dynamic grouping by month in SQL - sql

Question

I am using CASE statements to group data into Month columns, like this:
SUM(CASE WHEN MONTH(date) = 1 THEN ROUND(value) END) as jan,
SUM(CASE WHEN MONTH(date) = 2 THEN ROUND(value) END) as feb,
SUM(CASE WHEN MONTH(date) = 3 THEN ROUND(value) END) as mar
Is it possible to NOT have to define the different CASE groupings?
I want to define the data range in the WHERE statement, and then have the report group by month, for whatever range I define. For example, maybe my report starts with July'20, and not Jan.
Is this possible in an SQL query?
Thanks
edit - example output:
+-------+-------+------+-------+-------+
| | July | Aug | Sep | etc |
+-------+-------+------+-------+-------+
| value | 435 € | 24 € | 234 € | 453 € |
+-------+-------+------+-------+-------+
edit - possible solution/workaround:
if I do the following, it can be considered "semi-dynamic". I still need to define the month "buckets", but they can be trigged by the starting date (the month({ d '2021-01-01' }) part can also later be replaced with a variable, so that is also fixed in the code.
SUM (CASE WHEN MONTH(date) = month({ d '2021-01-01' }) THEN value END) as month_1,
SUM (CASE WHEN MONTH(date) = month({ d '2021-01-01' })+1 THEN value END) as month_2,
SUM (CASE WHEN MONTH(date) = month({ d '2021-01-01' })+2 THEN value END) as month_3,
etc
the main downside is that I have to hard-code the number of month groupings. So i'd be happy to hear of a better solution!

Answer 1

You can create a dynamic sql statement to generate the result into a temporary table and then return the result from the temporary table. Here is an example:
declare sqlStr string;
sqlStr = 'SELECT 1 AS column1, 2 AS column2 INTO #temp FROM system.iota';
execute immediate sqlStr;
select * from #temp;
The logic to generate the required grouping is up to you. You will need to use the while loop to construct the statement text.