I have table in Oracle SQL Developer like below:
col1
--------
2019-11-29 11:14:00.821822
2020-02-11 09:14:00.821847
And I would like to select only rows where date is '2019-11-29' how can I do that?
You can use:
where trunc(col1) = date '2019-11-29'
However, that cannot use an index on col1. So, it is often better to use:
where col1 >= date '2019-11-29' and
col1 < date '2019-11-30'
You can to_date() or to_char() functions. The Oracle/PLSQL TO_DATE function converts a string to a date and TO_CHAR function converts a date to a String. The TRUNC(date) function returns date without the time portion.
select *
from myTable
where trunc(col1) = to_date('2019-11-29', 'yyyy-mm-dd');
or:
select *
from myTable
where to_char(col1, 'yyyy-mm-dd') = '2019-11-29'
Related
I am using SQL Oracle DB, I am facing issue when using SQL Between Statement.
I have a requirement to search the values in between the date time range.
When I am using the below SQL statement, I am only receiving matching results or empty set but I need the results which are between the values inclusive the passing values if present.
select id,date
from Table_name
where date between '2020-10-21 10:00:17' AND '2017-10-21 22:00:17'
and id = '123';
I am receiving as Empty set
Example of output should be
ID DATE
123 2020-10-21 10:00:17
123 2020-09-07 09:87:22
123 2018-06-09 07:58:01
123 2017-08-12 08:00:10
Could anyone suggest what should be modified in the sql statement
Try to swap the two date values after between in your SQL statement.
Explanation: between in this statement means:
date >= '2020-10-21 10:00:17' and date <= '2017-10-21 22:00:17'
The correct statement is:
select id, date
from Table_name
where date between '2017-10-21 22:00:17' and '2020-10-21 10:00:17'
and id = '123';
You have two problems:
You want the lower bound of the range before the upper bound in the BETWEEN clause; and
You are not comparing on a date-time range, you are comparing on an alpha-numeric string comparison. This is because the values in the BETWEEN clause are string literals and not DATE values.
You want to use DATE values in the BETWEEN clause:
select id,
date_column
from Table_name
where date_column BETWEEN DATE '2017-10-21' + INTERVAL '22:00:17' HOUR TO SECOND
AND DATE '2020-10-21' + INTERVAL '10:00:17' HOUR TO SECOND
and id = '123';
or
select id,
date_column
from Table_name
where date_column BETWEEN TIMESTAMP '2017-10-21 22:00:17'
AND TIMESTAMP '2020-10-21 10:00:17'
and id = '123';
or
select id,
date_column
from Table_name
where date_column BETWEEN TO_DATE('2017-10-21 22:00:17', 'YYYY-MM-DD HH24:MI:SS')
AND TO_DATE('2020-10-21 10:00:17', 'YYYY-MM-DD HH24:MI:SS')
and id = '123';
If you use string literals and the NLS_DATE_FORMAT session parameter does not match then you will get an error:
select id,
date_column
from Table_name
where date_column between '2017-10-21 22:00:17' and '2020-10-21 10:00:17'
and id = '123';
Outputs:
ORA-01861: literal does not match format string
db<>fiddle here
I am trying to get the row from the Database which saves the date in the following format 2018-07-09 13:22:40
When I write the following query like this:-
SELECT *
FROM table_name
WHERE time_col = '2018-07-09 13:22:40';
it returns a single row
But When I write a query like this (no result):
SELECT *
FROM table_name
WHERE time_col = '2018-07-09';
it returns me nothing.
For the other operators, it works for <, >, <=, >= with the following query but why not with "=" Operator
SELECT *
FROM table_name
WHERE time_col < '2018-07-09';
Assuming your column is of type timestamp, then the string constant '2018-07-09' will be converted to a timestamp by Postgres - but with the time as 00:00:00.
So the following query:
SELECT *
FROM table_name
WHERE time_col = '2018-07-09';
is actually run as:
SELECT *
FROM table_name
WHERE time_col = timestamp '2018-07-09 00:00:00';
Which of course does not match the value 2018-07-09 13:22:40.
To get the rows on a specific day, you can cast the timestamp column to a date:
SELECT *
FROM table_name
WHERE time_col::date = date '2018-07-09'
This will however prevent the usage on the time_col column. So if that version of the query is slow, you have to revert to a range query:
SELECT *
FROM table_name
WHERE time_col >= timestamp '2018-07-09 00:00:00'
and time_col < timestamp '2018-07-10 00:00:00'
It does not work cause column is timestamp (date with time). But you trying compare that with date(no date), that is why they are not equal.
Use trunc function in oracle. trunc function cuts time from date and leaves only date:
SELECT * FROM table_name WHERE trunc(time_col) = '2018-07-09';
And for postgres use explicit cast:
SELECT * FROM table_name WHERE time_col::date = '2018-07-09';
SELECT *FROM table
WHERE update_date >= '2013-05-03'::date
AND update_date < ('2013-05-03'::date + '1 day'::interval);
How can I convert a date to a timestamp?
My query:
SELECT * FROM CTP0421
WHERE timestamp <= '2016-04-04'
This doesn't work for me.
SELECT * FROM CTP0421
WHERE trunc(timestamp) <= to_date('2016-04-04','yyyy-mm-dd');
I have the following values in my table
Select * From TimeSheetLogs where InTimeStamp <= '1/22/2013'
when i execute the above query i get null value
but as you can see i have 3 data with datefield as 1/22/2013
Then what i am doing wrong?
Thanks
that is correct because
'1/22/2013 19:21' > '1/22/2013 00:00'
You probably need to truncate your dates first to remove the time portion. Then convert both sides to date datatype. The string '1/22/2013' is a string, not a date. By looking at data your InTimeStamp is timestamp datatype. You cannot compare date or timestamp to character w/out converting the char-s to date. I'm not sure what Database are you using. This is how you'd convert in Oracle using to_date function .
SELECT in_date, compare_date
FROM
(-- This is your InTimeStamp on the fly
SELECT trunc(to_timestamp('2013-01-22 16:21:19.273', 'yyyy-mm-dd hh24:mi:ss.ff')) in_date -- this is your InTimeStamp
, to_date('1/22/2013', 'mm/dd/yyyy') compare_date
FROM dual
)
WHERE in_date <= compare_date
/
Now you can compare two dates below - this is the output of above query:
in_date compare_date
---------- ------------
1/22/2013 1/22/2013
Select * From TimeSheetLogs
where InTimeStamp <= select convert(datetime,'1/22/2013',101)
As per my comment to #Zdravko's good answer, you just need to cast your date:
Select * From TimeSheetLogs where CAST(InTimeStamp as Date) <= '1/22/2013'
I have a datetime field in my Postgresql, named "dt".
I'd like to do something like
SELECT * FROM myTable WHERE extract (date from dt) = '01/01/11'
What is the right syntax to do that?
Thanks!
I think you want to cast your dt to a date and fix the format of your date literal:
SELECT *
FROM table
WHERE dt::date = '2011-01-01' -- This should be ISO-8601 format, YYYY-MM-DD
Or the standard version:
SELECT *
FROM table
WHERE CAST(dt AS DATE) = '2011-01-01' -- This should be ISO-8601 format, YYYY-MM-DD
The extract function doesn't understand "date" and it returns a number.
With PostgreSQL there are a number of date/time functions available, see here.
In your example, you could use:
SELECT * FROM myTable WHERE date_trunc('day', dt) = 'YYYY-MM-DD';
If you are running this query regularly, it is possible to create an index using the date_trunc function as well:
CREATE INDEX date_trunc_dt_idx ON myTable ( date_trunc('day', dt) );
One advantage of this is there is some more flexibility with timezones if required, for example:
CREATE INDEX date_trunc_dt_idx ON myTable ( date_trunc('day', dt at time zone 'Australia/Sydney') );
SELECT * FROM myTable WHERE date_trunc('day', dt at time zone 'Australia/Sydney') = 'YYYY-MM-DD';