syntax#except
I am getting the error EXCEPT ALL is not supported, DISTINCT worked. Hope this helps.
StandardSQL Output for MINUS where ID is the composite key or primary key in Table 1 and Table2
same concept as Vamsi Mohan's
Select ID, Name from Table 1
where ID not in (Select distinct ID in Table 2)

select a set of values as a column without CREATE

I'm trying to write a query that will return all QUERY_ID values alongside all matching TABLE_ID values, where QUERY_ID is not specified in any table, and I can't create tables, so have to specify it in the query itself:
QUERY_ID TABLE_ID
1 1
2 NULL
3 3
4 4
5 NULL
I feel like there ought to be a simple way to do this, but I can't think of it for the life of me. Any help would be wonderful. Thanks!
select q.QUERY_ID, t.TABLE_ID
from (
select 1 as QUERY_ID
union all
select 2
union all
select 3
union all
select 4
union all
select 5
) q
left outer join MyTable t on q.QUERY_ID = t.TABLE_ID
one way by using the built in master..spt_values table
SELECT number AS QUERY_ID,TABLE_ID
FROM master..spt_values v
LEFT JOIN YourTable y ON y.QUERY_ID = y.TABLE_ID
WHERE TYPE = 'p'
AND number > 0
AND number <= (SELECT COUNT(*) FROM YourTable)
order by QUERY_ID
are you able to create #temp tables...can you do this?
create table #temp(QUERY_ID int identity,TABLE_ID varchar(200))
insert #temp(TABLE_ID)
select TABLE_ID
from YourTable
select * from #temp
order by QUERY_ID
drop table #temp
or like this
select identity(int,1,1) as QUERY_ID,TABLE_ID
into #temp
from YourTable
select * from #temp
order by QUERY_ID
On sql server 2005 and up there is the row_number function so maybe a reason to upgrade :-)