I'm on-boarding users onto Stripe connect. My node server generates a temporary HTTPS URL so that customers can sign on. According to their docs I need to provide a URL for when they complete the application.
https://stripe.com/docs/api/account_links/create#create_account_link
I have an Expo application. The user will open up the URL in their browser. However when they complete their application I would like them to go back to Expo App. If I try to use expo://MYAPP/ as the return_url, Stripe does not recognize the URL schema.
Does anyone have an idea how i can return the user back into my application after completing their on-boarding done via the browser?
For anyone one out there who runs into this post, this is was my solution. Your app has to link to a website. I am using Expo, but this is the React code to generate the link.
import * as WebBrowser from 'expo-web-browser';
import * as Linking from 'expo-linking';
const openPage = async () => {
try {
const result = await WebBrowser.openAuthSessionAsync(
`${url}?linkingUri=${Linking.createURL('/?')}`,
);
let redirectData;
if (result.url) {
redirectData = Linking.parse(result.url);
}
setstate({ result, redirectData });
} catch (error) {
console.log(error);
}
};
When you load the site, make sure to pass the URL that was generated from your backend
Backend code:
stripe.accountLinks
.create({
type: 'account_onboarding',
account: accountID,
refresh_url: `https://website.com/refresh`,
return_url: `https://website.com/return`,
})
When the user has the site open, have a button that redirects to the stripe URL.This is how i thought it went first
App -> Stripe connect
instead you have to approach it like this
App -> Website -> Stripe connect
Related
I am trying to login with facebook using Supabase on ios emulator. After logging in with Facebook, it redirects me back to localhost. I don't know exactly what to do on this side. Can you help me? I'm still very new.
const onHandleLogin = async () => {
const {data, error} = await supabase.auth.signInWithOAuth({
provider: 'facebook',
});
if (error) {
return;
}
if (data.url) {
const supported = await Linking.canOpenURL(data.url);
if (supported) {
await Linking.openURL(data.url);
}
}
};
After the login process, it still stays on the localhost address on the browser. My purpose is to send it to the application and get token information via the url, but I have no idea how.
I think I need to make changes here but I don't know what to write in the site url because it is a mobile application.
Thanks for your support and replies.
I tried to login with facebook using supabase, but after logging in, it keeps me in safari and gives token information on localhost. I want to direct the application after the login process and get the token information.
You will need to create a deep link for your React Native app: https://reactnative.dev/docs/linking and then set this as your redirect URL. Here a similar example with Flutter: https://supabase.com/docs/guides/getting-started/tutorials/with-flutter#setup-deep-links
I having a problem with my Google Sign In, I'm Currently using EXPO app I wish at all cost not to eject / opt out of Expo, the problem is that when I click on the Button to log in with Google in my App it does take me to the login page for me inside the browser, but once I put my Google credentials, it just lands inside the Google.com page.
I checked a lot of posts but still I'm unable to get it to come back to the app.
My app Code to log in is:
//import de Google en Expo
import * as Google from 'expo-google-app-auth';
import * as AppAuth from 'expo-app-auth';
export const googleLogin = () => {
console.log('***Entro en Google***');
return async dispatch => {
try {
const result = await Google.logInAsync({
androidClientId: '***my ID Censored***',
scopes: ['profile', 'email'],
behavior: 'web',
redirectUrl: `${AppAuth.OAuthRedirect}:/oauthredirect`
});
console.log('***Hizo Consulta***');
if (result.type === 'success') {
console.log(result.accessToken);
} else {
return { cancelled: true };
}
} catch (e) {
return { error: true };
}
}
};
I checked on many posts that the issue was the redirect URL and I tried setting 4 options:
${AppAuth.OAuthRedirect}:/oauthredirect
${AppAuth.OAuthRedirect}:/oauthredirect/google
'host.exp.exponent:/oauth2redirect/google'
'host.exp.exponent:/oauth2redirect/'
None of them worked, I did the last 2 of host.exp.exponent as that is the Bundle Identifier used by Expo on their documentation:
https://docs.expo.io/versions/latest/sdk/google/
Create an Android OAuth Client ID
Select "Android Application" as the Application Type. Give it a name
if you want (maybe "Android Development").
Run openssl rand -base64
32 | openssl sha1 -c in your terminal, it will output a string that
looks like A1:B2:C3 but longer. Copy the output to your clipboard.
Paste the output from the previous step into the
"Signing-certificate fingerprint" text field.
Use host.exp.exponent as the "Package name".
4.Click "Create"
You will now see a modal with the Client ID.
The client ID is used in the androidClientId option for Google.loginAsync (see code example below).
I did just that, and now it always gets stuck in the google.com page, any Ideas or recommendations?
Kind Regards
What have you added to your bundle id (e.g "Apple bundle ID")?
Take into account that there is a difference between production and development.
In development, you should use the default expo apple bundle id so you will be allowed to use the google login (and you won't get redirect_fail).
The default apple bundle id for development using expo is: host.exp.exponent
In production, you should have your own bundle id.
Please write up a follow-up message if any extra help is needed.
In app.json,
package name as to be all in small letters like com.app.cloneapp
On latest react-native 0.60 onwards, the default app will include a list of links at landing page as below
Now if this react-native project running on simulator and we click on one of the link, it will open up on our laptop instead of opening on browser from within the simulator. I'm wondering how it works so I took a look at node_modules/react-native/Libraries/Core/Devtools/openURLInBrowser.js and found below code
'use strict';
const getDevServer = require('./getDevServer');
function openURLInBrowser(url: string) {
// Made a console.log here and getDevServer().url = http://localhost:8081
fetch(getDevServer().url + 'open-url', {
method: 'POST',
body: JSON.stringify({url}),
});
}
module.exports = openURLInBrowser;
Despite having this source code, I still can't understand how can we use a fetch library to launch a url in host's browser? So far I've only use fetch to perform http request from some backend but apparently there's something more that fetch is providing?
The Metro bundler is running on 8081. fetch is performing a HTTP POST request to http://localhost:8081/open-url. Metro is able to handle this request and open up the browser accordingly.
An example Express web server may handle it like so:
app.post('/open-url', req => {
const { url } = req.body;
// Handle code to open URL
});
I've been trying to build a react native app that requires users to authenticate with their Instagram account. The Instagram API has a authorisation link and perhaps the only way to display that in an app would be through 'WebView' and so I used that.
The authentication workflow runs smoothly and then my server even gets the access token and user-id. But the problem is how to send this access token back to the app? I've used express-js for the 'redirect-uri' and so the WebView makes request to app.get() handler. In order to send response to same client on which the connection is opened, we must use res.send(). This would send the response to WebView, let's say I capture that using 'injectedJavaScript' but this javascript runs within WebView and so its unable to access react-native variables. In the event of a correct access-token, how would I ever navigate away from the WebView?
Any solutions to the above problems would be greatly appreciated. I suspect that there might even be problems with this approach(in my choice of WebView for this purpose, etc.), so a change of approach even entirely would also be of help. All I want is to authenticate the app users with Instagram and get my project going. Thanks a lot.
If you are using Expo, you can use AuthSessions to accomplish this (https://docs.expo.io/versions/latest/sdk/auth-session). The exact way to do it depends on whether you are using a managed workflow or a bare workflow, etc., but for managed workflow you can do the following:
Go to the Facebook Developer's console, go to your app, and add the Instagram Basic Display product.
Under Instagram Basic Display, under Valid OAuth Redirect URIs, use https://auth.expo.io/#your-expo-username/your-project-slug (project slug is in your app.json file)
On the same FB Developer page, add an Instagram tester profile and then follow the steps to authenticate that user.
In your project, install expo install expo-auth-session and import it into your Component
Also install expo-web-browser
Code your component like so:
import React, { useEffect } from 'react';
import { Button, Platform, Text, TouchableOpacity, View } from 'react-native';
import * as WebBrowser from 'expo-web-browser';
import { useAuthRequest, makeRedirectUri } from 'expo-auth-session';
WebBrowser.maybeCompleteAuthSession(); // <-- will close web window after authentication
const useProxy = Platform.select({ web: false, default: true });
const client_id = 9999999999999;
const redirect_uri = "https://auth.expo.io/#your-expo-username/your-project-slug";
const scope = "user_profile,user_media";
const site = "https://api.instagram.com/oauth/authorize?client_id=" + client_id + "&redirect_uri=" + redirect_uri + "&scope=" + scope + "&response_type=code&state=1";
const discovery = { authorizationEndpoint: site }
const GetInstagram = () => {
const [request, response, promptAsync] = useAuthRequest({
redirectUri: makeRedirectUri({
useProxy,
native: redirect_uri
}),
scopes: [scope],
clientId: client_id
}, discovery);
useEffect(() => {
if (response?.type === 'success') {
const { code } = response.params; <--- the IG code will be returned here
console.log("code : ", code);
}
}, [response]);
return (
<View>
<TouchableOpacity onPress={ () => promptAsync({useProxy,windowFeatures: { width: 700, height: 600 }}) }>
<Text>Connect Your Instagram</Text>
</TouchableOpacity>
</View>
)
}
export default GetInstagram;
One way to accomplish this is via using deeplink. I don't think it's the best practice though.
The response from the WebView will be sent to the redirect URL you've previously setup after successful authentication. Please set the redirect URL to your app. For example, on iOS if you have URL Scheme as "myapp123" then, anytime you open your browser and type myapp123://.. it will open your app and your app should be able to get response sent from the instagram.
How do you open a Bitcoin URL in a react native app? I am using React Native Linking to detect if there are any apps on the phone that can open a Bitcoin URL formatted according to BIP21. I have 3 apps installed that should handle it:
1) Coinbase
2) Breadwallet
3) Blockchain.info wallet
But it's not opening. Here's the code:
async _openWallet() {
const coinURL = 'bitcoin:15bMc6sQTiQ5jSqoRX3JzatAbQqJaffqup';
try {
const supported = await Linking.canOpenURL(coinURL);
if (supported) {
Linking.openURL(coinURL);
} else {
console.log('Could not find a compatible wallet on this device.');
}
} catch (error) {
console.log(error);
}
}
supported keeps returning false, which causes "Could not find a compatible wallet..." to execute. The weird thing is if I click on a Bitcoin URL on any random website via the Chrome / Safari browser, I get a popup that asks me if I want to open the URL in one of the above apps. So only URLs on websites are opening, but not URLs from inside react native code.
Any ideas?
Looks like every URI scheme you want to use at runtime must be defined up-front in Info.plist. Found the answer here: React Native: Linking API not discovering Uber app