SQL query select data between two date fields not working - sql

I have the following values in my table
Select * From TimeSheetLogs where InTimeStamp <= '1/22/2013'
when i execute the above query i get null value
but as you can see i have 3 data with datefield as 1/22/2013
Then what i am doing wrong?
Thanks

that is correct because
'1/22/2013 19:21' > '1/22/2013 00:00'

You probably need to truncate your dates first to remove the time portion. Then convert both sides to date datatype. The string '1/22/2013' is a string, not a date. By looking at data your InTimeStamp is timestamp datatype. You cannot compare date or timestamp to character w/out converting the char-s to date. I'm not sure what Database are you using. This is how you'd convert in Oracle using to_date function .
SELECT in_date, compare_date
FROM
(-- This is your InTimeStamp on the fly
SELECT trunc(to_timestamp('2013-01-22 16:21:19.273', 'yyyy-mm-dd hh24:mi:ss.ff')) in_date -- this is your InTimeStamp
, to_date('1/22/2013', 'mm/dd/yyyy') compare_date
FROM dual
)
WHERE in_date <= compare_date
/
Now you can compare two dates below - this is the output of above query:
in_date compare_date
---------- ------------
1/22/2013 1/22/2013

Select * From TimeSheetLogs
where InTimeStamp <= select convert(datetime,'1/22/2013',101)

As per my comment to #Zdravko's good answer, you just need to cast your date:
Select * From TimeSheetLogs where CAST(InTimeStamp as Date) <= '1/22/2013'

Related

How to select date from timestamp column in Oracle SQL Developer?

I have table in Oracle SQL Developer like below:
col1
--------
2019-11-29 11:14:00.821822
2020-02-11 09:14:00.821847
And I would like to select only rows where date is '2019-11-29' how can I do that?
You can use:
where trunc(col1) = date '2019-11-29'
However, that cannot use an index on col1. So, it is often better to use:
where col1 >= date '2019-11-29' and
col1 < date '2019-11-30'
You can to_date() or to_char() functions. The Oracle/PLSQL TO_DATE function converts a string to a date and TO_CHAR function converts a date to a String. The TRUNC(date) function returns date without the time portion.
select *
from myTable
where trunc(col1) = to_date('2019-11-29', 'yyyy-mm-dd');
or:
select *
from myTable
where to_char(col1, 'yyyy-mm-dd') = '2019-11-29'

How to extract No. of Days between 2 dates in oracle sql?

I want No. of days between these 2 dates using Oracle SQL
Dates:
BETWEEN "1/1/2018" AND "6/11/2018"
How to write SQL Query?
between date '2018-01-01' and date '2018-11-06'
where DATE literal looks exactly like that: DATE 'YYYY-MM-DD'
In your example:
double quote's can't be used
even if you used single quotes, that would be a string, not DATE so you'd depend on whether Oracle is capable of converting it (implicitly) to date or not
therefore, always use dates, not strings
[EDIT]
This is how you select the whole calendar between those two dates:
select date '2018-01-01' + level - 1
from dual
connect by level <= date '2018-11-06' - date '2018-01-01' + 1;
As other answers have pointed out you can simply divide two dates, but there is also no need for any additional arithmetic.
The code:
select to_date('6/11/2018', 'DD/MM/YYYY') - to_date('1/1/2018', 'DD/MM/YYYY')
from dual;
The result: 309
you can simple do:
select date1-date2 form dual;
or
select (sysdate-to_date('01-jan-2018'))-(sysdate-to_date('10-jan-2018'))from dual;
Just use
select date'2018-11-06' - date'2018-01-01' + 1 as days_difference
from dual;
DAYS_DIFFERENCE
---------------
310
or
with t( myDate ) as
(
select date'2018-11-06' from dual union all
select date'2018-01-01' from dual
)
select max(myDate) - min(myDate) + 1 as days_difference
from t;
DAYS_DIFFERENCE
---------------
310

How to convert current time to date without time in sql?

I want to select data where the operation_date between '01-Jan-2016' and yesterday. I used code as follows:
select *
where operation_date between '01-Jan-2016' and sysdate-1
from TABLE
But sysdate returns both date and time. Therefore, the above output includes all the data between '01-Jan-2016' and say, 14 Nov-2017 09:50:51. I only want the data before today. How to convert current time to date without time? Thanks.
Seems that you are looking for trunc().
Example
SELECT sysdate - 1 AS current_Date_Time
,trunc(sysdate) - 1 AS CURRENT_DATE1
,trunc(sysdate - 1) AS CURRENT_DATE2
FROM dual
Result
CURRENT_DATE_TIME CURRENT_DATE1 CURRENT_DATE2
----------------------------------------------------------
13.11.2017 18:08:41 13.11.2017 00:00:00 13.11.2017 00:00:00
DEMO
So the correct query will be as below.
SELECT *
WHERE operation_date BETWEEN DATE '2016-01-01' -- ANSI Date Literal
AND trunc(sysdate - 1)
FROM TABLE
OR
SELECT *
WHERE operation_date BETWEEN DATE '2016-01-01' -- ANSI Date Literal
AND trunc(sysdate) - 1
FROM TABLE

How to search by to_date function?

I have table as below:
Table Temp:
ID MAX MIN DATE_C
1 34 24 21-APR-17 02.41.38.520000 PM
2 32 26 20-APR-17 02.42.44.569000 PM
I execute the below SQL query to get temperature details on respective date:
SELECT *
FROM Temp t
WHERE t.date_c = TO_DATE( '2017-04-21', 'YYYY-MM-DD')
order by t.id
But it's returning empty records. Whats wrong with my query?
You need to remove the time component on the column. Here is one way:
SELECT *
FROM Temp t
WHERE TRUNC(t.date_c) = DATE '2017-04-21'
ORDER BY t.id;
However, I usually recommend using inequalities, rather than a function on the column:
SELECT *
FROM Temp t
WHERE t.date_c >= DATE '2017-04-21' AND
t.date_c < DATE '2017-04-22'
ORDER BY t.id;
This allows the query to use an index on date_c. I should add that the original version can use an index on (trunc(date_c, id).
21-APR-17 02.41.38.520000 PM is not a DATE; it has a fractional seconds component so it is a TIMESTAMP.
So, if you want to find items that are on a particular day (inputting the TIMESTAMP using an ISO/ANSI timestamp literal):
SELECT *
FROM Temp
WHERE date_c >= TIMESTAMP '2017-04-21 00:00:00' AND
date_c < TIMESTAMP '2017-04-21 00:00:00' + INTERVAL '1' DAY;
or
SELECT *
FROM Temp
WHERE date_c >= TO_TIMESTAMP( :your_date_string, 'YYYY-MM-DD' ) AND
date_c < TO_TIMESTAMP( :your_date_string, 'YYYY-MM-DD' ) + INTERVAL '1' DAY;
it's returning empty records. Whats wrong with my query?
date_c = TO_DATE( '2017-04-21', 'YYYY-MM-DD') matches all rows where the date_c value is exactly 2017-04-21 00:00:00.000000 (including the time component); if you do not have any rows with exactly that date and time then, as you noticed, it will return nothing. If you want to get records matching that day then you need to get values within a range of times between the start and end of the day.
You need to pass date on the column. Here is a way...
SELECT *
FROM Temp t
WHERE CAST(t.CREATED_ON as date)= N'2017-04-22'
ORDER BY t.id

Select rows where day is less than today

How do I select rows in the past starting from yesterday in Oracle DB where a field like created_date is a timestamp(6)?
I don't want to compare time, just date.
If you want exactly one day prior to the current time:
select *
from table t
where created_date < sysdate - 1;
If you want times before today:
select *
from table t
where created_date <= trunc(sysdate);
From the Oracle documentation on SELECT :
SELECT * FROM orders
WHERE created_date < TO_DATE('2014-04-28', 'YYYY-MM-DD');
I can pass this date format from my application, worked like a charm.
As you want to compare just date:
select *
from table t
where date(created_date) < DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY);
you can use cast function to deal with timestamp as date:
SELECT cast(SYSTIMESTAMP(6) as date)
FROM dual;
so you can select rows with "yesterdate" date by:
select ....
where cast(SYSTIMESTAMP(6) as date) like sysdate - 1
note: replace SYSTIMESTAMP(6) with column name which has timestamp type.