Get custom product selection upon dynamic ID in SQL - sql

Question

I have below table structure and I would like to obtain the result in the following form:
First, this is my item table output:
orderID code action id level description Price solvedChoice
--------------------------------------------------------------------------
321 622 RECIPE 0 0 SPICM1 15.5 NULL
321 10 RECIPE 0 1 SPICKN 17 NULL
321 7091 RECIPE 0 1 RFRY 8.5 NULL
321 521 CHOICE 0 1 R-COKE 7.5 10000003
321 612 RECIPE 1 0 BIGTM1 20.5 NULL
321 13 RECIPE 1 1 BTASTY 21 NULL
321 7091 RECIPE 1 1 RFRY 8.5 NULL
321 522 CHOICE 1 1 R-FANT 7.5 10000003
321 608 RECIPE 2 0 ROYAL1 18.5 NULL
321 11 RECIPE 2 1 MCROYA 18 NULL
321 7091 RECIPE 2 1 RFRY 8.5 NULL
321 411 CHOICE 2 1 ARWA 7.5 10000003
321 612 RECIPE 3 0 BIGTM1 20.5 NULL
321 13 RECIPE 3 1 BTASTY 21 NULL
321 7091 RECIPE 3 1 RFRY 8.5 NULL
321 524 CHOICE 3 1 R-SPRT 7.5 10000003
I want to get what select under each meal, for example id = 0, represent one meal with their sub-level (components) and we can see the choice made was R-Coke while for id =1 , the choice made is R-FANT.
The output should be like this:
R-COKE R-FANT ARWA R-SPRT
--------------------------------------
SPICM1 1 0 0 0
BIGTM1 0 1 0 1
ROYAL1 0 0 1 0

Answer 1

This looks like two levels of aggregation to me:
select col1,
sum(r_coke) as r_coke,
sum(r_fant) as r_fant,
sum(arwa) as arwa,
sum(r_sprt) as r_sprt
from (select max(case when level = 0 then description end) as col1,
sum(case when description = 'R-COKE' then 1 else 0 end) as r_coke,
sum(case when description = 'R-FANT' then 1 else 0 end) as r_fant,
sum(case when description = 'ARWA' then 1 else 0 end) as arwa,
sum(case when description = 'R-SPRT' then 1 else 0 end) as r_sprt
from t
group by id
) x
group by col1;
Or, perhaps more simply, using window functions:
select col1,
sum(case when description = 'R-COKE' then 1 else 0 end) as r_coke,
sum(case when description = 'R-FANT' then 1 else 0 end) as r_fant,
sum(case when description = 'ARWA' then 1 else 0 end) as arwa,
sum(case when description = 'R-SPRT' then 1 else 0 end) as r_sprt
from (select t.*,
max(case when level = 0 then description end) over (partition by id) as col1
from t
) t
group by col1;

Answer 2

Just following input and output provided
select orderID, x, [R-COKE], [R-FANT], [ARWA], [R-SPRT]
from (
select orderID, id
, max(case when level = 0 then description end) x
, max(case when level = 1 and solvedChoice is not null then description end) y
from mytable
group by orderID, id
) t
pivot (count(id) for y in ([R-COKE], [R-FANT], [ARWA], [R-SPRT]) ) pvt;

Answer 3

You could join the table to itself. Something like this
drop TABLE if exists #MyItemTable;
go
CREATE TABLE #MyItemTable
(
orderID INT,
code int,
action char(6),
id int,
level int,
description varchar(10),
price money,
solvedChoice int
)
INSERT INTO #MyItemTable (orderID, code, action, id , level, description, Price, solvedChoice)
VALUES
(321, 622 ,'RECIPE',0,0,'SPICM1',15.5 ,NULL)
,(321, 10 ,'RECIPE',0,1,'SPICKN',17 ,NULL )
,(321, 7091,'RECIPE',0,1,'RFRY ',8.5 ,NULL )
,(321, 521 ,'CHOICE',0,1,'R-COKE',7.5 ,10000003)
,(321, 612 ,'RECIPE',1,0,'BIGTM1',20.5 ,NULL )
,(321, 13 ,'RECIPE',1,1,'BTASTY',21 ,NULL )
,(321, 7091,'RECIPE',1,1,'RFRY ',8.5 ,NULL )
,(321, 522 ,'CHOICE',1,1,'R-FANT',7.5 ,10000003)
,(321, 608 ,'RECIPE',2,0,'ROYAL1',18.5 ,NULL )
,(321, 11 ,'RECIPE',2,1,'MCROYA',18 ,NULL )
,(321, 7091,'RECIPE',2,1,'RFRY ',8.5 ,NULL )
,(321, 411 ,'CHOICE',2,1,'ARWA ',7.5 ,10000003)
,(321, 612 ,'RECIPE',3,0,'BIGTM1',20.5 ,NULL )
,(321, 13 ,'RECIPE',3,1,'BTASTY',21 ,NULL )
,(321, 7091,'RECIPE',3,1,'RFRY ',8.5 ,NULL )
,(321, 524 ,'CHOICE',3,1,'R-SPRT',7.5 ,10000003);
select i.[description],
sum(case when i2.[description] = 'R-COKE' then 1 else 0 end) as r_coke,
sum(case when i2.[description] = 'R-FANT' then 1 else 0 end) as r_fant,
sum(case when i2.[description] = 'ARWA' then 1 else 0 end) as arwa,
sum(case when i2.[description] = 'R-SPRT' then 1 else 0 end) as r_sprt
from #MyItemTable i
left join #MyItemTable i2 on i.id=i2.id
and i2.[action]='CHOICE'
where i.[level]=0
group by i.[description];
description r_coke r_fant arwa r_sprt
BIGTM1 0 1 0 1
ROYAL1 0 0 1 0
SPICM1 1 0 0 0

Answer 4

The aim is to get 1 result for each type of order, that is represented by level=0, id is the order identifier.
You need to first normalize the results by querying the orders and the CHOICE items separately, then you can correlate them with a join.
Once you have identified the spearate order and item records, then we can easily target them with aggregates, in this case a simple COUNT
COUNT works well in this context because it will exclude NULL values.
SELECT [order].description
, COUNT(DISTINCT [order].id) as [Orders]
, COUNT(CASE WHEN item.description = 'R-COKE' THEN 1 END) as [R-COKE]
, COUNT(CASE WHEN item.description = 'R-FANT' THEN 1 END) as [R-FANT]
, COUNT(CASE WHEN item.description = 'ARWA' THEN 1 END) as [ARWA]
, COUNT(CASE WHEN item.description = 'R-SPRT' THEN 1 END) as [R-SPRT]
FROM tblOrders [order]
INNER JOIN tblOrders item ON item.id = [order].id AND item.level = 1
WHERE [order].level = 0
GROUP BY [order].description
Try it out in this fiddle: http://sqlfiddle.com/#!18/81ec5/1
To further highlight the groupings, I have included a count of the separate orders, seeing we are counting the drinks as well.