scrapy pagination not working on tripadvisor - scrapy

i'm trying to scrape the restaurant pages on tripadvisor (just to learn how it works)
However, i only get the first page.
What am I missing?
here is the code, thanks!
import scrapy
class TripadvSpider(scrapy.Spider):
name = 'tripadv'
allowed_domains = ['tripadvisor.com']
start_urls = ['https://www.tripadvisor.com/Restaurants-g60795-oa0-Philadelphia_Pennsylvania.html#EATERY_LIST_CONTENTS']
def parse(self, response):
for stores in response.css('div.emrzT'):
yield {
'name' : stores.css('a.bHGqj::text').extract(),
'link' : stores.css('a.bHGqj').xpath("#href").extract()
}
next_page = ('http://tripadvisor.com' + response.css('a.nav').attrib['href']).extract()
##next_page = response.xpath('//a[contains(text(), "Next")]/#href).extract())
#next_page = ('http://tripadvisor.com' + response.css('a:contains("Next")').attrib['href'].extract())
if next_page is not None:
yield response.follow(next_page, callback=self.parse)

#djmystica, Now it's working fine
import scrapy
class TripadvSpider(scrapy.Spider):
name = 'tripadv'
allowed_domains = ['tripadvisor.com']
start_urls = [
'https://www.tripadvisor.com/Restaurants-g60795-oa0-Philadelphia_Pennsylvania.html#EATERY_LIST_CONTENTS']
def parse(self, response):
for stores in response.css('div.emrzT'):
yield {
'name': stores.css('a.bHGqj::text').extract_first(),
'link': stores.css('a.bHGqj').xpath("#href").extract_first()}
#next_page = ('http://tripadvisor.com' +response.css('a.nav').attrib['href']).extract()
next_page = response.xpath('//a[contains(text(), "Next")]/#href').extract_first()
abs_next_page = f'https://www.tripadvisor.com{next_page}'
#next_page = ('http://tripadvisor.com' + response.css('a:contains("Next")').attrib['href'].extract())
if abs_next_page is not None:
yield response.follow(abs_next_page, callback=self.parse)

Related

How to limit levels of link that Scrapy crawler?

For this example code:
import scrapy
class QuotesSpider(scrapy.Spider):
name = "quotes"
start_urls = [
'http://quotes.toscrape.com/page/1/',
]
def parse(self, response):
for quote in response.css('div.quote'):
yield {
'text': quote.css('span.text::text').get(),
'author': quote.css('span small::text').get(),
'tags': quote.css('div.tags a.tag::text').getall(),
}
next_page = response.css('li.next a::attr(href)').get()
if next_page is not None:
yield response.follow(next_page, callback=self.parse)
If I the crowler to visit at most 3 levels of links, how to restrict that? Not the total number of links visited, but the level of links relative to the initial link.
You can use DEPTH_LIMIT setting in your spider in order to limit depth
of crawl:
class QuotesSpider(scrapy.Spider):
name = "quotes"
start_urls = [
'http://quotes.toscrape.com/page/1/',
]
custom_settins = {
`DEPTH_LIMIT`:3
}
...

Following urls in javascript - Scrapy Splash

I am extremely new to web scraping. I manage to extract information from static websites but am now trying my hand following urls and extracting data (which ofcourse involves some javascript). I have installed scrapy-splash for the same which is running perfectly fine.
The website I am trying to scrape is https://www.ta.com/portfolio/investments/ari-network-services-inc and the button to the top right side takes you to the next page (which is javascript, hence splash). I want to scrape some basic data (like company name, sectors etc) on all the pages till the last one. This is what I have done so far and I need help to correct this to successfully execute.
import scrapy
from scrapy_splash import SplashRequest
import urllib.parse as urlparse
class TAFolio(scrapy.Spider):
name = 'Portfolio'
start_urls = ['https://www.ta.com/portfolio/investments/ari-network-services-inc']
def start_requests(self):
for url in self.start_urls:
yield SplashRequest(url=url, callback = self.parse, args={"wait" : 3})
def parse(self, response):
companyname = response.css('h1.item_detail-main-info-heading::text').extract_first()
sectors = response.css('.item_detail-main-info-group-item::text')[0].extract()
investmentyear = response.css('.item_detail-main-info-group-item::text')[1].extract()
status = response.css('.item_detail-main-info-group-item::text')[2].extract()
location = response.css('.item_detail-main-info-group-item::text')[3].extract()
region = response.css('.item_detail-main-info-group-item::text')[4].extract()
team = response.css('div.item_detail-main-info-group a::text').extract()
yield {
'companyname': companyname,
'sectors': sectors,
'investmentyear': investmentyear,
'status': status,
'location': location,
'region': region,
'team': team
}
next_page = response.css('li.item_detail-nav-item--next a::attr(href)').extract()
if next_page is not None:
yield SplashRequest(urlparse.urljoin('https://www.ta.com',next_page),callback=self.parse, args={"wait":3})
This gives me the correct information for the start_url but doesn't proceed to the next page.
Update. The issue was in the order in which I had the scraping of websites. Below is the updated code which worked well.
import scrapy
from scrapy_splash import SplashRequest
import urllib.parse as urlparse
class TAFolio(scrapy.Spider):
name = 'Portfolio'
start_urls = [
'https://www.ta.com/portfolio/business-services',
'https://www.ta.com/portfolio/consumer',
'https://www.ta.com/portfolio/financial-services',
'https://www.ta.com/portfolio/healthcare',
'https://www.ta.com/portfolio/technology'
]
def start_requests(self):
for url in self.start_urls:
yield SplashRequest(url=url, callback = self.parse, args={"wait" : 3})
def parse(self, response):
companylink = response.css('div.tiles.js-portfolio-tiles a::attr(href)').extract()
for i in companylink:
yield response.follow('https://www.ta.com' + str(i), callback=self.parse1)
def parse1(self, response):
companyname = response.css('h1.item_detail-main-info-heading::text').extract_first()
sectors = response.css('.item_detail-main-info-group-item::text')[0].extract()
investmentyear = response.css('.item_detail-main-info-group-item::text')[1].extract()
status = response.css('.item_detail-main-info-group-item::text')[2].extract()
location = response.css('.item_detail-main-info-group-item::text')[3].extract()
region = response.css('.item_detail-main-info-group-item::text')[4].extract()
team = response.css('div.item_detail-main-info-group a::text').extract()
about_company = response.css('h2.item_detail-main-content-heading::text').extract()
about_company_detail = response.css('div.markdown p::text').extract()
yield {
'companyname': companyname,
'sectors': sectors,
'investmentyear': investmentyear,
'status': status,
'location': location,
'region': region,
'team': team,
'about_company': about_company,
'about_company_detail' : about_company_detail
}

Scrapy using start_requests with rules

I can't find any solution for using start_requests with rules, also I haven't seen any example on the Internet with this two. My purpose is simple, I wanna redefine start_request function to get an ability catch all exceptions dunring requests and also use meta in requests. This is a code of my spider:
class TestSpider(CrawlSpider):
name = 'test'
allowed_domains = ['www.oreilly.com']
start_urls = ['https://www.oreilly.com/library/view/practical-postgresql/9781449309770/ch04s05.html']
# Base on scrapy doc
def start_requests(self):
for u in self.start_urls:
yield Request(u, callback=self.parse_item, errback=self.errback_httpbin, dont_filter=True)
rules = (
Rule(LinkExtractor(), callback='parse_item', follow=True),
)
def parse_item(self, response):
item = {}
item['title'] = response.xpath('//head/title/text()').extract()
item['url'] = response.url
yield item
def errback_httpbin(self, failure):
self.logger.error('ERRRRROR - {}'.format(failure))
This code scrape only one page. I try to modify it and instead of:
def parse_item(self, response):
item = {}
item['title'] = response.xpath('//head/title/text()').extract()
item['url'] = response.url
yield item
I've tried to use this, based on this answer
def parse_item(self, response):
item = {}
item['title'] = response.xpath('//head/title/text()').extract()
item['url'] = response.url
return self.parse(response)
It seems to work, but it doesn't scrape anything, even if I add parse function to my spider. Does anybody know how to use start_request and rules together? I will be glad any information about this topic. Have a nice coding!
I found a solution, but frankly speaking I don't know how it works but it sertantly does it.
class TSpider(CrawlSpider):
name = 't'
allowed_domains = ['books.toscrapes.com']
start_urls = ['https://books.toscrapes.com']
login_page = 'https://books.toscrapes.com'
rules = (
Rule(LinkExtractor(), callback='parse_item', follow=True),
)
def start_requests(self):
yield Request(url=self.login_page, callback=self.login, errback=self.errback_httpbin, dont_filter=True)
def login(self, response):
return FormRequest.from_response(response)
def parse_item(self, response):
item = {}
item['title'] = response.xpath('//head/title/text()').extract()
item['url'] = response.url
yield item
def errback_httpbin(self, failure):
self.logger.error('ERRRRROR - {}'.format(failure))
To catch errors from your rules you need to define errback for your Rule(). But unfortunately this is not possible now.
You need to parse and yield request by yourself (this way you can use errback) or process each response using middleware.
Here is a solution for handle errback in LinkExtractor
Thanks this dude!

Scrapy response incomplete get url how to

I would like to parse the value obtained from parse again by connecting to another url. How do I fix it?
from scrapy import Spider
from scrapy.selector import Selector
from stack.items import StackItem
class StackSpider(Spider):
name = "stack"
allowed_domains = ["*"]
global n
#n = 1997
start_urls = ['https://www.melon.com/chart/age/list.htm?chartType=YE&chartGenre=KPOP&chartDate=2010',]
def parse(self, response):
url = 'https://www.melon.com/song/detail.htm?songId='
questions = Selector(response).xpath('//*[#id="frm"]/table/tbody/tr')
for question in questions:
item = StackItem()
item['musicid'] = question.xpath('td/div/input/#value').extract()[0]
item['title'] = question.xpath('td[4]/div/div/div/span/strong/a/#title').extract()
item['artlist'] = question.xpath(
'td[4]/div/div/div[2]/div[1]/a/text()').extract()
item['album'] = question.xpath(
'td[4]/div/div/div[2]/div[2]/a/text()').extract()
item['sunwhi'] = question.xpath(
'td[2]/div/span/text()').extract()[0]
response_url=requests.get(url+musicid)
def parse(self, response):
questions = Selector(response).xpath('//*[#id="downloadfrm"]/div/div/div[2]/div[2]/dl/dd')
for question in questions:
item = StackItem()
item['album'] = question.xpath('a/text()').extract()[0]
yield item
class StackSpider(Spider):
name = "stack"
allowed_domains = ["*"]
global n
#n = 1997
start_urls = ['https://www.melon.com/chart/age/list.htm?chartType=YE&chartGenre=KPOP&chartDate=2010',]
def parse(self, response):
url = 'https://www.melon.com/song/detail.htm?songId='
questions = Selector(response).xpath('//*[#id="frm"]/table/tbody/tr')
for question in questions:
item = StackItem()
item['musicid'] = question.xpath('td/div/input/#value').extract()[0]
item['title'] = question.xpath('td[4]/div/div/div/span/strong/a/#title').extract()
item['artlist'] = question.xpath(
'td[4]/div/div/div[2]/div[1]/a/text()').extract()
item['album'] = question.xpath(
'td[4]/div/div/div[2]/div[2]/a/text()').extract()
item['sunwhi'] = question.xpath(
'td[2]/div/span/text()').extract()[0]
response_url=requests.get(url+musicid)
def parse(self, response):
questions = Selector(response).xpath('//*[#id="downloadfrm"]/div/div/div[2]/div[2]/dl/dd')
for question in questions:
item = StackItem()
item['album'] = question.xpath('a/text()').extract()[0]
yield item

Get next page using scrapy

I'm interested in get contractors data for atlanta from this page:
http://www.1800contractor.com/d.Atlanta.GA.html?link_id=3658
So for I can open the links for the categories
'Additions & Remodeling'
'Architects & Engineers'
'Fountains & Ponds'
......
.....
.....
But I can open only the first page:
http://www.1800contractor.com/d.Additions-Remodeling.Atlanta.GA.-12001.html?startingIndex=0&showDirectory=true
I'm trying to open get the next one with the links of the 'Next' button:
next_page_url = response.xpath('/html/body/div[1]/center/table/tr[8]/td[2]/a/#href').extract_first()
absolute_next_page_url = response.urljoin(next_page_url)
request = scrapy.Request(absolute_next_page_url)
yield request
But it makes no difference.
This is the code of my spider:
import scrapy
class Spider_1800(scrapy.Spider):
name = '1800contractor'
allowed_domains = ['1800contractor.com']
start_urls = (
'http://www.1800contractor.com/d.Atlanta.GA.html?link_id=3658',
)
def parse(self, response):
urls = response.xpath('/html/body/center/table/tr/td[2]/table/tr[6]/td/table/tr[2]/td/b/a/#href').extract()
for url in urls:
absolute_url = response.urljoin(url)
request = scrapy.Request(
absolute_url, callback=self.parse_contractors)
yield request
# process next page
next_page_url = response.xpath('/html/body/div[1]/center/table/tr[8]/td[2]/a/#href').extract_first()
absolute_next_page_url = response.urljoin(next_page_url)
request = scrapy.Request(absolute_next_page_url)
yield request
def parse_contractors(self, response):
name = response.xpath(
'/html/body/div[1]/center/table/tr[5]/td/table/tr[1]/td/b/a/#href').extract()
contrator = {
'name': name,
'url': response.url}
yield contrator
You are not paginating the right request, parse handles the request generated with the urls in start_urls, which means that you need to enter each category in http://www.1800contractor.com/d.Atlanta.GA.html?link_id=3658 first.
def parse(self, response):
urls = response.xpath('/html/body/center/table/tr/td[2]/table/tr[6]/td/table/tr[2]/td/b/a/#href').extract()
for url in urls:
absolute_url = response.urljoin(url)
request = scrapy.Request(
absolute_url, callback=self.parse_contractors)
yield request
def parse_contractors(self, response):
name = response.xpath(
'/html/body/div[1]/center/table/tr[5]/td/table/tr[1]/td/b/a/#href').extract()
contrator = {
'name': name,
'url': response.url}
yield contrator
next_page_url = response.xpath('/html/body/div[1]/center/table/tr[8]/td[2]/a/#href').extract_first()
if next_page_url:
absolute_next_page_url = response.urljoin(next_page_url)
yield scrapy.Request(absolute_next_page_url, callback=self.parse_contractors)
After hitting start_url your xpath for picking url for contractors are not working. Next page is present on contractor page therefore its called after contractor url. this will work for you
def parse(self, response):
urls = response.xpath('//table//*[#class="hiCatNaked"]').extract()
for url in urls:
absolute_url = response.urljoin(url)
request = scrapy.Request(
absolute_url, callback=self.parse_contractors)
yield request
def parse_contractors(self, response):
name=response.xpath('/html/body/div[1]/center/table/tr[5]/td/table/tr[1]/td/b/a/#href').extract()
contrator = {
'name': name,
'url': response.url}
yield contrator
next_page_url = response.xpath('//a[b[contains(.,'Next')]]/#href').extract_first()
if next_page_url:
absolute_next_page_url = response.urljoin(next_page_url)
yield scrapy.Request(absolute_next_page_url, callback=self.parse_contractors)