I'm using the Native Base Select component. While Select's data is loading I set isDisabled prop on Select to make the component unpressable. Problem is that by making it disabled I get a different style of Select that I can't change and adjust.
You should use Pseudo Props
_disabled={{
opacity: 30,
}}
Example:
<Button
_hover={{
_text: { color: "secondary.400" },
}}
>
Related
I want to change the fill colour on a single element in a lottie.json file conditionally. How can I access the fill of 'circle' and update the colour?
I currently have this
<LottieView
source={require('../assets/splash_logo_2.json')}
autoPlay
loop={false}
onAnimationFinish={() => {
progress.value = 1;
}}
colorFilters={[
{
keypath: 'circle',
color: progress.value === 1 ? '#85AA82' : '#B5FFAF',
},
]}
/>
Check this answer:
How do I use ColorFilter with React-Native-Lottie?
and also this tool to help you to identify it better:
https://colorize-react-native-lottie.netlify.app/
I'm trying to throw together a simple phone app mockup using React Native & React Native Elements as a set of UI components. I want to set the styling of various elements to a common theme, so I'm following the example in the documentation: https://reactnativeelements.com/docs/customization#using-themeprovider.
But the trouble with the example there (as it says in the docs), it sets the style of all buttons. What I'd like to do is to set the background colour of only the solid buttons for example, leaving the clear buttons, clear! Can anyone point me in the right direction of how to do this?
Current snippet (trimmed to save space):
const myTheme = {
Button: {
buttonStyle: {
borderRadius: 4,
backgroundColor: '#03E0EE',
},
titleStyle: {
color: '#180D43',
},
},
};
...
<ThemeProvider theme={myTheme}>
<View style={styles.footerContainer}>
<Button title="Primary Button"/>
<Button title="Secondary Button" type="clear" />
</View>
</ThemeProvider>
Create a wrapper component for SolidButton and or ClearButton. Make this wrapper components consuming the myTheme context with style props (e.g. ButtonSolid\ButtonClear). AFAIK there are no selector capabilities like in css.
The react-native-paper docs suggest you can set the color of a disabled button using a theme, but this code does not work:
export const buttonTheme = {
colors: {
primary: COL_BASE_YELLOW,
disabled: COL_DARK_HIGHLIGHT,
},
}
<Button
loading={submittedPhoneNumber ? true : false}
mode="contained"
onPress={() => handleSubmitPhoneNumber(phoneNumber)}
theme={buttonTheme}
disabled={phoneNumber.length < 5 ? true : false}>
Continue
</Button>
The primary color works however.
How do I change the color of the button when it is disabled?
Don't use disabled props, it will always make your button grey, if you want to use your desired colour for disabled mode, do it like this :
<Button
loading={submittedPhoneNumber ? true : false}
mode="contained"
onPress={phoneNumber.length < 5 ? () => {} : () => handleSubmitPhoneNumber(phoneNumber)}
color={phoneNumber.length < 5 ? 'darkerColor' : 'fadedColor'}>
Continue
</Button>
From this Github issue:
The text if the contained button depends on the background color of
the button, which is automatically determined based on of the
background color is light it dark. Wherever theme is dark or not
doesn't affect it.
This is the desired behavior. We don't want to show white text on a
light background because you have a dark theme, otherwise the text
won't have enough contrast and will be illegible.
Changing the theme to dark changes the disabled button color, as I tested. Apart from this, I don't think its possible if you use react-native-paper. The author has decided to automatically set the color & background color of the button based on something, but his language is unclear.
However, you can give a labelStyle prop the button directly, and you could have a conditional in that style.
<Button labelStyle={{ color: phoneNumber.length < 5 ? 'red' : 'green' }}>
or,
[buttonDisabled, setButtonDisabled] = useState(false); // put this outside the render function.
<Button disabled={disabled} labelStyle={{ color: disabled ? 'red' : 'green' }}>
I'm may be late but here's my solution:
<Button
id="save-phonenumber"
color="darkColor">
onClick={doSomething}
disabled={phoneNumber.length < 5 ? true : false}>
<Button/>
In you Css file you can add
Button#save-phonenumber[disabled] {
background: "fadedColor"
}
Benefit of using this approach is that you don't additionally need to disable the clicking effect when the button is disabled.
If you're caring about light and dark themes at the moment, then you can achieve your goal like this -
I would suggest creating your own Button Component on the top of Paper Button.
// extending default Paper Button Component
<PaperButton style={[ props.disabled && { backgroundColor: 'cccccc' } ]}>
{children}
</PaperButton>
// Using component...
<MyButton disabled={disabled}>
Click Me!
</MyButton>
I have been using Styled-components with React web for a while now, but recently I have started working on a React Native app which I decided to use styled-compoents in. It's been great when styling components that have just the style property, such as the default react-native components.
The problem I've been having though is when I need to style a more complex component that has multiple style properties such as containerStyle, inputStyle, and others.
When it's only one style property with a different name I can do the following:
const StyledBadge = styled(({ style, ...rest }) => {
return <Badge {...rest} containerStyle={style} />;
})`
position: absolute;
right: 0;
top: 0;
`;
This works flawlessly but when the component has multiple styles, I have no idea what to do:
const StyledList = styled(({ style, ...rest }) => {
return <List {...rest} containerStyle={style} searchInputStyle={?} searchItemStyle={?} />;
})`
`;
With components like Gifted-React-Native-Chat is even worse because it has properties for passing properties as objects to its internal components, such as messageProps, listViewProps, containerProps and all of them have the style property.
Does anyone have any idea how to do that or if it's even possible?
I've been searching and trying to find a solution for this for a few days but I can't.
Thanks!
Here's how we ended up doing it.
Styled-components only work with the style prop but many custom components don't expose this prop. Instead they provide a *Style prop that gets passed to child component style props.
As an example, react-native-material-textfield has 5 style props.
We use the attrs function to keep the organization of styles in one file with the rest of the styled components.
This doesn't allow you to use traditional css syntax for the pseudo component, but it's the best we could think of to keep all styles organized.
This would bind background-color property to the <td> element.
<td :style="{backgroundColor: (props.item.release_date ? 'green' : 'transparent' ) }">
Some text
</td>
But what if I want to bind NOT ONLY the backgound-color same time I want to bind the foreground color (Normal color property) as well.
How do I bind multiple style properties to an element?
First of all, there's no foreground color in css. You can use multiple style with comma separated key: value pairs like:
:style="{
backgroundColor: (props.item.release_date ? 'green' : 'transparent' ),
color: 'red',
width: '120px'
}"
I was in a situation where I couldn't put all the styles in one object so I found this alternate way of style binding in vue:
vue style binding, Object syntax
vue style binding, Array syntax
basically you can have multiple style object and pass them as array to the style attribute like this:
:style="[styleObjectOne, styleObjectTwo]"