I have a table with many entries for many users. I would like to compute the 20th percentile for each user into a separate table.
I have:
User
Value
John
1
John
14
John
34
John
11
Mary
3
Mary
5
...
...
And I want to have a table with the 20th percentile for each user like:
Name
Percentile
John
xx
Mary
yy
Thank you in advance!
try below
select distinct user,
percentile_cont(value, 0.2) over(partition by user) percentile
from your_table
Related
How can I sort by number first and further sort same number names by alphabet?
Example:
Score | Name
-----------
12 John
11 Paul
10 Dave
9 Adam
9 Ben
9 David
Just use the SQL syntax for ordering by multiple columns:
order by Score, Name
Select * from Table Order by Score , Name
The simple SELECT query would return the data as below:
Select ID, User, Country, TimeLogged from Data
ID User Country TimeLogged
1 Samantha SCO 10
1 John UK 5
1 Andrew NZL 15
2 John UK 20
3 Mark UK 10
3 Mark UK 20
3 Steven UK 10
3 Andrew NZL 15
3 Sharon IRL 5
4 Andrew NZL 25
4 Michael AUS 5
5 Jessica USA 30
I would like to return a sum of time logged for each user grouped by ID
But for only ID numbers where both of these values Country = UK and User = Andrew are included within their rows.
So the output in the above example would be
ID User Country TimeLogged
1 John UK 5
1 Andrew NZL 15
3 Mark UK 30
3 Steven UK 10
3 Andrew NZL 15
First you need to identify which IDs you're going to be returning
SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew';
and based on that, you can then filter to aggregate the expected rows.
SELECT ID,
[User],
Country,
SUM(Timelogged) as Timelogged
FROM mytable
WHERE (Country='UK' OR [User]='Andrew')
AND ID IN( SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew')
GROUP BY ID, [User], country;
So, you have described what you need to write almost perfectly but not quite. Your result table indicates that you want Country = UK OR User = Andrew, rather than AND
You need to select and group by, then include a WHERE:-
Select ID, User, Country, SUM(Timelogged) as Timelogged from mytable
WHERE Country='UK' OR User='Andrew'
Group by ID, user, country
Below is my SQL Server 2012 query example. How do I add an extra column “StaffNo” to show an incremental integer?
This int always starts with 1, it doesn’t need to be matching with the staff name. for example “Joe” in this query running shows 1 in staff No, in next query running he could be 2 or 3 or any other number.
Same user always appear same staff No. Different user appear different No.
The number must be sequential and the increment is 1.
Because Staff is more than 100, so don’t write the query like “select case when staff = ‘Joe’ then 1 End”.
my query:
Staff CaseNumber
Joe 5880
Joe 4489
Joe 2235
Emily 7790
Emily 8813
expected result:
Staff CaseNumber StaffNo
Joe 5880 1
Joe 4489 1
Joe 2235 1
Emily 7790 2
Emily 8813 2
Use DENSE_RANK over the entire table, without a partiton, and order by the staff member's name.
SELECT
Staff,
CaseNumber,
DENSE_RANK() OVER (ORDER BY Staff) StaffNo
FROM yourTable;
Demo here:
Rextester
So let's say I have data in my query like this:
Name: | Cost:
Oliver 20
Oliver 3
Oliver 2
Sarah 100
Sarah 7
How would I go about merging the data for each person into one row and having a total cost?
you can use group by and sum()
select name, sum(cost)
from your_table
group by name
Assume I have a table with the following data:
Name TransID Cost
---------------------------------------
Susan 1 10
Johnny 2 10
Johnny 3 9
Dave 4 10
I want to find a way to sum the Costs per name (assume the Names are unique) so that I get a table like this:
Name Cost
---------------------------------------
Susan 10
Johnny 19
Dave 10
Any help is appreciated.
This is relatively straightforward: you need to use a GROUP BY clause in your query:
SELECT Name,SUM(Cost)
FROM MyTable
GROUP BY Name