I have two columns in my table:
col1 count
a 5
b 10
c 15
az 10
I want to change the value az to a and then sum count, so, result would be:
TABLE=
col1 count
a 15
b 10
c 15
How do I do this in SQL?
I did:
select col1, SUM(count)
FROM TABLE
WHERE
WHERE TABLE.col1 = CASE WHEN TABLE.col1 = 'az' THEN 'a' ELSE TABLE.col1 END GROUP BY fodc.country
But, it does not give the right results. It gives the unexpected results and completely eliminates az
How to do this in SQL?
You can put the case in the select:
select (case when col1 = 'az' then 'a' else col1 end),
sum(count)
from table1
group by 1;
Related
I'm trying to write a simple query to take a data set that looks like this:
ID | Col2
X B
X C
Y B
Y D
and return this:
ID | Col2 | Col3
X B C
Y B D
Essentially, I have an ID column that can have either B, C, or D in Col2. I am trying to identify which IDs only have B and D. I have a query to find both, but not only that combination. Query:
select ID, Col2
from Table1
where ID in (
select ID from Table1
group by ID
having count(distinct Col2) = 2)
order by ID
Alternatively, I could use help in finding a way to filter that query on B and D and leave off B and C. I have seen perhaps a self join, but am not sure how to implement that.
Thanks!
EDIT: Most of the data set has, for a given ID, all three of B, C, and D. The goal here is to isolate the IDs that are missing one, namely missing C.
I am trying to identify which IDs only have B and D. I have a query to find both
If this is what you want, you don't need multiple columns:
select id
from table1
where col2 in ('B', 'D')
group by id
having count(distinct col2) = 2;
If you want only 'B' and 'D' and no others, then:
select id
from table1
group by id
having sum(case when col2 = 'B' then 1 else 0 end) > 0 AND
sum(case when col2 = 'C' then 1 else 0 end) > 0 AND
sum(case when col2 not in ('B', 'D') then 1 else 0 end) = 0;
If there are only two columns, you can also easily pivot the values using aggregation:
select id, min(col2), nullif(max(col2), min(col2))
from table1
group by id;
I have a table with 4 columns, one of which is a non-null column, all others can be given a null value.
I just want a SELECT that returns results that have as many non-null columns as possible.
For example:
If I have 5 records in my Table, 1 of those records will have 3 columns with data, 2 of them will have 2 columns with data and 2 of them will have only 1 column with data. In my select, I want as a result only the first option: to bring me 3 columns with data. But it can be just 2 columns with data, it will be dynamic according to the table to be updated.
I'm using Oracle SQL.
One option is a conditional sort based on the count of non-null values in each row, and then a row-limiting clause (available since Oracle 12c). Assuming that the 3 nullable columns are col1, col2 and col3, that would be:
select *
from mytable
order by
case when col1 is null then 0 else 1 end
+ case when col2 is null then 0 else 1 end
+ case when col3 is null then 0 else 1 end desc
fetch first row with ties
If you are running an older version of Oracle, you can get the same result with window function rank():
select *
from (
select
t.*,
rank() over(order by
case when col1 is null then 0 else 1 end
+ case when col2 is null then 0 else 1 end
+ case when col3 is null then 0 else 1 end desc
) rn
from mytable t
) t
where rn = 1
Following query returns two rows. I'd like to combine these two rows. Is this possible? This logic will later become one of the columns for another query:
select SUM(case
when FreeRentMonth = 'Y'
then 1
else 0
end) as months
from LARBICRMFact
where rlm_spaceID in (
select RefCRMSpaceID
from #OneAE_Multiple_CRM_deals fs
where fs.RefLeaseAssumptionID = '58500-TSPECTENB-LSPECTENB-0210'
)
group by rlm_spaceID
Desired result:
6|7 (instead of 6 and 7 being in two separate rows).
NOTE*: The subquery can return 1 or many values.
You need to know the values of rlm_spaceID to convert then rows into columns.
for e.g. say the values 6 and 7 are for rlm_spaceID "value1" and "value2".
rlm_spaceID months
value1 6
value2 7
Something like this:
select SUM(case
when rlm_spaceID = 'value1'
and FreeRentMonth = 'Y'
then 1
else 0
end) as val1,
SUM(case
when rlm_spaceID = 'value2'
and FreeRentMonth = 'Y'
then 1
else 0
end) as val2
from LARBICRMFact
where rlm_spaceID in (
select RefCRMSpaceID
from #OneAE_Multiple_CRM_deals fs
where fs.RefLeaseAssumptionID = '58500-TSPECTENB-LSPECTENB-0210'
);
I will keep this simple- I would like to know if there is a good way to select all the values in a column when it never has a null in another column. For example.
A B
----- -----
1 7
2 7
NULL 7
4 9
1 9
2 9
From the above set I would just want 9 from B and not 7 because 7 has a NULL in A. Obviously I could wrap this as a subquery and USE the IN clause etc. but this is already part of a pretty unique set and am looking to keep this efficient.
I should note that for my purposes this would only be a one-way comparison... I would only be returning values in B and examining A.
I imagine there is an easy way to do this that I am missing, but being in the thick of things I don't see it right now.
You can do something like this:
select *
from t
where t.b not in (select b from t where a is null);
If you want only distinct b values, then you can do:
select b
from t
group by b
having sum(case when a is null then 1 else 0 end) = 0;
And, finally, you could use window functions:
select a, b
from (select t.*,
sum(case when a is null then 1 else 0 end) over (partition by b) as NullCnt
from t
) t
where NullCnt = 0;
The query below will only output one column in the final result. The records are grouped by column B and test if the record is null or not. When the record is null, the value for the group will increment each time by 1. The HAVING clause filters only the group which has a value of 0.
SELECT B
FROM TableName
GROUP BY B
HAVING SUM(CASE WHEN A IS NULL THEN 1 ELSE 0 END) = 0
If you want to get all the rows from the records, you can use join.
SELECT a.*
FROM TableName a
INNER JOIN
(
SELECT B
FROM TableName
GROUP BY B
HAVING SUM(CASE WHEN A IS NULL THEN 1 ELSE 0 END) = 0
) b ON a.b = b.b
My table structure is this
id last_mod_dt nr is_u is_rog is_ror is_unv
1 x uuid1 1 1 1 0
2 y uuid1 1 0 1 1
3 z uuid2 1 1 1 1
I want the count of rows with:
is_ror=1 or is_rog =1
is_u=1
is_unv=1
All in a single query. Is it possible?
The problem I am facing is that there can be same values for nr as is the case in the table above.
Case statments provide mondo flexibility...
SELECT
sum(case
when is_ror = 1 or is_rog = 1 then 1
else 0
end) FirstCount
,sum(case
when is_u = 1 then 1
else 0
end) SecondCount
,sum(case
when is_unv = 1 then 1
else 0
end) ThirdCount
from MyTable
you can use union to get multiple results e.g.
select count(*) from table with is_ror=1 or is_rog =1
union
select count(*) from table with is_u=1
union
select count(*) from table with is_unv=1
Then the result set will contain three rows each with one of the counts.
Sounds pretty simple if "all in a single query" does not disqualify subselects;
SELECT
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_ror=1 OR is_rog=1) cnt_ror_reg,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_u=1) cnt_u,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_unv=1) cnt_unv;
how about something like
SELECT
SUM(IF(is_u > 0 AND is_rog > 0, 1, 0)) AS count_something,
...
from table
group by nr
I think it will do the trick
I am of course not sure what you want exactly, but I believe you can use the logic to produce your desired result.