My data looks like below
with test(col) as (
select '01-06' from dual union all
select '45-52' from dual
) select col from test ;
Required OP
COL
01
02
.
.
.
06
45
46
.
.
52
Actually my table count is 20 thousand. I used connect by but its very slow.
You can generate values using recursive query:
with test(col) as (
select '01-06' from dual union all
select '45-52' from dual
), bounds (l,u) as (
select to_number(substr(col,1,2)), to_number(substr(col,4,2)) from test
), r (l,u) as (
select l,u from bounds
union all
select r.l + 1, r.u from r where r.l < r.u
)
select to_char(l,'00') from r order by l;
(edit substr expressions appropriately if any value is not 2-digit)
Saying "I used connect by but its very slow" without posting code you wrote doesn't help much. I presume you did it wrong, i.e. got too many duplicate values which slowed things down. See if this connect by option helps.
SQL> with test (col)
2 as
3 (select '1-6' from dual
4 union all
5 select '45-52' from dual
6 )
7 select lpad(to_number(substr(col, 1, instr(col, '-') - 1)) + column_value - 1, 2, '0') val
8 from test cross join
9 table(cast(multiset(select level from dual
10 connect by level <= to_number(substr(col, instr(col, '-') + 1)) -
11 to_number(substr(col, 1, instr(col, '-') - 1)) + 1
12 ) as sys.odcinumberlist));
VAL
---
01
02
03
04
05
06
45
46
47
48
49
50
51
52
14 rows selected.
SQL>
Related
I am trying to select all the values from multivalued data column. Values are separated with ý.
This query I wrote does exactly what I intended, but unfortunately I am working on 11g so I can't use CROSS APPLY. Any suggestions how to go around CROSS APPLY? Or any other ideas?
select REGEXP_SUBSTR (MFIELD, '([^ý]+)',1,l.lvl,NULL) AS item
FROM TABLE
CROSS APPLY
(
SELECT LEVEL AS lvl
FROM DUAL
CONNECT BY LEVEL <= REGEXP_COUNT( MFIELD, 'ý' )
)l;
Switch to
SQL> WITH
2 my_table (mfield)
3 AS
4 (SELECT 'abcýdef' FROM DUAL
5 UNION ALL
6 SELECT 'xyzýmnoýzzz' FROM DUAL
7 UNION ALL
8 SELECT 'ý18524ý2879' FROM DUAL)
9 SELECT mfield,
10 REGEXP_SUBSTR (mfield,
11 '[^ý]+',
12 1,
13 COLUMN_VALUE) AS item
14 FROM my_table
15 CROSS JOIN
16 TABLE (
17 CAST (
18 MULTISET (
19 SELECT LEVEL
20 FROM DUAL
21 CONNECT BY LEVEL <=
22 REGEXP_COUNT (LTRIM (mfield, 'ý'), 'ý') + 1)
23 AS SYS.odcinumberlist));
MFIELD ITEM
----------- -----------
abcýdef abc
abcýdef def
xyzýmnoýzzz xyz
xyzýmnoýzzz mno
xyzýmnoýzzz zzz
ý18524ý2879 18524
ý18524ý2879 2879
7 rows selected.
SQL>
I am trying to find out all the tables where table names consist of numbers less than a fixed number 16284961 at the end preceded by an underscore for example LOG_16282961.
Sample User_segments table:
Segment_name Bytes
---------------------------------------
LOG_16282961 34
BAL1_16282961 78
BIN$xIDte/qXAFbgU4IeBEeQpw==$0 12
EXCH_16282961 28
C$_0LOG_16282961 17
LOG_16283961 89
BAL1_16283961 10
BIN$xIDte/qWAFbgU4IeBEeQpw==$0 19
EXCH_16283961 90
C$_0LOG_16283961 45
LOG_16284961 21
BAL1_16284961 81
BIN$w1RLAvSeAWjgU4IeBEe2Mw==$0 33
EXCH_16284961 67
C$_0LOG_16284961 39
.......................................
.......................................
Expected Output:
Segment_name Bytes
----------------------
LOG_16282961 34
BAL1_16282961 78
EXCH_16282961 28
C$_0LOG_16282961 17
LOG_16283961 89
BAL1_16283961 10
EXCH_16283961 90
C$_0LOG_16283961 45
.......................
.......................
Query:
SELECT segment_name, bytes/1024/1024 AS "SIZE in MB" FROM user_segments WHERE segment_type='TABLE' AND to_number(regexp_substr(segment_name, '[0-9]+')) < 16284961;
Using above query, although I am getting my result but additionally it also includes following tables which are not required in my output:
BIN$xIDte/qXAFbgU4IeBEeQpw==$0 12
BIN$xIDte/qWAFbgU4IeBEeQpw==$0 19
BIN$w1RLAvSeAWjgU4IeBEe2Mw==$0 33
Can you please help fix my query to get the desired output? Thanks.
Here's one way - using regexp_substr to isolate one or more consecutive digits at the end of the input string, only if immediately preceded by underscore. (If the string does not have that structure, regexp_substr returns null and the filter condition becomes null < [something], which is never true.)
Create mock-up table for testing:
create table test_data (segment_name, bytes) as
select 'LOG_16282961' , 34 from dual union all
select 'BAL1_16282961' , 78 from dual union all
select 'BIN$xIDte/qXAFbgU4IeBEeQpw==$0', 12 from dual union all
select 'EXCH_16282961' , 28 from dual union all
select 'C$_0LOG_16282961' , 17 from dual union all
select 'LOG_16283961' , 89 from dual union all
select 'BAL1_16283961' , 10 from dual union all
select 'BIN$xIDte/qWAFbgU4IeBEeQpw==$0', 19 from dual union all
select 'EXCH_16283961' , 90 from dual union all
select 'C$_0LOG_16283961' , 45 from dual union all
select 'LOG_16284961' , 21 from dual union all
select 'BAL1_16284961' , 81 from dual union all
select 'BIN$w1RLAvSeAWjgU4IeBEe2Mw==$0', 33 from dual union all
select 'EXCH_16284961' , 67 from dual union all
select 'C$_0LOG_16284961' , 39 from dual
;
Query and output:
select *
from test_data
where to_number(regexp_substr(segment_name, '_(\d+)$', 1, 1, null, 1))
< 16284961
;
SEGMENT_NAME BYTES
------------------------------ ----------
LOG_16282961 34
BAL1_16282961 78
EXCH_16282961 28
C$_0LOG_16282961 17
LOG_16283961 89
BAL1_16283961 10
EXCH_16283961 90
C$_0LOG_16283961 45
If query you wrote works, just omit tables you don't want. Those you mentioned have been dropped and are now in recycle bin. So, either purge recyclebin before running the query, or use additional condition, e.g.
SELECT segment_name, bytes / 1024 / 1024 AS "SIZE in MB"
FROM user_segments
WHERE segment_type = 'TABLE'
AND substr(segment_name, 1, 4) <> 'BIN$' --> this
AND TO_NUMBER (REGEXP_SUBSTR (segment_name, '[0-9]+')) < 16284961;
I have table with column having data in below format in Oracle DB.
COL 1
abc,mno:EMP
xyz:EMP;tyu,opr:PROF
abc,mno:EMP;tyu,opr:PROF
I am trying to convert the data in below format
COL 1
abc:EMP;mno:EMP
xyz:EMP;tyu:PROF;opr:PROF
abc:EMP;mno:EMP;tyu:PROF;opr:PROF
Basically trying to get everything after : and before ; to move it substitute comma with it.
I tried some SUBSTR and LISTAGG but couldn't get anything worth sharing.
Regards.
Here's one option; read comments within code.
SQL> with test (id, col) as
2 -- sample data
3 (select 1, 'abc,mno:EMP' from dual union all
4 select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
5 select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual
6 ),
7 temp as
8 -- split sample data to rows
9 (select id,
10 column_value cv,
11 regexp_substr(col, '[^;]+', 1, column_value) val
12 from test cross join
13 table(cast(multiset(select level from dual
14 connect by level <= regexp_count(col, ';') + 1
15 ) as sys.odcinumberlist))
16 )
17 -- finally, replace comma with a string that follows a colon sign
18 select id,
19 listagg(replace(val, ',', substr(val, instr(val, ':')) ||';'), ';') within group (order by cv) new_val
20 from temp
21 group by id
22 order by id;
ID NEW_VAL
---------- ----------------------------------------
1 abc:EMP;mno:EMP
2 xyz:EMP;tyu:PROF;opr:PROF
3 abc:EMP;mno:EMP;tyu:PROF;opr:PROF
SQL>
Using the answer of littlefoot, if i were to use cross apply i wouldnt need to cast as multiset...
with test (id, col) as
-- sample data
(select 1, 'abc,mno:EMP' from dual union all
select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual
),
temp as
-- split sample data to rows
(select id,
column_value cv,
regexp_substr(col, '[^;]+', 1, column_value) val
from test
cross apply (select level as column_value
from dual
connect by level<= regexp_count(col, ';') + 1)
)
-- finally, replace comma with a string that follows a colon sign
select id,
listagg(replace(val, ',', substr(val, instr(val, ':')) ||';'), ';') within group (order by cv) new_val
from temp
group by id
order by id;
You do not need recursive anything, just basic regex: if the pattern is always something,something2:someCode (e.g. you have no colon before the comma), then it would be sufficient.
with test (id, col) as (
select 1, 'abc,mno:EMP' from dual union all
select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF;something:QWE;something2:QWE' from dual
)
select
/*
Grab this groups:
1) Everything before the comma
2) Then everything before the colon
3) And then everything between the colon and a semicolon
Then place group 3 between 1 and 2
*/
trim(trailing ';' from regexp_replace(col || ';', '([^,]+),([^:]+):([^;]+)', '\1:\3;\2:\3')) as res
from test
| RES |
| :------------------------------------------------------------- |
| abc:EMP;mno:EMP |
| xyz:EMP;tyu:PROF;opr:PROF |
| abc:EMP;mno:EMP;tyu:PROF;opr:PROF |
| abc:EMP;mno:EMP;tyu:PROF;opr:PROF;something:QWE;something2:QWE |
db<>fiddle here
What can I apply as function?
Query:
Select x, f(y) from table where y like '%ab%cd%ef';
sample table(y is sorted alphabatically)
x. y
1 ab
2 ab,cd
3 cd,ef
4 ab,ef,gh,yu
5 de,ef,rt
Expected Output:
Output:
x y
1 ab
2 ab,cd
3 cd,ef
4 ab,ef
5 ef
Use regexp_substr function with connect by level expressions as
with tab(x,y) as
(
select 1,'ab' from dual union all
select 2,'ab,cd' from dual union all
select 3,'cd,ef' from dual union all
select 4,'ab,ef,gh,yu' from dual union all
select 5,'de,ef,rt' from dual
), tab2 as
(
Select x, regexp_substr(y,'[^,]+',1,level) as y
from tab
connect by level <= regexp_count(y,',') + 1
and prior x = x
and prior sys_guid() is not null
), tab3 as
(
select x, y
from tab2
where y like '%ab%'
or y like '%cd%'
or y like '%ef%'
)
select x, listagg(y,',') within group (order by y) as y
from tab3
group by x;
X Y
1 ab
2 ab,cd
3 cd,ef
4 ab,ef
5 ef
Demo
Follow comments written within the code.
SQL> with test (x, y) as
2 -- your sample table
3 (select 1, 'ab' from dual union all
4 select 2, 'ab,cd' from dual union all
5 select 3, 'cd,ef' from dual union all
6 select 4, 'ab,ef,gh,yu' from dual union all
7 select 5, 'de,ef,rt' from dual
8 ),
9 srch (val) as
10 -- a search string, which is to be compared to the sample table's Y column values
11 (select 'ab,cd,ef' from dual),
12 --
13 srch_rows as
14 -- split search string into rows
15 (select regexp_substr(val, '[^,]+', 1, level) val
16 from srch
17 connect by level <= regexp_count(val, ',') + 1
18 ),
19 test_rows as
20 -- split sample values into rows
21 (select x,
22 regexp_substr(y, '[^,]+', 1, column_value) y
23 from test,
24 table(cast(multiset(select level from dual
25 connect by level <= regexp_count(y, ',') + 1
26 ) as sys.odcinumberlist))
27 )
28 -- the final result
29 select t.x, listagg(t.y, ',') within group (order by t.y) result
30 from test_rows t join srch_rows s on s.val = t.y
31 group by t.x
32 order by t.x;
X RESULT
---------- --------------------
1 ab
2 ab,cd
3 cd,ef
4 ab,ef
5 ef
SQL>
I have a column with below sample values
MyColumn
----------
NNNNNYYNNNNNYYNNNNNYYNNNNNYYNNN
NNYYNNNNNYYNNNNNYYNNNNNYYNNN
YYNNNNNYYNNNNNYYNNNNNYYNNNNNYY
YYNNNNNYYNNNNNYYNNNNNYYNNNNNYYN
I want to display the position of 'Y' through SQL select statement.
Below is my SQL query.
SELECT LISTAGG(instr(MyColumn, 'Y', 1, level), ' ') WITHIN
GROUP(
ORDER BY level)
FROM dual
CONNECT BY level < instr(MyColumn, 'Y', 1, level) Y_Position from MyTable;
Output of the query is,
Y_Position
------------
6 7 13 14 20 21 27 28
3 4 10 11 17 18 24 25
1
1
The query is not working for 3rd and 4th rows. How to fix this? Why is it not working?
Your query has invalid syntax as it has two FROM clauses one of which does not have a matching SELECT clause.
It also has:
CONNECT BY level < instr(MyColumn, 'Y', 1, level)
Which will not work when the string starts with a Y as LEVEL is 1 and INSTR( 'YYYY', 'Y', 1, 1 ) is 1 and then the filter is CONNECT BY 1 < 1 which is not true. You want to check that CONNECT BY INSTR( MyColumn, 'Y', 1, LEVEL ) > 0.
You also need another filter to check for the case when there are no Y characters as a hierarchical query will always return at least one row.
You can adapt your query to use a correlated sub-query:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE MyTable( MyColumn ) AS
SELECT 'NNNNNYYNNNNNYYNNNNNYYNNNNNYYNNN' FROM DUAL UNION ALL
SELECT 'NNYYNNNNNYYNNNNNYYNNNNNYYNNN' FROM DUAL UNION ALL
SELECT 'YYNNNNNYYNNNNNYYNNNNNYYNNNNNYY' FROM DUAL UNION ALL
SELECT 'YYNNNNNYYNNNNNYYNNNNNYYNNNNNYYN' FROM DUAL UNION ALL
SELECT 'NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN' FROM DUAL
Query 1:
SELECT (
SELECT LISTAGG( INSTR( t.MyColumn, 'Y', 1, LEVEL ), ' ' )
WITHIN GROUP ( ORDER BY LEVEL )
FROM DUAL
WHERE INSTR( t.MyColumn, 'Y' ) > 0
CONNECT BY INSTR( t.MyColumn, 'Y', 1, LEVEL ) > 0
) AS Y_position
FROM Mytable t
Results:
| Y_POSITION |
|---------------------------|
| 6 7 13 14 20 21 27 28 |
| 3 4 10 11 17 18 24 25 |
| 1 2 8 9 15 16 22 23 29 30 |
| 1 2 8 9 15 16 22 23 29 30 |
| (null) |