Could you please help me as below statement , i want to migrate from Greenplum to HiveSQL. kindly help me.
(date_trunc('week',idate) - INTERVAL '1 week')::DATE date_from
((date_trunc('week',idate) - INTERVAL '1 week')::DATE + '6 days'::INTERVAL)::DATE
date_trunc('week',idate)::DATE
note: idate is i have to parse the argument like 2021-02-20
If you are looking to
find start of week then use select next_day(date_sub(current_date, 7), 'MON')
add 1 week to the date then use select current_date + interval 7 day
convert date to string then use select to_date(current_date )
Now, from your code, it seems, you are looking for start of week and then deducting 1 week from that.
(date_trunc('week',idate) - INTERVAL '1 week')
This can be re-written in hive like below.
next_day(date_sub(current_date, 7), 'MON') - interval 7 day
I assumed Monday is your start of week. Please validate the SQL before using it.
Related
I want to Increment/Decrement the Year , Day , Month by pulling in the Current Date in Snowflake in a single query ?
For e.g.
Suppose Current System Date - 04082021 I want to make it 05092022. I have tried the dateadd function but I suppose it allows only one part i.e. either year or month or day to be incremented at once.
Is it Possible ? If Not, What are the other alternatives ?
If you want to useDATEADD function, here is the code:
SELECT DATEADD(YEAR,+1,DATEADD(MONTH,+1,DATEADD(DAY,+1,CURRENT_DATE())));
returns 2022-09-05 from 2021-08-04
If you want to keep your format, Please use following code
SELECT TO_CHAR(DATEADD(YEAR,+1,DATEADD(MONTH,+1,DATEADD(DAY,+1,CURRENT_DATE()))),'DDMMYYYY');
I would do the arithmetic in thee parts:
select current_date + interval '1 year' + interval '1 month' + interval '1 day'
You can also use:
select current_date + interval '1 year, 1 month, 1 day'
I have a table(pkg_date) in redshift. I want to fetch some data for every date for the last 3 months.
Here is my query
select * from pkg_data where scan_date < current_date;
How can I use current_date as a variable in the query itself and run this query for every date from April 1.
I have set a cron job which will run in every hour. In every hour it should run with different current_date
SELECT *
FROM pkg_data
WHERE scan_date > CURRENT_DATE - INTERVAL '3 months'
Be careful — Redshift works in UTC, so the CURRENT_DATE might suffer from timezone effects and be +/- what you expect sometimes.
SELECT
CURRENT_DATE,
(CURRENT_DATE - INTERVAL '3 months')::date
Returns:
2018-06-21 2018-03-21
Also be careful with strange lengths of months!
SELECT DATE '2018-05-31' - INTERVAL '3 months'
returns:
2018-02-28 00:00:00
Notice that it gave the last day of the month (31st vs 28th).
By the way, you can use DATE '2018-05-31' or '2018-05-31'::DATE, and also INTERVAL '3 months' or '3 months'::INTERVAL to convert types.
Use dateadd() for getting date 3 moth old day and GETDATE() for get current date.
ie code will look like.
select * from pkg_data where scan_date < dateadd(month,-3,GETDATE());
for cron refer How to execute scheduled SQL script on Amazon Redshift?
How to find the last day os the month in postgres?
I have a date columns stored as numeric(18) in the format(YYYYMMDD)
I am trying it to make it date using
to_date("act_dt",'YYYYMMDD') AS "act date"
then find the last day of this date:
like this:
(select (date_trunc('MONTH',to_date("act_dt",'YYYYMMDD')) + INTERVAL '1 MONTH - 1 day')::date)
but it gives me this error:
ERROR: Interval values with month or year parts are not supported
Detail:
-----------------------------------------------
error: Interval values with month or year parts are not supported
code: 8001
context: interval months: "1"
query: 673376
location: cg_constmanager.cpp:145
process: padbmaster [pid=20937]
-----------------------------------------------
Any help?
Postgres version:
PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.4.2 20041017 (Red Hat 3.4.2-6.fc3), Redshift 1.0.874
For anybody coming to this question looking for the Postgres way to do this (not using Redshift), here's how you'd do it:
SELECT (date_trunc('month', '2017-01-05'::date) + interval '1 month' - interval '1 day')::date
AS end_of_month;
Replacing the '2017-01-05' with whatever date you want to use. You can make this into a function like this:
create function end_of_month(date)
returns date as
$$
select (date_trunc('month', $1) + interval '1 month' - interval '1 day')::date;
$$ language 'sql'
immutable strict;
EDIT Postgres 11+
Pulling this out of the comments from #Gabriel, you can now combine interval expressions in one interval (which makes things a little shorter):
select (date_trunc('month', now()) + interval '1 month - 1 day')::date as end_of_month;
-- +--------------+
-- | end_of_month |
-- +--------------+
-- | 2021-11-30 |
-- +--------------+
-- (1 row)
If you're using Amazon AWS Redshift then you can use Redshift's LAST_DAY function. While Redshift is based on PostgreSQL, the LAST_DAY function is not available in PostgreSQL, for a solution for PostgreSQL see #wspurgin's answer.
https://docs.aws.amazon.com/redshift/latest/dg/r_LAST_DAY.html
LAST_DAY( { date | timestamp } )
LAST_DAY returns the date of the last day of the month that contains date. The return type is always DATE, regardless of the data type of the date argument.
For example:
SELECT LAST_DAY( TO_DATE( act_date, 'YYYYMMDD' ) )
Okay, so you've got a numeric(18) column containing numbers like 20150118. You can convert that to a date like:
to_date(your_date_column::text, 'YYYYMMDD')
From a date, you can grab the last day of the month like:
(date_trunc('month', your_date_column) +
interval '1 month' - interval '1 day')::date;
Combined, you'd get:
select (date_trunc('month', to_date(act_dt::text, 'YYYYMMDD')) +
interval '1 month' - interval '1 day')::date
from YourTable;
Example at SQL Fiddle.
date_trunc('month',current_date) + interval '1 month' - interval '1 day'
Truncating any date or timestamp to the month level will give you the first of the month containing that date. Adding a month gives you the first of the following month. Then, removing a day will give you the date of the last day of the month of the provided date.
For future searches, Redshift does not accept INTERVAL '1 month'. Instead use dateadd(month, 1, date) as documented here.
To get the end of the month use: DATEADD(DAY, -1, (DATE_TRUNC('month', DATEADD(MONTH, 1, date))))
select to_char(date_trunc('month', now() + '01 Months'::interval) - '01 Days'::interval, 'YYYYmmDD'::text)::numeric as end_period_n
I am trying to find the timestamp of a certain day of the week with postgrSQL. For example, one might use now() to get the current time, but I want to get the same type of data return for, say, the most recent Monday or Sunday.
I am looking for this because I have a query which retrieves data between now and a few months ago and I don't want to include the current week. As an example what it does now:
creation_date > now() - INTERVAL '2 month'
I thought this might achieve my goals:
BETWEEN now() - INTERVAL '4 month' AND now() - INTERVAL '1 week'
But it just subtracts 7 days from the query which is not what I want. Basically, I want:
BETWEEN now() - INTERVAL '4 month' AND ????
Where the question marks are timestamp for the most recent Sunday, at least I believe that would work.
date_trunc('week', current_date) - interval '1' day
date_trunc('week', current_date) will return the date at the start of the week.
The start of the week is always Monday in Postgres. That's why you need to subract another day from the result to get the Sunday.
You can extract the current day of the week (0-6, Sunday is 0) using EXTRACT(DOW FROM date). You could then use this to create an interval to add or subtract to reach a particular weekday. For example, the most recent Sunday would be now() - (EXTRACT(DOW FROM now()) || ' days')::interval.
Hallo all, i have this SQL
SELECT DATE_ADD( '2009-'+ MONTH( NOW() ) +'-01' , INTERVAL -1 MONTH );
i can't get it to work, what i make wrong here?
tanks for help.
SELECT CONCAT_WS('-', '2009', MONTH(NOW()), '01') - INTERVAL 1 MONTH
It's the concatenation of the date that doesn't work. It converts the strings to numbers, so you get 2009+11+-1 = 2019, which then fails to convert to a date.
Instead of concatenating a date from strings, you can use the last_day function to get the last day of the current month, add one day to get to the next day of the next month, then subtract two months to get to the first day of the previous month:
select last_day(now()) + interval 1 day - interval 2 month;
Plus is an arithmetical operator, you have to use concat.
SELECT DATE_ADD( concat('2009-',MONTH(NOW()),'-01') , INTERVAL -1 MONTH )
or better
select date(now()) - interval day(NOW())-1 day - interval 1 month;
(this will also work in 2010)