I have a column due date in the format 20210701 (YYYYMMDD), using SQL I want to extract all the dates apart from 5th of particular month ( As highlighted in the pic below )
I used the below code:
SELECT Due_Date_Key
FROM Table
WHERE Due_Date_Key <>20210705
However the error in the above code is it will exclude only the month of jul but not for other months.
How can extract the dates apart from 5th from the entire column.
Help would be much appreciated.
Note that column DUE_DATE_KEY is numeric.
A more SQLish way would be to convert string to date and then check if day is not 5
SELECT * FROM Table
WHERE DATE_PART('day', to_date(cast(DUE_DATE_KEY as varchar), 'YYYYMMDD')) != 5
Using modulo operator to determine whether the last two digits of DUE_DATE_KEY are 05.
select * from T where DUE_DATE_KEY % 100 <> 5
Using your sample data, the above query returns the following:
due_date_key
20210701
20210708
20210903
Refer to this db fiddle
Related
I have a month column with values from 1,2,3 up to 12. I am writing below query to convert column values with 1 digit to 2 digits that is values like 1 and 2 will be converted to 01 and 02, but that concatenation is not working, the month still remains as single digit.
Main query:
select
case
when len(month) = 1
then concat(0, month)
else month
end as month_new,
month
from
Table
But when I tried the query separately as below the concatenation works and it converts single digit month to 2 digits
Query 1
select top 10 concat(0, month), month
from table
Query 1 alone is working
Query 2
select
case
when len(month) = 1
then 1
else 0
end,
month
from
Table
Query 2 alone is working, means the checking of length in column month is working as expected. But when concat used inside case it is not working.
I have modified the query as below and worked for me
select
case
when len(month) = 1
then concat(0, month)
else cast(month as varchar)
end as month_new,
month
from
table
The problem is that month is an integer, whereas the result from concat() is a string. So. case is trying to cast the string back into an integer. You could force the integer into a string by using cast, but there are better ways to do this.
Instead, just use the FORMAT function:
select
format(month, '00') as month_new
, month
from viivscaazure.F_SALES_DETAIL
Don't know what database are you using and since you don't provide any sample data I only can assume that your CASE is not the problem, but if you want to do so that means your datatype is string and you tried to CONCAT string with integer in your query.
Maybe you can try to add "quote" to your zero string and CAST the result as a string.
I am merging 2 huge tables in Snowflake and I have 2 columns (one on each table):
"Year_birth" and "Exam_date" and the info inside looks like this respectively:
"1918" and "2007-03-13" (NUMBER(38,0) and VARCHAR(256))
I only want to merge the rows where the difference (i.e., age when the exam was made) is ">18" and "<60"
I was playing around with SELECT DATEDIFF(year,Exam_date, Year_birth) with no success.
Any ideas on how would I do it in Snowflake?
Cheers!
You only have a year, so there is not much you can do about the specific day of the year -- you need to deal with approximations.
So, extract the year from the date string (arggh! it should really be a date) and just compare them:
where (left(datestr, 4)::int - yearnum) not between 18 and 60
I would strongly advise you to fix the database and store these values using a proper date datatype.
You will need to convert the integer year into a date before doing a datediff
example:
set YearOfBirth = 1918;
set ExamDate = '2007-03-03'::DATE;
-- select $YearofBirth as YearofBirth, $ExamDate as ExamDate;
select $YearofBirth as YearofBirth,($YearofBirth::TEXT||'-01-01')::DATE as YearofBirthDate, $ExamDate as ExamDate, datediff(year,($YearofBirth::TEXT||'-01-01')::DATE,$ExamDate) as YearsSinceExam;
USE YEARS_DIFF IN WHERE CLAUSE TO FILTER DIFFERENCE BETWEEN 18 & 60
SELECT DATEDIFF( YEAR,'2007-03-03',TO_DATE(2018::CHAR(4),'YYYY')) YEARS_DIFF;
So this my table structure and data.
Now I want to filter data based on Month by ExpenseDate column.
So how can I achieve that?
I was trying
select * from tblExpenses where (ExpenseDate = MONTH('April'))
But it throws an error: "Conversion failed when converting date and/or time from character string."
Please help. Thank you.
You are putting month() on the wrong column. It can be applied to ExpensesDate:
select *
from tblExpenses
where month(ExpenseDate) = 4;
Note that month() returns a number, not the name of the month.
I think it is more likely that you want records from a particular April, not every April. This would be expressed as:
where ExpenseDate >= '2018-04-01' and ExpenseDate < '2018-05-01'
I think your where clause is just reversed I think you want this (and change the word to a number)
select * from tblExpenses where Month(ExpenseDate) = 4
Hi I have source data in a field in different formats like below
1Y3M6D (1 Year, 3 Months, 6 Days) I need to split this into 3 fields Year, Month, Days but the source data format can change like month can come first as 3M1Y6D OR source data can only have 3M with no year and day. How do I write a query to get the preceding number from M, Y or D?
Thanks in advance for help.
Thanks everyone, Unoembre command helped.
select my_value, REGEXP_SUBSTR(my_value,'(\d+)Y',1,1,NULL,1) REG_Y, REGEXP_SUBSTR(my_value,'(\d+)M',1,1,NULL,1) REG_M, REGEXP_SUBSTR(my_value,'(\d+)D',1,1,NULL,1) REG_D from ( select '3M6Y2D' my_value from dual );
How would I go about doing a query that returns results of all rows that contain dates for current year and month at the time of query.
Timestamps for each row are formated as such: yyyy-mm-dd
I know it probably has something to do with the date function and that I must somehow set a special parameter to make it spit out like such: yyyy-mm-%%.
Setting days to be wild card character would do the trick but I can't seem to figure it out how to do it.
Here is a link to for quick reference to date-time functions in mysql:
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
Thanks
I think EXTRACT is the function you are looking for:
SELECT * FROM table
WHERE EXTRACT(YEAR_MONTH FROM timestamp_field) = EXTRACT(YEAR_MONTH FROM NOW())
you could extract the year and month using a function, but that will not be able to use an index.
if you want scalable performance, you need to do this:
SELECT *
FROM myTable
WHERE some_date_column BETWEEN '2009-01-01' AND '2009-01-31'
select * from someTable where year(myDt) = 2009 and month(myDt) = 9 and day(myDt) = 12