I have a table which has different interval invoice. Please see sample data below:
Invoice_Start_Date Invoice_End_Date Amount
1/1/2019 2/1/2019 12
1/1/2019 1/1/2020 84
1/1/2019 1/1/2021 140
I need to split this data into monthly invoice. In this case First record will be as is. Second record should be split into 12 records with amount of 84/12 for each record.
Third record should be split into 24 records with amount of 140/24 for each record.
Expected Output:
Invoice_Start_Date Invoice_End_Date Amount
1/1/2019 2/1/2019 12
1/1/2019 2/1/2019 7
2/1/2019 3/1/2019 7
3/1/2019 4/1/2019 7
4/1/2019 5/1/2019 7
.........etc
Can someone please advise. I was thinking of writing many union statements ( one for each month but I realized my interval can be 12 months or 24 months etc. so it won't work)
One method is a recursive CTE:
with recursive cte as (
select Invoice_Start_Date, Invoice_End_Date,
Amount / datediff(month, Invoice_Start_Date, Invoice_End_Date) as month_amount
from t
union all
select dateadd(month, 1, invoice_start_date), invoice_end_date,
month_amount
from cte
where invoice_start_date < invoice_end_date
)
select invoice_start_date,
dateadd(month, 1, invoice_start_date) as invoice_end_date,
month_amount
from cte;
Recursive CTE can be slow for large data sets. This does the same thing with a simple join:
With TEMPTBL as (
select round(sqrt(row_number() over (order by null)*2)) as rnum
from table(generator(rowcount => 10000)) --10000 Allows for up to 140 months difference.
order by 1 )
select Invoice_Start_Date, Invoice_End_Date,
datediff(month, Invoice_Start_Date, Invoice_End_Date) as month_diff,
Amount / datediff(month, Invoice_Start_Date, Invoice_End_Date) as month_amount
from INVOICE t, TEMPTBL y
where t.month_diff = y.rnum
Related
I have a stored procedure, where takes number of numbers as a parameter. I do my query with where clause like this
select salesrepid, month(salesdate), year(salesdate), salespercentage
from SalesRecords
where salesdate >= DATEADD(month, -#NumberOfMonths, getdate())
So for example, if #NumberOFmonths passed = 3 and based on todays date,
It should bring, september 9, october 10 and november 11 in my resultset. My query brings it but request is I need to return null for those salesrep who doesnt have a value for a month,
for example:
salerepid month year salespercentage
232 9 2020 80%
232 10 2020 null
232 11 2020 90%
how can I achieve this ? Right now the query brings back only two records and does not bring october data as no value is there, but i want it to return october with null value.
If I follow you correctly, you can generate all start of months within the target interval, and cross join that with the table to generate all possible combinations. Then you can bring the table with a left join:
with all_dates as (
select datefromparts(year(getdate()), month(getdate()), 1) salesdate, 0 lvl
union all
select dateadd(month, - lvl - 1, salesdate), lvl + 1
from all_dates
where lvl < #NumberOfMonths
)
select r.salesrepid, d.salesdate , s.salespercentage
from all_dates d
cross join (select distinct salesrepid from salesrecords) r
left join salesrecord s
on s.salesrepid = r.salesrepid
and s.salesdate >= d.salesdate
and s.salesdate < dateadd(month, 1, d.salesdate )
Your original query and result imply that there is at most one record per sales rep and month, so this works under the same assumption. If that's not the case (which would somehow make more sense), you would need aggregation in the outer query.
Declare #numberofmonths int = 3;
with all_dates as (
select datefromparts(year(getdate()), month(getdate()), 1) dt, 0 lvl
union all
select dateadd(month, - lvl - 1, dt), lvl + 1
from all_dates
where lvl < 3
)
select * from all_dates
This gives me following result:
2020-11-01 0
2020-10-01 1
2020-08-01 2
2020-05-01 3
I want only:
2020-11-01 0
2020-10-01 1
2020-09-01 2
i have input data below
date amount
01-01-2020 10
01-02-2020 15
01-03-2020 10
01-05-2020 20
01-06-2020 30
01-08-2020 5
01-09-2020 6
01-10-2020 10
select sum(date),over(partition date) from table;
after add the missing month values i need output
output
Date amount cum_sum
01-01-2020 10 10
01-02-2020 15 25
01-03-2020 10 35
01-04-2020 0 35
01-05-2020 20 55
01-06-2020 30 85
01-07-2020 0 85
01-08-2020 5 90
01-09-2020 6 96
01-10-2020 10 106
You would typically generate the dates with a recursive query, then use window functions.
You don't tell which database you use. The exact syntax of recursive queries and date artithmetics varies across vendors, but here is what it would look like:
with recursive all_dates (dt, max_dt) as (
select min(date) dt, max(date) max_dt from mytable
union all
select dt + interval '1' day, max_dt from all_dates where dt < max_dt
)
select d.dt, sum(t.amount) over(order by c.dt) amount
from all_dates d
left join mytable t on t.date = d.dt
order by d.dt
You simply want a window function:
select t.*, sum(amount) over (order by date)
from table t
I'm trying to list the total number of orders for the last 12 rolling months (not including the current month).
This is my query:
Select
Year(CreatedOn)*100+Month(CreatedOn) YearMonth,
Count(*) OrderCount
From Orders
Where DateDiff(MM,CreatedOn,GetUTCDate()) Between 1 And 12
Group By Year(CreatedOn), Month(CreatedOn)
Order By YearMonth
As expected, I am getting the results correctly. However, when there are no orders in a specific month, the month is excluded from the result completely. I would like to show that month with 0. See sample result:
201809 70
201810 8
201811 53
201812 67
201901 15
201902 13
201903 10
201905 12
201908 9
See the missing months 201904, 201906 and 201907. There should be a total of 12 rows.
The query should be executable within a sub-query using For XML Path so that I can get a comma separated list of orders in the last 12 months.
How can I accomplish this?
You need to generate the rows that you want somehow. One method uses a recursive CTE:
with dates as (
select Year(getdate())*100+Month(getdate()) as yearmonth,
1 as n, datefromparts(year(getdate()), month(getdate()), 1) as yyyymm
union all
select year(dateadd(month, -1, yyyymm)) * 100 + month(dateadd(month, -1, yyyymm),
n + 1,
dateadd(month, -1, yyyymm)
from cte
where n < 12
),
q as (
<your query here>
)
select d.yearmonth, coalesce(q.orders, 0) as orders
from dates d left join
q
on d.yearmonth = q.yearmonth;
Check this-
WITH R(N) AS
(
SELECT 1
UNION ALL
SELECT N+1
FROM R
WHERE N < 12
)
SELECT REPLACE(LEFT(CAST (DATEADD(MONTH,DATEDIFF(MONTH,0,(DATEADD(MONTH,-N,GetUTCDate()))),0) AS DATE),7),'-','') AS [YearMonth],ISNULL(o.OrderCount,0) as OrderCount
FROM R A
LEFT JOIN
(
Select
Year(CreatedOn)*100+Month(CreatedOn) YearMonth,
Count(*) OrderCount
From Orders
Where DateDiff(MM,CreatedOn,GetUTCDate()) Between 1 And 12
Group By Year(CreatedOn), Month(CreatedOn)
) O ON O.YearMonth=REPLACE(LEFT(CAST (DATEADD(MONTH,DATEDIFF(MONTH,0,(DATEADD(MONTH,-N,GetUTCDate()))),0) AS DATE),7),'-','')
Order By REPLACE(LEFT(CAST (DATEADD(MONTH,DATEDIFF(MONTH,0,(DATEADD(MONTH,-N,GetUTCDate()))),0) AS DATE),7),'-','');
My table structure in SQL Server looks as below.
id startdate enddate value
---------------------------------------
1 2019-02-06 2019-02-07 11
1 2019-01-22 2019-02-05 10
1 2019-01-15 2019-01-21 14
1 2018-12-13 2018-01-14 15
1 2018-12-09 2018-12-12 14
1 2018-08-13 2018-12-08 17
1 2018-07-19 2018-08-12 19
1 2018-06-13 2018-07-18 20
Now my query needs to display value from highest start date for that month. Which is fine and I know what needs to be done but Not start just highest date value for that month, if no value is there for that start date, we carry forward value from last month. So basically if you notice on above data, after December 2018 values, there are no values for November, October, September etc but I want to return MM/YYYY values for that month in result but value for those months should be what we found on earlier month which is August values which in this example is 17. Please note that enddate will always be as of one day before new start date begins. Probably that can be used for back filling and carry forwarding missing month values?
So my result should look like below.
id date value
----------------------------
1 2019-02 11
1 2019-01 10
1 2018-12 15
1 2018-11 17
1 2018-10 17
1 2018-09 17
1 2018-08 17
1 2018-07 19
1 2018-06 20
Do you think this can be done without using cursor here?
Alexander Volok's answer is solid, so I won't go into too much extra code. But I thought I'd explain the reasoning. In essence, what you need to do is create a skeleton date table containing all the dates and primary keys you want returned. I'm guessing you have more than one id value in your real data, so probably something like this (whether you choose to persist it or not is up to you)
create table #skelly
(
id int,
_year int,
_month int
primary key (id, _year, _month)
)
You can get much more precise if you need to be, by only including dates which fall between the min and max StartDate per id, but that's an exercise I leave up to you.
From there, it's then just a matter of filling in the values you care about against that skeleton table. You can do this in a number of ways; by joining, cross applying or a correlated subquery (as Alexander Volok used).
DECLARE #start DATE, #end DATE;
SELECT #start = '20180601', #end = GETDATE();
;WITH Months AS
(
SELECT EOMONTH(DATEADD(month, n-1, #start)) AS DateValue FROM (
SELECT TOP (DATEDIFF(MONTH, #start, #end) + 1)
n = ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_objects
) D
)
, InputData AS
(
SELECT 1 AS id, '2019-02-06' startdate, '2019-02-07' as enddate, 11 AS [value] UNION ALL
SELECT 1, '2019-01-22', '2019-01-25', 10 UNION ALL
SELECT 1, '2019-01-15', '2019-01-17', 14 UNION ALL
SELECT 1, '2018-12-13', '2018-12-19', 15 UNION ALL
SELECT 1, '2018-12-09', '2018-12-10', 14 UNION ALL
SELECT 1, '2018-08-13', '2018-12-08', 17 UNION ALL
SELECT 1, '2018-07-19', '2018-07-25', 19 UNION ALL
SELECT 1, '2018-06-13', '2018-07-18', 20
)
SELECT FORMAT(m.DateValue, 'yyyy-MM') AS [Month]
, (SELECT TOP 1 I.value FROM InputData I WHERE I.startdate < M.DateValue ORDER BY I.startdate DESC ) [Value]
FROM months m
ORDER BY M.DateValue DESC
Results to:
Month Value
2019-02 11
2019-01 10
2018-12 15
2018-11 17
2018-10 17
2018-09 17
2018-08 17
2018-07 19
2018-06 20
I have an SQL Table in which I keep project information coming from primavera.
Suppose that i have columns for Start Date,End Date,Duration, and Total Qty as shown below .
How can i distribute Total Qty over Months using these information. What kind of additional columns, sql queries i need in order to get correct monthly distribution?
Thanks in Advance.
Columns in order:
itemname,quantity,startdate,duration,enddate
item1 -- 108 -- 2013-03-25 -- 720 -- 2013-07-26
item2 -- 640 -- 2013-03-25 -- 720 -- 2013-07-26
.
.
I think the key is to break the records apart by month. Here is an example of how to do it:
with months as (
select 1 as mon union all select 2 union all select 3 union all
select 4 as mon union all select 5 union all select 6 union all
select 7 as mon union all select 8 union all select 9 union all
select 10 as mon union all select 11 union all select 12
)
select item, m.mon, quantity / nummonths
from (select t.*, (month(enddate) - month(startdate) + 1) as nummonths
from t
) t join
months m
on month(t.startDate) <= m.mon and
months(t.endDate) >= m.mon;
This works because all the months are within the same year -- as in your example. You are quite vague on how the split should be calculated. So, I assumed that every month from the start to the end gets an equal amount.