SQL query sum of total corresponding rows - sql

Question

I have two tables as below. Caseid from first table is referenced in second table along with accidents. What I am trying to get total different accidents for a case type. Below two tables I documented sample data and expected result.
Table case:
caseId CaseType
1 AB
2 AB
3 AB
4 CD
5 CD
6 DE
Table CaseAccidents:
AccidentId caseID AccidentRating
1 1 High
2 1 High
3 1 Medium
4 1 LOW
5 2 High
6 2 Medium
7 2 LOW
8 5 High
9 5 High
10 5 Medium
11 5 LOW
Result should look like:
CaseType TotalHIghrating TotalMediumRating TotalLOWRating
AB 3 2 2
CD 2 1 1
DE 0 0 0

Answer 1

To get the sum of every rating, you can Use a SUM(CASE WHEN) clause, adding 1 by every record that match the rating.
In your question, you have pointed out that you want to see all distinct CaseType, you can get it by using a RIGHT JOIN, this will include all records of case table.
select case.CaseType,
sum(case when caseAccidents.AccidentRating = 'High' then 1 else 0 end) as TotalHighRating,
sum(case when caseAccidents.AccidentRating = 'Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when caseAccidents.AccidentRating = 'LOW' then 1 else 0 end) as TotalLowRating
from caseAccidents
right join case on case.caseId = caseAccidents.caseID
group by case.CaseType;
+----------+-----------------+-------------------+----------------+
| CaseType | TotalHighRating | TotalMediumRating | TotalLowRating |
+----------+-----------------+-------------------+----------------+
| AB | 3 | 2 | 2 |
+----------+-----------------+-------------------+----------------+
| CD | 2 | 1 | 1 |
+----------+-----------------+-------------------+----------------+
| DE | 0 | 0 | 0 |
+----------+-----------------+-------------------+----------------+
Check it: http://rextester.com/MCGJA9193

Answer 2

Have you use case in a select clause before?
select C.CaseType,
sum(case when CA.AccidentRating = 'High' then 1 else 0 end)
from Case C join CaseAccidents CA on C.CaseId = CA.CaseId
group by C.CaseType

Answer 3

Please see this. Sample query of the table and also that result
create table #case(caseid int,casetype varchar(5))
insert into #case (caseid,casetype)
select 1,'AB' union all
select 2,'AB' union all
select 3,'AB' union all
select 4,'CD' union all
select 5,'CD' union all
select 6,'DE'
create table #CaseAccidents(AccidentId int, CaseId int,AccidentRating varchar(10))
insert into #CaseAccidents(AccidentId, CaseId, AccidentRating)
select 1,1,'High' union all
select 2,1,'High' union all
select 3,1,'Medium' union all
select 4,1,'Low' union all
select 5,2,'High' union all
select 6,2,'Medium' union all
select 7,2,'Low' union all
select 8,5,'High' union all
select 9,5,'High' union all
select 10,5,'Medium' union all
select 11,5,'Low'
My script
select c.casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end) as TotalHighRating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when ca.AccidentRating='Low' then 1 else 0 end) as TotalLowRating
from #case c
Left join #CaseAccidents ca
on c.Caseid=ca.Caseid
group by c.casetype
Hope This could help!

Answer 4

Another approach using Pivot operator
SELECT casetype,
[High],
[Medium],
[Low]
FROM (SELECT c.casetype,
AccidentRating
FROM case c
LEFT JOIN CaseAccidents ca
ON ca.CaseId = c.caseid)a
PIVOT (Count(AccidentRating)
FOR AccidentRating IN ([High],
[Medium],
[Low]) ) p

Answer 5

Try This code once.
select casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end ) as TotalHIghrating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end ) as TotalMediumRating ,
sum(case when ca.AccidentRating='Low' then 1 else 0 end ) as TotalLOWRating
from #case c
left join #CaseAccidents ca on c.caseid=ca.CaseId
group by casetype