I have below sample values in a column
Abc-123-xyz
Def-456-uvw
Ghi-879-rst-123
Jkl-abc
Expected output is the third element split by '-', in case there is no third element, the last element will be retrieve.
See expected output below:
Xyz
Uvw
Rst
Abc
Thanks ahead for the help.
SELECT initcap(nvl(regexp_substr(word, '[^-]+', 1,3),regexp_substr(word, '[^-]+', 1,2))) FROM your_table;
Another approach:
SQL> with t1(col) as(
2 select 'Abc-123-xyz' from dual union all
3 select 'Def-456-uvw' from dual union all
4 select 'Ghi-879-rst-123' from dual union all
5 select 'Jkl-Abc' from dual
6 )
7 select regexp_substr( col
8 , '[^-]+'
9 , 1
10 , case
11 when regexp_count(col, '[^-]+') >= 3
12 then 3
13 else regexp_count(col, '[^-]+')
14 end
15 ) as res
16 from t1
17 ;
Result:
RES
---------------
xyz
uvw
rst
Abc
regexp_substr(column, '(.*?-){0,2}([^-]+)', 1, 1, '', 2)
You can also do it without RegEx:
with t1 as(
select 'Abc-123-xyz' as MyText from dual union all
select 'Def-456-uvw' from dual union all
select 'Ghi-879-rst-123' from dual union all
select 'Jkl-Abc' from dual
)
SELECT
SUBSTR(t1.mytext, LENGTH(t1.mytext) - INSTR(REVERSE(t1.mytext), '-') + 2)
FROM t1
;
Related
I have table with column having data in below format in Oracle DB.
COL 1
abc,mno:EMP
xyz:EMP;tyu,opr:PROF
abc,mno:EMP;tyu,opr:PROF
I am trying to convert the data in below format
COL 1
abc:EMP;mno:EMP
xyz:EMP;tyu:PROF;opr:PROF
abc:EMP;mno:EMP;tyu:PROF;opr:PROF
Basically trying to get everything after : and before ; to move it substitute comma with it.
I tried some SUBSTR and LISTAGG but couldn't get anything worth sharing.
Regards.
Here's one option; read comments within code.
SQL> with test (id, col) as
2 -- sample data
3 (select 1, 'abc,mno:EMP' from dual union all
4 select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
5 select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual
6 ),
7 temp as
8 -- split sample data to rows
9 (select id,
10 column_value cv,
11 regexp_substr(col, '[^;]+', 1, column_value) val
12 from test cross join
13 table(cast(multiset(select level from dual
14 connect by level <= regexp_count(col, ';') + 1
15 ) as sys.odcinumberlist))
16 )
17 -- finally, replace comma with a string that follows a colon sign
18 select id,
19 listagg(replace(val, ',', substr(val, instr(val, ':')) ||';'), ';') within group (order by cv) new_val
20 from temp
21 group by id
22 order by id;
ID NEW_VAL
---------- ----------------------------------------
1 abc:EMP;mno:EMP
2 xyz:EMP;tyu:PROF;opr:PROF
3 abc:EMP;mno:EMP;tyu:PROF;opr:PROF
SQL>
Using the answer of littlefoot, if i were to use cross apply i wouldnt need to cast as multiset...
with test (id, col) as
-- sample data
(select 1, 'abc,mno:EMP' from dual union all
select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual
),
temp as
-- split sample data to rows
(select id,
column_value cv,
regexp_substr(col, '[^;]+', 1, column_value) val
from test
cross apply (select level as column_value
from dual
connect by level<= regexp_count(col, ';') + 1)
)
-- finally, replace comma with a string that follows a colon sign
select id,
listagg(replace(val, ',', substr(val, instr(val, ':')) ||';'), ';') within group (order by cv) new_val
from temp
group by id
order by id;
You do not need recursive anything, just basic regex: if the pattern is always something,something2:someCode (e.g. you have no colon before the comma), then it would be sufficient.
with test (id, col) as (
select 1, 'abc,mno:EMP' from dual union all
select 2, 'xyz:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF' from dual union all
select 3, 'abc,mno:EMP;tyu,opr:PROF;something:QWE;something2:QWE' from dual
)
select
/*
Grab this groups:
1) Everything before the comma
2) Then everything before the colon
3) And then everything between the colon and a semicolon
Then place group 3 between 1 and 2
*/
trim(trailing ';' from regexp_replace(col || ';', '([^,]+),([^:]+):([^;]+)', '\1:\3;\2:\3')) as res
from test
| RES |
| :------------------------------------------------------------- |
| abc:EMP;mno:EMP |
| xyz:EMP;tyu:PROF;opr:PROF |
| abc:EMP;mno:EMP;tyu:PROF;opr:PROF |
| abc:EMP;mno:EMP;tyu:PROF;opr:PROF;something:QWE;something2:QWE |
db<>fiddle here
I have to find the name like : Robert#jr23 (There must be Alphabet,Any Special characters or Numbers except hyphen(-),apostrophe (') and Space).
I was doing as below:
select * from test where REGEXP_LIKE(trim(NAME_1), '[^- '']')
But I am not getting the right results with this.
Need to match:
Kevin#123
bob#jr
mike$dr
Needs to exclude:
Alex-jr
Robert'jr
Brian jr
You need to use not with a pattern matching the values you want to exclude. Otherwise you are matching strings that contain any character that is not in the exclusion list, which is all of them.
select column_value
from ora_mining_varchar2_nt
( 'Kevin#123'
, 'bob#jr'
, 'mike$dr'
, 'Alex-jr'
, 'Robert''jr'
, 'Brian jr'
, 'A!' )
where 1=1
and not regexp_like(column_value,'[- '']')
and regexp_like
(column_value, '([A-Z0-9]+[^A-Z0-9])|([^A-Z0-9]+[A-Z0-9])', 'i') ;
Edit: added a regex_like condition to ensure that values contain a letter or digit and a 'special character', meaning here a character that is neither a letter, digit or space, ' or -.
You can use following query to include all special characters except space, - and '
SQL> with tbl(name) as (
2 select 'Kevin#123' from dual union
3 select 'bob#jr' from dual union
4 select 'mike$dr' from dual union
5 select 'Alex-jr' from dual union
6 select 'Brian jr' from dual union
7 select 'Brian)jr' from dual union
8 select 'Robert''jr' from dual
9 )
10 select *
11 from tbl
12 where regexp_like(name, '[^[a-z]|[A-Z]|[:space:]|[:cntrl:]|/]')
13 and not regexp_like(name,'[- '']');
NAME
---------
Brian)jr -- see this is included
Kevin#123
bob#jr
mike$dr
SQL>
One option is to replace everything that's valid with NULL, and what remains is invalid:
SQL> with test (col) as
2 (select 'Robert#jr23' from dual union all
3 select 'Kevin#123' from dual union all
4 select 'bob#jr' from dual union all
5 select 'mike$dr' from dual union all
6 select 'Alex-jr' from dual union all
7 select 'Robert''jr' from dual union all
8 select 'Brian jr' from dual
9 )
10 select col
11 From test
12 where regexp_replace(col, '[[:alpha:]]|[[:digit:]]|-|''', null) is not null;
COL
-----------
Robert#jr23
Kevin#123
bob#jr
mike$dr
Brian jr
SQL>
I'm confused about what you, actually, want to get as a result. Here are some examples which show result of such a regular expression; which IDs do you want to get as a result?
SQL> with test (id, col) as
2 (select 1, 'Robert#jr23' from dual union all
3 select 2, 'Kevin#123' from dual union all
4 select 3, 'bob#jr' from dual union all
5 select 4, 'mike$dr' from dual union all
6 select 5, 'Alex-jr' from dual union all
7 select 6, 'Robert''jr' from dual union all
8 select 7, 'Brian jr' from dual union all
9 select 8, 'Brian10' from dual
10 )
11 select col,
12 regexp_replace(col,
13 '[[:alpha:]]|[[:digit:]]|[[:space:]]|-|''', null) result
14 from test;
COL RESULT
----------- ----------
Robert#jr23 #
Kevin#123 #
bob#jr #
mike$dr $
Alex-jr
Robert'jr
Brian jr
Brian10
8 rows selected.
SQL>
One of your comments says:
select a customer name where there must be a special character or numbers (except space, Hyphen and apostrophe)
which means that numbers and special characters should be treated as "equal". If that's so, does this help?
SQL> with test (id, col) as
2 (select 1, 'Robert#jr23' from dual union all
3 select 2, 'Kevin#123' from dual union all
4 select 3, 'bob#jr' from dual union all
5 select 4, 'mike$dr' from dual union all
6 select 5, 'Alex-jr' from dual union all
7 select 6, 'Robert''jr' from dual union all
8 select 7, 'Brian jr' from dual union all
9 select 8, 'Brian10' from dual
10 )
11 select id, col
12 from test
13 where regexp_replace(col, '[[:alpha:]]|[[:space:]]|-|''', '')
14 is not null;
ID COL
---------- -----------
1 Robert#jr23
2 Kevin#123
3 bob#jr
4 mike$dr
8 Brian10
SQL>
I have values like "ABC1234", "ABC", "DEF456", "GHI" etc. in a specific column which I need.
Now I need to split this string but only if the character (e.g. "ABC") are followed by digits.
So if the value is "ABC1234" then I need to cut out ABC and 1234 seperated. But if there is only "ABC" as a value, I just need the "ABC". I can't find any solution with SUBSTR. Do you have any idea?
Note: The length of the characters can differ from 1 to 10 and also the length from the digits (sometimes there isn't any like I showed you).
So if the value is "ABC1234" then I need to cut out ABC and 1234
seperated. But if there is only "ABC" as a value, I just need the
"ABC".
Amidst of other solutions, I propose one solution as shown below:
Logic:
1) Replace all the digits to 1. Check the position of the digit occurring in the string. If
there is no digit in the string then use the String.
2) Extract the alphabets from 1st position to the position where
digit starts.
3) Extract the digit from the position it starts till end. If digit doesnot exists the set it NULL
--Dataset Preparation
with test (col) as
(select 'ABC1234' from dual union all
select 'ABC' from dual union all
select 'dEfH456' from dual union all
select '123GHI' from dual union all
select '456' from dual
)
--Query
select col Original_Column,
CASE
WHEN (instr(regexp_replace(col,'[0-9]','1'),'1',1)) = 0
then col
else
substr( col,1,instr(regexp_replace(col,'[0-9]','1'),'1',1)-1)
end Col_Alp,
CASE
WHEN (instr(regexp_replace(col,'[0-9]','1'),'1',1)) = 0
then NULL
Else
substr( col,instr(regexp_replace(col,'[0-9]','1'),'1',1))
END col_digit
from test
where regexp_like(col, '^[a-zA-Z0-9]+$');
Result:
SQL> /
Original_Column Col_Alp col_digit
---------- ----- -----
ABC1234 ABC 1234
ABC ABC NULL
dEfH456 dEfH 456
123GHI NULL 123GHI
456 NULL 456
Using SUBSTR (and INSTR and TRANSLATE):
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE data ( value ) AS
SELECT 'ABC1234' FROM DUAL UNION ALL
SELECT 'ABC123D' FROM DUAL UNION ALL
SELECT 'ABC ' FROM DUAL UNION ALL
SELECT 'ABC' FROM DUAL UNION ALL
SELECT 'DEFG456' FROM DUAL UNION ALL
SELECT 'GHI' FROM DUAL UNION ALL
SELECT 'JKLMNOPQRS9' FROM DUAL;
Query 1:
SELECT value,
SUBSTR( value, 1, first_digit - 1 ) AS prefix,
TO_NUMBER( SUBSTR( value, first_digit ) ) AS suffix
FROM (
SELECT value,
INSTR(
TRANSLATE( value, '-1234567890', ' ----------' ),
'-',
1
) AS first_digit
FROM data
)
WHERE SUBSTR( value, first_digit ) IS NOT NULL
AND TRANSLATE( SUBSTR( value, first_digit ), '-1234567890', ' ' ) IS NULL
Results:
| VALUE | PREFIX | SUFFIX |
|-------------|------------|--------|
| ABC1234 | ABC | 1234 |
| DEFG456 | DEFG | 456 |
| JKLMNOPQRS9 | JKLMNOPQRS | 9 |
Try this below query for scenarios mentioned , I didn't split if characters followed by numbers:
with test (col) as
(select 'ABC1234' from dual union all
select 'ABC' from dual union all
select 'dEfH456' from dual union all
select '123GHI' from dual union all
select '456' from dual
)
select col,reverse(trim(regexp_replace(reverse(col),'^[0-9]+',' '))) string ,trim(regexp_replace(col,'^[a-zA-Z]+',' ')) numbers from test
if like to move that characters&string to any place my case statement
with test (col) as
(select 'ABC1234' from dual union all
select 'ABC' from dual union all
select 'dEfH456' from dual union all
select '123GHI' from dual union all
select '456' from dual
)
select v.col,case when v.string=v.numbers THEN NULL ELSE string end string , v.numbers
from (select col,reverse(trim(regexp_replace(reverse(col),'^[0-9]+',' '))) string ,trim(regexp_replace(col,'^[a-zA-Z]+',' ')) numbers from test) v
Would something like this do?
SQL> with test (col) as
2 (select '"ABC1234", "ABC", "dEf456", "123GHI", "456"' from dual),
3 inter as
4 (select trim(regexp_substr(replace(col, '"', ''), '[^,]+', 1, level)) token
5 from test
6 connect by level <= regexp_count(col, ',') + 1
7 )
8 select regexp_substr(token, '^[a-zA-Z]+') letters,
9 regexp_substr(token, '[0-9]+$') digits
10 from inter
11 where regexp_like(token, '^[a-zA-Z]+[0-9]+$');
LETTERS DIGITS
---------- ----------
ABC 1234
dEf 456
SQL>
How can I retrieve values in a row as column values?
Example:
Consider the output of below query as INPUT :
Select 1,2,3,4,5,6,7,8,9,10
from dual;
I need a query that can give below output:
COL1
----
1
2
3
4
5
6
7
8
9
10
SELECT 1 AS "COL1" FROM dual
UNION
SELECT 2 FROM dual
UNION
SELECT 3 FROM dual
UNION
SELECT 4 FROM dual
UNION
SELECT 5 FROM dual
UNION
SELECT 6 FROM dual
UNION
SELECT 7 FROM dual
UNION
SELECT 8 FROM dual
UNION
SELECT 9 FROM dual
UNION
SELECT 10 FROM dual ;
If you want to generate a sequence of numbers in Oracle:
with n as (
select level as n
from dual
connect by level <= 10
)
select *
from n;
Or, if you have 10 columns, you can do an unpivot. An easy way is with union all:
select col1 from t union all
select col2 from t union al
. . .
select col10 from t;
I have a column in the database in the following format: yymmddhh24miss
Sample Data:
140203101241
140202101141
140102101240
143001101244
142801101245
142701131347
142601121542
142101131744
...
I need to get the nearest high value from the list. Ex: If I pass 142701131333, then it should return 142701131347 from the above list.
Any help appreciated!
SELECT data
FROM
(
SELECT data
FROM tbl
WHERE data > '142701131333'
ORDER BY data
) a
WHERE rownum = 1
SQL> with t (x) as (
2 select 140203101241 from dual union all
3 select 140202101141 from dual union all
4 select 140102101240 from dual union all
5 select 143001101244 from dual union all
6 select 142801101245 from dual union all
7 select 142701131347 from dual union all
8 select 142601121542 from dual union all
9 select 142101131744 from dual
10 )
11 select min(x) minx from t where x > 142701131333
12 /
MINX
-----------------
142701131347
SELECT MIN(sample_data)
FROM tableName
WHERE sample_data > 142701131333