I am creating an executable to basically do a data guard task
I execute that file from another executable with code
putty.exe -ssh servername -l usernsme -pw password -m C:/auotomation/dgmgrl.sh
and the code in the file is
entdexport ORACLE_BASE=/u01/app/oracle
export ORACLE_HOME=/u01/app/oracle/product/12.1.0/NonValidated
export ORACLE_HOSTNAME=servername
export ORACLE_SID=ERIPRD
export PATH=/u01/app/oracle/product/12.1.0/NonValidated/bin:/usr/sbin:/usr/lib64/qt-
3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/home/oracle/bin
dgmgrl -echo << END
connect /;
show configuration
show database ERIPRD
exit
$SHELL
I have tried adding >> at the end
I can pause my file by adding $SHELL but when inside dgmgrl or sqlplus I am unable to do that.
Without any means of testing it (I neither have a windows machine nor an oracle server) - try this:
export ORACLE_BASE=/u01/app/oracle
export ORACLE_HOME=/u01/app/oracle/product/12.1.0/NonValidated
export ORACLE_HOSTNAME=servername
export ORACLE_SID=ERIPRD
export PATH=/u01/app/oracle/product/12.1.0/NonValidated/bin:/usr/sbin:/usr/lib64/qt-
3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/home/oracle/bin
dgmgrl -echo << END
connect /;
show configuration
show database ERIPRD
exit
END
bash -l
I assume that the exit is meant to be interpreted by dgmgrl, not the shell?
Related
Something I love about VS Code is that when I am using a terminal in WSL, I can run code file.txt, and it will open that file with VS Code on my local using the WSL remote extension.
Is it possible to do a similar thing with SSH? I.e., if I am SSH'ed into a remote host, is it possible to set things up so that running code file.txt will open VS Code on my local machine, connected via the remote SSH extension to open that file?
I found much better & simple answer thanks to this post.
Simply create new script file named code with below contents & put file under any folder from $PATH. (echo $PATH to see what folders you can use)
#! /usr/bin/env zsh
local max_retry=10
for i in {1..$max_retry}
do
local script=$(echo ~/.vscode-server/bin/*/bin/remote-cli/code(*oc[$i]N))
if [[ -z ${script} ]]
then
echo "VSCode remote script not found"
exit 1
fi
local socket=$(echo /run/user/$UID/vscode-ipc-*.sock(=oc[$i]N))
if [[ -z ${socket} ]]
then
echo "VSCode IPC socket not found"
exit 1
fi
export VSCODE_IPC_HOOK_CLI=${socket}
${script} $# > /dev/null 2>&1
if [ "$?" -eq "0" ]; then
exit 0
fi
done
echo "Failed to find valid VS Code window"
Bash version
#! /bin/bash
max_retry=10
for i in $(seq 1 $max_retry)
do
recent_folder=$(ls ~/.vscode-server/bin/ -t | head -n$i)
script=$(echo ~/.vscode-server/bin/$recent_folder/bin/remote-cli/code)
if [[ -z ${script} ]]
then
echo "VSCode remote script not found"
exit 1
fi
socket=$(ls /run/user/$UID/vscode-ipc-* -t | head -n$i)
if [[ -z ${socket} ]]
then
echo "VSCode IPC socket not found"
exit 1
fi
export VSCODE_IPC_HOOK_CLI=${socket}
${script} $#
if [ "$?" -eq "0" ]; then
exit 0
fi
done
echo "Failed to find valid VS Code window"
Update
Above script doesn't work with recent updates. I had to change first line to
local script=$(echo ~/.vscode-server/bin/*/bin/remote-cli/code(*oc[1]N))
Update2
Original script may fail if recently opened ssh window is closed, yet there is another SSHed window open. I have enhanced the script to enable retrying the command with recent N(default 10) windows.
You shouldn't have to do anything. VSCode automatically sets the path/PATH to the code in the path/PATH environment variable depending on your shell. See this response. You might be overwriting your path/PATH like I was. I was accidentally overwriting path in ~/.cshrc and PATH in ~/.bashrc and was running into the same issue. After fixing it, I can run code on the command line. which code returns the location of the command.
Until I spent time to figure it out, I was using the two methods mentioned below. Both of which worked for me in bash; you can modify it for your shell as you see fit. But really fix your path/PATH rather than using these methods.
Adding location of code to the PATH in ~/.bashrc
export PATH=${VSCODE_GIT_ASKPASS_NODE%/*}/bin:$PATH
OR
Setting alias to code in ~/.bashrc
alias code="${VSCODE_GIT_ASKPASS_NODE%/*}/bin/code"
More on path vs. PATH here and here
Yes, sort of.
From a VSCode terminal run the command
env | grep VSCODE_IPC_HOOK_CLI
then copy-and-paste that line that line with export into your ssh terminal.
After that, you should be able to run code from your ~/.vscode-server/bin/XXX/bin directory.
VSCode terminal
SSH terminal
Update:
You can to automate this with a .bashrc and .profile to place the IPC code into a temp file, and source that when you do your ssh login.
For example, this works for me...
Append this to ~/.bashrc
#
if [ "$VSCODE_IPC_HOOK_CLI" != "" ]; then
cat >$HOME/.vscode_env.sh <<EOF
#
if [ "\$VSCODE_IPC_HOOK_CLI" = "" ]; then
export VSCODE_IPC_HOOK_CLI="$VSCODE_IPC_HOOK_CLI"
alias code="${VSCODE_GIT_ASKPASS_NODE%/*}/bin/code"
fi
EOF
fi
And append this to your ~/.profile
[ -f $HOME/.vscode_env.sh ] && . $HOME/.vscode_env.sh
(There may be more elegant ways. And you still have to start at least 1 terminal in your remote VSCode session.)
this works to me
if [[ -n "$SSH_CLIENT" || -n "$SSH_TTY" ]]; then
local script=$(echo ~/.vscode-server/bin/*/bin/remote-cli/code(*oc[1]N))
if [[ -z ${script} ]]
then
echo "VSCode remote script not found"
exit 1
fi
local socket=$(echo /run/user/$UID/vscode-ipc-*.sock(=oc[1]N))
if [[ -z ${socket} ]]
then
echo "VSCode IPC socket not found"
exit 1
fi
export VSCODE_IPC_HOOK_CLI=${socket}
alias code=${script}
fi
Use the below commands to open a folder or a file on the remote terminal.
Note: vscode-server must be already installed on the remote host (It would be, if you have already connected to it). Also the absolute path has to be specified for the file or folder. Use -n to launch in new window,-r to reuse same window.
code --folder-uri <absolute-path>
code --file-uri <absolute-path-file-name>
Example:
code -r --folder-uri /home/myscripts/src
code -n --file-uri /home/myscripts/src/math/sample.py
I'm trying to set up an environment to execute BTEQ script via shell script in the local machine. On running the shell script I'm getting an error of BTEQ: Command not found. Not sure what I'm doing wrong.
I've created a separate .tdlogon file which contains .LOGON credentials. BTEQ script is a simple create table statement that I'm trying to execute.
My .tdlogon file is something like
.logon servername/uname,pwd
I'm calling the file like this
#!/bin/bash
server_path=/Users/xyz/xyz
log_path=/Users/xyz/xyz/logs
echo -e 'Starting the script'>> ${log_path}/test_log.log
cat ${server_path}/.tdlogon ${server_path}/code/temp_query.btq | bteq >> ${log_path}/test_log.log 2>&1
if [ ${rtn_code} -ne 0 ] ; then
echo -e 'Script completed successfully'>> ${log_path}/test_log.log
exit 0
else
echo -e 'Error in the script'>> ${log_path}/test_log.log
exit 1
fi
On executing the above code I'm getting below error in the log file
line 10: bteq: command not found
Appreciate any guidance related to this.
Seems like your Linux is not pointing to the bteq path. Update the bteq path:
export PATH=/usr/bin/bteq:$PATH
And, in some cases, there will be bteq32 instead of bteq in that case set path as:
export PATH=/usr/bin/bteq32:$PATH
I am trying to run a script in AIX to execute another script on a remote server. In addition to the remote script i need to send the stdout to /dev/null. The same command works fine on another server but when I run on the current server it hangs, any advice?
su - test -c "rsh testserver /scripts/testme" 2>&1 >/dev/null1
In your comment you write that a menu is presented when the user logins.
Let's say this is done in the .profile file, using echoes and a read command.
When a menu is presented, the read command in the menu code will not be skipped by redirecting the output. The menu still waits for your input and the su command seems to hang.
Can you change your .profile or .bashrc so that it will skip presenting the menu when called using a su command? When this is called during startup, you can look at the returncode of tty. When you use the su command from the commandline, you should look for another solution.
When your root shell is ksh, you can try the following:
if [[ "$(ps -fp $$)" != *"-ksh -c "* ]]; then
echo "Now I should call the Menu"
fi
Is there a way to execute a command before accessing a remote terminal
When I enter this command:
bash
$> ssh user#server.com 'ls'
The ls command is executed on the remote computer but ssh quits and I cannot continue in my remote session.
Is there a way of keeping the connection? The reason that I am asking this is that I want to create a setup for ssh session without having to modify the remote .bashrc file.
I would force the allocation of a pseudo tty and then run bash after the ls command:
syzdek#host1$ ssh -t host2.example.com 'ls -l /dev/null; bash'
-rwxrwxrwx 1 root other 27 Apr 1 2005 /dev/null
bash-4.1$
You can try using process subsitution on the init file of bash. In the example below, I define a function myfunc:
myfunc () {
echo "Running myfunc"
}
which I transform to a properly-escaped one-liner echoed in the <(...) construct for process subsitution for the --init-file argument of bash:
$ ssh -t localhost 'bash --init-file <( echo "myfunc() { echo \"Running myfunc\" ; }" ) '
Password:
bash-3.2$ myfunc
Running myfunc
bash-3.2$ exit
Note that once connected, my .bashrc is not sourced but myfunc is defined and properly usable in an interactive session.
It might prove a little difficult for more complex bash functions, but it works.
I have a .sql file that was created by postgresql a while back. I now want to import this file onto a windows machine running postgresql.
How do I do this. The file is about 1.5gb.
You should use psql command line tool:
psql -h hostname -p port_number -U username -f your_file.sql databasename
click on the SQL Shell and log into the database and use import
Server [localhost]:
Database [postgres]:
Port [5432]:
Username [postgres]:
Password for user postgres:
psql (9.2.4)
WARNING: Console code page (437) differs from Windows code page (1252)
8-bit characters might not work correctly. See psql reference
page "Notes for Windows users" for details.
Type "help" for help.
postgres=# \i c:/data/data01.sql
start you psql command tool, it will give you dialog like the following
Server [localhost]:
Database [postgres]:
Port [5432]:yourport
Username [postgres]:
Password for user postgres:**********
then connect to your database
postgres=# \c yourdatabase;
then import the file
yourdatabase=# \i c:/path/path/data/data01.sql
note the / for directory separator & no spaces in file path
This also works for me:
psql dbname username < file.sql
command prompt
open your cmd window and type the following (make sure the path of postgres is correct)
."C:\Program Files\PostgreSQL\9.4\bin\psql.exe" -h 127.0.0.1 -p 5432 -U postgres -d dbname <./query.sql
psql -U <dbusername>
if the prompt makes you enter password, do that.
\c <yourdatabasename>
\i 'thepathusing/delimiter.sql'
Two points you need to watch out that
Use / as writing path of the file instead of \.
Use single quote
symbol ' instead of ".
If you're doing it with a URI connection string make sure the arguments are before the URI, Powershell examples:
Works on windows:
.\psql -f TestFile.sql $connString
.\psql -c 'SELECT Version();' $connString
Won't work on windows (URI connection before arguments):
.\psql $connString -c 'SELECT Version();'