I am new to React Native and currently learning on developing a chat app.
I have a Modal that contain Rating UI
Working with these approach
ChatScreen.js
<Modal isVisible={showRateModal} >
<RatingModal />
</Modal>
RatingModal.js
<View style={styles.container}>
<RatingEmojiSection />
<View style={styles.buttonContainer}>
<Button/>
</View>
</View>
Not Working
It works all fine but when I move `Modal` into `RatingModal.js`, the Modal wont be showing anymore. Here is my approach
import { Modal } from 'react-native-paper';
<Modal isVisible={showRateModal} >
<View style={styles.container}>
<RatingEmojiSection />
<View style={styles.buttonContainer}>
<Button/>
</View>
</View>
</Modal>
Anyone have idea why this could happen? PS: the showRateModal state is working fine. I just curious why can't I move the Modal wrapper into RatingModal.js?
I think there are two problems with your current code
First you are rendering two Modals: ChatScreen.js contains a <Modal>, and then you RatingModal code also contains a <Modal> rendering.
Second: from the react-native docs you can see that the required property is not isVisible but visible.
Fixing these two issues should fix your problem.
Related
I have a small ReactNative app in Expo Snack that includes a single components with a TouchableOpacity.
export default function AssetExample() {
function clicked() {
alert('clicked')
}
return (
<View style={styles.container}>
<TouchableOpacity onPress={clicked()}>
<Text style={styles.paragraph}>
Click the icon
</Text>
<Image style={styles.logo} source={require('../assets/snack-icon.png')} />
</TouchableOpacity>
</View>
);
}
Every time the app is started the alert is shown, meaning TouchableOpacity triggers onPress. Why? And how can I circumvent this?
You should pass the reference of your function to TouchableOpacity like this
<TouchableOpacity onPress={clicked}>
</TouchableOpacity>
or pass it with arrow function
<TouchableOpacity onPress={()=> clicked()}>
</TouchableOpacity>
so it will be called inside TouchableOpacity component whenever required (button click), otherwise it will be called only one time during render phase.
See these docs for handling events in React https://reactjs.org/docs/handling-events.html
I'm a new react native developer and I have an issue with TouchableHighlight where it always shows an error "Error: React.Children.only expected to receive a single React element child." in addition while I remove it is work as usual and I assume if this issue come from my device/vscode/browser. Because I already follow the source code from https://reactnative.dev/docs/touchablehighlight but still show that error.
Error image
Image without TouchableHighlight tag
Here my code
render() {
return (
<View style={styles.container}>
<TouchableHighlight onPress={this.onPress}>
<View style={styles.button}>
<Text>Touch Here</Text>
</View>
</TouchableHighlight>
<View style={[styles.countContainer]}>
<Text style={[styles.countText]}>
{this.state.count ? this.state.count : null}
</Text>
</View>
</View>
);}
From the error message, the issue might happen if you pass Mutlipe child components to TouchableHighlight
From the docs:
TouchableHighlight must have one child (not zero or more than one). If you wish to have several child components, wrap them in a View
<TouchableHighlight onPress={onPress}>
<View style={styles.button}> // Mutlipe child components are wrapped in a View
<Text>Touch</Text> // component 1
<Text>Here</Text> // component 2
</View>
</TouchableHighlight>
I make check box list on Model Pop up by using react native multiple select
checkbox list listed but it take full screen height
i am not able to fix this issue
please Any body help me
Outer Element would be a modal, then make a view of a specific height inside that modal,
Example
<Modal transparent={true}
visible={this.state.showDialog}
animationType='fade'>
<View style={{opacity:.5, backgroundColor:'black',flex:1}}/>
<View
style={{position:'absolute',padding:16,top:0,bottom:0,left:0,right:0
,justifyContent:'center',alignContent:"center",
alignItems:'center'}}>
<View style={{backgroundColor:’red’,padding:16,borderRadius:5,
width:'60%',height:'10%',alignContent:'center',alignItems:'center',justifyContent:'center'}}>
<Text style={{fontSize:14,alignSelf:'center',textAlign:'center'}}>
Sorry!!
</Text>
<Text style={{marginTop:5,fontSize:12,alignSelf:'center',textAlign:'center',color:’black’}}>
{this.props.errorMessage}
</Text>
<Button title='close'
onPress={()=>this.setState({showDialog:false})}/>
</View>
</View>
</Modal>
enter code hereI want to show a toast when my modal is visible in my react native project.
I use react-native-modal.
I have a button in modal when i press it should show up a toast
I don't want to put my toast tag inside the modal tag
what should i do???
render(){
return(
<>
<Modal visible={this.state.visible}>
<Toast
ref="toast"
style={{backgroundColor:'red'}}
position='bottom'
positionValue={100}
fadeInDuration={1000}
fadeOutDuration={1000}
opacity={0.8}
textStyle={{color:'blue'}}
/>
<SafeAreaView style={{flex:1}}>
<View style={{flex:1,justifyContent:'center',alignItems:'center'}}>
<TouchableOpacity onPress={()=>this.refs.toast.show('hello world!')} style={{height:200,width:100,justifyContent:'center',alignItems:'center',backgroundColor:'blue'}}>
<Text>Modal Button</Text>
</TouchableOpacity>
</View>
</SafeAreaView>
</Modal>
<SafeAreaView style={{flex:1}}>
<View style={{flex:1,justifyContent:'center',alignItems:'center'}}>
<TouchableOpacity onPress={()=>{this.setState({visible:true})}} style={{height:100,width:100,justifyContent:'center',alignItems:'center',backgroundColor:'red'}}>
<Text>button</Text>
</TouchableOpacity>
</View>
</SafeAreaView>
</>
)
}
Actually i wanna be my toast out of my Modal tag but it show in top of screen when modal is visible
react native modal is a native view, so impossible to be covered by a js component.
I’m writing a React Native app and I want to detect tap/clicks anywhere on the screen so I put an onClick handler on my <View> element but it doesn’t seem to be working. Here is my render function:
<View style={styles.container} onClick={this.onClick}>
<Text style={styles.welcome}>
Tap to change the background
</Text>
</View>
What do I need to do?
For making any element to handle touch/click events in a React-Native UI, you need to put the element inside a TouchableOpacity, TouchableWithoutFeedback, TouchableNativeFeedback or TouchableHighlight element:
<TouchableHighlight onPress = { this.onClick }>
<View style={styles.container}>
<Text style={styles.welcome}>
Tap to change the background
</Text>
</View>
</TouchableHighlight>
Hope that helps.
In React Native version > 55.3 you make check onPress events into your View if use onStartShouldSetResponder props.
Like example:
<View
style={{ flex: 1 }}
onStartShouldSetResponder={() => console.log('You click by View')}
>
<ScrollView
refreshControl={
<RefreshControl
refreshing={this.state.refreshing}
onRefresh={this.onRefresh} />
}
>
<Text>Awesome</Text>
</ScrollView>
</View>
In example I showed how you can get onPress event on View and not blocking other event behind them. Refresh control still work correct.
In my case the following works fine. You can use onTouchStart and onTouchEnd handlers on any View via props, for example:
<View onTouchStart={() => this.doSomething()} />
More information
This worked for me...
onTouchEnd={() => alert('TAPPED')}
The easiest way to do that:
<TouchableOpacity style={styles.container} onPress={()=> whateverFunc(parameter)}>
<Text style={styles.welcome}>
Tap to change the background
</Text>
</TouchableOpacity>
So, you need to replace the 'View' component to a 'TouchableOpacity' or any other Touchable component and you also need to replace the 'onClick' prop to 'onPress'. That's all. The wrapping of a view with a TouchableWhatever component is not necessary at all.