I have two tables as below:
car table:
id
name
1
BMW
2
Volvo
3
Toyota
option table:
id
carid
name
value
1
1
airbag
1
2
1
seat
4
3
1
sunroof
1
4
2
airbag
0
5
2
seat
4
6
2
sunroof
1
7
3
airbag
0
8
3
seat
5
9
3
sunroof
0
how can I create the below table:
id
name
airbag
sunroof
seat
1
BMW
1
1
4
2
Volvo
0
1
4
3
Toyota
0
0
5
You may use pivoting logic here:
SELECT
c.id,
c.name,
MAX(o.value) FILTER (WHERE o.name = 'airbag') AS airbag,
MAX(o.value) FILTER (WHERE o.name = 'sunroof') AS sunroof,
MAX(o.value) FILTER (WHERE o.name = 'seat') AS seat
FROM car c
LEFT JOIN option o
ON o.carid = c.id
GROUP BY
c.id;
With the help of Postgres' support for the FILTER clause, the pivoting logic above becomes very terse and manageable.
Related
I need to create a new table base on two tables. I have a database in ms access and need to migrate.
tableT tableS
ID CustID DATE Exp1 Exp2 ID CustID DATE Tem1 Tem2
-------------------------------- ---------------------------------
1 1 1/1/00 5 5 1 1 1/1/00 3 4
2 2 1/1/00 1 3 2 2 1/1/00 5 0
3 1 3/1/00 3 2 3 1 5/1/00 0 3
4 3 4/1/00 4 1 4 3 6/1/00 0 0
Desired output table tableNew:
ID CustID DATE Exp1 Exp2 Tem1 Tem2
---------------------------------------------
1 1 1/1/00 5 5 3 4
2 2 1/1/00 1 3 5 0
3 1 3/1/00 3 2
4 3 4/1/00 4 1
5 1 5/1/00 0 3
6 3 6/1/00 0 0
If I use outer join, I will not get the output I need.
Any idea or help.
You want a full join. You can emulate this in MS Access using:
select t.CustID, t.DATE, t.Exp1, t.Exp2, s.tem1, s.tem2
from TableT as t left outer join
tableS as s
on t.CustId = s.CustId and t.date = s.date
union all
select s.CustID, s.DATE, null, null, s.tem1, s.tem2
from tableS as s left outer join
tableT as t
on t.CustId = s.CustId and t.date = s.date
where t.CustId is null;
I have a table as below in sqlite database. I want to create a line chart showing usage by product groups.
Table: ProductUsageData
UserID ProductName ProductGroup Qty RecordID
1 A1 A 12 1
2 A1 A 12 1
1 A2 A 15 1
3 A1 A 12 2
2 B1 B 12 2
5 B2 B 5 2
1 A1 A 12 3
1 A2 A 15 3
4 A1 A 12 3
3 C1 C 12 3
2 C2 C 15 3
Since I want separate line for each ProductGroup I am using below Query
SELECT
SUM(Qty) as UsedQty,
ProductGroup,
RecordID
FROM ProductUsageData
GROUP BY ProductGroup, RecordID
ORDER BY RecordID ASC;
While I get three records for A (for each RecordID) I get only 1 record each for B & C as they are not used during each RecordID.
Problem is when I am putting one line for each ProductGroup in the chart, the points for B & C are shown as per Qty in the first
My output is like this
A 39 1
A 12 2
B 17 2
A 39 3
C 27 3
So the graph looks like this
instead of
To fix this I changed the query using COALESCE to get 0 Qty if the ProductGroup is not used during each recording.
SELECT
COALESCE(SUM(Qty), 0) as UsedQty,
ProductGroup,
RecordID
FROM ProductUsageData
GROUP BY ProductGroup, RecordID
ORDER BY RecordID ASC;
I was expecting output as below
A 39 1
B 0 1
C 0 1
A 12 2
B 17 2
C 0 2
A 39 3
B 0 3
C 27 3
But I am getting same output as first
Please let me know how can I correct the query to get desired output
A typical solution is to first cross join two queries that select the distinct product groups and record ids from the table; this gives you all possible combinations of productGroup and recordID.
Then, you can bring in the original table with a left join, and aggregate:
select
g.productGroup,
coalesce(sum(p.qty), 0) qty,
r.recordID
from (select distinct productGroup from productUsageData) g
cross join (select distinct recordID from productUsageData) r
left join productUsageData p
on p.productGroup = g.productGroup
and p.recordID = r.recordID
group by r.recordID, g.productGroup
order by r.recordID, g.productGroup
In the real world, you might have separate referential tables for product groups and records ids, which would make the query simpler and more efficient (since it would avoid the need to select distinct in subqueries).
Demo on DB Fiddle:
productGroup | qty | recordID
:----------- | :-- | :-------
A | 39 | 1
B | 0 | 1
C | 0 | 1
A | 12 | 2
B | 17 | 2
C | 0 | 2
A | 39 | 3
B | 0 | 3
C | 27 | 3
tourid
tourname
1
PARIS
2
LANDON
3
MADRID
tour_detail_ID
tourid
custid
1
1
3
2
2
3
3
3
3
4
1
4
5
2
4
6
3
4
7
1
5
8
2
5
custid
custname
custPhoneNo
3
PETER
22332422
4
MARY
22332422
5
PAUL
22332422
enter image description here
How can I get all customers booked all tours?
If I understand what your data is and what your question is, this will involve finding out who has not scheduled all of the tours and then finding all customers who aren't in the previous list.
I'm not sure I like it, but something like this gets just Peter and Mary, since they are the only two who have scheduled all 3 tours:
SELECT c1.custid, c1.custName
FROM #customers c1
LEFT OUTER JOIN (
SELECT c2.custid
FROM #tours t
CROSS JOIN #customers c2
LEFT OUTER JOIN #tour_detail td ON td.tourid = t.tourid
AND td.custid = c2.custid
WHERE td.custid IS NULL
) noCustTour ON c1.custid = noCustTour.custid
WHERE noCustTour.custid IS NULL
I have a table that looks like this:
ReportID | TeamID | Inning | Runs
1 A 1 3
1 A 2 3
1 A 5 7
1 B 1 3
1 B 3 2
1 B 6 1
I need to select all of that data, plus null data for the missing innings. It also need to stop at the max Inning for both teams (i.e. teamB's highest inning is 6, so I would collect 6 rows for both teamA and teamB yielding 12 total rows.)
For a visual, I need the output of the query to look like this:
ReportID | TeamID | Inning | Runs
1 A 1 3
1 A 2 3
1 A 3 NULL
1 A 4 NULL
1 A 5 7
1 A 6 NULL
1 B 1 3
1 B 2 NULL
1 B 3 2
1 B 4 NULL
1 B 5 NULL
1 B 6 1
Is there anyway to do this with just a query? Modifying the original table to add the null values is not an option.
Self join to generate the permutations of reports and teams
Left self join to generate hits which might be nullable.
This is probably a lot more efficient if it's done outside of SQL
SELECT ins.ReportID, teams.TeamID, ins.inning, score.Runs
FROM games as ins
JOIN games AS teams
ON ins.ReportID = teams.ReportID
LEFT JOIN games AS score
ON ins.ReportID = score.ReportID
AND teams.TeamID = score.TeamID
AND ins.inning = score.inning
GROUP BY ins.ReportID, teams.TeamID, ins.inning;
I have this table structure
Product
product_id (PK)
name
Order_Detail
order_detail_id
product_id
quantity
Example data
Product :
1 product1
2 product2
3 product3
4 product4
5 product5
Order_Detail :
1 3 2
2 3 1
3 3 1
4 2 1
5 2 1
6 1 1
7 4 1
8 5 1
9 1 1
10 2 1
11 3 1
Please help me to get top 3 ordered product based on how many times the product ordered ?
I think this migth work:
SELECT p.`product_id`, p.`name`, SUM(o.`quantity`) AS quantity
FROM `Order_Detail` AS o
INNER JOIN `Product` AS p
ON o.`product_id` = p.`product_id`
GROUP BY o.`product_id`
ORDER BY SUM(o.`quantity`) DESC, p.`name` ASC
LIMIT 3