SUBSTR to ADD value in oracle - sql

Question

I have table with column having data in below format in Oracle DB.
COL 1
abc,mno:EMP
xyz:EMP;tyu,opr:PROF
abc,mno:EMP;tyu,opr:PROF
I am trying to convert the data in below format
COL 1
abc:EMP;mno:EMP
xyz:EMP;tyu:PROF;opr:PROF
abc:EMP;mno:EMP;tyu:PROF;opr:PROF
Basically trying to get everything after : and before ; to move it substitute comma with it.
I tried some SUBSTR and LISTAGG but couldn't get anything worth sharing.
Regards.

Answer 1

Here's one option; read comments within code.
SQL> with test (id, col) as
2 -- sample data
3 (select 1, 'abc,mno:EMP' from dual union all
4 select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
5 select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual
6 ),
7 temp as
8 -- split sample data to rows
9 (select id,
10 column_value cv,
11 regexp_substr(col, '[^;]+', 1, column_value) val
12 from test cross join
13 table(cast(multiset(select level from dual
14 connect by level <= regexp_count(col, ';') + 1
15 ) as sys.odcinumberlist))
16 )
17 -- finally, replace comma with a string that follows a colon sign
18 select id,
19 listagg(replace(val, ',', substr(val, instr(val, ':')) ||';'), ';') within group (order by cv) new_val
20 from temp
21 group by id
22 order by id;
ID NEW_VAL
---------- ----------------------------------------
1 abc:EMP;mno:EMP
2 xyz:EMP;tyu:PROF;opr:PROF
3 abc:EMP;mno:EMP;tyu:PROF;opr:PROF
SQL>

Answer 2

Using the answer of littlefoot, if i were to use cross apply i wouldnt need to cast as multiset...
with test (id, col) as
-- sample data
(select 1, 'abc,mno:EMP' from dual union all
select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual
),
temp as
-- split sample data to rows
(select id,
column_value cv,
regexp_substr(col, '[^;]+', 1, column_value) val
from test
cross apply (select level as column_value
from dual
connect by level<= regexp_count(col, ';') + 1)
)
-- finally, replace comma with a string that follows a colon sign
select id,
listagg(replace(val, ',', substr(val, instr(val, ':')) ||';'), ';') within group (order by cv) new_val
from temp
group by id
order by id;

Answer 3

You do not need recursive anything, just basic regex: if the pattern is always something,something2:someCode (e.g. you have no colon before the comma), then it would be sufficient.
with test (id, col) as (
select 1, 'abc,mno:EMP' from dual union all
select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF;something:QWE;something2:QWE' from dual
)
select
/*
Grab this groups:
1) Everything before the comma
2) Then everything before the colon
3) And then everything between the colon and a semicolon
Then place group 3 between 1 and 2
*/
trim(trailing ';' from regexp_replace(col || ';', '([^,]+),([^:]+):([^;]+)', '\1:\3;\2:\3')) as res
from test
| RES |
| :------------------------------------------------------------- |
| abc:EMP;mno:EMP |
| xyz:EMP;tyu:PROF;opr:PROF |
| abc:EMP;mno:EMP;tyu:PROF;opr:PROF |
| abc:EMP;mno:EMP;tyu:PROF;opr:PROF;something:QWE;something2:QWE |
db<>fiddle here